Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 60 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 59 B) 61 C) 58 D) 60 2 / 40 va bo'lsa x-y=? A) 8 B) 9 C) 5 D) 7 3 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) [-1; ∞) B) (0; ∞) C) (-1; ∞) D) (-2; ∞) 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5+5 C) 5 D) √5 5 / 40 Hisoblang: A) 4 B) 1 C) 2 D) 3 6 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 110° B) 120° C) 100° D) 130° 7 / 40 Agar bo'lsa, ni m orqali ifodalang. A) (m+4)/4 B) 2/m C) (m+1)/2 D) (4-m)/4 8 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 4 B) 3 C) 2 D) 1 9 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 1/3 B) 1/2 C) 5/6 D) 8/15 10 / 40 ni hisoblang. A) 1 B) 2 C) 3 D) 0 11 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 4 D) 3 12 / 40 bo‘lsa, A) 2/3 B) 3/2 C) 1 D) 2 13 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 6 C) 5 D) 11 14 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 14 C) 35 D) 23 15 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 2√2 D) 3√2 16 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 6 C) 4 yoki –12 D) 5 yoki –15 17 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 3 C) 5 D) 8 18 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 4√3 C) 6 D) 3√2 19 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 5 C) 7 D) 8 20 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bc/d C) bd/c D) cd/b 21 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 22 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) 0 C) -π/4+πk, k∈Z D) π/4+πk, k∈Z 23 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 10 C) 12 D) 20 24 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 22 D) 11 25 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 15 C) 12 D) 13 26 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 4 D) 2 27 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 96 C) 105 D) 25 28 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 48 D) 42 29 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 2 C) 4 D) 1 30 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 16(π-2) C) 64 D) 8(π+2) 31 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 7 C) 10 D) 5 32 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 24 C) 28 D) 30 33 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 45 C) 43 D) 42 34 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -3 C) 5 D) -6 35 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 10 C) 4√7 D) 6√7 36 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 10 C) 12 D) 9 37 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 116 D) 110 38 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 12 C) 8 D) 6 39 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) 6; -5 D) -6 40 / 40 √3 A) 5/5 B) 3/2 C) 7/3 D) 21/10 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16