Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 69 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 1:(2:3) son 1:2:3 sonidan qanchaga katta? A) 3 B) 4/3 C) 6 D) 9 2 / 40 Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ? A) 12 B) 14 C) 9 D) 6 3 / 40 tenglamani yeching. A) log(3/5)2 B) 5 C) log(5/3)2 D) 3 4 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 44 B) 50 C) 46 D) 40 5 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (28π)/3 B) 11π C) (29π)/3 D) (32π)/3 6 / 40 x ni toping ? A) 3 B) 4 C) 6 D) 5 7 / 40 Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi? A) qat’iy kamayuvchi B) dastlab kamayadi, keyin o‘sadi C) dastlab o‘sadi, keyin kamayadi D) qat’iy o‘suvchi 8 / 40 tenglama intervalda nechta ildizga ega? A) 4 B) 1 C) 3 D) 2 9 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) berilganlar yetarli emas B) 6 C) 8 D) 10 10 / 40 ni hisoblang. A) 2 B) 1 C) 3 D) 0 11 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,04 C) 0,0(2) D) 0,(04) 12 / 40 Tenglamani yeching: A) -6 B) 5 C) 6; -5 D) -6; 5 13 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 9 C) 11 D) 12 14 / 40 Hisoblang: A) 20/21 B) 10/11 C) 9/10 D) 19/20 15 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 24 C) 23 D) 14 16 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (2; 3) C) (7; 2), (28; -1) D) (9; 0), (2; 7) 17 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 4√2 C) 3√2 D) 6 18 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 2 D) 3 19 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 10 C) 15 D) 20 20 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 3 C) 2 D) 1 21 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 3 yoki –8 C) 4 yoki –12 D) 6 22 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -4 C) -6 D) -3 23 / 40 Hisoblang: A) cos50° B) cos10° C) 1 D) sin10° 24 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 15 C) 12 D) 13 25 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 4√3 D) 3√2 26 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 32 C) 28 D) 24 27 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 5 C) 11 D) 6 28 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 2 D) 4 29 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 116 C) 110 D) 115 30 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 48 C) 64 D) 32 31 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) BC > AD D) AB = BC 32 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 100 D) 25 33 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 50° C) 30° D) 20° 34 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 10 C) 20 D) 12 35 / 40 bo‘lsa, A) 2/3 B) 3/2 C) 2 D) 1 36 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 10 C) 4√7 D) 8 37 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 7 C) 6 D) 5 38 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) -2 D) 3 39 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 40 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bc/d C) cd/b D) bd/c O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16