Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tengsizlikni yeching. A) 2 B) 3 C) 1 D) 4 2 / 40 Berilgan sonlarning yig’indisini toping. A) 3/18 B) 2/4 C) 1/4 D) -452/18 3 / 40 tenglamalar sistemasi yechimga ega bo‘ladigan a ning barcha qiymatlari to‘plamini toping. A) 2 B) 4 C) 1 D) 3 4 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,9 m yoki 90 cm B) 0,6 m yoki 60 cm C) 0,5 m yoki 50 cm D) 0,7 m yoki 70 cm 5 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 35/6 B) 8 C) 25/3 D) 6 6 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 108 B) 96 C) 126 D) 114 7 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 12 B) 5 C) 1 D) 7 8 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 110° B) 120° C) 130° D) 100° 9 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 3 B) 4 C) 1 D) 2 10 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 0 B) 1 C) 5 D) 8 11 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 40 B) 25 C) 35 D) 20 12 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 8/15 B) 1/2 C) 1/3 D) 5/6 13 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 8 C) 12 D) 6 14 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 20 D) 10 15 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 64 C) 16(π-2) D) 32 16 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 3√2 C) 6 D) 4√2 17 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 2 C) 1 D) 4 18 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 3 D) 8 19 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) DC < AD D) BC > AD 20 / 40 bo‘lsa, A) 2 B) 2/3 C) 3/2 D) 1 21 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 10 C) 8 D) 15 22 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bc/d C) bd/c D) cd/b 23 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 9 C) 10 D) 12 24 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 8 C) 5 D) 7 25 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 4 C) 11 D) 5 26 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) Ø C) -π/4+πk, k∈Z D) π/4+πk, k∈Z 27 / 40 sonlarini taqqolsang. A) c B) c C) a D) b 28 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 100 C) 96 D) 25 29 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 3 C) 4 D) 1 30 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -6 D) -4 31 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 10 C) 6√7 D) 4√7 32 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (2; 3) D) (7; 2), (28; -1) 33 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(4) C) 0,04 D) 0,0(2) 34 / 40 Hisoblang: A) -1/2 B) 1/32 C) 0 D) -√3/2 35 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 121 C) 11 D) berilganlar yetarli emas 36 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 4 yoki –12 C) 5 yoki –15 D) 6 37 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 4 C) 2 D) 1 38 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 2 D) 3 39 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 3√2 C) 2√2 D) 2√3 40 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 5 D) 7 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
