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Matematika attestatsiya №4

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Yanvar 21, 2022

35 Ko'rishlar 1 izoh

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1 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №4

1 / 40

|x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping.

A) 6

B) 7

C) 0

D) 5

2 / 40

Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak.

A) Birinchi yo'l

B) To'rtinchi yo'l

C) Uchunchi yo'l

D) Ikkinchi yo'l

3 / 40

tengsizlik yechimi bo’la oladigan tub sonlar nechta?

A) 5

B) 3

C) 2

D) 4

4 / 40

Agar ni hisoblang.

A) 8

B) Cheksiz

C) 9

D) 0

5 / 40

va bo'lsa x-y=?

A) 8

B) 7

C) 5

D) 9

6 / 40

1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2ⁿ, 3^m va 7^k lar ishtirok etsa, n+m+k ni toping.

A) 46

B) 40

C) 50

D) 44

7 / 40

Umumiy hadi x_n=3+5n-n² formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam?

A) 6

B) 5,75

C) 13

D) 9,25

8 / 40

Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi?

A) 31/85

B) 11/5

C) 68/15

D) 67/15

9 / 40

f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping.

A) 13cosx-cos13x + C

B) -13cosx- cos13 x +C

C) 13sinx-sin13x + C

D) 13sinx+sin13x + C

10 / 40

Tenglama ildizlari ayirmasining modulini toping.

A) 2√5

B) 5

C) √5+5

D) √5

11 / 40

Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak?

A) 1

B) 4

C) 3

D) 2

12 / 40

Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor?

A) 64/5

B) 48/5

C) 16

D) 10

13 / 40

Hisoblang 200−199+198−197+⋯+4−3

A) 101

B) 100

C) 99

D) 98

14 / 40

Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ?
a)76 : 9 = 7 (qoldiq 13);
b)20 : 7 = 2 (qoldiq 6);
d)54 : 15 = 4 (qoldiq 1)

A) )a,b,d

B) b,d

C) a,b

D) b

15 / 40

Hisoblang:

A) 3

B) 4

C) 2

D) 1

16 / 40

Hisoblang:

A) 8

B) 6

C) 0

D) 4

17 / 40

tenglama intervalda nechta ildizga ega?

A) 3

B) 2

C) 4

D) 1

18 / 40

Tenglamani yeching:

A) 5*4

B) 6/5

C) 5/9

D) 9/5

19 / 40

ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping.

A) 132°

B) 138°

C) 142°

D) 135°

20 / 40

Integralni hisoblang:

A) 3

B) 4

C) 1

D) 2

21 / 40

f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)⁴ bo'lsa, f'(0) ni toping.

A) 25

B) 30

C) 0

D) 10

22 / 40

Funksiyaning aniqlanish sohasini toping.

A) [-3;2]

B) (-∞;0)∪(0;∞)

C) x∈R

D) (-∞;3]∪[2;∞)

23 / 40

Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping.

A) √6

B) 2,4

C) √5

D) 2,5

24 / 40

ni hisoblang.

A) 3

B) 1

C) 0

D) 2

25 / 40

Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping.

A) -4

B) 4

C) √17

D) -√17

26 / 40

To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping.

A) 14°

B) 17°

C) 7°

D) 24°

27 / 40

Yig‘indini toping.

A) 1/6

B) 1/12

C) 1/9

D) 1/4

28 / 40

Agar bo‘lsa, m/n ni toping.

A) 4

B) (1+√5)/2

C) 3

D) 2

29 / 40

cos75° ·cos 45° ·cos15° ni hisoblang.

A) 1/8

B) √3/8

C) √3/4

D) √2/8

30 / 40

sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan?

A) 2

B) 4

C) 1

D) 3

31 / 40

A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping.

A) 120

B) 100

C) 90

D) 80

32 / 40

Tenglamaning natural ildizining butun bo‘luvchilari nechta?

A) 4

B) 6

C) 5

D) 2

33 / 40

Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping.

A) 20

B) 25

C) 40

D) 35

34 / 40

Tenglamalar sistemasidan foydalanib x + y + z ni toping:

A) 8

B) 6

C) 10

D) berilganlar yetarli emas

35 / 40

Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1.

A) 25

B) 32

C) 41

D) 50

36 / 40

Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping.

A) 96π

B) 144π

C) 72π

D) 192π

37 / 40

Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin.

A) 3R

B) √3R(2-√3)

C) R(√3-√2)

D) 1,5R

38 / 40

Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping.

A) 8√3

B) 6√5

C) 9√5

D) 12√3

39 / 40

Agar x²-6x+7=0 bo‘lsa, ni toping.