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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

Kamayish tartibida joylashtiring.

a)5√6
b)12
c)4√10

A) a>b>c

B) a>c>b

C) c>a>b

D) b>a>c

2 / 40

tenglamalar sistemasi yechimga ega bo‘ladigan a ning barcha qiymatlari to‘plamini toping.

A) 3

B) 1

C) 2

D) 4

3 / 40

Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping.

A) x=a

B) y=-a

C) x=-a

D) y=1-a

4 / 40

a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping.

A) 6

B) 2

C) 4

D) 0

5 / 40

DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ?

A) 100°

B) 110°

C) 120°

D) 130°

6 / 40

n ning qanday qiymatida tenglik to`g`ri bo’ladi? (7³)=7¹⁵

A) 1

B) 7

C) 5

D) 12

7 / 40

Ayniyatdan foydalanib x + y + z ni toping:

A) 3

B) 6

C) 9

D) 12

8 / 40

Yig‘indini toping.

A) 1/6

B) 1/4

C) 1/9

D) 1/12

9 / 40

Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping.

A) √17

B) 4

C) -√17

D) -4

10 / 40

sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan?

A) 1

B) 3

C) 2

D) 4

11 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 115

B) 112

C) 116

D) 110

12 / 40

bo‘lsa,

A) 3/2

B) 2

C) 2/3

D) 1

13 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 6√7

B) 4√7

C) 8

D) 10

14 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 5

B) -2

C) 3

D) 8

15 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (2; 7)

B) (7; 2), (28; -1)

C) (9; 0), (28; -1)

D) (2; 3)

16 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 16(π-2)

B) 64

C) 32

D) 8(π+2)

17 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 12

B) 11

C) 10

D) 9

18 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 1

B) 3

C) 2

D) 4

19 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 32

B) 64

C) 48

D) 42

20 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -3

B) -6

C) -4

D) 5

21 / 40

Hisoblang:

A) 0

B) -√3/2

C) -1/2

D) 1/32

22 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 6

B) 4 yoki –12

C) 3 yoki –8

D) 5 yoki –15

23 / 40

√3

A) 21/10

B) 5/5

C) 7/3

D) 3/2

24 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 6

C) 5

D) 8

25 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 3

B) 4

C) 2

D) 1

26 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 3

B) 4

C) 2

D) 1

27 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 3

B) 4

C) 2

D) 1

28 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) π/4+πk, k∈Z

B) 0

C) Ø

D) -π/4+πk, k∈Z

29 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√3

B) 6

C) 3√2

D) 4√2

30 / 40

Hisoblang:

A) cos10°

B) 1

C) cos50°

D) sin10°

31 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 6

C) 10

D) 12

32 / 40

Chizmadan foydalanib α ni toping.

A) 50°

B) 30°

C) 20°

D) 40°

33 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 24

B) 14

C) 35

D) 23

34 / 40

Hisoblang:

A) 10/11

B) 19/20

C) 9/10

D) 20/21

35 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 10

B) 7

C) 11

D) 5

36 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 11

B) 6

C) 5

D) 4

37 / 40

sonlarini taqqolsang.

A) b

B) c

C) a

D) c

38 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 105

B) 100

C) 96

D) 25

39 / 40

Kvadratlarning yuzlari yig‘indisini toping.