6-sinf Matematika 1-chorak Oktabr 26, 2021Oktabr 26, 2021 da chop etilgan InfoMaster tomonidan 6-sinf Matematika 1-chorak ga 1 fikr bildirilgan 12 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 6-sinf Matematika 1-chorak 2-sinov Ismi familiyangizni kriting! 1 / 25 3 ta ketma-ket natural sonlarning ko`paytmasi quyidagi sonlarning qaysi biriga albatta bo`linadi ? A) 24 B) 6 C) 5 D) 12 2 / 25 9 ga bo`linadigan sonni toping. A) 6534 B) 1075 C) 2576 D) 2341 3 / 25 Ayirmani toping: A) 241/12 B) 483/24 C) 243/12 D) 121/12 4 / 25 Amallarni bajaring: 7758 : 18 + 720 : 8 A) 511 B) 510 C) 500 D) 521 5 / 25 Ikkinchi raqami 4 bo’lgan uch xonali son 9 ga va 2 ga bo’linadi, ammo 5 ga bo’linmaydi. Shu sonni toping? A) 144 B) 181 C) 243 D) 944 6 / 25 Ekub (21, 84) topilsin. A) 21 B) 3 C) 7 D) 14 7 / 25 kasrni qisqartiring. A) 1/2 B) 1/25 C) 5/29 D) 2/5 8 / 25 Gektarlarda ifodalang: 500 000 m2 A) 50 g B) 5 g C) 5000 g D) 500 g 9 / 25 Tub ko’paytuvchilarga ajrating. A) 5175 = 5 * 7 * 3 B) 5175 = 5 * 72 * 3 C) 5175 = 5² * 3² *23 D) To'g'ri javob yo'q 10 / 25 Tengsizlik nechta tub yechimga ega: 54 < x ≤ 79 A) 24 B) 25 C) 5 D) 6 11 / 25 Bir son ikkinchisidan 20 taga ko’p ularning yig’indisi 70 ga teng. Bu sonlarni toping? A) 30 va 40 B) 11 va 38 C) 25 va 45 D) 55 va 15 12 / 25 To’g’ri to’rtburchakning bo’yi 25 sm, eni esa 20 sm. Ularning perimetrini toping? A) 95 B) 100 C) 85 D) 90 13 / 25 Qaysi juftlik o`zaro tub sonlardan iborat ? A) (8; 10) B) ( 28; 24) C) (12; 15) D) (34; 45) 14 / 25 Ekuk (28, 70, 140) topilsin. A) 280 B) 130 C) 70 D) 140 15 / 25 Sonning bo’luvchilari nechta: 58 A) 4 B) 5 C) 2 D) 3 16 / 25 Yulduzcha o`rniga qanday raqam qo`yish mumkin: 196 = 2 · 2 · * · 7 A) 3 B) 13 C) 7 D) 11 17 / 25 Poezdda 936 yo’lovchi bor edi. Erkaklar ayollardan 7 marta, ayollar esa 5 marta ko’p. Poezdda qancha ayol bo’lgan? A) 240 B) 390 C) 360 D) 25 18 / 25 Kasrni airing: A) 1/2 B) 8/90 C) 18/60 D) 16/135 19 / 25 1; 2; 3; 15; 17; 21; 28; 47; 57; 89; 144; 300; 205 sonlari ichida nechta murakkab son bor ? A) 5 B) 8 C) 6 D) 7 20 / 25 30 soni nechta bo`luvchiga ega ? A) 4 B) 6 C) 8 D) 5 21 / 25 Tenglamani yeching: x : 20 = 10 A) 2000 B) 200 C) 20 D) 2 22 / 25 Tenglamani yechimini toping: A) 15 B) 16 C) 14 D) 13 23 / 25 Hisoblang: A) 4/20 B) 1/5 C) 1/2 D) 6/40 24 / 25 Ekub (215, 435, 600) topilsin A) 2 B) 3 C) 5 D) 0 25 / 25 Ekuk (106, 159, 530) topilsin. A) 3000 B) 3280 C) 150 D) 3180 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
8-sinf Matematika 4-chorak №2 May 17, 2021May 18, 2021 da chop etilgan InfoMaster tomonidan 8-sinf Matematika 4-chorak №2 ga 1 fikr bildirilgan 2 Yaratilgan sanasi May 18, 2021 tomonidan InfoMaster 8-sinf Matematika 4-chorak Ismi familiyangizni kriting! Ism 1 / 25 Viktor deb nimaga qaytiladi? A) Son qiymati va yo'nalishi bilan aniqlanadigan kattalikka B) Bunday tushuncha yo'q C) Faqat son qiymati bilan aniqlanadigan kattalikka D) Faqat yo'nalish qiymati bilan aniqlanadigan kattalikka 2 / 25 Kollinear vektorlar deb qanday vektorlarga aytiladi? A) Faqat son qiymati bilan aniqlanadigan kattalikka B) Parallel to'g'ri chiziqda yoki to'g'ri chiqiqda yotuvchi ikki vektorga C) Yig'indisi nolga teng bo'lgan vektorlarga D) Ko'paytmasi nolga teng bo'lgan vektorlarga 3 / 25 Tenglamani yeching A) x₁,₂=±8 B) x₁,₂=8 C) x₁,₂=√64 D) x₁,₂=-8 4 / 25 To'g'ri to'rtburchak bir tomoni 16 smga perimetri 70 smga teng ikkinchi tomonini toping. A) 35 B) 18 C) 20 D) 19 5 / 25 17 : 25 sonini 0,1 gacha aniqlikda o’nli kasr ko’rinishida tasvirlang: A) 0,7 B) 0,5 C) 0,8 D) 0,9 6 / 25 Teng yonli trapetsiyaning diagonallari o‘zaro perpendikular va balandligi 8 cm ga teng. Shu trapetsiyaning yuzini toping. A) 64 B) 55 C) 36 D) 45 7 / 25 Kvadrat tenglamani yeching A) x₁=1/3, x₂=1/4 B) x₁=-1/3, x₂=-1/4 C) x₁=0, x₂=-1 D) x₁=-1/3, x₂=1/4 8 / 25 Tenglmalar sistemasini yeching A) (1;4) va (4;1) B) x=1 , y=2 C) x=-2 , y=1 D) x=-4 , y=-1 9 / 25 Tenglamani yeching A) x₁,₂=±1 ,x₃,₄=±2 B) x₁,₂=±4 ,x₃,₄=1 C) x₁,₂=1 ,x₃,₄=±2 D) x₁,₂=±4 ,x₃,₄=-1 10 / 25 x ning qanday qiymatida funksiyaning qiymati 1 ga teng bo’ladi A) 16/10 B) 12/13 C) 17/8 D) 15/8 11 / 25 5 : 13 sonini 0,001 gacha aniqlikdagi o’nli kasr ko’rinishida tasvirlang: A) 0,853 B) 0,538 C) 0,385 D) 0,835 12 / 25 Ta'rifni to'ldiring. Ikala tamoni parallel, qolgan tamonlari parallel bo'lmagan to'rtburchak .... deb ataladi. A) kvadrat B) parallelogramm C) trapetsiya D) romb 13 / 25 Kvadrat tenglamani yeching A) x₁=2, x₂=5 B) ø C) x₁=-5, x₂=2 D) x₁=-2, x₂=5 14 / 25 Kvadrat tenglamani yeching =0 A) ø B) x₁=0, x₂=-2 C) x₁=-1, x₂=1 D) x₁=-6, x₂=-1 15 / 25 tengsizliklar sistemasining yechimi bo‘la olmaydigan sonni toping A) -12 B) -1 C) 10 D) 1 16 / 25 Kvadratning tomoni 1.2 dm bo'lsauning yuzini toping larda. A) 144 B) 2,44 C) 1,44 D) 14,2 17 / 25 Tengsizlikni yeching: 4(x-1)+5(x+1)<6(x+2)+7(x-1) A) x>1 B) x<-6 C) x>-1 D) x<-1 18 / 25 Tenglamani yeching: 2x+1=3 A) 1 B) 2 C) 0,5 D) 3 19 / 25 Ikki soning ayirmasi 3 ga, ularning ko`paytmasi 28 ga teng. Shu sonlarni toping A) 17 va 14 B) 7 va 4 C) 7 va 14 D) 5 va 2 20 / 25 Diagonallari 3,2 cm va 0,5 dm bo‘lgan rombning yuzini toping. larda. A) 0,8 B) 1,6 C) 0,5 D) 8 21 / 25 vektorning uzunligi 5 ga teng. m ni toping. A) 3 B) 4 C) 5 D) 2 22 / 25 Ta'rifni to'ldiring. Tamonlari teng bo'lgan parallelogramm .... deb ataladi. A) Trapetsiya B) Parallelogramm C) Romb D) Uchburchak 23 / 25 Yuzi 144 sm² , balandliklari 8 sm va 12 sm bo’lgan paraleligramning perimetrini toping. A) 56 sm B) 60 sm C) 46 sm D) 40 sm 24 / 25 Hisoblang: A) 3 B) 4 C) 16 D) -4 25 / 25 va berilgan bo'lsa vektorning kordinatalarini toping. A) 1;10 B) -1;10 C) 3;2 D) 3;10 0% Testni qayta ishga tushiring tomonidan Wordpress Quiz plugin Matematika choraklik
5-sinf Matematika 4-chorak May 10, 2021May 12, 2021 da chop etilgan InfoMaster tomonidan 5-sinf Matematika 4-chorak ga 1 fikr bildirilgan 2 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 5-sinf Matematika 4-chorak Testni Shirinboyev Temurbek tayyorladi! Ismi familiyangizni kriting! Ism 1 / 25 Kubning qirrasi 6 dm bo'lsa uning qirralari uzunliklari yig'indisini toping. A) 12 B) 72 C) 24 D) 36 2 / 25 Kubning qirrasi 5 dm bo'lsa uning sirtining yuzini toping. A) 125 B) 100 C) 60 D) 150 3 / 25 Noto’g’ri kasrni aralash songa aylantiring: A) 1,77/14 B) 5,7/14 C) 7,7/14 D) 2,6/14 4 / 25 Tenglamani yeching: 21 * x = 903 A) 36 B) 54 C) 43 D) 28 5 / 25 Kubning qirrasi 8 dm bo'lsa uning hajmini toping. A) 64 B) 256 C) 128 D) 512 6 / 25 Yig’indini songa bo’lish qoidasiga ko’ra ifodaning qiymatini toping: (34 + 51) : 17; A) 17 B) 16 C) 5 D) 12 7 / 25 Shunday son yozingki unda quyidagi xona birliklari bo’lsin. 8 ta ming, 3 ta yuz, 2 ta o’n, 7 ta bir A) 83207 B) 80032 C) 83007 D) 8327 8 / 25 Quyidagi o'nli kasrlarni taqqoslang. 0,76 va 0,8 A) Aniqlab bo'lmaydi. B) 0,76 = 0,8 C) 0,76 kichik 0,8 dan D) 0,76 katta 0,8 dan 9 / 25 Kubning hajmini 216 bo'lsa uning qirrasini toping. A) 4 B) 8 C) 5 D) 6 10 / 25 Amudaryoning uzunligi 2540 km . Sirdaryo unga qaraganda 479 km uzun. Sirdaryoning uzunligini toping. A) 2061 km B) 4765 km C) 18128 km D) 3019 km 11 / 25 Hadicha chork davomida matematikadan quyidagi baholarni oldi: 5, 5, 4, 5, 4, 5, 5, 4. Uning chorak bo’yicha o’ratacha bahosini toping va uni birlar xonasigacha yaxlidlang. A) 5 B) 6 C) 8 D) 12 12 / 25 400 ning 1% toping A) 400 B) 0,4 C) 4 D) 40 13 / 25 Hisoblang:4,387 : 100; A) 438700 B) 0,04387 C) 4387 D) 0,4387 14 / 25 Tenglamani yeching:3,08 : y = 4 A) 4,32 B) 0,48 C) 0,77 D) 12,32 15 / 25 Uchburchakning bitta burchagi 63o ,ikkinchi burchagi esa 42 o ga teng. Uning uchinchi burchagini toping. A) 60° B) 75° C) 180° D) 69° 16 / 25 ≤form≥ tegining name atributi qiymatining vazifasini toping. A) forma ma’lumotlarini jo‘natish usuli. B) formada har xil ko‘rinishdagi elementlarni hosil qiladi. C) Ikki tomoni cheksiz davom etadigan chiziq D) forma orqali jo‘natilayotgan ma’lumotlar qaysi sahifada qayta ishlanishi kerakligi beriladi. E) Ikki to`g`ri chiziqning kesishishidan hosil bo`lgan shakl F) formaga nom berish (bu nom skriptlar yozishda ishlatiladi) G) Tog`ri chiziqning bir tomoni chegaralangan H) Tog`ri chiziqning ikkala tomoni chegaralangan 17 / 25 ≤input type="checkbox" /≥ ushbu element qanday hollarda ishlatiladi. A) 740347 B) 740374 C) 74347 D) bir necha tanlovni amalga oshiruvchi bayroqchani hosil qiladi; E) bir necha tanlovdan faqat bittasini tanlash imkonini beradi; F) bir qatorli matn kiritish uchun ishlatiladi G) 704347 H) oddiy matnli element, asosan, parol yozish uchun ishlatiladi; 18 / 25 ≤form≥ tegining method atributi qiymatining vazifasini toping. A) forma orqali jo‘natilayotgan ma’lumotlar qaysi sahifada qayta ishlanishi kerakligi beriladi. B) sonli ifoda C) harfiy ifoda D) forma ma’lumotlarini jo‘natish usuli. E) a va b javoblar F) formaga nom berish (bu nom skriptlar yozishda ishlatiladi) G) formada har xil ko‘rinishdagi elementlarni hosil qiladi. H) qavsli misol 19 / 25 ≤table≥ tegining align="left" atributi qiymatining vazifasini toping. A) jadval foniga rang berish. B) jadvalni chap tomonga tekislash; C) jadvalni o‘ng tomonga tekislash. D) jadvalni markazga tekislash; 20 / 25 ≤table≥ tegining cellspacing atributi qiymatining vazifasini toping. A) jadvalning ramka qalinligi o‘rnatilgan bo‘lsa (border), jadval katagi bilan tashqi chegara ramkasi orasidagi masofani o‘rnatish. B) jadval balandligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin. C) jadval kengligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin. D) jadval chegarasidan yozuvgacha bo‘lgan masofani o‘rnatish (agar masofa o‘rnatilmasa, yozuv jadval chegarasiga yopishtirib yoziladi). 21 / 25 Yig’indining oxirgi raqamini toping A) 4 B) 2 C) 8 D) 3 22 / 25 Berilgan juftliklardan o'zaro tub sonlarni toping. A) (1001;469) B) (1167;2001) C) (80001;80002) D) (8001;2001) 23 / 25 Uchta natural bo’luvchiga ega dastlabki ikkita murakkab sonning yig’indisini toping. A) 15 B) 16 C) 13 D) 11 24 / 25 32 ni bo’lganda qoldiq 4 chiqadigan barcha natural sonlar yig’indisini toping? A) 49 B) 53 C) 52 D) 55 25 / 25 Quyidagi sonni 5 ga bo’lganda qanday qoldiq qoladi? A) 2 B) 3 C) 4 D) 1 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 4-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga 83 fikr bildirilgan 2 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin A) 21 B) 168 C) 84 D) 42 2 / 25 Agar f(x)=6+5tg22x bo’lsa, f '(π) ni toping A) 5 B) 3 C) 0 D) 1 3 / 25 Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 600 ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping A) 2√2 B) 4√2 C) 1 D) 2√3 4 / 25 Massasi 735 gr va konsentratsiyasi 16% bo’lgan yodning spirtdagi eritmasiga qancha toza spirt qo’shilsa, uning konsentratsiyasi 10% bo’ladi A) 256 B) 252 C) 441 D) 420 5 / 25 integralni hisoblang A) 5ln2e B) 5 C) 5ln3e³ D) 5ln4e 6 / 25 x=1, y=2x va y=2-x chiziqlari bilan chegaralangan sohaning yuzini toping A) log₄e B) ln4 C) log₃e D) ln3 7 / 25 Tandirdan olingan nonning temperaturasi 20 minut ichida 1000 dan 600 gacha pasayadi. Tashqi muhit temperaturasi 250. Nonning temperaturasi qancha vaqtda 300 gacha pasayadi? A) 51 B) 71 C) 41 D) 61 8 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 8100 C) 19600 D) 14400 9 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 8 B) 6 C) 6 D) 7 10 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 124 dm B) 135 dm² C) 124 dm² D) 224 dm² 11 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2300 B) 2330 C) 2025 D) 1023 12 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) √2 B) √22 C) 2 D) 1 13 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 75° B) 105° C) 125° D) 55° 14 / 25 cos150*cos450 *cos750 ni hisoblang A) √2/2 B) √8/2 C) √2 D) 2√2 15 / 25 sin3x+cos3x≥0 tengsizligini yeching A) [-π/9+2πn/3; 2π/9+2πn/3] B) (-π/2+n π;- π/2+n π) C) [-π/9+n π/3;2 π/9+n π/3] D) ø 16 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-3;6) C) (-4;-6;6) D) (-4;-3;9) 17 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0.5 B) 1.5 C) 0 D) 2 18 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 4 C) 3 D) 2 19 / 25 Limitni hisoblang: A) -3 B) 3 C) -4 D) 4 20 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 17 B) -17 C) 15 D) -13 21 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=2xsinx-x² C) y’=2xsinx+x²cosx D) y’=-2xsinx+x² 22 / 25 Nargiza 4minutda 260ta so`zni terib, 7ta imloviy xatoga yo`l qo`ydi. Nargizaning matn terish sifatini aniqlang A) 0,01 B) 0,0269 C) 0,5 D) 0,6 23 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=1/2 B) y=-x C) y=x D) y= 2x 24 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/31 B) 38/961 C) -38/961 D) 38/31 25 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (4;9;9) C) (-2;-5;-3) D) (2;5;3) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 3-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 3-chorak ga 8 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Funksiyaning statsionar nuqtalarini toping A) x=3, x=2 B) x=-1, x=2 C) x=-1, x=3 D) x=0, x=2 2 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²-3x-1 B) F(x)=x²+3x+1 C) F(x)=x²-3x+1 D) F(x)=x²+3x-1 3 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) -13 B) 15 C) 17 D) -17 4 / 25 limitni hisoblang A) 0 B) 6 C) 7 D) 5 5 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) 25 B) √26 C) √24 D) 16 6 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x C) y=35x+30 D) y=10x 7 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 17 B) 16 C) 14 D) 18 8 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-6;6) B) (-8;-3;6) C) (-4;-3;9) D) (-4;-3;6) 9 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/961 B) -38/961 C) -38/31 D) 38/31 10 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (4;9;9) B) (-2;-5;-3) C) (2;5;3) D) (4;9;9) 11 / 25 Funksiyaning kamayish oraliqlarini toping A) (-2;0) va (0;1) B) (-1;0) va (0;2) C) (-1;0) va (0;1) D) (-3;0) va (0;1) 12 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √19 B) √24 C) √66 D) √55 13 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=x²cosx-2xsinx B) y’=2xsinx+x²cosx C) y’=-2xsinx+x² D) y’=2xsinx-x² 14 / 25 sonini taqriban hisoblang. A) 3,08 B) 4,08 C) 5,01 D) 5,08 15 / 25 f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=2sin4x+c B) F(x)=-0,5cos2x+C C) F(x)=-2cos2x+C D) F(x)=0,5cos2x+C 16 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 6 B) 8 C) 6 D) 7 17 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 19600 B) 8100 C) 25600 D) 14400 18 / 25 chiziqlar bilan chegaralangan shaklning yuzini toping A) 0,5 B) √2 C) 1 D) 2 19 / 25 cos(2arctg(1/2)) ni hisoblang A) -37/35 B) -35/37 C) 37/35 D) 35/37 20 / 25 sin3x+cos3x≥0 tengsizligini yeching A) ø B) (-π/2+n π;- π/2+n π) C) [-π/9+n π/3;2 π/9+n π/3] D) [-π/9+2πn/3; 2π/9+2πn/3] 21 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 4 B) 8 C) 9 D) 16 22 / 25 aniq integralni hisoblang A) 2,5 B) 6 C) 2 D) 4 23 / 25 Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping A) 2 B) 3 C) 3√3 D) 2√3 24 / 25 tengsizlikning yechimi bo’lgan eng kichik natural sonni toping A) 3 B) 4 C) 5 D) 1 25 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 1 B) 3 C) 3√2 D) 4 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 2-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 2-chorak ga 16 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 2-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √55 B) √19 C) √66 D) √24 2 / 25 Funksiyaning kamayish oraliqlarini toping A) (-3;0) va (0;1) B) (-1;0) va (0;1) C) (-2;0) va (0;1) D) (-1;0) va (0;2) 3 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=2xsinx+x²cosx B) y’=x²cosx-2xsinx C) y’=-2xsinx+x² D) y’=2xsinx-x² 4 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-3;6) B) (-8;-3;6) C) (-4;-3;9) D) (-4;-6;6) 5 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,25 B) 0,15 C) 1,5 D) 0,5 6 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 2 C) 3 D) 4 7 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x B) 12x+14 C) 3x+1 D) 16x+14 8 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-2;-4;-1) B) (-1;-3;-1) C) (-1;-1;-1) D) (-1;-1;-4) 9 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²+3x+1 C) F(x)=x²-3x+1 D) F(x)=x²-3x-1 10 / 25 Funksiya hosilasini toping: f(x)=5 A) x B) 10 C) 5 D) 0 11 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y= 2x B) y=x C) y=1/2 D) y=-x 12 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=20x+20 B) y=35x+30 C) y=10x D) y=35x 13 / 25 Agar A(1;2;3), B(3;7;6) bo’lsa, A̅B̅ vector koordinatalarini toping A) (-2;-5;-3) B) (4;9;9) C) (4;9;9) D) (2;5;3) 14 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) -38/31 B) -38/961 C) 38/31 D) 38/961 15 / 25 Uchlari A(4;0;1), B(5;-2;1), C(4;8;5) nuqtalarda bo’lgan uchburchakning AL bissektrisasi uzunligini toping A) (4√2)3 B) (4√2)/5 C) 4 D) (2√5)/3 16 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) 13 B) 131 C) -4 D) -13 17 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 36 B) 12 C) -12 D) 0 18 / 25 limitni hisoblang A) 5 B) 0 C) 7 D) 6 19 / 25 A) 20 B) 13 C) 18 D) 14 20 / 25 Moddiy nuqta S(t)=5t3+3t2+2t+4 qonuniyat bilan harakatlanayotgan jismning t=2 sekunddagi tezligini toping. A) 74 B) 70 C) 84 D) 60 21 / 25 f(x)=(3x+2)2 funksiyasining barcha boshlang’ich funksiyalarini toping. A) F(x)=6x³+3x²-4 B) F(x)=6x³+6x+4 C) F(x)=6x³+3x²+4 D) F(x)=6x³+6x²+4 22 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;18 B) 4;10 C) 4;11 D) 8;10 23 / 25 Havo shariga t[0;10] minut oralig’ida V(t)=t3+13t2+t+20 (m3) havo purkamoqda. t=10 minutdagi havo hajmini toping. A) 2330 B) 2025 C) 1023 D) 2300 24 / 25 f(x)=excosx funksiyasi uchun f ’(π/2) ni aniqlang. A. e-0.5π B. e0,5π C. eπ D. e-π A) e^(-0.5π) B) e^(-π) C) e^(π) D) e^(0.5π) 25 / 25 Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping. A) 6 B) 7 C) 4 D) 5 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
11-sinf Matematika 1-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 1-chorak ga 8 fikr bildirilgan 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 11-sinf Matematika 1-chorak Testni Mamadoliyev Diyorbek tayyorladi. 1 / 25 funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing A) y=10x B) y=20x+20 C) y=35x+30 D) y=35x 2 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,0282 B) 0,623 C) 0,0321 D) 0,3265 3 / 25 Funksiya hosilasini toping: A) 21x²-10x B) 12x²-12 C) 14x+12 D) 12x+12 4 / 25 Moddiy nuqtaning berilgan t vaqtdagi tezligini hisoblang: , t=5 A) 80 B) 90 C) 70 D) 75 5 / 25 Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping. A) (-2;-4;-1) B) (-1;-1;-1) C) (-1;-3;-1) D) (-1;-1;-4) 6 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=x²cosx-2xsinx C) y’=2xsinx-x² D) y’=2xsinx+x²cosx 7 / 25 A(2;0;-3) va B(3;4;0) nuqtalar orasidagi masofani toping A) √26 B) 16 C) 25 D) √24 8 / 25 Karim uyida 14 bet matn terib, 8ta imloviy xatoga yo’l qo’ydi. Agar 1 betda o’rtacha 380 ta so’z bo’lsa, Karim 100ta so’z terganda o’rtacha qancha xato qiladi? A) 0,5 B) 0,15 C) 1,5 D) 0,25 9 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 2 B) 1 C) 3 D) 4 10 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-8;-3;6) B) (-4;-3;9) C) (-4;-3;6) D) (-4;-6;6) 11 / 25 Funksiya hosilasini toping f(x)=(2x+4)(3x+1) A) 12x+14 B) 16x+14 C) 3x+1 D) 12x 12 / 25 Agar f(x)=x² va bo`lsa ,f(g(2)) ni toping A) 36 B) 16 C) 0 D) 12 13 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x-2,25 B) y=3x-2,2 C) y=2x D) y=2x+3 14 / 25 limitni hisoblang A) 6 B) 5 C) 7 D) 0 15 / 25 Funksiya hosilasini toping: f(x)=5 A) 10 B) x C) 0 D) 5 16 / 25 funksiya hosilasining x0=-2 nuqtadagi qiymatini hisoblang. A) 38/961 B) -38/961 C) -38/31 D) 38/31 17 / 25 funksiyasining kamayish oralig’ini toping. A) [-1;-1/3] B) (-1/3;+∞) C) (-1;1/3) D) (-∞;-1) 18 / 25 Limitni hisoblang: A) -3 B) 4 C) 3 D) -4 19 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 15 B) 17 C) -13 D) -17 20 / 25 Agar f(x)=x² va bo`lsa ,f(g(-4)) ni toping A) 12 B) 0 C) -12 D) 36 21 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √19 C) √55 D) √66 22 / 25 A) 14 B) 18 C) 20 D) 13 23 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x-1 B) F(x)=x²-3x+1 C) F(x)=x²-3x-1 D) F(x)=x²+3x+1 24 / 25 funksiyaning [-4;2] oraliqdagi eng katta qiymatini toping A) 14 B) 18 C) 17 D) 16 25 / 25 tgx funksiya hosilasini toping A) 1/cos²x B) sinx C) cosx D) 1/sinx 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
5-sinf Matematika sinov test №1 Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 5-sinf Matematika sinov test №1 ga 1 fikr bildirilgan 3 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 5-sinf Matematika sinov test №1 Testni Raxmatullayev Feruz tayyorladi. 1 / 25 Yig’indining oxirgi raqamini toping. A) 3 B) 0 C) 1 D) 8 2 / 25 32 ni bo’lganda qoldiq 4 chiqadigan barcha natural sonlar yig’indisini toping? A) 55 B) 49 C) 52 D) 53 3 / 25 Quyidagi sonni 38 ga bo’lgandagi qoldiqni toping. A) 1 B) 7 C) 16 D) 32 4 / 25 Ko’paytmaning natural bo’luvchilari soni 75 ga teng bo’lsa, n ni toping. A) 11 B) 5 C) 6 D) 1 5 / 25 Quyidagi sonining oxirgi raqamini toping A) 6 B) 1 C) 5 D) 4 6 / 25 1591 va 1207 sonlarining EKUB va EKUK larini ko’paytmasini toping. A) 202057 B) 2798 C) 1920337 D) 191913 7 / 25 28900 sonining tub bo’luvchilari yig’indisini toping. A) 14 B) 19 C) 22 D) 24 8 / 25 202122232425…119120 ushbu son necha xonali son? A) 18 B) 100 C) 223 D) 20 9 / 25 80 va 60 sonlarining EKUBidan 15 ning natural bo’luvchilari sonini ayiring. A) 26 B) 16 C) 6 D) 14 10 / 25 2;0;1;4 raqamlardan foydalanib, eng kichik to’rt xonali son hosil qilindi. Hosil bo’lgan sonni 32 ga bo’lgandagi bo’linmani toping. A) 4 B) 32 C) 28 D) 0 11 / 25 1∙ 2 ∙ 3 ∙ ∙ 22 + 3 ∙ 7 ∙ 91 yig’indining oxirgi raqamini toping. A) 5 B) 1 C) 6 D) 4 12 / 25 Yig’indining oxirgi raqamini toping A) 8 B) 2 C) 4 D) 3 13 / 25 Hisoblang: A) -32 B) -243 C) 32 D) 243 14 / 25 Raqamlari yig’indisi 28 ga teng bo’lgan eng katta to’rt xonali son(turli raqamli)ning birlar xonasidagi raqamni toping. A) 7 B) 4 C) 5 D) 6 15 / 25 15 ∙ 8 ∙ 50 ∙ 27 ∙ 14 ∙ 125 ko’paytma nechta nol bilan tugaydi? A) 3 B) 6 C) 7 D) 5 16 / 25 Berilgan juftliklardan o'zaro tub sonlarni toping. A) (1001;469) B) (1167;2001) C) (8001;2001) D) (80001;80002) 17 / 25 Tub sonlar ichida 3 ga bo`linadiganlari nechta? A) cheksiz ko`p B) 2 ta C) 1 ta D) yo'q 18 / 25 30 gacha bo’lgan tub sonlar ko’paytmasining oxirgi raqamini toping. A) 7 B) 0 C) 5 D) 1 19 / 25 Quyidagilardan qaysi biri qoldiqli bo’lishni ifoda etmaydi? A) 65=4*17-3 B) 34=15*2+7 C) 41=6*6+5 D) 27=6*4+3 20 / 25 Quyidagi sonni 5 ga bo’lganda qanday qoldiq qoladi? A) 4 B) 2 C) 1 D) 3 21 / 25 EKUB(140;150;160)+EKUK(21;42;84)=? A) 116 B) 224 C) 52 D) 94 22 / 25 1* 2* 3*......74* 75 ko’paytma nechta nol bilan tugaydi? A) 17 B) 16 C) 18 D) 11 23 / 25 Quyidagi sonlardan qaysi biri 231 soniga qoldiqsiz bo’linadi ? A) 81 ∙ 54 ∙ 128 B) 28 ∙ 69 ∙ 132 C) 18 ∙ 72 ∙ 143 D) 56 ∙ 77 ∙ 104 24 / 25 Uchta natural bo’luvchiga ega dastlabki ikkita murakkab sonning yig’indisini toping. A) 16 B) 15 C) 13 D) 11 25 / 25 Quyidagi mulohazalarning qaysilari to’g’ri? 1) tub sonlar faqat toq sonlardan iborat; 2) 72 sonining tub bo’lmagan natural bo’luvchilari soni 10 ta; 3) har qanday natural sonning butun bo’luvchilari soni 0 ga teng; 4) agar ko’paytuvchilardan biri m soniga bo’linsa, u holda ko’paytma ham m songa bo’linadi; 5) Bir – tub son ham, murakkab son ham emas. A) 2; 4; 5 B) 1; 2; 3 C) 3; 4; 5 D) 1; 3; 4 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
10-sinf Matematika 4-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 10-sinf Matematika 4-chorak ga 10 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 10-sinf Matematika 4-chorak Testni Imomnazarov Ibrohim tayyorladi. 1 / 25 Kompleks sonlarni algebraik ko'rinishda yozing. Re(z)=-8, Im(z)=3 A) z=8+3i B) z=-8-√ 9i C) z=-8+√ 9i D) z=3+8i 2 / 25 Tenglamani yeching: A) -2 B) -1 C) 3 D) 4 3 / 25 Irratsional tenglamani yeching: A) 3 B) 1 C) 1/9 D) 2 4 / 25 z soniga qo‘shma bo‘lgan z̅ sonni toping. z=5−3i A) z=5−3i B) z=-5−3i C) z=5+3i D) z=-5+3i 5 / 25 Yig‘indini toping. 9i-(3-8i) A) -3+i B) -1-3i C) -i D) -3+17i 6 / 25 Hisoblang: A) 2 B) 10 C) 3 D) 6 7 / 25 Ko`paytmani toping. (-3+2i)(8+4i) A) -32+4i B) 6-4i C) -36+4i D) 18+28i 8 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) B∩C B) B' C) A∩B D) A∪B 9 / 25 p⇒q bu yerda « Zaruriy shart » qaysi ? A) q mulohaza p uchun zaruriy shart B) p mulohaza q uchun zaruriy shart C) bunday tushuncha yo’q D) to’g’ri javob yo’q 10 / 25 Quyidagi mulohazaning rostlik jadvalida nechta rost qatnashadi ? ¬(p∨q) A) 3 ta B) 2 ta C) 4 ta D) 1 ta 11 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) (A∪B∪C)' B) A∩B C) (A∪B)∪C D) A∪B∪C 12 / 25 x∈A kabi yozuvni o’qilishi to’g’ri ko’rsatilgan qatorni toping. A) x element A ga tegishli emas; B) x element A ga tegishli; C) bunday ifoda yo’q D) to’g’ri javob yo’q. 13 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) B B) A∩B C) A' D) A 14 / 25 Teng kuchli tenglamalarni ko‘rsating: A) 1 va 2; B) hammasi C) 1 va 3; D) 2 va 3; 15 / 25 Tenglamani yeching A) 1 B) 0 C) 3 D) 2,5 16 / 25 Tenglama ildizi 20dan qanchaga kam? A) 8 B) 7 C) 5 D) 6 17 / 25 Tenglama haqqiqiy ildizlari ko`paytmasini toping. A) -10 B) -32 C) -18 D) -25 18 / 25 Grafigikka qarab finksiyani toping. A) y=2cosx+1 B) y=sinx+1 C) y=cosx+1 D) y=cosx-1 19 / 25 Hisoblang: arctg1 A) π/6 B) -π C) π/3 D) π/4 20 / 25 Funksiyaning davrini aniqlang: y=sin5x/6 A) 432° B) 540° C) 180° D) 480° 21 / 25 Hisoblang: A) π/3 B) 5π/6 C) -π/6 D) π/6 22 / 25 Tengsizlikni yechimi quyidagi javoblarda qaysi biri? A) 4 B) 2 C) 3 D) 1 23 / 25 Hisoblang: A) 4π/3 B) π C) π/6 D) π/4 24 / 25 Hisoblang: arcsin 0 A) π/2 B) 0 C) 3π/2 D) π 25 / 25 Hisoblang: A) 6π/5 B) -π/6 C) π/3 D) 5π/6 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
10-sinf Matematika 3-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 10-sinf Matematika 3-chorak ga 7 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 10-sinf Matematika 3-chorak Testni Imomnazarov Ibrohim tayyorladi. 1 / 25 Hisoblang: A) π B) π/3 C) 2π/3 D) 5π/3 2 / 25 Funksiyaning davrini aniqlang: y=cos3x/4 A) 480° B) 60° C) 432° D) 180° 3 / 25 Grafigikka qarab finksiyani toping. A) y=cosx+1 B) y=cosx-1 C) y=sinx+1 D) y=2cosx+1 4 / 25 Funksiyaning davrini aniqlang: y=cos3x (gradusda) A) 240 B) 60 C) 120 D) 360 5 / 25 Hisoblang: arcsin 0 A) 0 B) 3π/2 C) π D) π/2 6 / 25 Hisoblang: A) π/6 B) -π/6 C) π/4 D) π/3 7 / 25 Hisoblang: arctg A) π/4 B) π/3 C) -π D) π/6 8 / 25 Hisoblang: A) π/6 B) -π/6 C) π/3 D) -π/4 9 / 25 Hisoblang: A) π/6 B) π/3 C) -π/6 D) 5π/6 10 / 25 Funksiyaning davrini aniqlang: y=cosx/3 (gradusda) A) 1200 B) 1080 C) 240 D) 120 11 / 25 Hisoblang: arctg1 A) -π B) π/4 C) π/3 D) π/6 12 / 25 Hisoblang: A) 2π/3 B) π/3 C) 3π/3 D) 5π/2 13 / 25 Tenglamani yeching A) 1 B) -1 C) 0 D) 2 14 / 25 Tenglamalar sistemasining nechta yechimi bor? A) 4 B) 1 C) 2 D) 3 15 / 25 Bikvadrat tenglamaning ildizlari yig‘indisini toping: A) 0 B) 1 C) -1 D) 11/3 16 / 25 Tenglama ildizi 5dan qancha kam A) 10 B) 0 C) 15 D) 5 17 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) A∩B B) (A∪B∪C)' C) (A∪B)∪C D) A∪B∪C 18 / 25 P mulohazaning inkori to’g’ri yozilgan qatorni toping. A) Øp B) ∩P C) ∪P D) ¬P 19 / 25 Quyidagilardan qaysi biri mulohaza bo’ladi? 1.Bugun yomg’ir yogadimi? 2.Uchburchakning beshta tamoni bor. 3.Sening yoshing nechada? 4.Bugun havo issiq. A) 2 va 4 B) Faqat 4 C) 1,2 va 3 D) 1 va 4 20 / 25 A={2,5,6,8,9,12}, B={3,6,9,12,15} to’plamlar uchun B∪A ni toping. A) B∪A={2,3,4,5,9,12} B) B∪A={2,6,9,12} C) B∪A={2,3,5,6,8,9,12,15} D) B∪A={1,2,3,4,5,6,7,8,9,10,11,12} 21 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) A B) A∩B C) A' D) B 22 / 25 p⇒q mulohazalarning konversiyasi qanday yoziladi ? A) TJY B) q ∪ p C) p ∪ q D) p⇒q 23 / 25 Ushbu ifoda qanday o’qiladi? A) A to’plamning elementlar soni 9 ta; B) A to’plamning elementlar soni 6 ta; C) A to’plam bo’sh to’plam; D) A to’plam cheksiz to’plam; 24 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) A∪B B) A' C) B' D) A 25 / 25 A to’plamning to’ldiruvchisi qanday belgilanadi? A) A'' B) A' C) A∩B D) A~B 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
10-sinf Matematika 2-chorak Aprel 17, 2021Aprel 17, 2021 da chop etilgan InfoMaster tomonidan 10-sinf Matematika 2-chorak ga 9 fikr bildirilgan 1 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 10-sinf Matematika 2-chorak Testni Imomnazarov Ibrohim tayyorladi. 1 / 25 Qaysidir davlat aholisi soni yiliga 3% kamaysa necha yildan so‘ng 20% kamayadi? A) 4 B) 2 C) 6 D) 8 2 / 25 Tenglamalar sistemasining nechta yechimi bor? A) 3 B) 4 C) 2 D) 1 3 / 25 Tenglamani katta ildizini toping: (x−5)(x+4)(x−11)=0 A) 5 B) -4 C) 16 D) 11 4 / 25 Tekislikda A(3;1) va B(7;3) nuqtalardan teng uzoqlikda joylashgan C(5;x) nuqtani toping. A) (5;3) B) (4;3) C) (5;2) D) (4;2) 5 / 25 Tenglamani yeching A) -1 B) 1 C) 0 D) 2 6 / 25 Tenglamani yeching: A) 4 B) 8 C) 2 D) 6 7 / 25 Tenglama ildizi 5dan qancha kam A) 15 B) 10 C) 0 D) 5 8 / 25 P mulohazaning inkori to’g’ri yozilgan qatorni toping. A) ∪P B) Øp C) ¬P D) ∩P 9 / 25 Diagrammadan foydalanib, quyidagi to‘plammi elementlari sonini toping: A∪¬B A) n(¬A∪B)=7 B) n(¬A∪B)=5 C) n(¬A∪B)=16 D) n(¬A∪B)=14 10 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) B' B) B∩C C) A∩B D) A∪B 11 / 25 U={x| 3 ≤x< 12, x∈N} , A={x| 5 A) 10 ta B) 9 ta C) 2 ta D) 3 ta 12 / 25 Odatda to’plamlar qaysi alifbo harflari bilan belgilanadi? A) Kril alifbo kichik harlari bilan B) Lotin alifbo bosh harlari bilan C) Lotin alifbo kichik harlari bilan D) Kril alifbo bosh harlari bilan 13 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) B∩C B) A∩B C) A∪B D) A∪B∪C 14 / 25 A={2,5,6,8,9,12}, B={3,6,9,12,15} to’plamlar uchun B∪A ni toping. A) B∪A={1,2,3,4,5,6,7,8,9,10,11,12} B) B∪A={2,3,5,6,8,9,12,15} C) B∪A={2,6,9,12} D) B∪A={2,3,4,5,9,12} 15 / 25 p⇒q bu yerda « Yetarli shart » qaysi ? A) p mulohaza q uchun yetarli shart B) q mulohaza p uchun yetarli shart C) to’g’ri javob yo’q D) bunday tushuncha yo’q 16 / 25 Quyidagilardan qaysi biri mulohaza bo’ladi? 1.Bugun yomg’ir yogadimi? 2.Uchburchakning beshta tamoni bor. 3.Sening yoshing nechada? 4.Bugun havo issiq. A) 1 va 4 B) 2 va 4 C) Faqat 4 D) 1,2 va 3 17 / 25 Diagrammadan foydalanib, quyidagi to‘plammi elementlari sonini toping: ¬A∩B A) n(¬A∩B)=14 B) n(¬A∩B)=16 C) n(¬A∩B)=5 D) n(¬A∩B)=7 18 / 25 To’plamlarni umumiy ko’rinishini toping. A) A = a B) A = {a,b,c,...} C) A = [a,b,c,...] D) A = (a,b,c,...) 19 / 25 A={a,b,c,d} ushbu to’plam nechta qisim to’plamga ega? A) 16 ta B) 5 ta C) 8 ta D) 4 ta 20 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) A' B) B' C) A∪B D) A 21 / 25 U=N, P={8 dan katta butun sonlar} bo’lsa n(P) ni toping. A) 15 ta B) 8 ta C) 7 ta D) Cheksiz ko’p 22 / 25 Ushbu ifoda qanday o’qiladi? A) A to’plamning elementlar soni 9 ta; B) A to’plamning elementlar soni 6 ta; C) A to’plam cheksiz to’plam; D) A to’plam bo’sh to’plam; 23 / 25 x∈A kabi yozuvni o’qilishi to’g’ri ko’rsatilgan qatorni toping. A) bunday ifoda yo’q B) x element A ga tegishli; C) x element A ga tegishli emas; D) to’g’ri javob yo’q. 24 / 25 Mulohaza deb nimaga aytiladi? A) Faqat rost darak gapga. B) So’roq gapga. C) Faqat yolg’on darak gapga. D) Rost yoki yolg’on bo’ladigan darak gapga. 25 / 25 To‘plamni tashkil etgan obyektlar uning ………..deyiladi. A) Xossasi B) Kesishmasi C) Elementlari D) Kattaligi 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
10-sinf Matematika 1-chorak Aprel 17, 2021Aprel 21, 2021 da chop etilgan InfoMaster tomonidan 10-sinf Matematika 1-chorak ga 10 fikr bildirilgan 0 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 10-sinf Matematika 1-chorak Testni Imomnazarov Ibrohim tayyorladi. 1 / 25 Quyidagi mulohazalar teng kuchlimi ? (p∨q) va ¬p∧¬q A) Mulohazalarning berilishi xato B) Teng kuchli C) Teng kuchli emas D) Tavtologiya 2 / 25 Har doim rost bo’ladigan mulohaza nima deyiladi ? A) Teng kuchli B) Dezyunksiya C) Konyuksiya D) Tavtologiya 3 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) A∪B B) A∩B C) A∪B∪C D) B∩C 4 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) (A∪B)∪C B) A∩B C) (A∪B∪C)' D) A∪B∪C 5 / 25 Ikkita to’plam teng bo’lishi uchun qanday xossaga ega bo’ishi kerak? A) Elementlar soni chesiz bo’lishi kerak. B) Ular har xil elementga ega bo’lishi kerak va A∪B, B∩A kabi belgilanadi. C) Ular bir xil elementga ega bo’lishi kerak va A⊆B, B⊆A kabi belgilanadi. D) Ikkita to’plam bir biriga teng bo’lmaydi. 6 / 25 A={a,b,c,d} ushbu to’plam nechta qisim to’plamga ega? A) 5 ta B) 4 ta C) 16 ta D) 8 ta 7 / 25 U=N, P={8 dan katta butun sonlar} bo’lsa n(P) ni toping. A) Cheksiz ko’p B) 7 ta C) 8 ta D) 15 ta 8 / 25 x∈A kabi yozuvni o’qilishi to’g’ri ko’rsatilgan qatorni toping. A) x element A ga tegishli; B) to’g’ri javob yo’q. C) bunday ifoda yo’q D) x element A ga tegishli emas; 9 / 25 U={x| 3 ≤x< 12, x∈N} , A={x| 5 A) 10 ta B) 2 ta C) 3 ta D) 9 ta 10 / 25 Quyidagi mulohazaning rostlik jadvalida nechta rost qatnashadi ? ¬(p∨q) A) 2 ta B) 3 ta C) 4 ta D) 1 ta 11 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) A∩B B) A' C) A D) B 12 / 25 Quyidagi mulohazaning rostlik jadvalida nechta rost qatnashadi ? ¬p∧q A) 3 ta B) 4 ta C) 2 ta D) 1 ta 13 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) B' B) A∩B C) A∪B D) B∩C 14 / 25 A,B,C to’plamlar Venn diagrammasida tasvirlangan, A∩B∩C to’plamlarni elementlarini toping. A) {b,i,l} B) {a,b,f,e,i,l} C) {a,b,c,d,h,j} D) {a} 15 / 25 To‘plamni tashkil etgan obyektlar uning ………..deyiladi. A) Kesishmasi B) Kattaligi C) Xossasi D) Elementlari 16 / 25 P mulohazaning inkori to’g’ri yozilgan qatorni toping. A) ∪P B) ¬P C) ∩P D) Øp 17 / 25 To’plamlarni umumiy ko’rinishini toping. A) A = {a,b,c,...} B) A = a C) A = (a,b,c,...) D) A = [a,b,c,...] 18 / 25 Ushbu ifoda qanday o’qiladi? A) A to’plamning elementlar soni 6 ta; B) A to’plam bo’sh to’plam; C) A to’plamning elementlar soni 9 ta; D) A to’plam cheksiz to’plam; 19 / 25 Diagrammadan foydalanib, quyidagi to‘plammi elementlari sonini toping: ¬A∩B A) n(¬A∩B)=16 B) n(¬A∩B)=5 C) n(¬A∩B)=14 D) n(¬A∩B)=7 20 / 25 A={2,5,6,8,9,12}, B={3,6,9,12,15} to’plamlar uchun B∪A ni toping. A) B∪A={2,3,5,6,8,9,12,15} B) B∪A={2,3,4,5,9,12} C) B∪A={1,2,3,4,5,6,7,8,9,10,11,12} D) B∪A={2,6,9,12} 21 / 25 Mulohaza deb nimaga aytiladi? A) Faqat yolg’on darak gapga. B) So’roq gapga. C) Rost yoki yolg’on bo’ladigan darak gapga. D) Faqat rost darak gapga. 22 / 25 Ushbu Venn diagrammasida bo’yalgan sohada qaysi to’plam keltirilgan? A) B' B) A∪B C) A' D) A 23 / 25 (p⇒q) ∧ (q⇒p) ko‘rinishdagi mulohaza p va q mulohazalarning ....deyiladi. A) Ekvivalensiyasi B) Konversiyasi C) Dezyunksiyasi D) Implikatsiyasi 24 / 25 p⇒q mulohazalarning konversiyasi qanday yoziladi ? A) q ∪ p B) p ∪ q C) TJY D) p⇒q 25 / 25 A to’plamning to’ldiruvchisi qanday belgilanadi? A) A' B) A~B C) A'' D) A∩B 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
9-sinf Matematika 4-chorak Aprel 15, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 9-sinf Matematika 4-chorak ga 3 fikr bildirilgan 2 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 9-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 tg60° ni toping A) 1 B) √2/2 C) √3 D) √2 2 / 25 Proporsiyaning noma’lum hadini toping A) 2 B) 7/11 C) 14/11 D) 1 3 / 25 Uchburchak medianalari uchun noto’g’ri tasdiqni ko’rsating A) Kesishish nuqtasida 2:1 nisbatda bo’linadi B) Har biri uchburchakni ikkita tengdosh qismga ajratadi C) Bir – biriga teng D) Bir nuqtada kesishadi 4 / 25 Sonlarni o’sish tartibida joylashtiring A) c>a>b B) a<b<c C) c<a<b D) b<a<c 5 / 25 Ifodani soddalashtiring: (13x2-8xy-y2 )+( -11x2 -9xy+y2) A) x² -xy B) 2x² C) 17xy D) 2x² -17xy 6 / 25 Amallarni bajaring: A) 213 B) 69 C) 60 D) 61 7 / 25 Kvadrat tengsizlikni yeching: x2 – 4x +6 > 0 A) (2; 3) B) (-∞;1) U (6; ∞) C) (-4; 6) D) to'g'ri javob yo`q 8 / 25 x = 41 qiymat qaysi tengsizlikning yechimi bo`ladi A) (x +1)(x + 42) < 0 B) (x-7)(x-2010) > 0 C) (x - 29)(x - 31) > 0 D) (x-30)(x-34) < 0 9 / 25 To`rtburchak shaklidagi paxta maydoni xaritada yuzi 12 sm2 bo`lgan to`rtburchak bilan tasvirlanadi. Agar xarita masshtabi 1: 5000 bo`lsa, maydonning haqiqiy yuzini toping A) 3 ga B) 2 ga C) 2,4 ga D) 0,6 ga 10 / 25 Kvadrat funksiyaning nollarini toping: y = x2 - 5x + 6 A) x₁= -2, x₂= -3 B) x₁=1, x₂=6 C) x₁= -1, x₂= - 6 D) x₁=2, x₂ =3 11 / 25 Tengsizlikni yeching: (x – 6)(x – 13) <0 A) (-13; -6) B) (-∞;6) U (13; ∞) C) (-∞;-13) U (6; ∞) D) (6;13) 12 / 25 Cheksiz kamayuvchi geometric progressiyada b1=1/4 , S=16 bo'lsa, q ni toping? A) 64/65 B) 1/4 C) 1/2 D) 63/64 E) 1/8 13 / 25 Ifodani soddalashtiring: A) ctgɑ*tgβ B) tgɑ*cosβ C) tgɑ*tgβ D) sinɑ*tgβ 14 / 25 Aylananing 90° li yoyi uzunligi 15π sm. Aylana radiusini toping A) 30 sm B) 40 sm C) 38 sm D) 42 sm 15 / 25 Arifmetik progressiyada = d=1,8 bo'lsa, qaysi nomerli haddan boshlab progressiyaning barcha hadlari musbat bo'ladi? A) 15 B) 18 C) 13 D) 12 16 / 25 8 ga bo’lganda 7 qoldiq beradign ketma-ketlikning 5-hadini belgilang? A) 63 B) 74 C) 55 D) 39 17 / 25 1002, 999, 996, progressiyaning nechanchi nomerli hadidan boshlab uning hadlari manfiy sonlar bo'ladi? A) 337 B) 334 C) 335 D) 336 18 / 25 Arifmetik progressiyada =44, =20 bo'lsa ni toping? A) 335 B) 502 C) 334 D) 495 19 / 25 Ifodaning qiymatini toping: A) 1/2 B) √3/3 C) √2/2 D) √3/2 20 / 25 Burchakning gradus o’lchovini toping: 3π/4 A) 150° B) 135° C) 35° D) 140° 21 / 25 Tomoni 7√2 sm va o‘tmas burchagi 135° bo‘lgan romb yuzini toping A) 50√3 sm² B) 49√3 sm² C) 64√2 sm² D) 49√2 sm² 22 / 25 Ifodani soddalashtiring A) 1 B) 1/sinɑ C) -1 D) 1/cosɑ 23 / 25 Hisoblang: tg1800° - sin495° + cos495° A) -1 B) 0 C) 1 D) 2 24 / 25 To’g’ri burchakli uchburchakning gipotenuzasi 18 sm va bir kateti 4 sm bo’lsa, uning ikkinchi katetini toping A) 340 B) 72 C) 320 D) 2√27 25 / 25 Funksiyalarning qaysi biri juft funksiya A) 1,2 B) 3,4 C) 2,3 D) 1,4 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
9-sinf Matematika 3-chorak Aprel 15, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 9-sinf Matematika 3-chorak ga 1 fikr bildirilgan 26 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 9-sinf Matematika 3-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Teng yonli trapetsiyaning ikkita burchagi ayirmasi 400 ga teng. uning burchaklarini toping A) 110°; 70°; 110°; 70° B) 115° ; 75° ; 115° ; 75° C) 135°; 45°; 135°; 45° D) 140°; 40°; 140°; 40° 2 / 25 Bo`yi 160 sm bo`lgan o`quvchi soyasining uzunligi 128 sm bo`lsa, bo`yi 210 sm bo`lgan basketbolchining soyasining uzunligini toping A) 178 sm B) 158 sm C) 168 sm D) 148 sm 3 / 25 Quyidagi tengsizliklardan qaysi biri kvadrat tengsizlik ekanini toping A) 2x³ + 3x²-4x +7 > 0 B) 4x -5 > 0 C) 41x² – 9x + 1 < 0 D) x⁴-4< 0 4 / 25 To`rtburchak shaklidagi paxta maydoni xaritada yuzi 12 sm2 bo`lgan to`rtburchak bilan tasvirlanadi. Agar xarita masshtabi 1: 5000 bo`lsa, maydonning haqiqiy yuzini toping A) 2,4 ga B) 3 ga C) 0,6 ga D) 2 ga 5 / 25 A(7;11), B(10; 7) bo`lsa, AB kesmaning uzunligini toping A) 5 B) 7 C) 35 D) 147 6 / 25 y = -2x2 +6 funksiyaning grafigi qaysi koordinata choraklarida joylashgan ? A) I, II, III, IV B) III, IV C) I, III, IV D) I, II 7 / 25 Quyidagi funksiyalardan qaysi biri kvadrat funksiya bo`ladi ? A) y = 5x⁴ + 6x B) y = 3x² + x³ – 8 C) y = 2x -3 D) y = 2010x² + 41x + 9 8 / 25 Berilgan uchburchak tomonlari 21 sm, 27 sm va 32 sm. Agar perimetri 120 sm bo`lgan uchburchak berilgan uchburchakka o`xshash bo`lsa, uning eng katta tomonini toping A) 40,5 sm B) 42 sm C) 48 sm D) 31,5 sm 9 / 25 Agar va 90°° bo’lsa, sina ni toping A) 14/13 B) 5/12 C) 12/13 D) 5/13 10 / 25 Proporsiyaning noma’lum hadini toping A) 7/11 B) 2 C) 14/11 D) 1 11 / 25 Parabola uchining koordinatalarini toping: y=x2+6x+5 A) (3;-4) B) (-3;-4) C) (3;4) D) (-3;4) 12 / 25 Amallarni bajaring: A) 69 B) 213 C) 61 D) 60 13 / 25 Tenglamaning musbat ildizini toping A) 32 B) 9 C) 64 D) 45 14 / 25 Hisoblang: A) 3,4 B) 2,4 C) 24 D) 5,76 15 / 25 Agar 90°° bo’lsa, quyidagilardan qaysi biri musbat A) sina B) tga C) ctga D) cosa 16 / 25 To’g’ri burchakli uchburchakning gipotenuzasi 18 sm va bir kateti 4 sm bo’lsa, uning ikkinchi katetini toping A) 340 B) 2√27 C) 72 D) 320 17 / 25 Tomonlari 3 va 5 bo‘lgan parallelogrammning bir diagonali 4 ga teng. Uning ikkinchi diagonalini toping A) √3 B) 2√13 C) √13 D) 2√3 18 / 25 Funksiyalarning qaysi biri juft funksiya A) 2,3 B) 1,2 C) 1,4 D) 3,4 19 / 25 Hisoblang: tg1800° - sin495° + cos495° A) 0 B) 2 C) -1 D) 1 20 / 25 Tenglamani yeching: cos(x-π )=0 A) πk B) 2πk C) 3π/2+2πk D) 3π/2 21 / 25 Tomoni 7√2 sm va o‘tmas burchagi 135° bo‘lgan romb yuzini toping A) 49√3 sm² B) 50√3 sm² C) 64√2 sm² D) 49√2 sm² 22 / 25 To‘g‘ri burchakli trapetsiyaning o‘tkir burchagi 30° ga, balandligi 4 sm ga va kichik asosi 6 sm ga teng. Trapetsiyaning yuzini toping A) 8√3 sm² B) (2+8√3) sm² C) 1 D) (24+8√3) sm² 23 / 25 Burchakning gradus o’lchovini toping: 3π/4 A) 135° B) 140° C) 150° D) 35° 24 / 25 Ko’paytmaning qaysi biri manfiy? A) sin100° * cos300° B) cos320° * ctg17° C) sin190° * tg200° D) tg190° * cos400° 25 / 25 Tenglamani yeching: sin(π -x)=1 A) 2πk B) π/2+2πk C) π/2 D) π/2-2πk 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik
9-sinf Matematika 2-chorak Aprel 15, 2021Aprel 15, 2021 da chop etilgan InfoMaster tomonidan 9-sinf Matematika 2-chorak ga 1 fikr bildirilgan 11 OMAD YOR BO'LSIN! Tomonidan yaratilgan InfoMaster 9-sinf Matematika 2-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Uchburchak medianalari uchun noto’g’ri tasdiqni ko’rsating A) Har biri uchburchakni ikkita tengdosh qismga ajratadi B) Kesishish nuqtasida 2:1 nisbatda bo’linadi C) Bir – biriga teng D) Bir nuqtada kesishadi 2 / 25 sin60° nimaga teng A) √3/2 B) √2/2 C) 1/2 D) 1 3 / 25 Sonlarni taqqoslang A) b=a B) b<a C) a = b + 0,5 D) b=a+0,8 4 / 25 Ifodaning qiymatini toping: (-8)2-(-5)3-(12) 2 A) 189 B) 122 C) 45 D) 48 5 / 25 Hisoblang A) 45 B) 53 C) 8 D) 2 6 / 25 x= -2 da y=2x2 +5x-3 funksiyaning qiymatini toping A) 5 B) -5 C) -4 D) 0,5 7 / 25 Ikkita gomotetik ko’pburchak uchun to’g’ri tasdiqni ko’rsating A) Ular o’xshash B) To’g’ri javob yo’q C) Ular tengdosh D) Ular teng 8 / 25 Hisoblang A) 7 B) -2 C) 6 D) 2 9 / 25 Hisoblang A) -2 B) 2 C) 9 D) 3 10 / 25 Agar va 90°° bo’lsa, sina ni toping A) 5/12 B) 5/13 C) 14/13 D) 12/13 11 / 25 Agar sina=3/5 va 90°° bo’lsa, сosa ni toping A) 4/5 B) 3/4 C) -3/4 D) -4/5 12 / 25 Proporsiyaning noma’lum hadini toping A) 14/11 B) 7/11 C) 1 D) 2 13 / 25 sina=1/2 bo’lgan o’tkir burchakni ko’rsating A) 90° B) 30° C) 60° D) 45° 14 / 25 Sonlarni o’sish tartibida joylashtiring A) c>a>b B) a<b<c C) c<a<b D) b<a<c 15 / 25 Bo`yi 160 sm bo`lgan o`quvchi soyasining uzunligi 128 sm bo`lsa, bo`yi 210 sm bo`lgan basketbolchining soyasining uzunligini toping A) 158 sm B) 178 sm C) 168 sm D) 148 sm 16 / 25 Kvadrat tengsizlikni yeching: 3x2 – 5x -2 > 0 A) (-∞; 1/3 ) U ( 2; ∞) B) (-∞; -1/3 ) U ( 2; ∞) C) (1/3 ; 2) D) (-1/3 ; 2) 17 / 25 A(7;11), B(10; 7) bo`lsa, AB kesmaning uzunligini toping A) 147 B) 5 C) 35 D) 7 18 / 25 AB va CD kesmalar O nuqtada kesishadi, AO = 12m, BO = 3 sm, CO = 28 sm, DO = 7 sm bo`lsa, AOC va BOD uchburchaklar yuzlari nisbatini toping A) 4 B) 16 C) 9 D) 12 19 / 25 x2 + 8x+15 ≤ 0 tengsizlikning butun yechimlari yig`indisini toping A) -12 B) 12 C) 23 D) -4 20 / 25 Berilgan uchburchak tomonlari 21 sm, 27 sm va 32 sm. Agar perimetri 120 sm bo`lgan uchburchak berilgan uchburchakka o`xshash bo`lsa, uning eng katta tomonini toping A) 48 sm B) 40,5 sm C) 42 sm D) 31,5 sm 21 / 25 y = x2 +x -6 funksiya x ning qanday qiymatlarida manfiy qiymatlar qabul qiladi A) (-3; 2) B) (-∞;1) U (6; ∞) C) (-∞;2) U (3; ∞) D) (2; 3) 22 / 25 Kvadrat tengsizlikni yeching: x2 – 4x +6 > 0 A) (-∞;1) U (6; ∞) B) to'g'ri javob yo`q C) (-4; 6) D) (2; 3) 23 / 25 y = 4x2 +12x +9 funksiyaning o`sish oralig`ini toping A) (-∞; -1,5) B) (1,5; ∞) C) (-1,5; ∞) D) (-∞; 1,5) 24 / 25 Tengsizlikni yeching: (x + 4)(x + 9) >0 A) (-∞;4) U (9; ∞) B) (-9; -4) C) (4; 9) D) (-∞; -9) U (-4; ∞) 25 / 25 Teng yonli trapetsiyaning ikkita burchagi ayirmasi 400 ga teng. uning burchaklarini toping A) 115° ; 75° ; 115° ; 75° B) 135°; 45°; 135°; 45° C) 110°; 70°; 110°; 70° D) 140°; 40°; 140°; 40° 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika choraklik