Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 97 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 va bo'lsa x-y=? A) 8 B) 9 C) 7 D) 5 2 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 4 B) 1 C) 2 D) 3 3 / 40 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/3 B) 4 C) 1/5 D) 1/4 4 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 31/85 B) 67/15 C) 11/5 D) 68/15 5 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 1 B) 3 C) 4 D) 2 6 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 64/5 B) 48/5 C) 16 D) 10 7 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 72π B) 144π C) 96π D) 192π 8 / 40 Tenglamani yeching: A) 5*4 B) 5/9 C) 6/5 D) 9/5 9 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 12 B) 9 C) 15 D) 7 10 / 40 Hisoblang: A) 6 B) 8 C) 0 D) 4 11 / 40 Tenglamani yeching: A) 5 B) 6; -5 C) -6 D) -6; 5 12 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(2) C) 0,0(4) D) 0,04 13 / 40 Hisoblang: A) sin10° B) cos50° C) 1 D) cos10° 14 / 40 √3 A) 5/5 B) 7/3 C) 21/10 D) 3/2 15 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) -2 D) 8 16 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 48 D) 42 17 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 2√3tg50° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 18 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 45 C) 42 D) 43 19 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 16(π-2) C) 32 D) 64 20 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) 0 C) Ø D) -π/4+πk, k∈Z 21 / 40 bo‘lsa, A) 2 B) 2/3 C) 1 D) 3/2 22 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 14 D) 12 23 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 23 C) 14 D) 24 24 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 10 C) 7 D) 5 25 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 28 D) 24 26 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 100 C) 105 D) 25 27 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 8 D) 6 28 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 4√3 D) 3√2 29 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BC > AD C) DC < AD D) BD = BC 30 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 3 D) 2 31 / 40 sonlarini taqqolsang. A) c B) c C) b D) a 32 / 40 Hisoblang: A) 0 B) 1/32 C) -1/2 D) -√3/2 33 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) 121 D) berilganlar yetarli emas 34 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√2 C) 4√3 D) 6 35 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 10 D) 8 36 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 2 D) 4 37 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 3 yoki –8 C) 5 yoki –15 D) 4 yoki –12 38 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 3 C) 4 D) 2 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) cd/b C) bd/c D) 1 40 / 40 Hisoblang: A) 20/21 B) 9/10 C) 19/20 D) 10/11 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16