Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 72 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 289 B) 203 C) 201 D) 200 2 / 40 bo‘lsa, y = ? A) 26 B) 2 C) 3 D) 8 3 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 11/5 B) 68/15 C) 31/85 D) 67/15 4 / 40 tenglamani yeching. A) log(3/5)2 B) 5 C) log(5/3)2 D) 3 5 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 12 B) 13 C) 11 D) 10 6 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b B) a,b C) )a,b,d D) b,d 7 / 40 Agar bo'lsa, ni m orqali ifodalang. A) (m+4)/4 B) (4-m)/4 C) (m+1)/2 D) 2/m 8 / 40 sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan? A) 3 B) 2 C) 1 D) 4 9 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 1 B) 3 C) 4 D) 2 10 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 3R B) √3R(2-√3) C) 1,5R D) R(√3-√2) 11 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) 5 C) -3 D) -4 12 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,04 C) 0,0(2) D) 0,(04) 13 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 20 D) 10 14 / 40 Hisoblang: A) -1/2 B) 0 C) -√3/2 D) 1/32 15 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 3√2 D) 4√3 16 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 5 C) 8 D) 6 17 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 105 C) 96 D) 100 18 / 40 Tenglamani yeching: A) -6; 5 B) -6 C) 6; -5 D) 5 19 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 11 C) 22 D) berilganlar yetarli emas 20 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 45 C) 42 D) 43 21 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 14 C) 15 D) 13 22 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 8(π+2) C) 32 D) 16(π-2) 23 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 2 C) 1 D) 3 24 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 6 C) 3√2 D) 4√2 25 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 42 D) 32 26 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (2; 3) C) (9; 0), (28; -1) D) (9; 0), (2; 7) 27 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 10 D) 8 28 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 29 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 2 D) 4 30 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 5 C) -2 D) 8 31 / 40 Hisoblang: A) 1 B) sin10° C) cos50° D) cos10° 32 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) cd/b D) 1 33 / 40 Hisoblang: A) 20/21 B) 9/10 C) 19/20 D) 10/11 34 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BD = BC C) DC < AD D) BC > AD 35 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 11 D) 10 36 / 40 √3 A) 5/5 B) 7/3 C) 21/10 D) 3/2 37 / 40 bo‘lsa, A) 1 B) 3/2 C) 2 D) 2/3 38 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 10 D) 8 39 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 32 C) 30 D) 24 40 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 6 C) 4 yoki –12 D) 3 yoki –8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16