Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 89 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 21 B) 24 C) 32 D) 28 2 / 40 va bo'lsa x-y=? A) 7 B) 5 C) 9 D) 8 3 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)=x²+3x+7 B) f(x)+2x²-1 C) f(x)=x²-x+5 D) f(x)=x²-4 4 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;√2] B) [-√2;-1)∪(-1;1)∪(1;√2] C) [-√2;0)∪(0;√2] D) (-2√2;√2) 5 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 8 C) 9 D) 6 6 / 40 Hisoblang: -121+(-135)-(-1)28 A) 0 B) -2 C) -3 D) -1 7 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 1 B) 3 C) 4 D) 2 8 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 9 B) 6 C) 8 D) 10 9 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 4 B) 6 C) 5 D) 2 10 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 14° B) 24° C) 17° D) 7° 11 / 40 bo‘lsa, A) 2/3 B) 1 C) 3/2 D) 2 12 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 96 C) 25 D) 105 13 / 40 sonlarini taqqolsang. A) c B) b C) c D) a 14 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 10 C) 12 D) 8 15 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) BC > AD D) DC < AD 16 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 30° C) 20° D) 40° 17 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) 1 D) bc/d 18 / 40 √3 A) 5/5 B) 3/2 C) 7/3 D) 21/10 19 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 12 C) 11 D) 10 20 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -3 D) -4 21 / 40 Hisoblang: A) 1 B) cos10° C) cos50° D) sin10° 22 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 42 C) 44 D) 45 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 3√2 C) 4√2 D) 4√3 24 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 3 D) 2 25 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,04 C) 0,0(2) D) 0,(04) 26 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 4√3 C) 2√3 D) 2√2 27 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 12 C) 14 D) 13 28 / 40 Hisoblang: A) 10/11 B) 20/21 C) 9/10 D) 19/20 29 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 3 D) 4 30 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 24 D) 35 31 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 22 D) 11 32 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 5 C) 11 D) 4 33 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) π/4+πk, k∈Z C) Ø D) 0 34 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 64 C) 8(π+2) D) 32 35 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 6 C) 7 D) 8 36 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 4 C) 1 D) 2 37 / 40 Hisoblang: A) -1/2 B) 0 C) 1/32 D) -√3/2 38 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 116 C) 112 D) 115 39 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 32 D) 48 40 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 15 C) 8 D) 20 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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