Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 97 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 va bo'lsa x-y=? A) 8 B) 7 C) 5 D) 9 2 / 40 Agar ning qiymatini toping. A) 75/23 B) 23/25 C) 23/75 D) 3 3 / 40 funksiyaning qiymatlar to'plamini toping. A) (-2√2;√2) B) [-√2;√2] C) [-√2;-1)∪(-1;1)∪(1;√2] D) [-√2;0)∪(0;√2] 4 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 11/5 B) 67/15 C) 31/85 D) 68/15 5 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 8 B) 7 C) 9 D) 6 6 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 101 B) 98 C) 100 D) 99 7 / 40 ni hisoblang. A) 3 B) 2 C) 1 D) 0 8 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 32 B) 64 C) 16 D) 48 9 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 4 B) 6 C) 2 D) 5 10 / 40 Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping. A) 2,5 B) 2,4 C) √5 D) √6 11 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 8 C) 10 D) 4√7 12 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 15 C) 13 D) 12 13 / 40 Tenglamani yeching: A) -6; 5 B) -6 C) 5 D) 6; -5 14 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) -π/4+πk, k∈Z C) 0 D) Ø 15 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -6 C) -3 D) 5 16 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 17 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) AB = BC D) BC > AD 18 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) bc/d C) 1 D) cd/b 19 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (2; 3) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 20 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 35 C) 23 D) 24 21 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 22 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) -2 D) 5 23 / 40 Hisoblang: A) 1 B) cos10° C) sin10° D) cos50° 24 / 40 Hisoblang: A) 9/10 B) 20/21 C) 19/20 D) 10/11 25 / 40 bo‘lsa, A) 3/2 B) 2 C) 2/3 D) 1 26 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 30° C) 50° D) 20° 27 / 40 √3 A) 21/10 B) 7/3 C) 3/2 D) 5/5 28 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 12 C) 20 D) 14 29 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 6 D) 7 30 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 5 C) 7 D) 11 31 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 8 D) 20 32 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 10 D) 12 33 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 2 C) 3 D) 1 34 / 40 Hisoblang: A) -1/2 B) 0 C) 1/32 D) -√3/2 35 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,(04) C) 0,0(2) D) 0,0(4) 36 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 45 D) 44 37 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 1 C) 4 D) 3 38 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 12 C) 6 D) 8 39 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 4√3 D) 2√3 40 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 3 D) 1 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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