11-sinf Matematika 4-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga 83 fikr bildirilgan 4 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,68 dm²; 4,2 dm B) 17,64 dm; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,64 dm²; 4,2 dm 2 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-π) B) e^(-0.5π) C) e^(π) D) e^(0.5π) 3 / 25 sonini taqriban hisoblang. A) 5,08 B) 4,08 C) 3,08 D) 5,01 4 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x+4 B) F(x)=6x³+3x²-4 C) F(x)=6x³+6x²+4 D) F(x)=6x³+3x²+4 5 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 1023 B) 2025 C) 2330 D) 2300 6 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 4 B) 5 C) 3 D) 1 7 / 25 Uchburchakli muntazam prizma asosining radiusi ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping A) 36 B) 3 C) 335 D) 4 8 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) √2 B) 1 C) 0,5 D) 2 9 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) √2 B) 1 C) 2 D) √22 10 / 25 sin3x+cos3x≥0 tengsizligini yeching A) [-π/9+n π/3;2 π/9+n π/3] B) (-π/2+n π;- π/2+n π) C) [-π/9+2πn/3; 2π/9+2πn/3] D) ø 11 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²+3x+1 C) F(x)=x²+3x-1 D) F(x)=x²-3x+1 12 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;9) B) (-8;-3;6) C) (-4;-6;6) D) (-4;-3;6) 13 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;2) B) (-3;0) va (0;1) C) (-1;0) va (0;1) D) (-2;0) va (0;1) 14 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,25 B) 0,15 C) 0,5 D) 1,5 15 / 25 Funksiya hosilasini toping: f(x)=5 A) 10 B) 0 C) x D) 5 16 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 1.5 C) 0.5 D) 0 17 / 25 limitni hisoblang A) 6 B) 0 C) 7 D) 5 18 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (2;5;3) C) (4;9;9) D) (4;9;9) 19 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 16 B) 18 C) 17 D) 14 20 / 25 Limitni hisoblang: A) -4 B) -3 C) 3 D) 4 21 / 25 Funksiyaning statsionar nuqtalarini toping A) x=0, x=2 B) x=-1, x=3 C) x=-1, x=2 D) x=3, x=2 22 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) 4 B) (4√2)/5 C) (2√5)/3 D) (4√2)3 23 / 25 integralni hisoblang A) 5ln3e³ B) 5ln4e C) 5ln2e D) 5 24 / 25 Funksiyaning aniqlanish sohasini toping : y=logx-2(x2+7x-8) A) (-∞;-8)U(2;3)U(3;+∞) B) (2;3)U(3;+∞) C) (8;+∞) D) (-∞;-1)U(8;+∞) 25 / 25 Massasi 735 gr va konsentratsiyasi 16% bo’lgan yodning spirtdagi eritmasiga qancha toza spirt qo’shilsa, uning konsentratsiyasi 10% bo’ladi A) 441 B) 252 C) 420 D) 256 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 3-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 3-chorak ga 8 fikr bildirilgan 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) 24 B) -24 C) 23 D) -23 2 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 55° B) 125° C) 105° D) 75° 3 / 25 cos150*cos450 *cos750 ni hisoblang A) √2/2 B) √2 C) √8/2 D) 2√2 4 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) 2 B) √22 C) √2 D) 1 5 / 25 Ixtiyoriy kvadratga tashqi va ichki chizilgan aylanalar yuzlari nisbati a ga teng. Ixtiyoriy aylanaga ichki va tashqi chizilgan kvadratlar yuzlari nisbati b ga teng bolsa, a/b ni toping A) 4 B) 1 C) 1/2 D) 335 6 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) 0,5 B) √2 C) 2 D) 1 7 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 4 B) 3 C) 5 D) 1 8 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0.5 B) 2 C) 0 D) 1.5 9 / 25 Limitni hisoblang: A) 4 B) -4 C) -3 D) 3 10 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 1,5 B) 0,5 C) 0,25 D) 0,15 11 / 25 Funksiyaning kamayish oraliqlarini toping A) (-3;0) va (0;1) B) (-2;0) va (0;1) C) (-1;0) va (0;2) D) (-1;0) va (0;1) 12 / 25 Funksiya hosilasini toping: A) 21x²-10x B) 12x+12 C) 12x²-12 D) 14x+12 13 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/961 B) -38/961 C) -38/31 D) 38/31 14 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1/3;+∞) C) (-1;1/3) D) (-∞;-1) 15 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 75 B) 80 C) 70 D) 90 16 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √19 B) √66 C) √55 D) √24 17 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 7 B) 6 C) 4 D) 5 18 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2300 B) 1023 C) 2330 D) 2025 19 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 8 C) 7 D) 6 20 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=-2cos2x+C C) F(x)=2sin4x+c D) F(x)=-0,5cos2x+C 21 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;18 B) 4;11 C) 4;10 D) 8;10 22 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(-π) C) e^(0.5π) D) e^(π) 23 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=cos(5x+12) B) f(x)=-0,5sin(5x+12) C) f(x)=-cos(5x+12) D) f(x)=0.5cos(5x+12) 24 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,64 dm²; 4,9 dm B) 17,64 dm²; 4,2 dm C) 17,64 dm; 4,2 dm D) 17,68 dm²; 4,2 dm 25 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²-4 B) F(x)=6x³+6x+4 C) F(x)=6x³+3x²+4 D) F(x)=6x³+6x²+4 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 2-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga 16 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 7 B) 8 C) 6 D) 6 2 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 5 C) 7 D) 4 3 / 25 sonini taqriban hisoblang. A) 5,08 B) 4,08 C) 5,01 D) 3,08 4 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm² B) 135 dm² C) 124 dm D) 224 dm² 5 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=-2cos2x+C C) F(x)=-0,5cos2x+C D) F(x)=2sin4x+c 6 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-cos(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=-0,5sin(5x+12) D) f(x)=cos(5x+12) 7 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²+4 B) F(x)=6x³+6x+4 C) F(x)=6x³+3x²-4 D) F(x)=6x³+6x²+4 8 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(0.5π) B) e^(-0.5π) C) e^(-π) D) e^(π) 9 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 14400 C) 19600 D) 8100 10 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,5 B) 0,6 C) 0,0269 D) 0,01 11 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 80° B) 15° C) 90° D) 52° 12 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) 4 C) (2√5)/3 D) (4√2)3 13 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=35x+30 B) y=10x C) y=35x D) y=20x+20 14 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 12 B) 36 C) 16 D) 0 15 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y= 2x B) y=-x C) y=1/2 D) y=x 16 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) -12 B) 12 C) 36 D) 0 17 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 3 B) 1 C) 2 D) 4 18 / 25 Limitni hisoblang: A) -4 B) -3 C) 3 D) 4 19 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 80 B) 90 C) 75 D) 70 20 / 25 A) 13 B) 18 C) 14 D) 20 21 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-1;-3;-1) C) (-1;-1;-4) D) (-2;-4;-1) 22 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x+1 B) F(x)=x²+3x+1 C) F(x)=x²-3x-1 D) F(x)=x²+3x-1 23 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/961 B) 38/31 C) -38/31 D) -38/961 24 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) √24 C) √26 D) 16 25 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (-2;-5;-3) C) (2;5;3) D) (4;9;9) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 1-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 1-chorak ga 8 fikr bildirilgan 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 1-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=10x B) y=20x+20 C) y=35x+30 D) y=35x 2 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,0269 B) 0,6 C) 0,01 D) 0,5 3 / 25 Limitni hisoblang: A) -4 B) 3 C) 4 D) -3 4 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-1;-1) B) (-2;-4;-1) C) (-1;-1;-4) D) (-1;-3;-1) 5 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 16 B) 12 C) 0 D) 36 6 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;1) B) (-2;0) va (0;1) C) (-3;0) va (0;1) D) (-1;0) va (0;2) 7 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=2x-2,25 C) y=2x+3 D) y=3x-2,2 8 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)3 B) (4√2)/5 C) (2√5)/3 D) 4 9 / 25 limitni hisoblang A) 7 B) 0 C) 5 D) 6 10 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 17 B) 15 C) -13 D) -17 11 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √66 B) √55 C) √24 D) √19 12 / 25 Funksiya hosilasini toping: f(x)=5 A) 10 B) 0 C) x D) 5 13 / 25 Funksiya hosilasini toping: A) 14x+12 B) 12x+12 C) 12x²-12 D) 21x²-10x 14 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=2xsinx-x² C) y’=-2xsinx+x² D) y’=2xsinx+x²cosx 15 / 25 A) 14 B) 18 C) 13 D) 20 16 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (-2;-5;-3) C) (2;5;3) D) (4;9;9) 17 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 80° B) 15° C) 52° D) 90° 18 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) 16 C) √26 D) √24 19 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-3;6) C) (-4;-3;9) D) (-4;-6;6) 20 / 25 tgx funksiya hosilasini toping A) 1/sinx B) cosx C) 1/cos²x D) sinx 21 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 2 B) 1 C) 3 D) 4 22 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/961 B) 38/961 C) -38/31 D) 38/31 23 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=2 B) x=-1, x=3 C) x=0, x=2 D) x=3, x=2 24 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²-3x-1 C) F(x)=x²-3x+1 D) F(x)=x²+3x+1 25 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0321 B) 0,3265 C) 0,623 D) 0,0282 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik