Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 60 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16sin3x*sin5x B) -16cos3x*sin5x C) 16sin3x*cos5x D) 16cos3x*cos5x 2 / 40 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 24 B) 32 C) 21 D) 28 3 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) y=1-a B) x=a C) x=-a D) y=-a 4 / 40 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 2 B) 4 C) 6 D) 0 5 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 4 B) 1 C) 2 D) 3 6 / 40 x ni toping ? A) 5 B) 4 C) 3 D) 6 7 / 40 Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi? A) qat’iy kamayuvchi B) qat’iy o‘suvchi C) dastlab kamayadi, keyin o‘sadi D) dastlab o‘sadi, keyin kamayadi 8 / 40 Integralni hisoblang: A) 1 B) 4 C) 3 D) 2 9 / 40 Yig‘indini toping. A) 1/4 B) 1/9 C) 1/6 D) 1/12 10 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 35 B) 40 C) 25 D) 20 11 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 12 C) 13 D) 15 12 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 24 C) 35 D) 23 13 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 5 yoki –15 C) 3 yoki –8 D) 6 14 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 2√3 D) 3√2 15 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 20° D) 30° 16 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 7 C) 5 D) 6 17 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 25 C) 100 D) 105 18 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 1 C) 4 D) 3 19 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (9; 0), (2; 7) C) (7; 2), (28; -1) D) (2; 3) 20 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(4) C) 0,(04) D) 0,0(2) 21 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 11 D) 10 22 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) DC < AD D) BD = BC 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√3 C) 4√2 D) 3√2 24 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 20 C) 10 D) 15 25 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) -2 C) 5 D) 3 26 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 2 C) 3 D) 4 27 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 8(π+2) C) 32 D) 16(π-2) 28 / 40 bo‘lsa, A) 2/3 B) 1 C) 2 D) 3/2 29 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 10 C) 20 D) 14 30 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -4 C) 5 D) -6 31 / 40 Hisoblang: A) 19/20 B) 20/21 C) 10/11 D) 9/10 32 / 40 √3 A) 21/10 B) 5/5 C) 3/2 D) 7/3 33 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 30 C) 32 D) 28 34 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 8 C) 10 D) 4√7 35 / 40 Hisoblang: A) 1 B) cos50° C) sin10° D) cos10° 36 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) berilganlar yetarli emas D) 121 37 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 1/32 D) 0 38 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) -π/4+πk, k∈Z C) 0 D) π/4+πk, k∈Z 39 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 6 C) 4 D) 5 40 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 4 D) 2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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