Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №4 Matematika attestatsiya Matematika attestatsiya №4 InfoMaster Yanvar 21, 2022 35 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 1 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №4 1 / 40 |x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping. A) 6 B) 7 C) 0 D) 5 2 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) Birinchi yo'l B) To'rtinchi yo'l C) Uchunchi yo'l D) Ikkinchi yo'l 3 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 5 B) 3 C) 2 D) 4 4 / 40 Agar ni hisoblang. A) 8 B) Cheksiz C) 9 D) 0 5 / 40 va bo'lsa x-y=? A) 8 B) 7 C) 5 D) 9 6 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 46 B) 40 C) 50 D) 44 7 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 6 B) 5,75 C) 13 D) 9,25 8 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 31/85 B) 11/5 C) 68/15 D) 67/15 9 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13cosx-cos13x + C B) -13cosx- cos13 x +C C) 13sinx-sin13x + C D) 13sinx+sin13x + C 10 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) 5 C) √5+5 D) √5 11 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 1 B) 4 C) 3 D) 2 12 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 64/5 B) 48/5 C) 16 D) 10 13 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 101 B) 100 C) 99 D) 98 14 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) )a,b,d B) b,d C) a,b D) b 15 / 40 Hisoblang: A) 3 B) 4 C) 2 D) 1 16 / 40 Hisoblang: A) 8 B) 6 C) 0 D) 4 17 / 40 tenglama intervalda nechta ildizga ega? A) 3 B) 2 C) 4 D) 1 18 / 40 Tenglamani yeching: A) 5*4 B) 6/5 C) 5/9 D) 9/5 19 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 132° B) 138° C) 142° D) 135° 20 / 40 Integralni hisoblang: A) 3 B) 4 C) 1 D) 2 21 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 25 B) 30 C) 0 D) 10 22 / 40 Funksiyaning aniqlanish sohasini toping. A) [-3;2] B) (-∞;0)∪(0;∞) C) x∈R D) (-∞;3]∪[2;∞) 23 / 40 Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping. A) √6 B) 2,4 C) √5 D) 2,5 24 / 40 ni hisoblang. A) 3 B) 1 C) 0 D) 2 25 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -4 B) 4 C) √17 D) -√17 26 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 14° B) 17° C) 7° D) 24° 27 / 40 Yig‘indini toping. A) 1/6 B) 1/12 C) 1/9 D) 1/4 28 / 40 Agar bo‘lsa, m/n ni toping. A) 4 B) (1+√5)/2 C) 3 D) 2 29 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) 1/8 B) √3/8 C) √3/4 D) √2/8 30 / 40 sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan? A) 2 B) 4 C) 1 D) 3 31 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 120 B) 100 C) 90 D) 80 32 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 4 B) 6 C) 5 D) 2 33 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 20 B) 25 C) 40 D) 35 34 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) 8 B) 6 C) 10 D) berilganlar yetarli emas 35 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 25 B) 32 C) 41 D) 50 36 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 96π B) 144π C) 72π D) 192π 37 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 3R B) √3R(2-√3) C) R(√3-√2) D) 1,5R 38 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 8√3 B) 6√5 C) 9√5 D) 12√3 39 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 48 B) 52 C) 28 D) 40 40 / 40 Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi? A) qat’iy kamayuvchi B) dastlab o‘sadi, keyin kamayadi C) dastlab kamayadi, keyin o‘sadi D) qat’iy o‘suvchi O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16