11-sinf Matematika 4-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga 15 fikr bildirilgan 2 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 tgx funksiya hosilasini toping A) 1/sinx B) 1/cos²x C) cosx D) sinx 2 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x-2,25 B) y=2x+3 C) y=3x-2,2 D) y=2x 3 / 25 Funksiya hosilasini toping: A) 12x+12 B) 12x²-12 C) 21x²-10x D) 14x+12 4 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (-2;-5;-3) C) (2;5;3) D) (4;9;9) 5 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-1;-3;-1) B) (-1;-1;-4) C) (-2;-4;-1) D) (-1;-1;-1) 6 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 60 B) 84 C) 70 D) 74 7 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) (4√2)3 C) (2√5)/3 D) 4 8 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 16 C) 14 D) 18 9 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/961 B) 38/31 C) -38/31 D) 38/961 10 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-4;-6;6) C) (-8;-3;6) D) (-4;-3;9) 11 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 3 C) 4 D) 2 12 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 16 B) 0 C) 12 D) 36 13 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) -24 B) -23 C) 23 D) 24 14 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 1 B) 3 C) 5 D) 4 15 / 25 cos(2arctg(1/2)) ni hisoblang A) 37/35 B) -35/37 C) 35/37 D) -37/35 16 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) √2 B) 1 C) √22 D) 2 17 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 16 B) 4 C) 8 D) 9 18 / 25 Uchburchakli muntazam prizma asosining radiusi ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping A) 3 B) 4 C) 335 D) 36 19 / 25 y=x2-│2x-4│ funksiya grafigiga x=3 va x= -3 nuqtalarda o’tkazilgan urinmalar kesishish nuqtasi ordinatasini toping A) -5 B) -9 C) -6 D) -12 20 / 25 Hisoblang: cos2330+cos2450-sin2600+cos2570 A) 0,5 B) 0,75 C) 2,25 D) 1,5 21 / 25 B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping A) 1 B) 3/4 C) 3 D) 4 22 / 25 integralni hisoblang A) 5ln4e B) 5ln2e C) 5 D) 5ln3e³ 23 / 25 Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin A) 84 B) 21 C) 168 D) 42 24 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=2sin4x+c C) F(x)=-2cos2x+C D) F(x)=-0,5cos2x+C 25 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2025 C) 2300 D) 1023 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 3-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 3-chorak ga 1 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²+4 B) F(x)=6x³+3x²-4 C) F(x)=6x³+6x²+4 D) F(x)=6x³+6x+4 2 / 25 sonini taqriban hisoblang. A) 4,08 B) 5,01 C) 5,08 D) 3,08 3 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 14400 B) 19600 C) 25600 D) 8100 4 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-cos(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=-0,5sin(5x+12) D) f(x)=cos(5x+12) 5 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 6 C) 7 D) 8 6 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(0.5π) B) e^(-π) C) e^(-0.5π) D) e^(π) 7 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 8 B) 4 C) 16 D) 9 8 / 25 Silindr shaklidagi idishga 6 sm3 suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang A) 23 B) 14 C) 3 D) 1 9 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 4 B) 3 C) 3√2 D) 1 10 / 25 Ushbu funksiyasining boshlang’ich funksiyasini toping A) (x+2)(x+1) B) ln(|x+2|*|x+1|) C) lnI(x-2)(x-3)I D) lnIx-1I 11 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 75° B) 125° C) 55° D) 105° 12 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) 0,5 B) √2 C) 2 D) 1 13 / 25 Limitni hisoblang: A) -3 B) -4 C) 4 D) 3 14 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0 B) 0.5 C) 2 D) 1.5 15 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 0 B) 36 C) -12 D) 12 16 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) √24 C) 25 D) 16 17 / 25 funksiyasining kamayish oralig’ini toping. A) (-1/3;+∞) B) [-1;-1/3] C) (-∞;-1) D) (-1;1/3) 18 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (2;5;3) B) (4;9;9) C) (-2;-5;-3) D) (4;9;9) 19 / 25 A(1;-2;2), B(1;4;0), C(-4;1;1) va D(-5;-5;3) nuqtalar berilgan. AC va BD vektorlar orasidagi burchakni toping A) 52° B) 80° C) 90° D) 15° 20 / 25 Funksiyaning statsionar nuqtalarini toping A) x=3, x=2 B) x=-1, x=2 C) x=-1, x=3 D) x=0, x=2 21 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 15 B) -17 C) 17 D) -13 22 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √55 B) √19 C) √24 D) √66 23 / 25 Funksiya hosilasini toping: f(x)=5 A) x B) 0 C) 5 D) 10 24 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-4;-6;6) C) (-4;-3;9) D) (-8;-3;6) 25 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y= 2x C) y=-x D) y=x 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 2-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga 4 fikr bildirilgan 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 14400 B) 19600 C) 8100 D) 25600 2 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=0,5cos2x+C B) F(x)=-2cos2x+C C) F(x)=-0,5cos2x+C D) F(x)=2sin4x+c 3 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=-0,5sin(5x+12) B) f(x)=0.5cos(5x+12) C) f(x)=-cos(5x+12) D) f(x)=cos(5x+12) 4 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 224 dm² B) 124 dm² C) 124 dm D) 135 dm² 5 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;18 B) 8;10 C) 4;10 D) 4;11 6 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+6x+4 B) F(x)=6x³+6x²+4 C) F(x)=6x³+3x²-4 D) F(x)=6x³+3x²+4 7 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 60 B) 70 C) 74 D) 84 8 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,25 B) 1,5 C) 0,5 D) 0,15 9 / 25 funksiyasining kamayish oralig’ini toping. A) (-∞;-1) B) (-1;1/3) C) (-1/3;+∞) D) [-1;-1/3] 10 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 2 B) 3 C) 1 D) 4 11 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x+1 B) F(x)=x²+3x-1 C) F(x)=x²-3x-1 D) F(x)=x²-3x+1 12 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 1.5 B) 0 C) 0.5 D) 2 13 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0321 B) 0,623 C) 0,0282 D) 0,3265 14 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √55 C) √66 D) √19 15 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y= 2x B) y=x C) y=1/2 D) y=-x 16 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)/5 B) (2√5)/3 C) 4 D) (4√2)3 17 / 25 Funksiya hosilasini toping: f(x)=5 A) 0 B) 10 C) x D) 5 18 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 16 B) 17 C) 18 D) 14 19 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 16 B) 0 C) 12 D) 36 20 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -17 B) 17 C) 15 D) -13 21 / 25 Funksiya hosilasini toping: A) 14x+12 B) 21x²-10x C) 12x+12 D) 12x²-12 22 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 3x+1 B) 16x+14 C) 12x+14 D) 12x 23 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,6 B) 0,0269 C) 0,5 D) 0,01 24 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (2;5;3) C) (-2;-5;-3) D) (4;9;9) 25 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x+3 B) y=3x-2,2 C) y=2x D) y=2x-2,25 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 1-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 1-chorak ga 1 fikr bildirilgan 14 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 1-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √66 B) √55 C) √24 D) √19 2 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0321 B) 0,0282 C) 0,3265 D) 0,623 3 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 70 B) 60 C) 74 D) 84 4 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=3x-2,2 B) y=2x C) y=2x-2,25 D) y=2x+3 5 / 25 Funksiya hosilasini toping: A) 12x²-12 B) 21x²-10x C) 12x+12 D) 14x+12 6 / 25 Funksiya hosilasini toping: f(x)=5 A) 5 B) 10 C) x D) 0 7 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,0269 B) 0,6 C) 0,01 D) 0,5 8 / 25 funksiyasining kamayish oralig’ini toping. A) (-∞;-1) B) (-1;1/3) C) (-1/3;+∞) D) [-1;-1/3] 9 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 17 B) 15 C) -13 D) -17 10 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 4 B) 2 C) 3 D) 1 11 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=x B) y= 2x C) y=1/2 D) y=-x 12 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x B) 16x+14 C) 3x+1 D) 12x+14 13 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=2xsinx+x²cosx B) y’=-2xsinx+x² C) y’=x²cosx-2xsinx D) y’=2xsinx-x² 14 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-6;6) B) (-8;-3;6) C) (-4;-3;6) D) (-4;-3;9) 15 / 25 Funksiyaning kamayish oraliqlarini toping A) (-1;0) va (0;1) B) (-3;0) va (0;1) C) (-2;0) va (0;1) D) (-1;0) va (0;2) 16 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) √26 C) √24 D) 16 17 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 2 B) 0 C) 1.5 D) 0.5 18 / 25 Limitni hisoblang: A) -4 B) 4 C) -3 D) 3 19 / 25 A) 13 B) 18 C) 20 D) 14 20 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -4 B) 131 C) -13 D) 13 21 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 18 B) 16 C) 14 D) 17 22 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x C) y=10x D) y=35x+30 23 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,25 B) 0,5 C) 0,15 D) 1,5 24 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/961 B) 38/961 C) -38/31 D) 38/31 25 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 90 B) 80 C) 75 D) 70 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik