Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 72 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Agar va bo'lsa f(4) ning qiymatini toping. A) 4 B) 11 C) 12 D) 35 2 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 2 B) 3 C) 5 D) 4 3 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 7,5 B) 3 C) 4,5 D) 4 4 / 40 Hisoblang: A) 9 B) 7 C) 4 D) 27 5 / 40 Soddalshtiring. A) 1 B) -1 C) 2 D) 6 6 / 40 x ni toping ? A) 5 B) 4 C) 6 D) 3 7 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 3 B) 2 C) 4 D) 1 8 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 1 B) 5 C) 8 D) 0 9 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 12 B) 15 C) 9 D) 7 10 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 96π B) 144π C) 192π D) 72π 11 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 116 C) 115 D) 110 12 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 44 C) 42 D) 45 13 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 20 C) 12 D) 10 14 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 9 C) 11 D) 10 15 / 40 √3 A) 3/2 B) 5/5 C) 7/3 D) 21/10 16 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,0(4) D) 0,(04) 17 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) 1 C) bd/c D) bc/d 18 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) 121 D) berilganlar yetarli emas 19 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√3 C) 4√2 D) 6 20 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 3 C) 1 D) 2 21 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 8 C) 10 D) 6 22 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) 5 C) -3 D) -4 23 / 40 Hisoblang: A) 20/21 B) 19/20 C) 9/10 D) 10/11 24 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 3√2 C) 2√3 D) 2√2 25 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 26 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 14 C) 12 D) 15 27 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 25 C) 105 D) 100 28 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 6 C) 4 D) 5 29 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 11 D) 10 30 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 30° C) 20° D) 40° 31 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 5 D) 6; -5 32 / 40 bo‘lsa, A) 3/2 B) 2/3 C) 2 D) 1 33 / 40 Hisoblang: A) 1 B) cos50° C) sin10° D) cos10° 34 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 24 C) 28 D) 30 35 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 8 D) 10 36 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 64 C) 8(π+2) D) 16(π-2) 37 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 4 C) 3 D) 2 38 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) DC < AD D) AB = BC 39 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) 8 D) -2 40 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 32 D) 42 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16