Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 92 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 bo‘lsa, y = ? A) 8 B) 3 C) 2 D) 26 2 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16sin3x*sin5x B) 16sin3x*cos5x C) -16cos3x*sin5x D) 16cos3x*cos5x 3 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)+2x²-1 B) f(x)=x²+3x+7 C) f(x)=x²-x+5 D) f(x)=x²-4 4 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13cosx-cos13x + C B) 13sinx-sin13x + C C) 13sinx+sin13x + C D) -13cosx- cos13 x +C 5 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 2 B) 3 C) 1 D) 4 6 / 40 Soddalashtiring. A) (a-1)/(a-3) B) (b+2)/(1-b) C) (a-1)/(1-b) D) (a+1)/(-a-3) 7 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 17° B) 14° C) 24° D) 7° 8 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 20 C) 40 D) 35 9 / 40 ABC o‘tkir burchakli uchburchakda sinA=4/5 va sinB=15/13 bo'lsa, sinC ni qiymatini toping. A) 36/65 B) 48/65 C) 40/63 D) 56/65 10 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 144π B) 72π C) 96π D) 192π 11 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 2 C) 4 D) 3 12 / 40 Hisoblang: A) 0 B) 1/32 C) -1/2 D) -√3/2 13 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 8 D) 10 14 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 50° C) 20° D) 40° 15 / 40 sonlarini taqqolsang. A) c B) c C) b D) a 16 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) AB = BC D) BC > AD 17 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 100 C) 96 D) 25 18 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 2√3tg50° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 19 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 116 C) 112 D) 115 20 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 4 C) 2 D) 3 21 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 30 D) 24 22 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (2; 7) C) (9; 0), (28; -1) D) (2; 3) 23 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 8(π+2) C) 64 D) 16(π-2) 24 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 15 C) 20 D) 8 25 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 2√3 C) 3√2 D) 4√3 26 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 10 D) 4√7 27 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 14 D) 23 28 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) berilganlar yetarli emas D) 22 29 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 8 C) 3 D) 5 30 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 10 C) 14 D) 12 31 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 48 D) 42 32 / 40 √3 A) 3/2 B) 7/3 C) 21/10 D) 5/5 33 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 5 C) 11 D) 10 34 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 1 C) 2 D) 3 35 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 4 D) 11 36 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 42 C) 44 D) 45 37 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -4 C) -6 D) 5 38 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) 1 D) cd/b 39 / 40 Tenglamani yeching: A) 6; -5 B) 5 C) -6; 5 D) -6 40 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 14 D) 13 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16