Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №2 Matematika olimpiadaTuman 2019-2020 o'quv yili 10-sinf Matematika olimpiada №2 InfoMaster Avgust 19, 2024 6 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 1 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №2 2019-yil tuman bosqichida tushgan savollar 1 / 25 1. ko‘phadning bir ko‘paytuvchisi x+1 bo‘lsa, m ni toping. A) 4 B) 1 C) 3 D) 2 2 / 25 2. ko‘phadni standart ko‘rinishda ifodalangandagi koeffitsientlar yig‘indisini toping. 1. 2. 3. 4.1 A) 1 B) 4 C) 3 D) 2 3 / 25 3. Ta`lim muassasida barcha o`quvchilar kamida bitta ingliz yoki nemis tilida so`zlashа oladilar. Ayrimlari ikkala tilni ham biladilar. O`quvchilarning 85%i ingliz tilini, 75%i nemis tilini biladilar. Ikkala tilni ham biladigan o`quvchilar barcha o`quvchilarning necha % ini tashkil etadi. A) 60% B) 65% C) 70% D) 50% 4 / 25 4. tengsizlik yechimi bo`la oladigan tub sonlar nechta? A) 4 B) 3 C) 2 D) 5 5 / 25 5. Funksiyaning aniqlanish sohasini toping. A) (3/4;7) B) (-∞;3/4)∪(4; 7] C) [3/4;7] D) (3/4;4) 6 / 25 6. Agar f(x+1) =7+3x funksiya uchun f (a)=2 tenglik o`rinli bo`lsa, a ning qiymatini toping. A) 12 B) 8 C) -2/3 D) 10 7 / 25 7. Uchburchakning ikki tomoni 12 va 13 sm ga, ular orasidagi burchak kosinusi 5/13 ga teng bo`lsa, uning yuzini toping. A) 72 B) 70 C) 71 D) 60 8 / 25 8. Tenglamaning ildizini nimchoragi nechaga teng ? A) 20/69 B) 0,125 C) 0,25 D) 0,5 9 / 25 9. Uchburchakning tomonlari 7 va 11 ga, uchinchi tomonining medianasi √21 ga teng. Uchburchakning uchunchi tomonini toping. A) 12 B) 16 C) 15 D) 14 10 / 25 10. Korxona xom−ashyuo qimmatlashgani sababli maxsulot narxi 20% ga oshirildi, biroq mijojlar soni 20 % ga kamayib ketdi. Shunda korxona narxni qanchadir foizga kamaytirib mijozlari sonini 25% ga oshirishga erishdi. Shundan keyin korxona tushumi narx o`zgarmasdan oldingi tushumga qaraganda 8% ga oshgan bo`lsa, yangi narx necha foizga kamaytirilgan? A) 12 B) 20 C) 10 D) 4 11 / 25 11. Tengsizlikni yeching: A) (4/3;3) B) (5/3;2) C) (2/3;2) D) (1/2;∞) 12 / 25 12. Agar f(g(x))=x²-6x+6 va f(x)=x−3 funksiyalar berilgan bo`lsa, g(x) funksiya ko`rinishini aniqlang. A) (x+3)² B) (x-3)² C) x²+12x+3 D) x²-12-3 13 / 25 13. Berilgan funksiyaga teskari funksiyani aniqlang. f(x)=x2f2(x)+f(x) A) IV B) II C) III D) I 14 / 25 14. ifodani soddalshtiring A) 2cosα B) 2sinα C) 1 D) cosα 15 / 25 15. f(x)=x²-4x va f(x)=-2x²+8x-p funksiyalar umumiy uchga ega bo`lsa, p ning qiymatini toping. A) 18 B) 6 C) 24 D) 12 16 / 25 16. [2x-1]=x tenglamani butun yechimlar sonini toping. Bu yerda [a]− a sonining butun qismi. A) 2 ta B) 3 ta C) 4 ta D) 1 ta 17 / 25 17. Uchburchakning ikkita burchagi mos ravishda 38o va 52oga teng. Uchinchi burchagi uchidan tushirilgan bissektrisa va mediana orasidagi burchakni toping. A) 10° B) 7° C) 17° D) 14° 18 / 25 18. Ko`paytmani hisoblang. cos12°cos24°cos36°cos48°cos60°cos72°cos84° A) 1/16 B) 1/64 C) 1/32 D) 1/128 19 / 25 19. Agar x²(a²+b²+9)+2(a+b+3)x+3=0 tenglama haqiqiy yechimga ega bo`lsa, a+b ni toping. A) 6 B) 3 C) 4 D) 2 20 / 25 20. Hisoblang: A) -1/8 B) 1/4 C) -1/4 D) 1/8 21 / 25 21. trigonometrik tenglamani yeching. A) π/6+πk; k∈Z B) π/12+πk/2; k∈Z C) π/12+2πk; k∈Z D) π/12+πk; k∈Z 22 / 25 22. 7(kx−2)=7k+2(x−8) tenglama k ning qanday qiymatlarida ildizga ega bo`lmaydi? A) (−∞; 2/7) B) k=2/7 C) ∅ D) (2/7; ∞) 23 / 25 23. Beshta a1, a2, a3, a4, a5 tub sonlar ayirmasi 6 ga teng bo`lgan arifmetik progressiyani tashkil qiladi. 2a2+a3 ni toping. A) 43 B) 31 C) 39 D) 40 24 / 25 24. bo'lsa kasrning qiymatini hisoblang. A) √11-1 B) 2-√11 C) √11-2 D) √11+1 25 / 25 25. 2x²-2ax+1=0 kvadrat tenglama ildizlari uchun tengliko`rinlibo`lsa, a ni toping. A) -1 B) 7 C) 1 D) -3 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
