Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 75 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin? A) 6 B) 7 C) 9 D) 27 2 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 4 B) 2 C) 2,5 D) 3 3 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (0; ∞) B) (-1; ∞) C) (-2; ∞) D) [-1; ∞) 4 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 1 B) 3 C) 2 D) 4 5 / 40 x ni toping ? A) 5 B) 6 C) 3 D) 4 6 / 40 Soddalashtiring. A) (a-1)/(1-b) B) (b+2)/(1-b) C) (a+1)/(-a-3) D) (a-1)/(a-3) 7 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) √3R(2-√3) B) 1,5R C) 3R D) R(√3-√2) 8 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 28 B) 48 C) 40 D) 52 9 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 1 B) 9 C) 5 D) 0 10 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 14° B) 7° C) 24° D) 17° 11 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 2 D) 1 12 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 15 C) 12 D) 13 13 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 4 D) 11 14 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) Ø 15 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 10 C) 14 D) 20 16 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 96 C) 105 D) 25 17 / 40 Hisoblang: A) 1 B) cos10° C) cos50° D) sin10° 18 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 24 C) 35 D) 23 19 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -4 C) 5 D) -6 20 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 44 D) 43 21 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 32 C) 16(π-2) D) 8(π+2) 22 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 3 D) 2 23 / 40 bo‘lsa, A) 2/3 B) 2 C) 1 D) 3/2 24 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 2 C) 1 D) 3 25 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 6 D) 8 26 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) DC < AD D) BC > AD 27 / 40 sonlarini taqqolsang. A) c B) c C) b D) a 28 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 3 yoki –8 D) 6 29 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 110 C) 112 D) 115 30 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 11 C) 121 D) 22 31 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 3√2 D) 2√2 32 / 40 Hisoblang: A) 20/21 B) 9/10 C) 10/11 D) 19/20 33 / 40 Tenglamani yeching: A) 5 B) 6; -5 C) -6 D) -6; 5 34 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,(04) C) 0,0(4) D) 0,0(2) 35 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 10 C) 8 D) 4√7 36 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 1/32 D) 0 37 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 30 D) 24 38 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 8 C) 12 D) 10 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) 1 C) bd/c D) cd/b 40 / 40 √3 A) 3/2 B) 7/3 C) 5/5 D) 21/10 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16