Barcha fanlardan online testlar

Matematika attestatsiya №6

InfoMaster

Yanvar 30, 2022

71 Ko'rishlar 2 izohlar

SaqlashSaqlanganOlib tashlandi 0

0 ovozlar, 0 avg

Matematika fanidan attestatsiya savollari №6

1 / 40

Qayiq daryo oqimga qarshi 48 km va oqim bo‘yicha ham shuncha yo‘l bosib, butun yo‘lga 5 soat vaqt sarfladi. Daryo oqimining tezligi 4 km/soat bo‘lsa, qayiqning xususiy tezligini toping.

A) 22

B) 18

C) 20

D) 25

2 / 40

Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi?

A) 2

B) 1

C) 3

D) 4

3 / 40

f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping.

A) 13cosx-cos13x + C

B) -13cosx- cos13 x +C

C) 13sinx+sin13x + C

D) 13sinx-sin13x + C

4 / 40

Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping.

A) 2

B) √3

C) √2

D) 1

5 / 40

Hisoblang: -1²¹+(-1³⁵)-(-1)²⁸

A) 0

B) -3

C) -2

D) -1

6 / 40

n ning qanday qiymatida tenglik to`g`ri bo’ladi? (7³)=7¹⁵

A) 12

B) 5

C) 1

D) 7

7 / 40

Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor?

A) 0,144

B) 0,288

C) 0,216

D) 0,432

8 / 40

f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)⁴ bo'lsa, f'(0) ni toping.

A) 25

B) 0

C) 10

D) 30

9 / 40

Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin.

A) R(√3-√2)

B) 1,5R

C) √3R(2-√3)

D) 3R

10 / 40

Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping.

A) √6

B) 2,5

C) 2,4

D) √5

11 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) bc/d

B) bd/c

C) cd/b

D) 1

12 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 112

B) 110

C) 115

D) 116

13 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 10

B) 9

C) 12

D) 11

14 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 12

C) 10

D) 6

15 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 6

C) 8

D) 5

16 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) π/4+πk, k∈Z

B) 0

C) -π/4+πk, k∈Z

D) Ø

17 / 40

sonlarini taqqolsang.

A) c

B) a

C) c

D) b

18 / 40

Tenglamalar sistemani yeching:

A) (7; 2), (28; -1)

B) (9; 0), (2; 7)

C) (9; 0), (28; -1)

D) (2; 3)

19 / 40

Ifodaning qiymatini toping.

A) 0,(04)

B) 0,04

C) 0,0(4)

D) 0,0(2)

20 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 6

B) 4 yoki –12

C) 3 yoki –8

D) 5 yoki –15

21 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 10

B) 11

C) 7

D) 5

22 / 40

Hisoblang:

A) 10/11

B) 20/21

C) 9/10

D) 19/20

23 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 43

B) 44

C) 45

D) 42

24 / 40

Rasmdagi shakl perimetrini toping.

A) 30

B) 24

C) 32

D) 28

25 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 3√2

B) 2√2

C) 2√3

D) 4√3

26 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 35

B) 23

C) 14

D) 24

27 / 40

Chizmadan foydalanib α ni toping.

A) 30°

B) 50°

C) 40°

D) 20°

28 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√3

B) 4√2

C) 3√2

D) 6

29 / 40

Tenglamani yeching:

A) -6; 5

B) 6; -5

C) -6

D) 5

30 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 3

B) -2

C) 5

D) 8

31 / 40

bo‘lsa,

A) 2/3

B) 3/2

C) 2

D) 1

32 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 1

B) 2

C) 4

D) 3

33 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 6

B) 11

C) 5

D) 4

34 / 40

Hisoblang:

A) -1/2

B) 1/32

C) 0

D) -√3/2

35 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 13

B) 14

C) 15

D) 12

36 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 2

B) 4

C) 3

D) 1

37 / 40

√3

A) 5/5

B) 3/2

C) 7/3

D) 21/10

38 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 48

B) 32

C) 42

D) 64

39 / 40

Hisoblang:

A) 1

B) sin10°

C) cos50°

D) cos10°

40 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 15

B) 20

C) 10

D) 8

O'rtacha ball 0%

Author: InfoMaster

Foydali bo'lsa mamnunmiz

SaqlashSaqlanganOlib tashlandi 0

Oldingi

Javob qoldiring

Sharhlash uchun siz saytga kirishingiz lozim.

Yanvar 2022
Du	Se	Ch	Pa	Ju	Sh	Ya
	1	2
3	4	5	6	7	8	9
10	11	12	13	14	15	16
17	18	19	20	21	22	23
24	25	26	27	28	29	30
31

Elementlarni Solishtiring

Jami (0)

Solishtiring

Matematika attestatsiya №6

Author: InfoMaster

Ona tili va adabiyot attestatsiya №5

Huquq attestatsiya №4

Matematika fanidan attestatsiya savollari №16

Matematika attestatsiya №15

Matematika attestatsiya №14

Matematika attestatsiya №13

Javob qoldiring

Elementlarni Solishtiring