Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №4 Matematika attestatsiya Matematika attestatsiya №4 InfoMaster Yanvar 21, 2022 52 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 1 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №4 1 / 40 Jamshid bir kunda 70,5 kgdan paxta tersa, 8460 kg paxtani necha kunda terib bo’ladi ? A) 100 kun B) 140 kun C) 130 kun D) 120 kun 2 / 40 Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping. A) 8 B) 16 C) 24 D) 32 3 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 18 B) 24 C) 30 D) 12 4 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) c>a>b B) a>c>b C) a>b>c D) b>a>c 5 / 40 ni qanoatlantiruvchi yechimlar nechta? A) 2 B) 1 C) 0 D) 3 6 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 44 B) 40 C) 50 D) 46 7 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,5 m yoki 50 cm B) 0,6 m yoki 60 cm C) 0,9 m yoki 90 cm D) 0,7 m yoki 70 cm 8 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 114 B) 96 C) 108 D) 126 9 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5 C) 5 D) √5+5 10 / 40 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x+2y-2=0 B) 3x+2y+2=0 C) 3x-2y+2=0 D) 3x-2y-2=0 11 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUK B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUK 3-EKUB D) 1-EKUB 2-EKUB 3-EKUK 12 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 8 B) 7 C) 9 D) 6 13 / 40 x ni toping ? A) 4 B) 3 C) 6 D) 5 14 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 48/5 B) 10 C) 64/5 D) 16 15 / 40 Hisoblang: -121+(-135)-(-1)28 A) -1 B) 0 C) -3 D) -2 16 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 10 B) 30 C) 25 D) 0 17 / 40 ni hisoblang. A) 3 B) 1 C) 2 D) 0 18 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 1 B) 8 C) 5 D) 0 19 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 1 B) 5 C) 4 D) 2 20 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 28 B) 48 C) 40 D) 52 21 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 7 B) 12 C) 9 D) 15 22 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 4800 B) 5050 C) 600 D) 3600 23 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,288 B) 0,432 C) 0,216 D) 0,144 24 / 40 Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping. A) 2,5 B) √6 C) 2,4 D) √5 25 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 9√5 B) 8√3 C) 12√3 D) 6√5 26 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 3 B) 4 C) 1 D) 2 27 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 80 B) 100 C) 90 D) 120 28 / 40 Yig‘indini toping. A) 1/9 B) 1/6 C) 1/4 D) 1/12 29 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) R(√3-√2) B) √3R(2-√3) C) 3R D) 1,5R 30 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 10 B) 8 C) 9 D) 6 31 / 40 ABC o‘tkir burchakli uchburchakda sinA=4/5 va sinB=15/13 bo'lsa, sinC ni qiymatini toping. A) 48/65 B) 56/65 C) 36/65 D) 40/63 32 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 32 B) 64 C) 16 D) 48 33 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 4 B) 3 C) 1 D) 2 34 / 40 Integralni hisoblang: A) 3 B) 4 C) 1 D) 2 35 / 40 Agar bo‘lsa, m/n ni toping. A) 2 B) (1+√5)/2 C) 4 D) 3 36 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;3]∪[2;∞) B) (-∞;0)∪(0;∞) C) [-3;2] D) x∈R 37 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 40 B) 35 C) 20 D) 25 38 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 8/15 B) 1/2 C) 1/3 D) 5/6 39 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 72π B) 144π C) 192π D) 96π 40 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) berilganlar yetarli emas B) 6 C) 8 D) 10 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
