Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 48 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2 B) 3 C) 2,5 D) 4 2 / 40 Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ? A) 12 B) 9 C) 6 D) 14 3 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5 C) 5 D) √5+5 4 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln2 B) ln3 C) ln4 D) ln5 5 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 6 B) 3 C) 4 D) 5 6 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 3 B) 4 C) 1 D) 2 7 / 40 Funksiyaning aniqlanish sohasini toping. A) x∈R B) (-∞;3]∪[2;∞) C) [-3;2] D) (-∞;0)∪(0;∞) 8 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 6 B) 8 C) 9 D) 10 9 / 40 Yig‘indini toping. A) 1/6 B) 1/4 C) 1/12 D) 1/9 10 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/4 B) √2/8 C) 1/8 D) √3/8 11 / 40 bo‘lsa, A) 2 B) 2/3 C) 3/2 D) 1 12 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,04 C) 0,0(4) D) 0,0(2) 13 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 14 C) 15 D) 13 14 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) berilganlar yetarli emas C) 22 D) 121 15 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 44 C) 43 D) 42 16 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 3√2 C) 2√2 D) 4√3 17 / 40 Tenglamani yeching: A) 6; -5 B) -6 C) 5 D) -6; 5 18 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 115 C) 110 D) 116 19 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 12 C) 14 D) 10 20 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 2 C) 3 D) 1 21 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 28 D) 24 22 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) Ø 23 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 11 D) 9 24 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 8 D) 20 25 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 16(π-2) C) 32 D) 64 26 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BC > AD C) DC < AD D) BD = BC 27 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 8 D) 10 28 / 40 Hisoblang: A) 9/10 B) 20/21 C) 19/20 D) 10/11 29 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) 1 C) bc/d D) cd/b 30 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 5 C) 8 D) -2 31 / 40 √3 A) 3/2 B) 5/5 C) 7/3 D) 21/10 32 / 40 Hisoblang: A) 0 B) -1/2 C) 1/32 D) -√3/2 33 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 3 C) 4 D) 1 34 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (2; 3) C) (9; 0), (2; 7) D) (9; 0), (28; -1) 35 / 40 sonlarini taqqolsang. A) a B) b C) c D) c 36 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -3 D) -4 37 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 5 D) 6 38 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 6 D) 7 39 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 14 C) 35 D) 23 40 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 6√7 C) 10 D) 8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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