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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

|x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping.

A) 7

B) 6

C) 5

D) 0

2 / 40

ko’paytmani hisoblang.

A) 86420000

B) 0

C) 480000

D) 10000

3 / 40

Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping.

A) 0,6 m yoki 60 cm

B) 0,9 m yoki 90 cm

C) 0,7 m yoki 70 cm

D) 0,5 m yoki 50 cm

4 / 40

funksiyaning qiymatlar to'plamini toping.

A) (-2√2;√2)

B) [-√2;-1)∪(-1;1)∪(1;√2]

C) [-√2;√2]

D) [-√2;0)∪(0;√2]

5 / 40

Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ?

A) 13

B) 12

C) 14

D) 11

6 / 40

x ni toping ?

A) 5

B) 6

C) 3

D) 4

7 / 40

x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi?

A) 7

B) 9

C) 15

D) 12

8 / 40

Funksiyaning aniqlanish sohasini toping.

A) x∈R

B) [-3;2]

C) (-∞;3]∪[2;∞)

D) (-∞;0)∪(0;∞)

9 / 40

tenglama intervalda nechta ildizga ega?

A) 3

B) 2

C) 1

D) 4

10 / 40

Agar bo‘lsa, m/n ni toping.

A) 4

B) (1+√5)/2

C) 2

D) 3

11 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 8

B) 15

C) 20

D) 10

12 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 4

B) 2

C) 3

D) 1

13 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 44

B) 45

C) 42

D) 43

14 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -6

B) 5

C) -3

D) -4

15 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 5

B) -2

C) 3

D) 8

16 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 42

B) 64

C) 48

D) 32

17 / 40

Hisoblang:

A) -1/2

B) 0

C) 1/32

D) -√3/2

18 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 2

B) 3

C) 1

D) 4

19 / 40

sonlarini taqqolsang.

A) c

B) c

C) b

D) a

20 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 3√2

B) 2√2

C) 4√3

D) 2√3

21 / 40

Hisoblang:

A) 20/21

B) 19/20

C) 9/10

D) 10/11

22 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 12

B) 11

C) 10

D) 9

23 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) π/4+πk, k∈Z

B) 0

C) Ø

D) -π/4+πk, k∈Z

24 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (28; -1)

B) (2; 3)

C) (7; 2), (28; -1)

D) (9; 0), (2; 7)

25 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) bc/d

B) cd/b

C) 1

D) bd/c

26 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) berilganlar yetarli emas

B) 121

C) 11

D) 22

27 / 40

√3

A) 3/2

B) 7/3

C) 21/10

D) 5/5

28 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 10

B) 12

C) 6

D) 8

29 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 64

C) 16(π-2)

D) 32

30 / 40

bo‘lsa,

A) 2

B) 2/3

C) 3/2

D) 1

31 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 10

B) 6√7

C) 8

D) 4√7

32 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 20

B) 10

C) 14

D) 12

33 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 4

B) 11

C) 6

D) 5

34 / 40

Tenglamani yeching:

A) 5

B) -6

C) -6; 5

D) 6; -5

35 / 40

Hisoblang:

A) cos50°

B) sin10°

C) 1

D) cos10°

36 / 40

Rasmdagi shakl perimetrini toping.

A) 24

B) 28

C) 30

D) 32

37 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 116

B) 110

C) 115

D) 112

38 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 24

B) 23

C) 35

D) 14

39 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 96

B) 100

C) 25

D) 105

40 / 40

Chizmadan foydalanib α ni toping.