11-sinf Matematika 2-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga fikr bildirilmagan. 1 OMAD YOR BO'LSIN! 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 limitni hisoblang A) 7 B) 6 C) 5 D) 0 2 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -4 B) -13 C) 13 D) 131 3 / 25 Funksiya hosilasini toping: A) 12x+12 B) 12x²-12 C) 21x²-10x D) 14x+12 4 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=-x C) y=x D) y= 2x 5 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) √24 C) 25 D) 16 6 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 70 C) 84 D) 60 7 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,5 B) 0,15 C) 0,25 D) 1,5 8 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (4;9;9) C) (2;5;3) D) (4;9;9) 9 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √66 B) √24 C) √19 D) √55 10 / 25 Limitni hisoblang: A) 3 B) -4 C) 4 D) -3 11 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x C) y=10x D) y=35x+30 12 / 25 A) 14 B) 13 C) 20 D) 18 13 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 14400 C) 19600 D) 8100 14 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=3 B) x=3, x=2 C) x=-1, x=2 D) x=0, x=2 15 / 25 funksiyasining kamayish oralig’ini toping. A) (-1/3;+∞) B) (-∞;-1) C) (-1;1/3) D) [-1;-1/3] 16 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 5 B) 7 C) 6 D) 4 17 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,623 B) 0,0282 C) 0,0321 D) 0,3265 18 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=0.5cos(5x+12) B) f(x)=cos(5x+12) C) f(x)=-cos(5x+12) D) f(x)=-0,5sin(5x+12) 19 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;10 B) 4;18 C) 8;10 D) 4;11 20 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0 B) 0.5 C) 2 D) 1.5 21 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 6 C) 6 D) 8 22 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;9) B) (-4;-6;6) C) (-8;-3;6) D) (-4;-3;6) 23 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(π) C) e^(0.5π) D) e^(-π) 24 / 25 Agar va bo`lsa ,f(g(-4)) ni toping A) -12 B) 36 C) 12 D) 0 25 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm C) 224 dm² D) 124 dm² 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Matematika choraklik Teglar:11-sinf, matematika
