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Matematika attestatsiya №6

InfoMaster

Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin?

A) 9

B) 6

C) 27

D) 7

2 / 40

y=4cos 2x+cos8x funksiyaning hosilasini toping

A) 16cos3x*cos5x

B) 16sin3x*sin5x

C) -16cos3x*sin5x

D) 16sin3x*cos5x

3 / 40

tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping.

A) 0

B) 1

C) 2

D) 3

4 / 40

Hisoblang:

A) 7

B) 9

C) 4

D) 27

5 / 40

Standart shaklda yozing 0,000000000000013

1,3·10^-12
1,3·10^-13
1,3·10^-14
1,3·10^-15

A) 1

B) 4

C) 2

D) 3

6 / 40

Hisoblang 200−199+198−197+⋯+4−3

A) 101

B) 100

C) 99

D) 98

7 / 40

1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri?

A) 3

B) 4

C) 2

D) 1

8 / 40

ni hisoblang.

A) 3

B) 0

C) 1

D) 2

9 / 40

tenglama intervalda nechta ildizga ega?

A) 1

B) 3

C) 2

D) 4

10 / 40

A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping.

A) 120

B) 90

C) 80

D) 100

11 / 40

Hisoblang:

A) 9/10

B) 10/11

C) 20/21

D) 19/20

12 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 6

C) 10

D) 12

13 / 40

Ifodaning qiymatini toping.

A) 0,(04)

B) 0,04

C) 0,0(4)

D) 0,0(2)

14 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 5

B) 8

C) 6

D) 7

15 / 40

Tenglamalar sistemani yeching:

A) (2; 3)

B) (7; 2), (28; -1)

C) (9; 0), (2; 7)

D) (9; 0), (28; -1)

16 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 12

B) 15

C) 14

D) 13

17 / 40

sonlarini taqqolsang.

A) a

B) c

C) c

D) b

18 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -3

B) -4

C) 5

D) -6

19 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 20

B) 10

C) 15

D) 8

20 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 9

B) 10

C) 11

D) 12

21 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 3√2

B) 2√3

C) 4√3

D) 2√2

22 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 11

B) 4

C) 5

D) 6

23 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 8

B) 5

C) -2

D) 3

24 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 16(π-2)

C) 32

D) 64

25 / 40

√3

A) 21/10

B) 7/3

C) 3/2

D) 5/5

26 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 32

B) 42

C) 48

D) 64

27 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) √3ctg40° tg70°

B) 2√3tg50° tg70°

C) 4 √3tg50° tg70°

D) √3tg50° tg70°

28 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) Ø

B) 0

C) π/4+πk, k∈Z

D) -π/4+πk, k∈Z

29 / 40

Chizmadan foydalanib α ni toping.

A) 40°

B) 50°

C) 20°

D) 30°

30 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 20

B) 14

C) 12

D) 10

31 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 3√2

B) 6

C) 4√2

D) 4√3

32 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 23

B) 35

C) 24

D) 14

33 / 40

Hisoblang:

A) -1/2

B) -√3/2

C) 1/32

D) 0

34 / 40

Tenglamani yeching:

A) -6

B) -6; 5

C) 5

D) 6; -5

35 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 112

B) 115

C) 116

D) 110

36 / 40

bo‘lsa,

A) 2/3

B) 2

C) 1

D) 3/2

37 / 40

Hisoblang:

A) 1

B) sin10°

C) cos50°

D) cos10°

38 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 44

B) 45

C) 43

D) 42

39 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 11

B) 7

C) 10

D) 5

40 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 4

B) 3

C) 1

D) 2

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