Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №2 Matematika olimpiadaTuman 2019-2020 o'quv yili 10-sinf Matematika olimpiada №2 InfoMaster Avgust 19, 2024 36 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 1 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №2 2019-yil tuman bosqichida tushgan savollar 1 / 25 1. ko‘phadni standart ko‘rinishda ifodalangandagi koeffitsientlar yig‘indisini toping. 1. 2. 3. 4.1 A) 4 B) 3 C) 1 D) 2 2 / 25 2. Teng yonli uchburchakning asosi 12 sm, yon tomoni 18 sm. Yon tomonlariga bissektrisalar tushirilgan. Bissektrisalarning tomonlari bilan kesishgan nuqtalari orasidagoi masofani toping. A) 8,1 sm B) 7,2 sm C) 6,4 sm D) 5,6 sm 3 / 25 3. Agar f(x+1) =7+3x funksiya uchun f (a)=2 tenglik o`rinli bo`lsa, a ning qiymatini toping. A) 12 B) 8 C) -2/3 D) 10 4 / 25 4. Beshta a1, a2, a3, a4, a5 tub sonlar ayirmasi 6 ga teng bo`lgan arifmetik progressiyani tashkil qiladi. 2a2+a3 ni toping. A) 39 B) 40 C) 43 D) 31 5 / 25 5. Ko`paytmani hisoblang. cos12°cos24°cos36°cos48°cos60°cos72°cos84° A) 1/16 B) 1/64 C) 1/32 D) 1/128 6 / 25 6. Tenglamaning ildizini nimchoragi nechaga teng ? A) 20/69 B) 0,5 C) 0,125 D) 0,25 7 / 25 7. Agar x²(a²+b²+9)+2(a+b+3)x+3=0 tenglama haqiqiy yechimga ega bo`lsa, a+b ni toping. A) 4 B) 2 C) 3 D) 6 8 / 25 8. tengsizlik yechimi bo`la oladigan tub sonlar nechta? A) 5 B) 4 C) 2 D) 3 9 / 25 9. trigonometrik tenglamani yeching. A) π/12+πk/2; k∈Z B) π/12+2πk; k∈Z C) π/6+πk; k∈Z D) π/12+πk; k∈Z 10 / 25 10. Uchburchakning ikki tomoni 12 va 13 sm ga, ular orasidagi burchak kosinusi 5/13 ga teng bo`lsa, uning yuzini toping. A) 72 B) 70 C) 60 D) 71 11 / 25 11. 7(kx−2)=7k+2(x−8) tenglama k ning qanday qiymatlarida ildizga ega bo`lmaydi? A) (2/7; ∞) B) ∅ C) k=2/7 D) (−∞; 2/7) 12 / 25 12. 2x²-2ax+1=0 kvadrat tenglama ildizlari uchun tengliko`rinlibo`lsa, a ni toping. A) 1 B) -1 C) -3 D) 7 13 / 25 13. Tengsizlikni yeching: A) (5/3;2) B) (2/3;2) C) (1/2;∞) D) (4/3;3) 14 / 25 14. Hisoblang: A) -1/8 B) -1/4 C) 1/4 D) 1/8 15 / 25 15. bo'lsa kasrning qiymatini hisoblang. A) √11+1 B) 2-√11 C) √11-1 D) √11-2 16 / 25 16. Funksiyaning aniqlanish sohasini toping. A) (-∞;3/4)∪(4; 7] B) (3/4;7) C) [3/4;7] D) (3/4;4) 17 / 25 17. Ta`lim muassasida barcha o`quvchilar kamida bitta ingliz yoki nemis tilida so`zlashа oladilar. Ayrimlari ikkala tilni ham biladilar. O`quvchilarning 85%i ingliz tilini, 75%i nemis tilini biladilar. Ikkala tilni ham biladigan o`quvchilar barcha o`quvchilarning necha % ini tashkil etadi. A) 65% B) 70% C) 60% D) 50% 18 / 25 18. Uchburchakning ikkita burchagi mos ravishda 38o va 52oga teng. Uchinchi burchagi uchidan tushirilgan bissektrisa va mediana orasidagi burchakni toping. A) 7° B) 17° C) 14° D) 10° 19 / 25 19. Uchburchakning tomonlari 7 va 11 ga, uchinchi tomonining medianasi √21 ga teng. Uchburchakning uchunchi tomonini toping. A) 16 B) 15 C) 12 D) 14 20 / 25 20. [2x-1]=x tenglamani butun yechimlar sonini toping. Bu yerda [a]− a sonining butun qismi. A) 4 ta B) 2 ta C) 1 ta D) 3 ta 21 / 25 21. f(x)=x²-4x va f(x)=-2x²+8x-p funksiyalar umumiy uchga ega bo`lsa, p ning qiymatini toping. A) 18 B) 12 C) 6 D) 24 22 / 25 22. Agar f(g(x))=x²-6x+6 va f(x)=x−3 funksiyalar berilgan bo`lsa, g(x) funksiya ko`rinishini aniqlang. A) x²-12-3 B) x²+12x+3 C) (x-3)² D) (x+3)² 23 / 25 23. Korxona xom−ashyuo qimmatlashgani sababli maxsulot narxi 20% ga oshirildi, biroq mijojlar soni 20 % ga kamayib ketdi. Shunda korxona narxni qanchadir foizga kamaytirib mijozlari sonini 25% ga oshirishga erishdi. Shundan keyin korxona tushumi narx o`zgarmasdan oldingi tushumga qaraganda 8% ga oshgan bo`lsa, yangi narx necha foizga kamaytirilgan? A) 4 B) 20 C) 12 D) 10 24 / 25 24. ifodani soddalshtiring A) 1 B) cosα C) 2cosα D) 2sinα 25 / 25 25. Berilgan funksiyaga teskari funksiyani aniqlang. f(x)=x2f2(x)+f(x) A) II B) IV C) III D) I 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz