Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 72 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Agar va bo'lsa f(4) ning qiymatini toping. A) 35 B) 4 C) 11 D) 12 2 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) a>b>c B) c>a>b C) b>a>c D) a>c>b 3 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,6 m yoki 60 cm B) 0,5 m yoki 50 cm C) 0,9 m yoki 90 cm D) 0,7 m yoki 70 cm 4 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 31/85 B) 68/15 C) 11/5 D) 67/15 5 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 1 B) 3 C) 2 D) 4 6 / 40 Hisoblang? A) 2 B) 0,5 C) 0,25 D) 4 7 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 9 B) 3 C) 6 D) 12 8 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 4 B) 1 C) 2 D) 5 9 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 8√3 B) 9√5 C) 6√5 D) 12√3 10 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 35 B) 20 C) 25 D) 40 11 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (2; 3) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 12 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 5 C) -2 D) 3 13 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 9 D) 11 14 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√2 C) 2√3 D) 3√2 15 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) Ø D) -π/4+πk, k∈Z 16 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 1 C) 3 D) 4 17 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 3√2 C) 4√3 D) 4√2 18 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 23 C) 35 D) 24 19 / 40 √3 A) 3/2 B) 5/5 C) 7/3 D) 21/10 20 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 3 yoki –8 D) 5 yoki –15 21 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 14 D) 10 22 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 44 C) 43 D) 45 23 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 4 C) 5 D) 11 24 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) √3tg50° tg70° C) 2√3tg50° tg70° D) 4 √3tg50° tg70° 25 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 42 D) 64 26 / 40 sonlarini taqqolsang. A) c B) c C) a D) b 27 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 8 C) 20 D) 15 28 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 40° C) 20° D) 50° 29 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) 1 D) bd/c 30 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 10 D) 4√7 31 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 28 C) 24 D) 32 32 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,0(2) C) 0,(04) D) 0,04 33 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 3 D) 2 34 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 6 C) 12 D) 8 35 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 32 C) 8(π+2) D) 64 36 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 0 D) 1/32 37 / 40 bo‘lsa, A) 2/3 B) 1 C) 2 D) 3/2 38 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BC > AD C) AB = BC D) BD = BC 39 / 40 Hisoblang: A) 19/20 B) 10/11 C) 20/21 D) 9/10 40 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 5 C) 7 D) 8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16