Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 91 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 3 B) 2 C) 4 D) aniqlab bo‘lmaydi 2 / 40 tengsizlikni yeching. A) 1 B) 2 C) 3 D) 4 3 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 6 B) 8 C) 25/3 D) 35/6 4 / 40 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/3 B) 4 C) 1/4 D) 1/5 5 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) 11π B) (32π)/3 C) (28π)/3 D) (29π)/3 6 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b,d B) )a,b,d C) b D) a,b 7 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 6 B) 12 C) 9 D) 3 8 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 120 B) 80 C) 100 D) 90 9 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 35 B) 40 C) 20 D) 25 10 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 3R B) 1,5R C) R(√3-√2) D) √3R(2-√3) 11 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 8 D) 10 12 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 2 C) 3 D) 1 13 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 2√3 C) 3√2 D) 4√3 14 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) DC < AD C) AB = BC D) BC > AD 15 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 16 / 40 Tenglamani yeching: A) -6 B) 6; -5 C) -6; 5 D) 5 17 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 4 yoki –12 D) 6 18 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 10 D) 20 19 / 40 bo‘lsa, A) 3/2 B) 1 C) 2 D) 2/3 20 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) -2 C) 5 D) 8 21 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 64 D) 42 22 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 16(π-2) C) 8(π+2) D) 64 23 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 1 D) 2 24 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -6 C) 5 D) -3 25 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) 121 D) berilganlar yetarli emas 26 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 4 D) 2 27 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 35 C) 24 D) 14 28 / 40 Hisoblang: A) cos10° B) sin10° C) cos50° D) 1 29 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 20 D) 8 30 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 3 C) 4 D) 1 31 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,04 D) 0,0(2) 32 / 40 Hisoblang: A) 19/20 B) 9/10 C) 20/21 D) 10/11 33 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 6 C) 4√3 D) 4√2 34 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 30° D) 20° 35 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 45 D) 44 36 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (28; -1) C) (7; 2), (28; -1) D) (9; 0), (2; 7) 37 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 24 C) 32 D) 30 38 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) 1 D) bd/c 39 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 105 C) 96 D) 25 40 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 1/32 D) 0 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16