Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 75 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16cos3x*cos5x B) 16sin3x*sin5x C) -16cos3x*sin5x D) 16sin3x*cos5x 2 / 40 Agar ning qiymatini toping. A) 3 B) 23/75 C) 23/25 D) 75/23 3 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln3 B) ln2 C) ln5 D) ln4 4 / 40 Hisoblang: A) 4 B) 9 C) 7 D) 27 5 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 3 B) 4 C) 5 D) 6 6 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 64/5 C) 16 D) 48/5 7 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 64 B) 32 C) 48 D) 16 8 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) R(√3-√2) B) 1,5R C) √3R(2-√3) D) 3R 9 / 40 Agar bo‘lsa, m/n ni toping. A) 2 B) (1+√5)/2 C) 4 D) 3 10 / 40 sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan? A) 3 B) 4 C) 1 D) 2 11 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 32 C) 30 D) 28 12 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) berilganlar yetarli emas D) 121 13 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 1 C) 3 D) 4 14 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) 1 C) bd/c D) cd/b 15 / 40 Hisoblang: A) 1/32 B) 0 C) -√3/2 D) -1/2 16 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 17 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 2 D) 1 18 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 19 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 16(π-2) C) 64 D) 32 20 / 40 √3 A) 5/5 B) 7/3 C) 3/2 D) 21/10 21 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 3 C) 4 D) 1 22 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 44 D) 43 23 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 25 C) 105 D) 96 24 / 40 Hisoblang: A) 1 B) sin10° C) cos50° D) cos10° 25 / 40 Hisoblang: A) 20/21 B) 10/11 C) 19/20 D) 9/10 26 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 110 D) 116 27 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 5 D) 7 28 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 9 C) 10 D) 11 29 / 40 Tenglamani yeching: A) 6; -5 B) 5 C) -6; 5 D) -6 30 / 40 bo‘lsa, A) 1 B) 3/2 C) 2 D) 2/3 31 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 10 C) 12 D) 8 32 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 20 C) 12 D) 10 33 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 23 C) 35 D) 24 34 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 3√2 C) 2√2 D) 2√3 35 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 7 C) 8 D) 5 36 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 42 D) 64 37 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) 0 C) -π/4+πk, k∈Z D) Ø 38 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 8 C) 15 D) 20 39 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 6 C) 4 D) 5 40 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 1 D) 3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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