Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №2 Matematika olimpiadaTuman 2019-2020 o'quv yili 10-sinf Matematika olimpiada №2 InfoMaster Avgust 19, 2024 13 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 1 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №2 2019-yil tuman bosqichida tushgan savollar 1 / 25 1. Tenglama ildizlarining o‘rta arifmetik qiymatini toping: A) 1 B) 3 C) 5 D) 2 2 / 25 2. tenglama ildizlari yig‘indisini toping. A) 2 B) 3 C) 0 D) 1 3 / 25 3. Uchburchakning ikki tomoni 12 va 13 sm ga, ular orasidagi burchak kosinusi 5/13 ga teng bo`lsa, uning yuzini toping. A) 60 B) 72 C) 70 D) 71 4 / 25 4. ifodani soddalshtiring A) 2sinα B) cosα C) 2cosα D) 1 5 / 25 5. Tengsizlikni yeching: A) (2/3;2) B) (4/3;3) C) (1/2;∞) D) (5/3;2) 6 / 25 6. bo'lsa kasrning qiymatini hisoblang. A) √11-2 B) √11+1 C) 2-√11 D) √11-1 7 / 25 7. 7(kx−2)=7k+2(x−8) tenglama k ning qanday qiymatlarida ildizga ega bo`lmaydi? A) (−∞; 2/7) B) ∅ C) (2/7; ∞) D) k=2/7 8 / 25 8. Uchburchakning tomonlari 7 va 11 ga, uchinchi tomonining medianasi √21 ga teng. Uchburchakning uchunchi tomonini toping. A) 14 B) 16 C) 15 D) 12 9 / 25 9. Ta`lim muassasida barcha o`quvchilar kamida bitta ingliz yoki nemis tilida so`zlashа oladilar. Ayrimlari ikkala tilni ham biladilar. O`quvchilarning 85%i ingliz tilini, 75%i nemis tilini biladilar. Ikkala tilni ham biladigan o`quvchilar barcha o`quvchilarning necha % ini tashkil etadi. A) 60% B) 50% C) 65% D) 70% 10 / 25 10. Uchburchakning ikkita burchagi mos ravishda 38o va 52oga teng. Uchinchi burchagi uchidan tushirilgan bissektrisa va mediana orasidagi burchakni toping. A) 14° B) 10° C) 17° D) 7° 11 / 25 11. Tenglamaning ildizini nimchoragi nechaga teng ? A) 0,125 B) 0,25 C) 0,5 D) 20/69 12 / 25 12. Ko`paytmani hisoblang. cos12°cos24°cos36°cos48°cos60°cos72°cos84° A) 1/128 B) 1/32 C) 1/16 D) 1/64 13 / 25 13. trigonometrik tenglamani yeching. A) π/6+πk; k∈Z B) π/12+πk; k∈Z C) π/12+2πk; k∈Z D) π/12+πk/2; k∈Z 14 / 25 14. Funksiyaning aniqlanish sohasini toping. A) (3/4;7) B) (3/4;4) C) [3/4;7] D) (-∞;3/4)∪(4; 7] 15 / 25 15. [2x-1]=x tenglamani butun yechimlar sonini toping. Bu yerda [a]− a sonining butun qismi. A) 2 ta B) 3 ta C) 4 ta D) 1 ta 16 / 25 16. Agar f(x+1) =7+3x funksiya uchun f (a)=2 tenglik o`rinli bo`lsa, a ning qiymatini toping. A) -2/3 B) 8 C) 12 D) 10 17 / 25 17. f(x)=x²-4x va f(x)=-2x²+8x-p funksiyalar umumiy uchga ega bo`lsa, p ning qiymatini toping. A) 24 B) 12 C) 6 D) 18 18 / 25 18. Agar x²(a²+b²+9)+2(a+b+3)x+3=0 tenglama haqiqiy yechimga ega bo`lsa, a+b ni toping. A) 4 B) 2 C) 6 D) 3 19 / 25 19. Beshta a1, a2, a3, a4, a5 tub sonlar ayirmasi 6 ga teng bo`lgan arifmetik progressiyani tashkil qiladi. 2a2+a3 ni toping. A) 39 B) 43 C) 31 D) 40 20 / 25 20. Berilgan funksiyaga teskari funksiyani aniqlang. f(x)=x2f2(x)+f(x) A) I B) IV C) III D) II 21 / 25 21. Hisoblang: A) 1/4 B) -1/8 C) 1/8 D) -1/4 22 / 25 22. Agar f(g(x))=x²-6x+6 va f(x)=x−3 funksiyalar berilgan bo`lsa, g(x) funksiya ko`rinishini aniqlang. A) (x-3)² B) x²+12x+3 C) x²-12-3 D) (x+3)² 23 / 25 23. Korxona xom−ashyuo qimmatlashgani sababli maxsulot narxi 20% ga oshirildi, biroq mijojlar soni 20 % ga kamayib ketdi. Shunda korxona narxni qanchadir foizga kamaytirib mijozlari sonini 25% ga oshirishga erishdi. Shundan keyin korxona tushumi narx o`zgarmasdan oldingi tushumga qaraganda 8% ga oshgan bo`lsa, yangi narx necha foizga kamaytirilgan? A) 12 B) 10 C) 20 D) 4 24 / 25 24. 2x²-2ax+1=0 kvadrat tenglama ildizlari uchun tengliko`rinlibo`lsa, a ni toping. A) -3 B) 1 C) 7 D) -1 25 / 25 25. tengsizlik yechimi bo`la oladigan tub sonlar nechta? A) 5 B) 4 C) 2 D) 3 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz