Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 84 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 2 B) 4 C) 5 D) 3 2 / 40 bo‘lsa, y = ? A) 8 B) 3 C) 2 D) 26 3 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln3 B) ln2 C) ln5 D) ln4 4 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)+2x²-1 B) f(x)=x²-4 C) f(x)=x²+3x+7 D) f(x)=x²-x+5 5 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 1 C) 4 D) 3 6 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 7 B) 12 C) 5 D) 1 7 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 0 B) 25 C) 30 D) 10 8 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) 1/8 B) √3/4 C) √2/8 D) √3/8 9 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -√17 B) -4 C) 4 D) √17 10 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 8 B) 6 C) 10 D) 9 11 / 40 √3 A) 7/3 B) 5/5 C) 21/10 D) 3/2 12 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 32 D) 42 13 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 10 D) 12 14 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√2 C) 2√3 D) 3√2 15 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 4 C) 3 D) 1 16 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) -2 C) 5 D) 3 17 / 40 Tenglamani yeching: A) -6 B) 5 C) 6; -5 D) -6; 5 18 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 32 C) 30 D) 28 19 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 2 C) 3 D) 1 20 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 35 D) 24 21 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 32 C) 64 D) 8(π+2) 22 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 20 C) 8 D) 10 23 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 5 C) 6 D) 8 24 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 4√7 C) 8 D) 6√7 25 / 40 Hisoblang: A) 9/10 B) 19/20 C) 20/21 D) 10/11 26 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) Ø C) 0 D) π/4+πk, k∈Z 27 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 6 D) 3 yoki –8 28 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) 1 D) bc/d 29 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,04 C) 0,0(4) D) 0,0(2) 30 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 0 D) 1/32 31 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 32 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 10 C) 5 D) 7 33 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) BD = BC C) DC < AD D) AB = BC 34 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 35 / 40 Hisoblang: A) cos50° B) 1 C) sin10° D) cos10° 36 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 110 C) 116 D) 115 37 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (28; -1) C) (9; 0), (2; 7) D) (7; 2), (28; -1) 38 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 10 D) 20 39 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) berilganlar yetarli emas C) 11 D) 22 40 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 3 C) 4 D) 2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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