Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 37 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 58 B) 59 C) 61 D) 60 2 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16sin3x*sin5x B) -16cos3x*sin5x C) 16cos3x*cos5x D) 16sin3x*cos5x 3 / 40 va bo'lsa x-y=? A) 8 B) 9 C) 5 D) 7 4 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13sinx+sin13x + C B) 13cosx-cos13x + C C) 13sinx-sin13x + C D) -13cosx- cos13 x +C 5 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;0)∪(0;√2] B) (-2√2;√2) C) [-√2;-1)∪(-1;1)∪(1;√2] D) [-√2;√2] 6 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-1; ∞) B) [-1; ∞) C) (0; ∞) D) (-2; ∞) 7 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 12 B) 13 C) 10 D) 11 8 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b,d B) a,b C) b D) )a,b,d 9 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) 11π B) (32π)/3 C) (28π)/3 D) (29π)/3 10 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 9 B) 3 C) 6 D) 12 11 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 0 B) 1 C) 8 D) 5 12 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 10 B) 9 C) 6 D) 8 13 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 14 D) 12 14 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 2 C) 4 D) 3 15 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 3 C) 2 D) 1 16 / 40 Tenglamani yeching: A) -6; 5 B) 6; -5 C) -6 D) 5 17 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 8 C) 10 D) 12 18 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 24 D) 28 19 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 14 D) 23 20 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 5 C) 6 D) 11 21 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 22 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 42 C) 45 D) 44 23 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 4√3 C) 2√3 D) 2√2 24 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3tg50° tg70° C) √3ctg40° tg70° D) 4 √3tg50° tg70° 25 / 40 Hisoblang: A) 0 B) -1/2 C) -√3/2 D) 1/32 26 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 3 C) 2 D) 4 27 / 40 sonlarini taqqolsang. A) c B) a C) b D) c 28 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 6 D) 7 29 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 10 C) 12 D) 11 30 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 5 C) 3 D) -2 31 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 15 C) 12 D) 14 32 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 20 C) 8 D) 15 33 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 50° C) 30° D) 20° 34 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 64 C) 48 D) 32 35 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 3√2 C) 4√3 D) 4√2 36 / 40 Hisoblang: A) 19/20 B) 20/21 C) 9/10 D) 10/11 37 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 10 D) 8 38 / 40 bo‘lsa, A) 2 B) 2/3 C) 3/2 D) 1 39 / 40 √3 A) 3/2 B) 7/3 C) 21/10 D) 5/5 40 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 10 C) 11 D) 7 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
