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Matematika attestatsiya №6

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Yanvar 30, 2022

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Matematika fanidan attestatsiya savollari №6

1 / 40

y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak?

A) n > 0, k = 0

B) n = 0, k > 0

C) n = 0, k < 0

D) n < 0, k = 0

2 / 40

Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping.

A) 24

B) 16

C) 8

D) 32

3 / 40

Umumiy hadi x_n=3+5n-n² formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam?

A) 6

B) 9,25

C) 13

D) 5,75

4 / 40

Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi?

A) 67/15

B) 68/15

C) 11/5

D) 31/85

5 / 40

n ning qanday qiymatida tenglik to`g`ri bo’ladi? (7³)=7¹⁵

A) 1

B) 12

C) 7

D) 5

6 / 40

Hisoblang:

A) 2

B) 4

C) 3

D) 1

7 / 40

A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping.

A) 80

B) 90

C) 100

D) 120

8 / 40

Tenglamalar sistemasidan foydalanib x + y + z ni toping:

A) berilganlar yetarli emas

B) 10

C) 6

D) 8

9 / 40

Tenglamaning natural ildizining butun bo‘luvchilari nechta?

A) 6

B) 5

C) 4

D) 2

10 / 40

ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping.

A) 135°

B) 138°

C) 132°

D) 142°

11 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 1

B) 2

C) 4

D) 3

12 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 23

B) 35

C) 24

D) 14

13 / 40

bo‘lsa,

A) 1

B) 2/3

C) 2

D) 3/2

14 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 8

C) 10

D) 6√7

15 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 42

B) 48

C) 32

D) 64

16 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 8

B) -2

C) 3

D) 5

17 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 32

C) 16(π-2)

D) 64

18 / 40

Hisoblang:

A) 0

B) 1/32

C) -1/2

D) -√3/2

19 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 5

B) 6

C) 8

D) 7

20 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√2

B) 2√3

C) 4√3

D) 3√2

21 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 12

B) 10

C) 20

D) 14

22 / 40

Ifodaning qiymatini toping.

A) 0,04

B) 0,0(2)

C) 0,(04)

D) 0,0(4)

23 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 13

B) 15

C) 14

D) 12

24 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) AB = BC

B) DC < AD

C) BD = BC

D) BC > AD

25 / 40

Tenglamani yeching:

A) 6; -5

B) -6; 5

C) -6

D) 5

26 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 3 yoki –8

B) 6

C) 5 yoki –15

D) 4 yoki –12

27 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 9

B) 10

C) 12

D) 11

28 / 40

Hisoblang:

A) 20/21

B) 9/10

C) 10/11

D) 19/20

29 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 5

B) 4

C) 11

D) 6

30 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 2

B) 4

C) 3

D) 1

31 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 1

B) 3

C) 2

D) 4

32 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 1

B) 4

C) 3

D) 2

33 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 10

B) 7

C) 5

D) 11

34 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -6

B) -4

C) 5

D) -3

35 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 12

B) 8

C) 6

D) 10

36 / 40

Hisoblang: