11-sinf Matematika 4-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga 74 fikr bildirilgan 5 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 integralni hisoblang A) 5ln2e B) 5 C) 5ln3e³ D) 5ln4e 2 / 25 B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping A) 4 B) 3/4 C) 3 D) 1 3 / 25 2cosx+sinx=-2 tenglamaning [-π;π] kesmada nechta ildizi bor A) 3 B) 2 C) Ø D) 1 4 / 25 Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping A) (2-√3)(2√3-π) B) (4-√3)(2√3-π) C) (2-√3)(2-π) D) 2√3-π 5 / 25 Bir burchagi 600 bo’lgan to’g’ri burchakli uchburchakka tomoni 6 ga teng romb shunday ichki chizilganki, 600 li burchak ular uchun umumiy, rombning barcha uchlari uchburchakning tomonlarida yotadi. Uchburchak yuzini toping A) (81√3)/2 B) √3/2 C) (8√3)/2 D) (1√3)/2 6 / 25 Hisoblang: cos2330+cos2450-sin2600+cos2570 A) 1,5 B) 0,5 C) 0,75 D) 2,25 7 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-1;-3;-1) C) (-2;-4;-1) D) (-1;-1;-4) 8 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 70 C) 60 D) 84 9 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,3265 B) 0,0321 C) 0,0282 D) 0,623 10 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 90 B) 80 C) 70 D) 75 11 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²-3x+1 C) F(x)=x²-3x-1 D) F(x)=x²+3x+1 12 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 14 C) 16 D) 18 13 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 1.5 B) 0.5 C) 0 D) 2 14 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x B) y=10x C) y=20x+20 D) y=35x+30 15 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -13 B) 131 C) 13 D) -4 16 / 25 Funksiyaning statsionar nuqtalarini toping A) x=3, x=2 B) x=0, x=2 C) x=-1, x=3 D) x=-1, x=2 17 / 25 limitni hisoblang A) 0 B) 7 C) 6 D) 5 18 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)/5 C) (4√2)3 D) (2√5)/3 19 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 9 B) 16 C) 4 D) 8 20 / 25 Silindr shaklidagi idishga 6 sm3 suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang A) 1 B) 23 C) 3 D) 14 21 / 25 Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping A) 1 B) 4 C) 335 D) 1/2 22 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 8 C) 6 D) 6 23 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm B) 224 dm² C) 135 dm² D) 124 dm² 24 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 51 B) 71 C) 41 D) 61 25 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(π) C) e^(0.5π) D) e^(-π) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 3-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 3-chorak ga 2 fikr bildirilgan 3 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping A) 1/2 B) 335 C) 4 D) 1 2 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 1 B) 3 C) 3√2 D) 4 3 / 25 Silindr shaklidagi idishga 6 sm3 suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang A) 23 B) 3 C) 1 D) 14 4 / 25 Uchburchakli muntazam prizma asosining radiusi ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping A) 3 B) 36 C) 335 D) 4 5 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2300 C) 1023 D) 2025 6 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=0.5cos(5x+12) B) f(x)=-cos(5x+12) C) f(x)=cos(5x+12) D) f(x)=-0,5sin(5x+12) 7 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm² B) 124 dm C) 135 dm² D) 224 dm² 8 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,68 dm²; 4,2 dm B) 17,64 dm²; 4,2 dm C) 17,64 dm; 4,2 dm D) 17,64 dm²; 4,9 dm 9 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 8 B) 6 C) 7 D) 6 10 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -4 B) 131 C) -13 D) 13 11 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 18 C) 16 D) 14 12 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-1;0) va (0;2) C) (-3;0) va (0;1) D) (-1;0) va (0;1) 13 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-∞;-1) C) (-1/3;+∞) D) (-1;1/3) 14 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 16 B) √24 C) 25 D) √26 15 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x+30 C) y=10x D) y=35x 16 / 25 limitni hisoblang A) 7 B) 0 C) 5 D) 6 17 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (4;9;9) C) (-2;-5;-3) D) (2;5;3) 18 / 25 Funksiya hosilasini toping: f(x)=5 A) 0 B) x C) 10 D) 5 19 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 90 B) 70 C) 75 D) 80 20 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)3 B) (4√2)/5 C) 4 D) (2√5)/3 21 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 60 C) 84 D) 74 22 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,5 B) 0,01 C) 0,0269 D) 0,6 23 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 4 C) 2 D) 3 24 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=3 B) x=-1, x=2 C) x=3, x=2 D) x=0, x=2 25 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y= 2x B) y=x C) y=-x D) y=1/2 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 2-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga 1 fikr bildirilgan 7 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 tgx funksiya hosilasini toping A) cosx B) 1/cos²x C) sinx D) 1/sinx 2 / 25 Funksiya hosilasini toping: f(x)=5 A) 0 B) 10 C) x D) 5 3 / 25 Funksiyaning kamayish oraliqlarini toping A) (-3;0) va (0;1) B) (-1;0) va (0;1) C) (-1;0) va (0;2) D) (-2;0) va (0;1) 4 / 25 funksiyasining kamayish oralig’ini toping. A) (-1;1/3) B) [-1;-1/3] C) (-∞;-1) D) (-1/3;+∞) 5 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 12 B) 36 C) 0 D) 16 6 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (-2;-5;-3) C) (4;9;9) D) (4;9;9) 7 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-4;-3;9) C) (-4;-6;6) D) (-8;-3;6) 8 / 25 Limitni hisoblang: A) 3 B) -4 C) -3 D) 4 9 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,15 B) 0,25 C) 1,5 D) 0,5 10 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -13 B) 17 C) -17 D) 15 11 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 0 B) 36 C) 12 D) -12 12 / 25 Funksiya hosilasini toping: A) 21x²-10x B) 12x+12 C) 14x+12 D) 12x²-12 13 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=2xsinx+x²cosx C) y’=x²cosx-2xsinx D) y’=2xsinx-x² 14 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x B) y=20x+20 C) y=35x+30 D) y=10x 15 / 25 limitni hisoblang A) 7 B) 0 C) 5 D) 6 16 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)3 C) (4√2)/5 D) (2√5)/3 17 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 80° B) 15° C) 52° D) 90° 18 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 3x+1 B) 16x+14 C) 12x+14 D) 12x 19 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 18 B) 16 C) 17 D) 14 20 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 19600 B) 8100 C) 25600 D) 14400 21 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 5 B) 4 C) 6 D) 7 22 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 224 dm² B) 135 dm² C) 124 dm² D) 124 dm 23 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=-0,5cos2x+C C) F(x)=2sin4x+c D) F(x)=-2cos2x+C 24 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 8 C) 6 D) 6 25 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 8;10 B) 4;18 C) 4;10 D) 4;11 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 1-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 1-chorak ga 2 fikr bildirilgan 9 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 1-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 A) 20 B) 13 C) 18 D) 14 2 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²-3x+1 C) F(x)=x²+3x-1 D) F(x)=x²+3x+1 3 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 80 B) 75 C) 90 D) 70 4 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 16 B) 18 C) 14 D) 17 5 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 12 C) 36 D) 0 6 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -13 B) -4 C) 131 D) 13 7 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=-x C) y= 2x D) y=x 8 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-1;-1;-4) C) (-1;-3;-1) D) (-2;-4;-1) 9 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 0 B) 16 C) 12 D) 36 10 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0 B) 1.5 C) 0.5 D) 2 11 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 2 B) 3 C) 1 D) 4 12 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (2;5;3) C) (-2;-5;-3) D) (4;9;9) 13 / 25 Funksiya hosilasini toping: A) 12x+12 B) 14x+12 C) 21x²-10x D) 12x²-12 14 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-6;6) B) (-8;-3;6) C) (-4;-3;6) D) (-4;-3;9) 15 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √55 B) √19 C) √66 D) √24 16 / 25 Funksiyaning statsionar nuqtalarini toping A) x=3, x=2 B) x=-1, x=3 C) x=0, x=2 D) x=-1, x=2 17 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 1,5 B) 0,5 C) 0,25 D) 0,15 18 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 3x+1 B) 16x+14 C) 12x D) 12x+14 19 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,01 B) 0,6 C) 0,5 D) 0,0269 20 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-1;0) va (0;1) C) (-1;0) va (0;2) D) (-3;0) va (0;1) 21 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=2x C) y=3x-2,2 D) y=2x-2,25 22 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) 25 C) 16 D) √24 23 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 60 B) 84 C) 74 D) 70 24 / 25 limitni hisoblang A) 5 B) 6 C) 0 D) 7 25 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -17 B) 17 C) -13 D) 15 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik