Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar va bo'lsa f(4) ning qiymatini toping. A) 35 B) 12 C) 4 D) 11 2 / 40 tengsizlikni yeching. A) 1 B) 3 C) 4 D) 2 3 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 30 B) 24 C) 18 D) 12 4 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) 1 B) √3 C) √2 D) 2 5 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) y=1-a B) x=-a C) y=-a D) x=a 6 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 32 B) 26 C) 27 D) 48 7 / 40 Hisoblang? A) 0,5 B) 0,25 C) 4 D) 2 8 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 36 B) 32 C) 40 D) 34 9 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b,d B) a,b C) b D) )a,b,d 10 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 35 C) 40 D) 20 11 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) R(√3-√2) B) √3R(2-√3) C) 1,5R D) 3R 12 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -4 B) 4 C) -√17 D) √17 13 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (9; 0), (2; 7) D) (2; 3) 14 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 45 D) 44 15 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 6 D) 4 16 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 24 C) 30 D) 28 17 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 2 C) 3 D) 4 18 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 13 C) 14 D) 15 19 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 7 D) 6 20 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 1 D) 2 21 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) DC < AD C) BC > AD D) AB = BC 22 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) 22 D) berilganlar yetarli emas 23 / 40 Hisoblang: A) cos10° B) cos50° C) sin10° D) 1 24 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 3√2 C) 6 D) 4√2 25 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 2√2 D) 3√2 26 / 40 bo‘lsa, A) 1 B) 2/3 C) 3/2 D) 2 27 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 20 C) 15 D) 10 28 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 5 yoki –15 C) 6 D) 3 yoki –8 29 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 3 C) 2 D) 4 30 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 11 D) 9 31 / 40 Tenglamani yeching: A) -6; 5 B) 6; -5 C) -6 D) 5 32 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 32 D) 42 33 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 3 D) 4 34 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 25 C) 96 D) 105 35 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 5 C) 3 D) -2 36 / 40 sonlarini taqqolsang. A) a B) b C) c D) c 37 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) Ø C) -π/4+πk, k∈Z D) π/4+πk, k∈Z 38 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) cd/b C) bd/c D) 1 39 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 10 C) 12 D) 8 40 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 116 C) 115 D) 112 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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