10-sinf Matematika olimpiada №4 Oktabr 18, 2022Oktabr 18, 2022 da chop etilgan InfoMaster tomonidan 10-sinf Matematika olimpiada №4 ga fikr bildirilmagan. 0 123456789101112131415161718192021222324252627282930 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 10-sinf Matematika olimpiada №4 2022-yil 12-oktabr: 2022-2023 o'quv yili tuman bosqichida tushgan savollar! 1 / 30 1. Uchinchi raqami to‘rtinchi raqamidan 1 ga kichik bo‘lgan to‘rt xonali sonlar sonini toping A) 900 B) 990 C) 720 D) 810 2 / 30 2. ? parametrning qanday musbat qiymatlarida ?² − (? + 3)? + 3? + 11 = 0 tenglamaning barcha ildizlari butun sonlardan iborat bo‘ladi? A) 3 B) 10 C) 16 D) 15 3 / 30 3. Soddalashtiring: A) a+b B) 2b C) a-b D) 2a 4 / 30 4. y = 4x² − 3x − 5 parabolaga x(0; 0) nuqtaga nisbatan simmetrik bo‘lgan parabola tenglamasini ko‘rsating. A) y= -4x² − 3x - 5 B) y= 4x² + 3x - 5 C) y=-4x² − 3x+ 5 D) y= 4x² − 3x + 5 5 / 30 5. Soddalashtiring: bunda, |?| < 3 A) 9 B) 1-2? C) 9-2? D) 2? − 9 6 / 30 6. Qavariq o‘n ikki burchakning diagonallar sonini toping. A) 48 B) 40 C) 36 D) 54 7 / 30 7. Tenglamani yeching: A) 15/17 B) 0 C) -1 D) 8/17 8 / 30 8. tenglamalar sistemasining yechimlari bo‘lsin. ayirmani toping. A) -4 B) -3 C) -5 D) 4 9 / 30 9. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 35 B) 4√21 C) 2√21 D) √21 10 / 30 10. ABCD qavariq to‘rtburchakka aylana ichki chizilgan. Agar АВ = 7, BC= 11 bo‘lsa, CD − AD ni toping. A) 3 B) 4 C) 2 D) 5 11 / 30 11. tenglama bilan berilgan aylananing markazi koordinata tekisligining qaysi choragida yotadi? A) IV B) II C) I D) III 12 / 30 12. Uchburchakning ikki tomoni 12 va 13 sm ga, ular orasidagi burchak kosinusi 5/13 ga teng bo`lsa, uning yuzini toping. A) 70 B) 72 C) 71 D) 60 13 / 30 13. Ikki son o’rtasidagi ∆ operatsiyasiga ko‘ra quyidagi natijalar olindi: 7 ∆ 1 operatsiya natijasini toping. A) 592 B) 86 C) 32 D) 125 14 / 30 14. Chizmada ABCD −parallelolgramm. DE ni ntoping. A) 9 B) 6 C) 4 D) 5 15 / 30 15. ?³?³ = 1024 tenglikni qanoatlantiruvchi nechta (?; b) butun sonlar juftligi mavjud? A) 5 B) 4 C) 2 D) 3 16 / 30 16. Supermarketda reklama aksiyasi o‘tkazilmoqda: 3 ta shokolad sotib olgan xaridorga 4-shokolad sovg‘a tariqasida qo‘shib beriladi. Bitta shokolad narxi 28000 so‘m. Xaridor 300 000 so‘m evaziga eng ko‘pi bilan nechta shokolad xarid qila oladi? A) 14 B) 11 C) 13 D) 12 17 / 30 17. bo’lsa, (2? − 3)² ifodaning qiymatini toping. A) 2 B) 5 C) 3 D) 6 18 / 30 18. f(x) = ax² + b funksiya grafigi A(-1;5) va B(2;-1) nuqtalardan o‘tadi. f(5 − f(1)) ning qiymatini toping. A) 6 B) 2 C) 5 D) 7 19 / 30 19. Agar ni toping. A) 8 B) 0.16 C) 4 D) 0.8 20 / 30 20. 1,2,3,4…..,2021,2022 sonlar orasidan nechtasi 3 ga ham, 7 ga ham bo‘linmaydi? A) 1098 B) 1156 C) 1084 D) 1128 21 / 30 21. tenglama nechta haqiqiy yechimga ega? A) 3 B) 1 C) 2 D) 4 22 / 30 22. Agar bo'lsa, ni toping. A) 3.5 B) 4 C) 4.5 D) 5 23 / 30 23. ∠BAD= ∠ABD= 20∘, ∠DBC= 110∘, ∠BCD= 30∘ va AB= 2, CD=? A) 2 B) 4 C) 1 D) 3 24 / 30 24. trigonometrik tenglamani yeching. A) π/12+2πk; k∈Z B) π/12+πk; k∈Z C) π/6+πk; k∈Z D) π/12+πk/2; k∈Z 25 / 30 25. ?1 va ?2 sonlari ?² − 7? − 1 = 0 tenglama ildizlari bo‘lsa, ?²1 + ?²2 ni toping. A) 53 B) 49 C) 4 D) 51 26 / 30 26. Chizmada AE = 2, BE= 6, DE= 3. Aylana diametrini toping. A) 36 B) √65 C) √25 D) 2√45 27 / 30 27. ?1 va ?2 sonlari ?² − 7? − 1 = 0 tenglama ildizlari bo‘lsa, ?²1 + ?²2 ni toping. A) 49 B) 4 C) 51 D) 53 28 / 30 28. bo‘lsa, f (5 − f (1− f (1− f (0)))) ni toping. A) 18 B) 19 C) 21 D) 20 29 / 30 29. Tenglamani yeching: A) 5 B) 3 C) 2 D) 4 30 / 30 30. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) -2 B) -1 C) 0 D) 1 0% Testni qayta ishga tushiring Author: InfoMaster Matematika olimpiada
