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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping.

A) 3

B) 2

C) 4

D) 1

2 / 40

Berilgan sonlarning yig’indisini toping.

A) 2/4

B) -452/18

C) 3/18

D) 1/4

3 / 40

1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2ⁿ, 3^m va 7^k lar ishtirok etsa, n+m+k ni toping.

A) 50

B) 44

C) 40

D) 46

4 / 40

a va b musbat sonlari uchun a^lnb·b^lna+a^lnb+b^lnabo'lsa, (lna)·(lnb)=?

A) ln2

B) ln4

C) ln3

D) ln5

5 / 40

n ning qanday qiymatida tenglik to`g`ri bo’ladi? (7³)=7¹⁵

A) 1

B) 5

C) 7

D) 12

6 / 40

Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ?

A) 7

B) 6

C) 8

D) 9

7 / 40

x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi?

A) 7

B) 9

C) 15

D) 12

8 / 40

Tenglamalar sistemasidan foydalanib x + y + z ni toping:

A) 10

B) 6

C) 8

D) berilganlar yetarli emas

9 / 40

f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng?

A) 600

B) 5050

C) 3600

D) 4800

10 / 40

x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping.

A) 48

B) 32

C) 16

D) 64

11 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 45

B) 43

C) 42

D) 44

12 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 14

B) 12

C) 10

D) 20

13 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 1

B) 4

C) 2

D) 3

14 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) √3ctg40° tg70°

B) 2√3tg50° tg70°

C) √3tg50° tg70°

D) 4 √3tg50° tg70°

15 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 22

B) berilganlar yetarli emas

C) 11

D) 121

16 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 8

B) -2

C) 5

D) 3

17 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 3

B) 1

C) 2

D) 4

18 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 42

B) 32

C) 64

D) 48

19 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 5

B) 7

C) 8

D) 6

20 / 40

bo‘lsa,

A) 3/2

B) 2

C) 2/3

D) 1

21 / 40

√3

A) 21/10

B) 7/3

C) 3/2

D) 5/5

22 / 40

Hisoblang:

A) cos50°

B) sin10°

C) cos10°

D) 1

23 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 12

B) 10

C) 11

D) 9

24 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -4

B) 5

C) -6

D) -3

25 / 40

Ifodaning qiymatini toping.

A) 0,04

B) 0,(04)

C) 0,0(2)

D) 0,0(4)

26 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√3

B) 3√2

C) 2√2

D) 4√3

27 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 3√2

B) 6

C) 4√3

D) 4√2

28 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 64

B) 16(π-2)

C) 8(π+2)

D) 32

29 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BC > AD

B) BD = BC

C) AB = BC

D) DC < AD

30 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 15

B) 8

C) 20

D) 10

31 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 24

B) 14

C) 23

D) 35

32 / 40

Tenglamani yeching:

A) -6

B) -6; 5

C) 5

D) 6; -5

33 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 10

B) 6√7

C) 4√7

D) 8

34 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 15

B) 14

C) 12

D) 13

35 / 40

sonlarini taqqolsang.

A) c

B) b

C) c

D) a

36 / 40

Chizmadan foydalanib α ni toping.

A) 20°

B) 50°

C) 30°

D) 40°

37 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 6

C) 12

D) 10

38 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.