Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 64 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 2 B) 1 C) 3 D) 4 2 / 40 tengsizlikni yeching. A) 2 B) 3 C) 4 D) 1 3 / 40 Aniq integralni hisoblang: A) 0 B) 2 C) 0,5 D) 3 4 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 3 B) 4 C) 7,5 D) 4,5 5 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 120° B) 110° C) 130° D) 100° 6 / 40 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 0,2km B) 200 km C) 2 km D) 20 km 7 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 10 B) 0 C) 25 D) 30 8 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 5/6 B) 8/15 C) 1/3 D) 1/2 9 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 9 B) 5 C) 1 D) 0 10 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/8 B) √2/8 C) 1/8 D) √3/4 11 / 40 Tenglamani yeching: A) -6 B) 6; -5 C) 5 D) -6; 5 12 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 23 D) 14 13 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 43 D) 44 14 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 5 C) 8 D) 7 15 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 5 yoki –15 C) 4 yoki –12 D) 3 yoki –8 16 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 20 D) 10 17 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) DC < AD D) AB = BC 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 12 D) 10 19 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 25 C) 105 D) 100 20 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) 0 C) π/4+πk, k∈Z D) -π/4+πk, k∈Z 21 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 2 C) 1 D) 4 22 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 110 C) 115 D) 116 23 / 40 Hisoblang: A) sin10° B) cos10° C) 1 D) cos50° 24 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 2√3 C) 4√3 D) 3√2 25 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 4√2 C) 3√2 D) 6 26 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) 5 C) -4 D) -6 27 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,04 D) 0,0(2) 28 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 12 C) 10 D) 6 29 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 2 D) 4 30 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) 1 D) bc/d 31 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 32 D) 42 32 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 11 C) berilganlar yetarli emas D) 22 33 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) -2 D) 8 34 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 5 C) 10 D) 11 35 / 40 Hisoblang: A) -1/2 B) 0 C) 1/32 D) -√3/2 36 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 37 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 1 D) 2 38 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 32 C) 8(π+2) D) 16(π-2) 39 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 30° C) 50° D) 20° 40 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 20 C) 10 D) 8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16