Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 83 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 funksiyaning eng kichik musbat davrini toping. A) 18 B) 24 C) 12 D) 26 2 / 40 Jamshid bir kunda 70,5 kgdan paxta tersa, 8460 kg paxtani necha kunda terib bo’ladi ? A) 120 kun B) 140 kun C) 100 kun D) 130 kun 3 / 40 tenglamani yeching. A) log(3/5)2 B) 3 C) log(5/3)2 D) 5 4 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) x=-a B) y=-a C) x=a D) y=1-a 5 / 40 Hisoblang: -121+(-135)-(-1)28 A) -3 B) -2 C) -1 D) 0 6 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) )a,b,d B) a,b C) b D) b,d 7 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 600 B) 3600 C) 4800 D) 5050 8 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 1 B) 2 C) 5 D) 4 9 / 40 Agar bo'lsa, ni m orqali ifodalang. A) (4-m)/4 B) (m+1)/2 C) (m+4)/4 D) 2/m 10 / 40 Yig‘indini toping. A) 1/9 B) 1/6 C) 1/12 D) 1/4 11 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 8(π+2) C) 16(π-2) D) 32 12 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 44 C) 42 D) 43 13 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 4√3 D) 2√3 14 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 30° D) 50° 15 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) 4 √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 16 / 40 sonlarini taqqolsang. A) c B) c C) a D) b 17 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 3√2 C) 6 D) 4√2 18 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 3 D) 2 19 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 12 D) 14 20 / 40 √3 A) 21/10 B) 7/3 C) 5/5 D) 3/2 21 / 40 Hisoblang: A) 1 B) cos10° C) sin10° D) cos50° 22 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 24 C) 28 D) 32 23 / 40 Tenglamani yeching: A) -6; 5 B) -6 C) 6; -5 D) 5 24 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 64 C) 48 D) 32 25 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 1 D) 2 26 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 11 C) 5 D) 6 27 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 24 C) 35 D) 23 28 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 4 C) 3 D) 2 29 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) DC < AD D) AB = BC 30 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 5 yoki –15 C) 3 yoki –8 D) 4 yoki –12 31 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 20 D) 8 32 / 40 Hisoblang: A) -√3/2 B) 1/32 C) -1/2 D) 0 33 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 10 C) 4√7 D) 6√7 34 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) 22 D) berilganlar yetarli emas 35 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 5 D) 6 36 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 10 C) 8 D) 6 37 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 14 D) 15 38 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) bc/d D) 1 39 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) 3 D) -2 40 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,(04) C) 0,04 D) 0,0(4) O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16