Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 27 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n = 0, k < 0 B) n > 0, k = 0 C) n < 0, k = 0 D) n = 0, k > 0 2 / 40 Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping. A) 24 B) 8 C) 32 D) 16 3 / 40 Hisoblang: A) 7 B) 4 C) 27 D) 9 4 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 5,75 B) 9,25 C) 13 D) 6 5 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 120° B) 100° C) 110° D) 130° 6 / 40 Soddalshtiring. A) 6 B) -1 C) 2 D) 1 7 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -4 B) √17 C) 4 D) -√17 8 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 1 B) 0 C) 9 D) 5 9 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 96π B) 72π C) 192π D) 144π 10 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 5 B) 6 C) 2 D) 4 11 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 4 D) 2 12 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 3 yoki –8 C) 4 yoki –12 D) 6 13 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 2 C) 1 D) 3 14 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 4 √3tg50° tg70° C) 2√3tg50° tg70° D) √3tg50° tg70° 15 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 12 C) 6 D) 10 16 / 40 bo‘lsa, A) 3/2 B) 2/3 C) 1 D) 2 17 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√2 C) 3√2 D) 2√3 18 / 40 Hisoblang: A) cos50° B) 1 C) cos10° D) sin10° 19 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 15 C) 8 D) 20 20 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 44 C) 45 D) 43 21 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) BC > AD D) DC < AD 22 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 42 D) 32 23 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -4 D) -6 24 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 64 C) 16(π-2) D) 32 25 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(4) C) 0,0(2) D) 0,(04) 26 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√2 C) 4√3 D) 3√2 27 / 40 Hisoblang: A) 20/21 B) 9/10 C) 19/20 D) 10/11 28 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (7; 2), (28; -1) D) (2; 3) 29 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 4 C) 11 D) 6 30 / 40 Tenglamani yeching: A) -6; 5 B) -6 C) 6; -5 D) 5 31 / 40 sonlarini taqqolsang. A) c B) a C) c D) b 32 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 100 C) 96 D) 105 33 / 40 √3 A) 3/2 B) 21/10 C) 7/3 D) 5/5 34 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 8 C) 7 D) 5 35 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) -π/4+πk, k∈Z D) 0 36 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) -2 C) 8 D) 5 37 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) bc/d C) cd/b D) 1 38 / 40 Hisoblang: A) -√3/2 B) 0 C) 1/32 D) -1/2 39 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) berilganlar yetarli emas C) 22 D) 11 40 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 3 C) 1 D) 4 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 11 Matematika fanidan attestatsiya savollari №16