Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №4 Matematika attestatsiya Matematika attestatsiya №4 InfoMaster Yanvar 21, 2022 62 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 1 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №4 1 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 16 B) 25 C) 4 D) 9 2 / 40 tengsizlikni yeching. A) 3 B) 2 C) 4 D) 1 3 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) To'rtinchi yo'l B) Ikkinchi yo'l C) Birinchi yo'l D) Uchunchi yo'l 4 / 40 To’g’ri turt burchakning bo’yining perimetriga nisbatini toping. A) 3/18 B) 1/2 C) -452/18 D) 5/3 5 / 40 Agar bo‘lsa, x ni toping. A) -2 B) 5 C) -5 D) 2 6 / 40 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x+2y+2=0 B) 3x-2y+2=0 C) 3x+2y-2=0 D) 3x-2y-2=0 7 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 3 B) 7 C) 9 D) 1 8 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 114 B) 108 C) 96 D) 126 9 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 31/85 B) 68/15 C) 67/15 D) 11/5 10 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 8 B) 4 C) 6 D) 2 11 / 40 Soddalashtiring: A) Aniqlab bo`lmaydi B) 2 C) 1 D) 3 12 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 4 C) 3 D) 1 13 / 40 x ni toping ? A) 6 B) 4 C) 3 D) 5 14 / 40 Hisoblang: -121+(-135)-(-1)28 A) -1 B) -2 C) 0 D) -3 15 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 6 B) 4 C) 5 D) 3 16 / 40 Tenglamani yeching: A) 5*4 B) 9/5 C) 5/9 D) 6/5 17 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 3 B) 4 C) 2 D) 1 18 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 10 B) 6 C) 8 D) 9 19 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 9 B) 6 C) 3 D) 12 20 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 48 B) 16 C) 32 D) 64 21 / 40 Funksiyaning aniqlanish sohasini toping. A) x∈R B) (-∞;3]∪[2;∞) C) [-3;2] D) (-∞;0)∪(0;∞) 22 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 142° B) 135° C) 138° D) 132° 23 / 40 Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping. A) 2,4 B) √5 C) 2,5 D) √6 24 / 40 Yig‘indini toping. A) 1/6 B) 1/12 C) 1/9 D) 1/4 25 / 40 sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan? A) 1 B) 3 C) 4 D) 2 26 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 41 B) 50 C) 32 D) 25 27 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) 10 B) 8 C) berilganlar yetarli emas D) 6 28 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -4 B) -√17 C) 4 D) √17 29 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 14° B) 7° C) 24° D) 17° 30 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 2 B) 1 C) 5 D) 4 31 / 40 Hisoblang: A) 6 B) 0 C) 8 D) 4 32 / 40 Agar bo'lsa, ni m orqali ifodalang. A) (4-m)/4 B) 2/m C) (m+4)/4 D) (m+1)/2 33 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 90 B) 120 C) 100 D) 80 34 / 40 tenglama intervalda nechta ildizga ega? A) 4 B) 2 C) 1 D) 3 35 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 8/15 B) 1/3 C) 5/6 D) 1/2 36 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 96π B) 192π C) 72π D) 144π 37 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 40 B) 35 C) 20 D) 25 38 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 40 B) 28 C) 52 D) 48 39 / 40 Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi? A) qat’iy kamayuvchi B) dastlab kamayadi, keyin o‘sadi C) dastlab o‘sadi, keyin kamayadi D) qat’iy o‘suvchi 40 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/4 B) √2/8 C) 1/8 D) √3/8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
