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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=?

A) 60

B) 61

C) 58

D) 59

2 / 40

Bobur 14 m/s tezlik bilan 5 soat, 36 km/soat tezlik bilan 5 minut yugurgan bo’lsa , Boburning umumiy yurgan yo’li topilsin

A) 670 km

B) 255 km

C) 456 km

D) 13 km

3 / 40

x⁴+8x³+ax²+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping.

A) 48

B) 27

C) 26

D) 32

4 / 40

Umumiy hadi x_n=3+5n-n² formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam?

A) 5,75

B) 6

C) 9,25

D) 13

5 / 40

DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ?

A) 110°

B) 100°

C) 120°

D) 130°

6 / 40

Hisoblang:

A) 2

B) 1

C) 4

D) 3

7 / 40

Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin.

A) R(√3-√2)

B) 1,5R

C) 3R

D) √3R(2-√3)

8 / 40

Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping.

A) 72π

B) 144π

C) 192π

D) 96π

9 / 40

x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi?

A) 15

B) 9

C) 12

D) 7

10 / 40

1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri?

A) 2

B) 4

C) 1

D) 3

11 / 40

bo‘lsa,

A) 1

B) 2

C) 3/2

D) 2/3

12 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 6

C) 10

D) 12

13 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 4

B) 1

C) 2

D) 3

14 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 4

B) 1

C) 3

D) 2

15 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 32

B) 64

C) 16(π-2)

D) 8(π+2)

16 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) berilganlar yetarli emas

B) 121

C) 22

D) 11

17 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) -π/4+πk, k∈Z

B) Ø

C) 0

D) π/4+πk, k∈Z

18 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -3

B) 5

C) -6

D) -4

19 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 9

B) 11

C) 12

D) 10

20 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 6√7

C) 8

D) 10

21 / 40

Hisoblang:

A) 1

B) sin10°

C) cos50°

D) cos10°

22 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 8

C) 5

D) 6

23 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 20

B) 10

C) 15

D) 8

24 / 40

Tenglamani yeching:

A) 6; -5

B) -6

C) -6; 5

D) 5

25 / 40

Chizmadan foydalanib α ni toping.

A) 40°

B) 20°

C) 30°

D) 50°

26 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 25

B) 96

C) 100

D) 105

27 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 4√3

B) 3√2

C) 2√3

D) 2√2

28 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 6

B) 4√2

C) 3√2

D) 4√3

29 / 40

Hisoblang:

A) 19/20

B) 9/10

C) 10/11

D) 20/21

30 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 14

B) 13

C) 12

D) 15

31 / 40

sonlarini taqqolsang.

A) a

B) b

C) c

D) c

32 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 5

B) 6

C) 4

D) 11

33 / 40

Ifodaning qiymatini toping.

A) 0,(04)

B) 0,0(2)

C) 0,04

D) 0,0(4)

34 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BD = BC

B) BC > AD

C) DC < AD

D) AB = BC

35 / 40

Tenglamalar sistemani yeching: