Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 58 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 funksiyaning eng kichik musbat davrini toping. A) 24 B) 18 C) 12 D) 26 2 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 3 B) 2 C) 1 D) 4 3 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 46 B) 40 C) 50 D) 44 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5+5 C) √5 D) 5 5 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 32 B) 40 C) 34 D) 36 6 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 10 B) 12 C) 13 D) 11 7 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 9 B) 6 C) 10 D) 8 8 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 9 B) 0 C) 5 D) 1 9 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 1 B) 2 C) 3 D) 4 10 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 5 B) 4 C) 1 D) 2 11 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) DC < AD D) BD = BC 12 / 40 Hisoblang: A) cos50° B) sin10° C) 1 D) cos10° 13 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 20 C) 8 D) 10 14 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 4 C) 2 D) 3 15 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 4√7 C) 6√7 D) 8 16 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 25 C) 105 D) 96 17 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 9 C) 11 D) 12 18 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 11 C) 4 D) 5 19 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 2 C) 3 D) 1 20 / 40 Tenglamani yeching: A) -6; 5 B) 6; -5 C) -6 D) 5 21 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 32 C) 64 D) 16(π-2) 22 / 40 Hisoblang: A) 0 B) -√3/2 C) -1/2 D) 1/32 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 6 C) 4√3 D) 4√2 24 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 12 C) 10 D) 6 25 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (9; 0), (2; 7) C) (7; 2), (28; -1) D) (2; 3) 26 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 30° C) 50° D) 20° 27 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 110 C) 112 D) 116 28 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 23 C) 35 D) 24 29 / 40 sonlarini taqqolsang. A) a B) b C) c D) c 30 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 2√3tg50° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 31 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) bd/c D) 1 32 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 2√3 D) 4√3 33 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 14 C) 20 D) 12 34 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(4) C) 0,0(2) D) 0,04 35 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) -2 D) 3 36 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) 0 D) -π/4+πk, k∈Z 37 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 12 D) 13 38 / 40 bo‘lsa, A) 3/2 B) 2 C) 1 D) 2/3 39 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 7 C) 6 D) 5 40 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 3 D) 1 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16