Matematika attestatsiya №5 Yanvar 24, 2022Yanvar 24, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №5 ga fikr bildirilmagan. 0% 2 ovozlar, 1 o'rtacha 13 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 To’g’ri turt burchakning bo’yining perimetriga nisbatini toping. A) 1/2 B) -452/18 C) 3/18 D) 5/3 2 / 40 ni hisoblang. A) e-1 B) (e+1)/2 C) e+1 D) (e-1)/2 3 / 40 bo‘lsa, ning qiymatini toping. A) 0,5 B) 1 C) 2 D) 0,7 4 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;-1)∪(-1;1)∪(1;√2] B) (-2√2;√2) C) [-√2;√2] D) [-√2;0)∪(0;√2] 5 / 40 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/4 B) 1/3 C) 1/5 D) 4 6 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 3 B) 0 C) 2 D) 1 7 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b,d B) b C) a,b D) )a,b,d 8 / 40 Hisoblang: A) 4 B) 3 C) 2 D) 1 9 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUK B) 1-EKUB 2-EKUB 3-EKUK C) 1-EKUB 2-EKUB 3-EKUB D) 1-EKUB 2-EKUK 3-EKUB 10 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 5 B) 4 C) 6 D) 2 11 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 138° B) 142° C) 132° D) 135° 12 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √2/8 B) 1/8 C) √3/8 D) √3/4 13 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -3 D) -4 14 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bd/c C) bc/d D) cd/b 15 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) Ø C) π/4+πk, k∈Z D) -π/4+πk, k∈Z 16 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 110 C) 116 D) 112 17 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 6 C) 10 D) 12 18 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 16(π-2) C) 8(π+2) D) 32 19 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 50° C) 30° D) 20° 20 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 24 C) 32 D) 28 21 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 32 C) 64 D) 48 22 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) √3tg50° tg70° C) 4 √3tg50° tg70° D) 2√3tg50° tg70° 23 / 40 √3 A) 7/3 B) 3/2 C) 21/10 D) 5/5 24 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 4 D) 2 25 / 40 Hisoblang: A) 0 B) -√3/2 C) -1/2 D) 1/32 26 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 3√2 D) 4√3 27 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 4 D) 1 28 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) BD = BC C) DC < AD D) AB = BC 29 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (7; 2), (28; -1) C) (9; 0), (2; 7) D) (9; 0), (28; -1) 30 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 8 D) 10 31 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,(04) C) 0,0(4) D) 0,04 32 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 5 C) 11 D) 6 33 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 3 yoki –8 C) 6 D) 5 yoki –15 34 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 11 D) 9 35 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√2 C) 3√2 D) 4√3 36 / 40 Hisoblang: A) 20/21 B) 9/10 C) 10/11 D) 19/20 37 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 14 D) 35 38 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) 5 D) -2 39 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 14 D) 15 40 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 6 D) 7 O'rtacha ball 74% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya