Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №3 Matematika attestatsiya Matematika attestatsiya №3 InfoMaster Yanvar 15, 2022 108 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 9 ovozlar, 3.9 avg 1 123456789101112131415161718192021222324252627282930313233343536373839 Matematika fanidan attestatsiya savollari №3 1 / 39 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 3 B) 4 C) 2 D) aniqlab bo‘lmaydi 2 / 39 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 4 B) 2,5 C) 3 D) 2 3 / 39 bo‘lsa, y = ? A) 8 B) 2 C) 3 D) 26 4 / 39 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 18 B) 12 C) 30 D) 24 5 / 39 Agar va bo'lsa f(4) ning qiymatini toping. A) 4 B) 35 C) 12 D) 11 6 / 39 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 4 B) 2 C) 6 D) 0 7 / 39 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 3 B) 2 C) 1 D) 0 8 / 39 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) y=1-a B) x=a C) y=-a D) x=-a 9 / 39 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 4 B) 3 C) 4,5 D) 7,5 10 / 39 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,6 m yoki 60 cm B) 0,9 m yoki 90 cm C) 0,7 m yoki 70 cm D) 0,5 m yoki 50 cm 11 / 39 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-1; ∞) B) [-1; ∞) C) (-2; ∞) D) (0; ∞) 12 / 39 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/4 B) 1/3 C) 1/5 D) 4 13 / 39 cosx=0,2x tenglama nechta yechimga ega? A) 4 B) 2 C) 3 D) 1 14 / 39 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 126 B) 114 C) 108 D) 96 15 / 39 funksiyaning qiymatlar to'plamini toping. A) [-√2;0)∪(0;√2] B) [-√2;√2] C) (-2√2;√2) D) [-√2;-1)∪(-1;1)∪(1;√2] 16 / 39 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 40 B) 32 C) 36 D) 34 17 / 39 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 3 B) 2 C) 1 D) 4 18 / 39 Hisoblang: A) 3 B) 1 C) 4 D) 2 19 / 39 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 20° B) 10° C) 40° D) 30° 20 / 39 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 9 B) 6 C) 7 D) 8 21 / 39 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) )a,b,d B) b,d C) b D) a,b 22 / 39 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 3 B) 1 C) 4 D) 2 23 / 39 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUB 3-EKUK B) 1-EKUB 2-EKUK 3-EKUB C) 1-EKUB 2-EKUB 3-EKUB D) 1-EKUB 2-EKUK 3-EKUK 24 / 39 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 12 B) 10 C) 11 D) 13 25 / 39 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 120° B) 130° C) 100° D) 110° 26 / 39 Hisoblang 200−199+198−197+⋯+4−3 A) 99 B) 101 C) 100 D) 98 27 / 39 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 1 B) 12 C) 5 D) 7 28 / 39 Soddalashtiring. A) (a-1)/(1-b) B) (a-1)/(a-3) C) (b+2)/(1-b) D) (a+1)/(-a-3) 29 / 39 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 20 km B) 2 km C) 200 km D) 0,2km 30 / 39 Soddalashtiring: A) 3 B) Aniqlab bo`lmaydi C) 1 D) 2 31 / 39 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 2 B) 3 C) 1 D) 4 32 / 39 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (29π)/3 B) 11π C) (28π)/3 D) (32π)/3 33 / 39 Hisoblang? A) 4 B) 0,5 C) 0,25 D) 2 34 / 39 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 16 B) 10 C) 64/5 D) 48/5 35 / 39 x ni toping ? A) 4 B) 6 C) 5 D) 3 36 / 39 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 5 B) 6 C) 3 D) 4 37 / 39 Soddalshtiring. A) 1 B) 6 C) -1 D) 2 38 / 39 Hisoblang: -121+(-135)-(-1)28 A) -3 B) -2 C) 0 D) -1 39 / 39 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 11 B) 12 C) 13 D) 14 O'rtacha ball 59% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
