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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ?

A) 9

B) 14

C) 6

D) 12

2 / 40

y=4cos 2x+cos8x funksiyaning hosilasini toping

A) 16sin3x*cos5x

B) -16cos3x*sin5x

C) 16sin3x*sin5x

D) 16cos3x*cos5x

3 / 40

Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping.

A) 8

B) 2

C) 6

D) 4

4 / 40

cosx=0,2x tenglama nechta yechimga ega?

A) 3

B) 1

C) 4

D) 2

5 / 40

Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ?

A) 14

B) 11

C) 12

D) 13

6 / 40

Soddalshtiring.

A) -1

B) 6

C) 2

D) 1

7 / 40

ni hisoblang.

A) 3

B) 1

C) 2

D) 0

8 / 40

Tenglamani yeching:

A) 5*4

B) 5/9

C) 9/5

D) 6/5

9 / 40

Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping.

A) 1

B) 8

C) 5

D) 0

10 / 40

Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping.

A) √5

B) 2,4

C) 2,5

D) √6

11 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -6

B) 5

C) -4

D) -3

12 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 7

B) 10

C) 11

D) 5

13 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 12

B) 14

C) 15

D) 13

14 / 40

Hisoblang:

A) 19/20

B) 9/10

C) 20/21

D) 10/11

15 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 10

C) 8

D) 6√7

16 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 45

B) 42

C) 43

D) 44

17 / 40

Hisoblang:

A) 0

B) 1/32

C) -√3/2

D) -1/2

18 / 40

Hisoblang:

A) cos10°

B) sin10°

C) cos50°

D) 1

19 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 20

B) 10

C) 15

D) 8

20 / 40

√3

A) 5/5

B) 7/3

C) 21/10

D) 3/2

21 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 5

B) 8

C) 6

D) 7

22 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 3

B) 8

C) -2

D) 5

23 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 4

B) 11

C) 5

D) 6

24 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√2

B) 2√3

C) 4√3

D) 3√2

25 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) π/4+πk, k∈Z

B) Ø

C) -π/4+πk, k∈Z

D) 0

26 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 12

B) 9

C) 11

D) 10

27 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 3

B) 2

C) 4

D) 1

28 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 100

B) 105

C) 96

D) 25

29 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 1

B) 2

C) 4

D) 3

30 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (28; -1)

B) (7; 2), (28; -1)

C) (2; 3)

D) (9; 0), (2; 7)

31 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 2

B) 4

C) 1

D) 3

32 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 24

B) 14

C) 23

D) 35

33 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 16(π-2)

B) 32

C) 64

D) 8(π+2)

34 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 3

B) 2

C) 4

D) 1

35 / 40

sonlarini taqqolsang.

A) c

B) b

C) c

D) a

36 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 32

B) 42

C) 64

D) 48

37 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 10

B) 6

C) 8

D) 12

38 / 40

Ifodaning qiymatini toping.