Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 2-chorak Matematika choraklik 11-sinf Matematika 2-chorak InfoMaster Aprel 20, 2021 32 Ko'rishlar 16 izohlar SaqlashSaqlanganOlib tashlandi 1 0 OMAD YOR BO'LSIN! 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 6 C) 7 D) 8 2 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-0,5sin(5x+12) B) f(x)=cos(5x+12) C) f(x)=-cos(5x+12) D) f(x)=0.5cos(5x+12) 3 / 25 sonini taqriban hisoblang. A) 3,08 B) 4,08 C) 5,08 D) 5,01 4 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;11 B) 8;10 C) 4;18 D) 4;10 5 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=-0,5cos2x+C B) F(x)=-2cos2x+C C) F(x)=0,5cos2x+C D) F(x)=2sin4x+c 6 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 61 B) 41 C) 71 D) 51 7 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,9 dm B) 17,68 dm²; 4,2 dm C) 17,64 dm²; 4,2 dm D) 17,64 dm; 4,2 dm 8 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm² C) 224 dm² D) 124 dm 9 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(π) B) e^(-π) C) e^(-0.5π) D) e^(0.5π) 10 / 25 Limitni hisoblang: A) -3 B) 4 C) -4 D) 3 11 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 52° B) 80° C) 90° D) 15° 12 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √55 B) √19 C) √24 D) √66 13 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,0269 B) 0,5 C) 0,01 D) 0,6 14 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 60 C) 84 D) 70 15 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 0 B) 36 C) 12 D) 16 16 / 25 funksiyasining kamayish oralig’ini toping. A) (-∞;-1) B) (-1;1/3) C) [-1;-1/3] D) (-1/3;+∞) 17 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)/5 C) (4√2)3 D) (2√5)/3 18 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-3;-1) B) (-1;-1;-4) C) (-2;-4;-1) D) (-1;-1;-1) 19 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) √24 C) 25 D) 16 20 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=-x C) y=x D) y= 2x 21 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -13 B) -17 C) 17 D) 15 22 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x+30 C) y=10x D) y=35x 23 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;1) B) (-3;0) va (0;1) C) (-2;0) va (0;1) D) (-1;0) va (0;2) 24 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=3x-2,2 B) y=2x C) y=2x+3 D) y=2x-2,25 25 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 4 B) 3 C) 2 D) 1 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz