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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping.

A) 30

B) 12

C) 18

D) 24

2 / 40

Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping.

A) 8

B) 24

C) 16

D) 32

3 / 40

Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping.

A) x=-a

B) x=a

C) y=-a

D) y=1-a

4 / 40

cosx=0,2x tenglama nechta yechimga ega?

A) 3

B) 2

C) 4

D) 1

5 / 40

x ni toping ?

A) 3

B) 4

C) 6

D) 5

6 / 40

Soddalashtiring:

A) Aniqlab bo`lmaydi

B) 2

C) 3

D) 1

7 / 40

Hisoblang:

A) 8

B) 0

C) 6

D) 4

8 / 40

x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping.

A) 48

B) 16

C) 64

D) 32

9 / 40

f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng?

A) 3600

B) 600

C) 4800

D) 5050

10 / 40

Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping.

A) 9√5

B) 8√3

C) 12√3

D) 6√5

11 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 3

B) 5

C) 8

D) -2

12 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (28; -1)

B) (7; 2), (28; -1)

C) (2; 3)

D) (9; 0), (2; 7)

13 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 8

B) 7

C) 5

D) 6

14 / 40

Hisoblang:

A) 10/11

B) 19/20

C) 20/21

D) 9/10

15 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 42

B) 48

C) 64

D) 32

16 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) 4 √3tg50° tg70°

B) 2√3tg50° tg70°

C) √3tg50° tg70°

D) √3ctg40° tg70°

17 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√2

B) 2√3

C) 3√2

D) 4√3

18 / 40

√3

A) 21/10

B) 7/3

C) 5/5

D) 3/2

19 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 15

B) 8

C) 10

D) 20

20 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 25

B) 100

C) 96

D) 105

21 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 6√7

B) 8

C) 10

D) 4√7

22 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -3

B) -6

C) -4

D) 5

23 / 40

Ifodaning qiymatini toping.

A) 0,0(2)

B) 0,(04)

C) 0,0(4)

D) 0,04

24 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 1

B) 4

C) 2

D) 3

25 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 22

B) 121

C) 11

D) berilganlar yetarli emas

26 / 40

Tenglamani yeching:

A) 6; -5

B) -6; 5

C) 5

D) -6

27 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) bc/d

B) 1

C) cd/b

D) bd/c

28 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) π/4+πk, k∈Z

B) -π/4+πk, k∈Z

C) 0

D) Ø

29 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 3

B) 4

C) 1

D) 2

30 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 43

B) 42

C) 45

D) 44

31 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 116

B) 112

C) 115

D) 110

32 / 40

bo‘lsa,

A) 2/3

B) 3/2

C) 2

D) 1

33 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 12

C) 10

D) 6

34 / 40

sonlarini taqqolsang.

A) a

B) c

C) b

D) c

35 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BD = BC

B) AB = BC

C) DC < AD

D) BC > AD

36 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.