Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №3 Matematika attestatsiya Matematika attestatsiya №3 InfoMaster Yanvar 15, 2022 108 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 9 ovozlar, 3.9 avg 1 123456789101112131415161718192021222324252627282930313233343536373839 Matematika fanidan attestatsiya savollari №3 1 / 39 bo‘lsa, ning qiymatini toping. A) 1 B) 0,5 C) 2 D) 0,7 2 / 39 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 4 B) 1 C) 3 D) 2 3 / 39 Qayiq daryo oqimga qarshi 48 km va oqim bo‘yicha ham shuncha yo‘l bosib, butun yo‘lga 5 soat vaqt sarfladi. Daryo oqimining tezligi 4 km/soat bo‘lsa, qayiqning xususiy tezligini toping. A) 22 B) 20 C) 18 D) 25 4 / 39 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2 B) 3 C) 2,5 D) 4 5 / 39 tengsizlikni yeching. A) 3 B) 2 C) 4 D) 1 6 / 39 Tengsizlikni yeching. A) [-2;1]∪{-3} B) [-3;-2] C) (-∞;-2] D) [-3;2]∪{1} 7 / 39 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-1; ∞) B) [-1; ∞) C) (-2; ∞) D) (0; ∞) 8 / 39 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,5 m yoki 50 cm B) 0,7 m yoki 70 cm C) 0,9 m yoki 90 cm D) 0,6 m yoki 60 cm 9 / 39 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 3 B) 9 C) 7 D) 1 10 / 39 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 3 B) 2 C) 1 D) 4 11 / 39 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 114 B) 108 C) 96 D) 126 12 / 39 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 4 B) 1/5 C) 1/4 D) 1/3 13 / 39 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x-2y-2=0 B) 3x+2y+2=0 C) 3x+2y-2=0 D) 3x-2y+2=0 14 / 39 Hisoblang: A) 4 B) 9 C) 27 D) 7 15 / 39 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) √2 B) 1 C) √3 D) 2 16 / 39 Soddalashtiring: A) 1 B) 3 C) 2 D) Aniqlab bo`lmaydi 17 / 39 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 4 B) 1 C) 3 D) 2 18 / 39 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 64/5 B) 16 C) 10 D) 48/5 19 / 39 Soddalashtiring. A) (b+2)/(1-b) B) (a-1)/(a-3) C) (a-1)/(1-b) D) (a+1)/(-a-3) 20 / 39 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUB 3-EKUK B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUK 3-EKUK D) 1-EKUB 2-EKUK 3-EKUB 21 / 39 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 4 B) 1 C) 3 D) 2 22 / 39 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 6 B) 3 C) 4 D) 5 23 / 39 Hisoblang 200−199+198−197+⋯+4−3 A) 101 B) 100 C) 98 D) 99 24 / 39 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 5 B) 12 C) 1 D) 7 25 / 39 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 34 B) 32 C) 36 D) 40 26 / 39 Soddalshtiring. A) 6 B) 1 C) 2 D) -1 27 / 39 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) )a,b,d B) b,d C) a,b D) b 28 / 39 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 0,2km B) 20 km C) 200 km D) 2 km 29 / 39 Hisoblang: A) 2 B) 3 C) 4 D) 1 30 / 39 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 100° B) 130° C) 120° D) 110° 31 / 39 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 12 B) 11 C) 14 D) 13 32 / 39 x ni toping ? A) 3 B) 5 C) 4 D) 6 33 / 39 Hisoblang? A) 2 B) 4 C) 0,25 D) 0,5 34 / 39 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (32π)/3 B) 11π C) (28π)/3 D) (29π)/3 35 / 39 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 40° B) 30° C) 10° D) 20° 36 / 39 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 1 B) 3 C) 4 D) 2 37 / 39 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 9 B) 8 C) 6 D) 7 38 / 39 Hisoblang: -121+(-135)-(-1)28 A) -1 B) -2 C) 0 D) -3 39 / 39 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 11 B) 12 C) 10 D) 13 O'rtacha ball 59% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
