Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 84 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 ko’paytmani hisoblang. A) 10000 B) 0 C) 480000 D) 86420000 2 / 40 tengsizlikni yeching. A) x∈(-∞;5) B) x∈(-5;1) C) x∈(-∞;5)∪(-3;1) D) x∈(-3;1) 3 / 40 Aniq integralni hisoblang: A) 0,5 B) 3 C) 2 D) 0 4 / 40 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 4 B) 2 C) 6 D) 0 5 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 3 C) 5 D) 6 6 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 4 B) 1 C) 2 D) 3 7 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 5 B) 4 C) 2 D) 1 8 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) x∈R C) [-3;2] D) (-∞;3]∪[2;∞) 9 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 1 B) 2 C) 3 D) 4 10 / 40 Integralni hisoblang: A) 2 B) 1 C) 3 D) 4 11 / 40 Tenglamani yeching: A) 5 B) 6; -5 C) -6; 5 D) -6 12 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 10 C) 15 D) 8 13 / 40 Hisoblang: A) 1 B) sin10° C) cos10° D) cos50° 14 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 11 D) 4 15 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 22 C) 121 D) 11 16 / 40 √3 A) 3/2 B) 7/3 C) 21/10 D) 5/5 17 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 28 C) 32 D) 24 18 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 4√3 D) 2√3 19 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 0 D) 1/32 20 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 4 D) 3 21 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 3 C) 2 D) 4 22 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 2 C) 3 D) 4 23 / 40 Hisoblang: A) 10/11 B) 19/20 C) 9/10 D) 20/21 24 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (9; 0), (2; 7) D) (2; 3) 25 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 30° D) 50° 26 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 5 yoki –15 C) 3 yoki –8 D) 4 yoki –12 27 / 40 sonlarini taqqolsang. A) a B) c C) c D) b 28 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) -2 D) 5 29 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) 2√3tg50° tg70° C) √3ctg40° tg70° D) √3tg50° tg70° 30 / 40 bo‘lsa, A) 3/2 B) 2/3 C) 1 D) 2 31 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 10 C) 6√7 D) 4√7 32 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) 0 C) Ø D) π/4+πk, k∈Z 33 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 10 C) 6 D) 8 34 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 14 C) 12 D) 20 35 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 24 D) 35 36 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 1 D) 2 37 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 45 C) 42 D) 43 38 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 6 D) 5 39 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -4 C) -6 D) 5 40 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 42 C) 48 D) 64 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16