Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №6 Matematika attestatsiya Matematika attestatsiya №6 InfoMaster Yanvar 30, 2022 71 Ko'rishlar 2 izohlar SaqlashSaqlanganOlib tashlandi 0 0% 0 ovozlar, 0 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 ko’paytmani hisoblang. A) 0 B) 480000 C) 86420000 D) 10000 2 / 40 Yig’indi quydagilardan qaysi biriga teng? A) 450,608 B) 4506,08 C) 45,0608 D) 40560,8 3 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (0; ∞) B) [-1; ∞) C) (-1; ∞) D) (-2; ∞) 4 / 40 Tengsizlikni yeching. A) [-3;-2] B) (-∞;-2] C) [-3;2]∪{1} D) [-2;1]∪{-3} 5 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 8 C) 9 D) 6 6 / 40 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 20 km B) 200 km C) 2 km D) 0,2km 7 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 1 B) 3 C) 4 D) 2 8 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 144π B) 96π C) 192π D) 72π 9 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 8 B) 5 C) 1 D) 0 10 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 20 C) 40 D) 35 11 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 115 D) 110 12 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 64 C) 32 D) 48 13 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 1 C) 2 D) 3 14 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 3 yoki –8 C) 4 yoki –12 D) 5 yoki –15 15 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) BD = BC C) DC < AD D) AB = BC 16 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 121 C) 11 D) berilganlar yetarli emas 17 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 10 C) 4√7 D) 6√7 18 / 40 Tenglamani yeching: A) 5 B) -6; 5 C) -6 D) 6; -5 19 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 24 C) 23 D) 14 20 / 40 Hisoblang: A) 20/21 B) 10/11 C) 19/20 D) 9/10 21 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 12 C) 13 D) 14 22 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 8 C) 10 D) 12 23 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) 2√3tg50° tg70° D) √3ctg40° tg70° 24 / 40 bo‘lsa, A) 2/3 B) 2 C) 1 D) 3/2 25 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 28 C) 24 D) 32 26 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) 0 C) π/4+πk, k∈Z D) -π/4+πk, k∈Z 27 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 2 C) 1 D) 4 28 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -4 C) -3 D) 5 29 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 30° C) 20° D) 50° 30 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 6 D) 7 31 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 5 C) 11 D) 6 32 / 40 sonlarini taqqolsang. A) c B) b C) c D) a 33 / 40 √3 A) 21/10 B) 7/3 C) 5/5 D) 3/2 34 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 35 / 40 Hisoblang: A) sin10° B) 1 C) cos50° D) cos10° 36 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 10 C) 15 D) 20 37 / 40 Hisoblang: A) 1/32 B) 0 C) -1/2 D) -√3/2 38 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (2; 3) C) (9; 0), (28; -1) D) (9; 0), (2; 7) 39 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 64 C) 8(π+2) D) 32 40 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 100 C) 25 D) 105 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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