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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

va bo'lsa x-y=?

A) 5

B) 9

C) 7

D) 8

2 / 40

Yig’indi quydagilardan qaysi biriga teng?

A) 45,0608

B) 40560,8

C) 4506,08

D) 450,608

3 / 40

P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping.

A) 3x+2y-2=0

B) 3x-2y-2=0

C) 3x+2y+2=0

D) 3x-2y+2=0

4 / 40

P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping.

A) 3

B) 1

C) 4

D) 2

5 / 40

x ni toping ?

A) 4

B) 3

C) 5

D) 6

6 / 40

Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ?

A) 13

B) 11

C) 10

D) 12

7 / 40

ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping.

A) 132°

B) 135°

C) 142°

D) 138°

8 / 40

Hisoblang:

A) 8

B) 6

C) 4

D) 0

9 / 40

7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping.

A) 4

B) 2

C) 1

D) 5

10 / 40

108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng?

2¹²·3¹⁸
2²·3³
2⁸·3¹⁰
2⁶·3⁹

A) 4

B) 3

C) 1

D) 2

11 / 40

Hisoblang:

A) -1/2

B) -√3/2

C) 1/32

D) 0

12 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√3

B) 3√2

C) 4√3

D) 2√2

13 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 5

B) 8

C) 3

D) -2

14 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 4 yoki –12

B) 5 yoki –15

C) 3 yoki –8

D) 6

15 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 14

B) 12

C) 15

D) 13

16 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 112

B) 115

C) 110

D) 116

17 / 40

Tenglamani yeching:

A) -6; 5

B) -6

C) 5

D) 6; -5

18 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 121

B) 11

C) 22

D) berilganlar yetarli emas

19 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 24

B) 14

C) 23

D) 35

20 / 40

Hisoblang:

A) 10/11

B) 9/10

C) 19/20

D) 20/21

21 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) Ø

B) -π/4+πk, k∈Z

C) π/4+πk, k∈Z

D) 0

22 / 40

Rasmdagi shakl perimetrini toping.

A) 32

B) 30

C) 24

D) 28

23 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) 1

B) bd/c

C) cd/b

D) bc/d

24 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 8

C) 5

D) 6

25 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 6√7

B) 4√7

C) 8

D) 10

26 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 9

B) 11

C) 10

D) 12

27 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 6

B) 4

C) 5

D) 11

28 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) AB = BC

B) BC > AD

C) BD = BC

D) DC < AD

29 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 16(π-2)

C) 64

D) 32

30 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 7

B) 5

C) 11

D) 10

31 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 64

B) 42

C) 32

D) 48

32 / 40

√3

A) 7/3

B) 5/5

C) 21/10

D) 3/2

33 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 44

B) 45

C) 42

D) 43

34 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 6

B) 4√3

C) 4√2

D) 3√2

35 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 4

B) 2

C) 1

D) 3

36 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 12

C) 6

D) 10

37 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 105

B) 100

C) 25

D) 96

38 / 40

Chizmadan foydalanib α ni toping.