Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 84 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 votes, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 58 B) 60 C) 61 D) 59 2 / 40 Berilgan sonlarning yig’indisini toping. A) 1/4 B) 3/18 C) 2/4 D) -452/18 3 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) y=1-a B) x=-a C) x=a D) y=-a 4 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)=x²-4 B) f(x)=x²+3x+7 C) f(x)+2x²-1 D) f(x)=x²-x+5 5 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUB B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUB 3-EKUK D) 1-EKUB 2-EKUK 3-EKUK 6 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 120° B) 100° C) 130° D) 110° 7 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 10 B) 30 C) 0 D) 25 8 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,432 B) 0,288 C) 0,216 D) 0,144 9 / 40 ABC o‘tkir burchakli uchburchakda sinA=4/5 va sinB=15/13 bo'lsa, sinC ni qiymatini toping. A) 36/65 B) 56/65 C) 48/65 D) 40/63 10 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) 1/8 B) √3/4 C) √2/8 D) √3/8 11 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 1 C) 4 D) 3 12 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 32 C) 30 D) 28 13 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) bc/d D) 1 14 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,0(2) D) 0,04 15 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√3 C) 3√2 D) 4√2 16 / 40 sonlarini taqqolsang. A) c B) c C) a D) b 17 / 40 Hisoblang: A) 0 B) -1/2 C) -√3/2 D) 1/32 18 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (7; 2), (28; -1) C) (2; 3) D) (9; 0), (28; -1) 19 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 4 C) 2 D) 1 20 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) 121 D) berilganlar yetarli emas 21 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 35 C) 24 D) 23 22 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 20° D) 30° 23 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) -π/4+πk, k∈Z C) π/4+πk, k∈Z D) Ø 24 / 40 √3 A) 7/3 B) 3/2 C) 5/5 D) 21/10 25 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 43 C) 42 D) 44 26 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 13 D) 12 27 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 8 C) 6 D) 10 28 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 42 D) 32 29 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 5 C) -2 D) 3 30 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -4 D) -3 31 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 10 D) 8 32 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) 2√3tg50° tg70° C) √3ctg40° tg70° D) √3tg50° tg70° 33 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 7 D) 5 34 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 12 C) 11 D) 10 35 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 14 C) 10 D) 12 36 / 40 Tenglamani yeching: A) 5 B) -6; 5 C) 6; -5 D) -6 37 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 1 D) 3 38 / 40 Hisoblang: A) cos10° B) sin10° C) cos50° D) 1 39 / 40 Hisoblang: A) 9/10 B) 20/21 C) 19/20 D) 10/11 40 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 The average score is 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16