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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

$y^4+9x^2-4y^2-30x+29=0$ tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping.

A) 289

B) 203

C) 200

D) 201

2 / 40

Berilgan sonlarning yig’indisini toping.

A) 3/18

B) -452/18

C) 1/4

D) 2/4

3 / 40

Aniq integralni hisoblang:

A) 2

B) 0

C) 0,5

D) 3

4 / 40

a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping.

A) 4

B) 2

C) 6

D) 0

5 / 40

Soddalashtiring:

A) 3

B) Aniqlab bo`lmaydi

C) 2

D) 1

6 / 40

Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor?

A) 48/5

B) 16

C) 64/5

D) 10

7 / 40

Funksiyaning aniqlanish sohasini toping.

A) (-∞;0)∪(0;∞)

B) x∈R

C) (-∞;3]∪[2;∞)

D) [-3;2]

8 / 40

Agar bo'lsa, ni m orqali ifodalang.

A) (m+1)/2

B) 2/m

C) (4-m)/4

D) (m+4)/4

9 / 40

Agar bo‘lsa, m/n ni toping.

A) 4

B) (1+√5)/2

C) 2

D) 3

10 / 40

2⁷⁵+3³⁰ sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang.

A) 5

B) 9

C) 0

D) 1

11 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 100

B) 25

C) 105

D) 96

12 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) 5

B) -6

C) -3

D) -4

13 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 1

B) 3

C) 2

D) 4

14 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 11

B) 5

C) 7

D) 10

15 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 22

B) 11

C) 121

D) berilganlar yetarli emas

16 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) -2

B) 3

C) 5

D) 8

17 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 115

B) 112

C) 110

D) 116

18 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 14

B) 15

C) 13

D) 12

19 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 20

B) 12

C) 10

D) 14

20 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 6

B) 4√2

C) 4√3

D) 3√2

21 / 40

bo‘lsa,

A) 2

B) 1

C) 2/3

D) 3/2

22 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 8

B) 20

C) 15

D) 10

23 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 3√2

B) 2√3

C) 2√2

D) 4√3

24 / 40

sonlarini taqqolsang.

A) b

B) c

C) c

D) a

25 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 32

B) 42

C) 64

D) 48

26 / 40

Hisoblang:

A) 1/32

B) -1/2

C) 0

D) -√3/2

27 / 40

Ifodaning qiymatini toping.

A) 0,0(4)

B) 0,(04)

C) 0,0(2)

D) 0,04

28 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 3

B) 2

C) 1

D) 4

29 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 44

B) 42

C) 45

D) 43

30 / 40

√3

A) 5/5

B) 21/10

C) 7/3

D) 3/2

31 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 6

B) 5

C) 7

D) 8

32 / 40

Rasmdagi shakl perimetrini toping.

A) 28

B) 24

C) 30

D) 32

33 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 6√7

B) 10

C) 8

D) 4√7

34 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BC > AD

B) AB = BC

C) BD = BC

D) DC < AD

35 / 40

Tenglamalar sistemani yeching:

A) (7; 2), (28; -1)

B) (2; 3)

C) (9; 0), (2; 7)

D) (9; 0), (28; -1)

36 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 10

B) 6

C) 12

D) 8

37 / 40

Tenglamani yeching: