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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

ni hisoblang.

A) e-1

B) (e-1)/2

C) (e+1)/2

D) e+1

2 / 40

y=4cos 2x+cos8x funksiyaning hosilasini toping

A) -16cos3x*sin5x

B) 16sin3x*sin5x

C) 16sin3x*cos5x

D) 16cos3x*cos5x

3 / 40

Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping.

A) 0,7 m yoki 70 cm

B) 0,5 m yoki 50 cm

C) 0,9 m yoki 90 cm

D) 0,6 m yoki 60 cm

4 / 40

f(x)=3^x-2 funksiyaning qiymatlar sohasini toping.

A) [-1; ∞)

B) (-2; ∞)

C) (-1; ∞)

D) (0; ∞)

5 / 40

x ni toping ?

A) 4

B) 5

C) 3

D) 6

6 / 40

Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³

A) (29π)/3

B) (32π)/3

C) (28π)/3

D) 11π

7 / 40

x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping.

A) 48

B) 32

C) 16

D) 64

8 / 40

Yig‘indini toping.

A) 1/6

B) 1/12

C) 1/9

D) 1/4

9 / 40

Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping.

A) 6√5

B) 8√3

C) 9√5

D) 12√3

10 / 40

Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping.

A) -√17

B) 4

C) -4

D) √17

11 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -4

B) -6

C) -3

D) 5

12 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 11

B) 9

C) 10

D) 12

13 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 23

B) 14

C) 24

D) 35

14 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 11

B) 10

C) 7

D) 5

15 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 44

B) 45

C) 43

D) 42

16 / 40

Hisoblang:

A) sin10°

B) 1

C) cos50°

D) cos10°

17 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) 1

B) cd/b

C) bd/c

D) bc/d

18 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) -π/4+πk, k∈Z

B) π/4+πk, k∈Z

C) Ø

D) 0

19 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 16(π-2)

C) 32

D) 64

20 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 10

B) 8

C) 6√7

D) 4√7

21 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 4√3

B) 2√2

C) 2√3

D) 3√2

22 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 8

B) 3

C) 5

D) -2

23 / 40

Ifodaning qiymatini toping.

A) 0,0(4)

B) 0,04

C) 0,(04)

D) 0,0(2)

24 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 6

B) 8

C) 5

D) 7

25 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 1

B) 2

C) 3

D) 4

26 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) berilganlar yetarli emas

B) 11

C) 22

D) 121

27 / 40

√3

A) 5/5

B) 3/2

C) 21/10

D) 7/3

28 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) 4 √3tg50° tg70°

B) √3ctg40° tg70°

C) 2√3tg50° tg70°

D) √3tg50° tg70°

29 / 40

Hisoblang:

A) -1/2

B) 1/32

C) -√3/2

D) 0

30 / 40

Hisoblang:

A) 9/10

B) 19/20

C) 20/21

D) 10/11

31 / 40

Chizmadan foydalanib α ni toping.

A) 30°

B) 20°

C) 50°

D) 40°

32 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (2; 7)

B) (2; 3)

C) (9; 0), (28; -1)

D) (7; 2), (28; -1)

33 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 96

B) 105

C) 25

D) 100

34 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 12

C) 6

D) 10

35 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√3

B) 3√2

C) 4√2

D) 6

36 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.