Uy » Online olimpiada » Matematika olimpiada » 9-sinf Matematika olimpiada №2 Matematika olimpiadaTuman 2019-2020 o'quv yili 9-sinf Matematika olimpiada №2 InfoMaster Avgust 19, 2024 341 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 9-sinf Matematika olimpiada №2 2019-yil tuman bosqichida tushgan savollar 1 / 25 1. Rombning diagonallari 6 va 8 ga teng bo‘lsa, uning tomonini toping. A) 6 B) 5 C) 8 D) 3 2 / 25 2. Uchburchakning perimetri 24 sm ga teng bo‘lib, uning tomonlari uzunliklari arifmetik progressiya tashkil etadi. Shu uchburchakning kichik tomoni 6 sm bo‘lsa, uchburchak turini aniqlang. A) O’tkir burchakli B) O’tmas burchakli C) Bunday uchburchak yo’q D) To‘g‘ri burchakli 3 / 25 3. Agar bo‘lsa, ni hisoblang. A) 3 B) 4 C) -4 D) ±4 4 / 25 4. Agar cheksiz kamayuvchi geometrik progressiyaning hadlari yig`indisi ga teng bo`lsa, uning hadlari kublari yig`indisining hadlari kvadratlari yig`indisiga nisbatini toping. A) 3 B) 1 C) 2 D) 4 5 / 25 5. Tenglamalar sistemasi nechta yechimga ega? A) 4 B) 6 C) 1 D) 2 6 / 25 6. Agar bo’lsa , x va y sonlarning ko’paytmasini toping. A) -4 B) -2 C) 6 D) 8 7 / 25 7. x0 soni tenglamani ildizi bo`lsa, x²0 -64 ni toping. A) 20/69 B) 8 C) -48 D) 0 8 / 25 8. ax²+bc+c=0 kvadrat tenglama bitta manfiy, bitta musbat ildizga ega bo`lsa, quyidagilardan qaysibiri to`g`ri?(D=b2−4ac) A) 4 B) 2 C) 1 D) 3 9 / 25 9. ABCD trapetsiyaning yuzi 36 gateng, asoslari DC=6, AB=2. BC tomonidan E nuqta olingan bo’lib, BE=2EC bo’lsa, ADE uchbutchakning yuzini toping. A) 21 B) 14 C) 12 D) 16 10 / 25 10. ABC uchburchakning AB tomonidan M va N nuqtalar shunday tanlab olinganki, BN=NM=MA. AC tomonidan K va L nuqtalar shunday tanlab olindiki AK=3KL=1,5LC bo'ldi. SMNLK: SMNLK=? A) 1 B) 3 C) 0,5 D) 2 11 / 25 11. Sonlarni o`sish tartibida yozing. A) a B) c C) c D) b 12 / 25 12. Funksiya berilgan. f(f(−1)) ni toping. A) 18 B) 5 C) 15 D) 29 13 / 25 13. Agar sin x + cos x = 1,04 tenglik o’rinli bo’lsa, x qaysi chorakda joylashgan? A) II B) III C) I D) IV 14 / 25 14. Bahodir o`zidagi 411 dona yong`oqni 4 ta bolaga bo`lib berdi. Agar Sanjar va O`ktamning olgan yong`oqlari soni 2 va 3 sonlariga to`g`ri proporsional ,O`ktam va Sohibning yong`oqlari 7 va 5 sonlariga teskari proporsional , Sanjar va G`anisherning yong`oqlari esa 9 va 4 sonlariga teskari proporsional ekanligi ma`lum bo`lsa, G`anisher nechta yong`oq olgan? A) 126 B) 135 C) 145 D) 180 15 / 25 15. tengsizlikni yeching. A) (-∞;3)∪(3;∞) B) (-∞;-1/2)∪(-1/2;3)∪(3;∞) C) (-∞;-1/2)∪(-1/2;∞) D) xℇR 16 / 25 16. Agar f(x) = (a + b − 4)x3+ 2x2+ (b − 3)x +6 juftfunksiyaberilganbo’lsa, f(b) ningqiymatini toping. A) 27 B) 7 C) 20 D) 24 17 / 25 17. 20 dan 250 gacha sonlarichida 4 ga bo`linadigan, lekin 6 ga bo`linmaydigan nechta natural son bor? A) 30 B) 33 C) 48 D) 39 18 / 25 18. Muntazam uchburchakning ichidagi nuqtadan tomonlarigacha bo`lgan masofalar yig`indisi 6 ga teng bo`lsa, uchburchak yuzini toping. A) 55 B) 99 C) 12√3 D) 84 19 / 25 19. Agar arifmetik progressiyada bo`lsa, ayirmani toping. A) 1 B) 2 C) 4 D) 3 20 / 25 20. (a2- 9)x = a2+ 2a - 3 tenglama a ningqandayqiymatidacheksizko’pyechimgaega? A) a ≠1 B) a = 1 C) a=−3 D) a=2 ; a = -3 21 / 25 21. ABC uchburchakda O nuqta AD medianava BE bissektrisalar kesishishnuqtasi. AOEva BOD uchburchaklar yuzlari mos ravishda 1 va 3 ga teng bo`lsa, EOC uchburchakning yuzini toping. A) 2 B) 4 C) 3 D) 5 22 / 25 22. Agar a-b =|x| + 3 bo’lsa a va b lar uchun to’g’ri munosabatni aniqlang. A) a=b+1 B) a C) a>b D) a ≤ b 23 / 25 23. Hisoblang: cos 10o − 2 cos 50o − cos 70o A) –sin40° B) –cos40° C) sin40° D) cos40° 24 / 25 24. To’g’riburchakli uchburchakning o’tkir burchaklaridan chiquvchi medianalar √156 va √89 ga teng bo’lsa, uchburchak gipotenuzasini toping. A) 13 B) 12 C) 15 D) 14 25 / 25 25. ?, ? natural sonlari uchun 3? + 2? soni 11 ga qoldiqsiz bo‘linadi. u holda quyidagi sonlardan qaysi biri 11 ga qoldiqsiz bo’linmasligi mumkin? A) 47? + 34? B) 8(10? + 3?) C) 14? + 13b D) 58? + 90? 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
