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Matematika attestatsiya №5

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Yanvar 24, 2022

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

|x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping.

A) 5

B) 7

C) 0

D) 6

2 / 40

Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi?

A) 2

B) 3

C) 4

D) 1

3 / 40

ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping.

A) 2

B) aniqlab bo‘lmaydi

C) 4

D) 3

4 / 40

Ushbu sistemaga ko'ra (ac+bd)² ni toping.

A) 1

B) 2

C) 4

D) 3

5 / 40

Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping.

A) 0,6 m yoki 60 cm

B) 0,7 m yoki 70 cm

C) 0,5 m yoki 50 cm

D) 0,9 m yoki 90 cm

6 / 40

tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping.

A) 1

B) 3

C) 2

D) 0

7 / 40

Hisoblang:

A) 3

B) 2

C) 1

D) 4

8 / 40

Hisoblang 200−199+198−197+⋯+4−3

A) 100

B) 99

C) 98

D) 101

9 / 40

Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak?

A) 3

B) 2

C) 4

D) 1

10 / 40

Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping.

A) 40

B) 25

C) 35

D) 20

11 / 40

Agar x²-6x+7=0 bo‘lsa, ni toping.

A) 48

B) 52

C) 28

D) 40

12 / 40

108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng?

2¹²·3¹⁸
2²·3³
2⁸·3¹⁰
2⁶·3⁹

A) 2

B) 4

C) 3

D) 1

13 / 40

Hisoblang:

A) 0

B) 1/32

C) -1/2

D) -√3/2

14 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 5

B) 7

C) 10

D) 11

15 / 40

Tenglamani yeching:

A) -6

B) 6; -5

C) 5

D) -6; 5

16 / 40

√3

A) 5/5

B) 21/10

C) 7/3

D) 3/2

17 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BC > AD

B) DC < AD

C) AB = BC

D) BD = BC

18 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 2

B) 4

C) 1

D) 3

19 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 3√2

B) 6

C) 4√3

D) 4√2

20 / 40

sonlarini taqqolsang.

A) c

B) c

C) a

D) b

21 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 4

B) 1

C) 2

D) 3

22 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 10

B) 20

C) 14

D) 12

23 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 121

B) berilganlar yetarli emas

C) 11

D) 22

24 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 115

B) 110

C) 112

D) 116

25 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 24

B) 35

C) 14

D) 23

26 / 40

Hisoblang:

A) 19/20

B) 9/10

C) 10/11

D) 20/21

27 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 5

B) 6

C) 11

D) 4

28 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) bc/d

B) bd/c

C) cd/b

D) 1

29 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 10

C) 6√7

D) 8

30 / 40

Rasmdagi shakl perimetrini toping.

A) 30

B) 24

C) 32

D) 28

31 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 5 yoki –15

B) 6

C) 3 yoki –8

D) 4 yoki –12

32 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 2

B) 1

C) 3

D) 4

33 / 40

Chizmadan foydalanib α ni toping.

A) 40°

B) 50°

C) 30°

D) 20°

34 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (2; 7)

B) (9; 0), (28; -1)

C) (7; 2), (28; -1)

D) (2; 3)

35 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 12

B) 13

C) 14

D) 15

36 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 1

B) 3

C) 4

D) 2

37 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 100

B) 25

C) 105

D) 96

38 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 10

B) 8

C) 15

D) 20

39 / 40

Ifodaning qiymatini toping.