7-sinf Matematika olimpiada №1 Aprel 29, 2022Aprel 29, 2022 da chop etilgan InfoMaster tomonidan 7-sinf Matematika olimpiada №1 ga 1 fikr bildirilgan 38 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 7-sinflar Matematika olimpiada №1 2019-yil bilimlar bellashuvida tushgan savollar Ismi familiyangizni kriting! Iltimos ma'lumotlaringizni to'g'ri kritishga e'tibor bering! 1 / 25 1. Sonni standart ko`rinishda yozing: 1247800000 A) IV B) II C) I D) III 2 / 25 2. To`g`ri burchakli parallelepipedning asosi tomoni c sm ga teng bo`lgan kvadratdan iborat bo`lib,balandligi d Bu parallelepipeddan qirrasi c sm bo`lgan kub qirqib olindi. Qolgan qismining hajmi V (sm3)ni hisoblash formulasini tuzing. Agar c=2,5 sm, d=4 sm bo`lsa, V ni toping. A) 9 B) 75/8 C) 81/8 D) 1/8 3 / 25 3. Qo`shni burchaklar 1450 va 350 ga teng. Bu qo`shni burchaklar bissektrisalari tashkil qilgan burchakni toping. A) 70° B) 86° C) 90° D) 80° 4 / 25 4. Ifodani soddalashtiring: A) 15x⁵y¹⁰ B) 15x⁵y⁶ C) 15x⁷y¹⁰ D) 15x⁶y¹⁰ 5 / 25 5. Ikkita parallel to`g`ri chiziqlarni to`g`ri chiziq bilan kesishishidan hosil bo`lgan mos burchaklarning yig`indisi 2100 ga teng.Bu burchaklarni toping. A) 110°; 100° B) 105°; 105° C) 115°; 95° D) 80°; 130° 6 / 25 6. Bir ishni 10 kishi 8 kunda bajara oladi. 2 kundan so`ng, uchinchi kuni ularga yordam berish uchun bir necha kishi qo`shildi va qolgan ishni 4 kunda bajarishdi. Necha kishi kelib qo`shilgan? A) 5 B) 4 C) 6 D) 3 7 / 25 7. 1, 2, 3, 4, 5, 6 va 7 raqamlaridan, ularni takrorlamasdan nechta 4 xonali son tuzish mumkin? A) 36 ta B) 35 ta C) 34 ta D) 33 ta 8 / 25 8. To`g`ri burchakli uchburchakning gipotenuzasiga tushirilgan medianasi 8 sm. Uchburchakning burchaklaridan biri 600 bo`lsa, bu burchakka yopishgan tomonlarini toping (sm). A) 9 B) 8 C) 7 D) 5 9 / 25 9. Ifodani ko`paytuvchilarga ajrating: 9b²-(a-3b)² A) a² B) (6b-a)a C) 18b²-a²+6ab D) (6b-a)(6b+a) 10 / 25 10. Telefon stansiyasi mijozlarining uy telefon raqamlari 7 xonali sonlardan iborat va 573 sonidan boshlanadi. Shu stansiya nechta mijozga xizmat ko`rsatishi mumkin? A) 10000 B) 30000 C) 15000 D) 1000 11 / 25 11. M ni shunday birhad bilan almashtiringki, natijada noma’lumning barcha qiymatlarida to`g`ri tenglik hosil bo`lsin: A) III B) I C) IV D) II 12 / 25 12. Asosi BC bo`lgan teng yonli ABC uchburchakning perimetri 40 sm va teng tomonli BCD uchburchakning perimetri 45 sm ga teng. AB va BC tomonlarni toping. A) AB =12 sm; BC =16 sm; B) AB =15 sm; BC =12,5 sm; C) AB =12,5 sm; BC =15 sm; D) AB =16 sm; BC =12 sm; 13 / 25 13. ABC uchburchakning AD medianasi BC tomondan keyin DE= AD bo`lgan kesmaga davom ettirilib, E nuqta B nuqta bilan tutashtirildi.Agar ∠ACD=450, ∠ABD=350 bo`lsa, ∠ABE ni toping. A) 70° B) 75° C) 80° D) 10° 14 / 25 14. Tenglamaning ildizi x0 bo’lsa, 18:x0 ifodaning son qiymatini toping. A) 6 B) -7 C) 7 D) 78/7 15 / 25 15. Tenglamani yeching. 4,5-1,6∙(5x-3)=1,2∙(4x-1)-15,1 A) 0 B) 3 C) 1 D) 2 16 / 25 16. Uchburchakning ikkita uchidagi tashqi burchaklari o`zaro teng va perimetri 74 sm, uning bir tomoni 16 sm ga teng. Ikkita qolgan tomonlarini toping. A) 29, 29 B) 31, 29 C) 27, 32 D) 29, 30 17 / 25 17. Ifodani soddalashtiring: 125a³-225a² b+135ab²-27b³ A) (3a-5b)³ B) (5a)³-(3b)³ C) (3a+5b)³ D) (5a-3b)³ 18 / 25 18. Umumiy AB asosga ega bo`lgan ACB va ADB uchburchaklar berilgan. CD va AB lar O nuqtada kesishadi. Agar ∠DAB= ∠CBA, ∠CAB= ∠DBA, DB=24 sm bo`lsa, CA ni toping. A) 30 sm B) 24 sm C) 48 sm D) 12 sm 19 / 25 19. O’lchovlari 8 va 20 ga teng bo’lgan to’g’ri to’rt burchaklardan eng kamida nechtasini birlashtirib, kvadrat hosil qilish mumkin? A) 11 B) 9 C) 15 D) 10 20 / 25 20. Agar qo`shni burchaklardan biri ikkinchisidan 450 katta bo`lsa,ularni toping . A) 111°30'; 68°30' B) 112°30'; 67°30' C) 135°;45° D) 113°;67° 21 / 25 21. A, B va C nuqtalar bir to`g`ri chiziqda yotadi. Agar AB=14 sm, BC=16,5 sm bo`lsa, AC ni toping. A) 3,5 sm va 29,5 sm B) 2,5 sm va 30,5 sm C) 2,5 sm D) 30,5 sm 22 / 25 22. Soddalashtiring: 5b-(6b-a)-(a-6b) A) 17b-2a B) 5b+2a C) 5b D) 5b-2a 23 / 25 23. Hisoblang: A) II B) IV C) III D) I 24 / 25 24. Ko’paytuvchilarga ajrating: x⁴+x²+1 A) III B) IV C) II D) I 25 / 25 25. Gazlamaning narxi 20 Ma’lum vaqtdan so’ng, yangi narx ham 25 ortdi. Gazlamaning narxi jami necha foiz ortdi? A) 55 % B) 60 % C) 70 % D) 50 % 0% Testni qayta ishga tushiring Author: InfoMaster Matematika olimpiada
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Howdy! I’m at work surfing around your blog from my new iphone! Just wanted to say I love reading your blog and look forward to all your posts! Carry on the fantastic work!