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Matematika attestatsiya №5

InfoMaster

Yanvar 24, 2022

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

1:(2:3) son 1:2:3 sonidan qanchaga katta?

A) 6

B) 9

C) 4/3

D) 3

2 / 40

ko’paytmani hisoblang.

A) 86420000

B) 10000

C) 480000

D) 0

3 / 40

Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping.

A) 20

B) aniqlab bo‘lmaydi

C) 16

D) 18

4 / 40

Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi?

A) 31/85

B) 67/15

C) 68/15

D) 11/5

5 / 40

Hisoblang:

A) 27

B) 4

C) 7

D) 9

6 / 40

Tengsizlikni yeching.

A) [-2;1]∪{-3}

B) [-3;2]∪{1}

C) (-∞;-2]

D) [-3;-2]

7 / 40

DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ?

A) 110°

B) 100°

C) 120°

D) 130°

8 / 40

Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ?

A) 12

B) 13

C) 11

D) 10

9 / 40

Soddalashtiring.

A) (a-1)/(1-b)

B) (a-1)/(a-3)

C) (a+1)/(-a-3)

D) (b+2)/(1-b)

10 / 40

Agar x²-6x+7=0 bo‘lsa, ni toping.

A) 48

B) 28

C) 40

D) 52

11 / 40

Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1.

A) 41

B) 32

C) 25

D) 50

12 / 40

Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping.

A) 6

B) 8

C) 10

D) 9

13 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 10

B) 9

C) 11

D) 12

14 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 3

B) 5

C) 8

D) -2

15 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 5 yoki –15

B) 3 yoki –8

C) 6

D) 4 yoki –12

16 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) berilganlar yetarli emas

B) 121

C) 22

D) 11

17 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 3

B) 2

C) 1

D) 4

18 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -3

B) -6

C) -4

D) 5

19 / 40

Ifodaning qiymatini toping.

A) 0,0(4)

B) 0,0(2)

C) 0,(04)

D) 0,04

20 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 5

C) 8

D) 6

21 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 4

B) 2

C) 3

D) 1

22 / 40

Chizmadan foydalanib α ni toping.

A) 30°

B) 50°

C) 20°

D) 40°

23 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 25

B) 105

C) 96

D) 100

24 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 42

B) 45

C) 43

D) 44

25 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 4

B) 1

C) 2

D) 3

26 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 10

B) 15

C) 8

D) 20

27 / 40

Hisoblang:

A) 1/32

B) -1/2

C) -√3/2

D) 0

28 / 40

sonlarini taqqolsang.

A) c

B) c

C) b

D) a

29 / 40

Tenglamalar sistemani yeching:

A) (2; 3)

B) (9; 0), (28; -1)

C) (7; 2), (28; -1)

D) (9; 0), (2; 7)

30 / 40

Hisoblang:

A) sin10°

B) 1

C) cos10°

D) cos50°

31 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 10

B) 4√7

C) 8

D) 6√7

32 / 40

Rasmdagi shakl perimetrini toping.

A) 30

B) 32

C) 24

D) 28

33 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 12

B) 8

C) 6

D) 10

34 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) AB = BC

B) BC > AD

C) BD = BC

D) DC < AD

35 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.