Uy » Choraklik online testlar » Fizika choraklik » 7-sinf Fizika 2-chorak Fizika choraklik 7-sinf Fizika 2-chorak InfoMaster Aprel 26, 2021 646 Ko'rishlar 0 SaqlashSaqlanganOlib tashlandi 0 0 Tomonidan yaratilgan InfoMaster 7-sinf Fizika 2-chorak Testni Vafaqulov Alisher tayyorladi. 1 / 25 Massasi 60 kg bo’lgan jism tik yuqoriga 1 m /s2 tezlanish bilan ko’tarilayotgan bo’lsa, uning og’irligi qanday bo’ladi? A) 480 N B) 540 N C) 660 N D) 600 N 2 / 25 Agar reaktiv samolyot dvigatelining tortish kuchi 90 k N bo’lsa, massasi 60 t bo’lgan samolyot tezlik olish vaqtida qanday tezlanish bilan harakatlanadi? A) 0 B) 1 m/s² C) 0,5 m/s² D) 2 m/s² 3 / 25 Vaznsiz ko’zg’almas blok orqali o’tkazilgan vaznsiz cho’zilmas ipga massalari 6 va 4 kg bo’lgan ikki yuk osilgan. Ishqalanish yo’q. Agar bu sistema o’ziga qo’yib berilsa, yuklar qanday tezlanish (m/s2) bilan xarakat qiladi? A) 1 B) 2 C) 4 D) 3 4 / 25 Qaysi shart bajarilganda, jism suyuqlikda tekis cho’ka boshlaydi? (mg-og’irlik kuchi, Fa- Arximed kuchi, F-qarshilik kuchi) 1) m g > F = F a 2) m g = F 3) m g = F = F a 4) mg < F = F a A) 4 B) 3 C) 1 D) 2 5 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift yuqoriga xarakatlana boshlaganda kuchlar orasidagi munosabatni ko’rsating. 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 2 C) 3 D) 1 6 / 25 Nyutonning 2-qonuni formulasini ko’rsating A) a = F / m B) a = v/t C) a = v² /R D) a = 2s/ t² 7 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tekis xarakatlanganda kuchlar orasidagi munosabatni ko’rsating. Lift yuqoriga xarakatlana boshlaydi 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 3 B) 2 C) 4 D) 1 8 / 25 Xalqaro birliklar sistemasida kuch birligi A) kg*m / s² B) kg*m²/s² C) kg / s² D) m / s² 9 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift tinch turganda kuchlar orasidagi munosabatni ko’rsating 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 3 C) 1 D) 2 10 / 25 Nyutonning 3 qonuni formulasi qaysi ifodada to’g’ri ko’rsatilgan? A) F = mg B) F = mv²/ R C) F1 =- F2 D) F = - k x 11 / 25 Odam liftda turibdi. Odamga ta’sir qiluvchi kuchlar: mg – og’irlik kuchi, N – tayanch reaksiya kuchi, Lift pastda to’xtashdan oldin sekinlashganda kuchlar orasidagi munosabatni ko’rsating. Lift pastda to’xtashdan oldin sekinlashyapti 1) mg > N 2) mg < N 3) mg = N 4) mg = 0; N = 0 A) 4 B) 2 C) 3 D) 1 12 / 25 1 m/s2 tezlanish bilan tushayotgan liftdagi 20 kg massali bolaning og’irligi qancha? A) 170 N B) 190 N C) 180 N D) 200 N 13 / 25 Tekis tezlanuvchan harakat qilayotgan “Matiz” 10 s davomida tezligini 54 km / soat dan 100 km / soat ga oshirdi. «Matiz»ning tezlanishini toping A) 2,5 m/s² B) 13 m/s² C) 15 m/s² D) 3 m/s² 14 / 25 Jism 20 m/s tezlik bilan tik yuqoriga otildi. Jism necha sekund eng baland nuqtasigacha ko’tariladi? g = 10 m/s2 A) 2 c B) 1 c C) 3 c D) 4 c 15 / 25 Tekis sekinlanuvchan harakatda tezlik va tezlanish ishoralarining munosabatini ko’rsating. 1) υ0 > 0, a<0 2) υ0 = 0, a<0 3) υ0 < 0, a>0 4) υ >0, a>0 A) 1,3 B) 2,3 C) 3,4 D) 4 16 / 25 m/s2 tezlanish bilan to’g’ri chiziq bo’ylab harakatlanayotgan jismning holatidan boshlab birinchi sekunda qanday masofani (m) o’tadi? A) 7 B) 8 C) 6 D) 4 17 / 25 Tekis tezlanuvchan harakatda tezlik va tezlanish ishoralarning munosabatini ko’rsating. 1) υ0 > 0, a>0 2) υ0 > 0, a<0 3) υ0 < 0, a<0 4) υ0<0, a>0 A) 3,4 B) 1,2 C) 1,3 D) 2,4 18 / 25 Erkin tushayotgan jism ikkinchi sekundda qanday masofani (m) o’tadi? A) 25 B) 35 C) 5 D) 15 19 / 25 Jism harakat tenglamasi x=5+3t–t2 formula bilan berilgan. Jismning boshlang’ich koordinatasi nimaga teng? A) 9 m B) 3 m C) 1 m D) 5 m 20 / 25 Boshlang’ich tezliksiz erkin tushayotgan jism birinchi sekunda qanday masofani o’tadi?g = 10 m/s2 A) 0,5 m B) 50 m C) 5 m D) 5,5 m 21 / 25 Jismning harakat tenglamasi x = 2 – 3 t + 2 t2 formula bilan berilgan. Bu harakat uchun tezlik tenglamasini yozing A) υ= 4 - 3 t B) υ= 4 + 3 t C) υ = 4 t D) υ= - 3 + 4 t 22 / 25 Tezlanish formulasi qanday ifodalanadi A) p = m / v B) p = F / S C) S = at² / 2 D) a = (v - v˳)/t 23 / 25 25 m/s tezlik bilan yuqoriga tik otilgan jismning 2 s dan keyingi tezligi qancha bo’ladi? A) 10 m/s B) 15 m/s C) 20 m/s D) 5 m/s 24 / 25 Tezligi υ=5-3 t (m/s) tenglama bilan berilgan jismning boshlangich tezligi (m/s) nimaga teng? A) 5 B) 3 C) 4 D) 2 25 / 25 Jism tezlik proporsiyasining vaqtga bog’lanish v = 3+2t (m/s) ko’rinishga ega. Ko’chish proyeksiyasining vaqtga bog’lanishi qanday? A) S = 3t + 1 t² B) S = 2t² C) S = 2t + 3 ² D) S = 3t + 2 t² 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz