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Matematika attestatsiya №6

InfoMaster

Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin?

A) 9

B) 27

C) 6

D) 7

2 / 40

Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping.

A) 24

B) 32

C) 16

D) 8

3 / 40

f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping.

A) -13cosx- cos13 x +C

B) 13sinx-sin13x + C

C) 13sinx+sin13x + C

D) 13cosx-cos13x + C

4 / 40

Hisoblang:

A) 4

B) 27

C) 7

D) 9

5 / 40

Hisoblang:

A) 1

B) 3

C) 4

D) 2

6 / 40

Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ?

A) 2 km

B) 200 km

C) 20 km

D) 0,2km

7 / 40

Hisoblang:

A) 6

B) 8

C) 0

D) 4

8 / 40

Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1.

A) 50

B) 41

C) 25

D) 32

9 / 40

sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan?

A) 3

B) 2

C) 1

D) 4

10 / 40

ni hisoblang.

A) 3

B) 1

C) 2

D) 0

11 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 32

B) 16(π-2)

C) 8(π+2)

D) 64

12 / 40

√3

A) 5/5

B) 3/2

C) 7/3

D) 21/10

13 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 8

B) 10

C) 15

D) 20

14 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 10

B) 11

C) 12

D) 9

15 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 2

B) 1

C) 3

D) 4

16 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 6

C) 5

D) 8

17 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 10

C) 6√7

D) 8

18 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 14

B) 24

C) 35

D) 23

19 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) AB = BC

B) BC > AD

C) DC < AD

D) BD = BC

20 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 11

B) 5

C) 7

D) 10

21 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) √3ctg40° tg70°

B) 2√3tg50° tg70°

C) √3tg50° tg70°

D) 4 √3tg50° tg70°

22 / 40

Tenglamani yeching:

A) 5

B) 6; -5

C) -6

D) -6; 5

23 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 25

B) 105

C) 96

D) 100

24 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√3

B) 4√2

C) 3√2

D) 6

25 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) cd/b

B) bc/d

C) bd/c

D) 1

26 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√3

B) 3√2

C) 4√3

D) 2√2

27 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 12

B) 8

C) 6

D) 10

28 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.