Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 39 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Berilgan sonlarning yig’indisini toping. A) 3/18 B) 2/4 C) -452/18 D) 1/4 2 / 40 tengsizlikni yeching. A) x∈(-3;1) B) x∈(-5;1) C) x∈(-∞;5) D) x∈(-∞;5)∪(-3;1) 3 / 40 Merganning nishonga tekkizish ehtimoli 0,8 ga teng. U ishonga 2 marta o‘q uzganda o‘qlardan biri nishonga tegishining ehtimolligini toping. A) 0,32 B) 0,8 C) 0,5 D) 0,16 4 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 3 B) 7 C) 1 D) 9 5 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 4 B) 8 C) 6 D) 2 6 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 27 B) 48 C) 26 D) 32 7 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 5 B) 12 C) 7 D) 1 8 / 40 Hisoblang? A) 2 B) 4 C) 0,5 D) 0,25 9 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 40 B) 36 C) 34 D) 32 10 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 5050 B) 600 C) 3600 D) 4800 11 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 5 B) 9 C) 0 D) 1 12 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 138° B) 135° C) 132° D) 142° 13 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 2 D) 3 14 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 40° C) 20° D) 50° 15 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 3 C) 2 D) 4 16 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 4 C) 2 D) 1 17 / 40 Hisoblang: A) cos50° B) 1 C) cos10° D) sin10° 18 / 40 √3 A) 3/2 B) 7/3 C) 5/5 D) 21/10 19 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 8 C) 6 D) 12 20 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 21 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) berilganlar yetarli emas D) 22 22 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 42 C) 64 D) 48 23 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) 0 C) π/4+πk, k∈Z D) -π/4+πk, k∈Z 24 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 110 C) 115 D) 116 25 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 8(π+2) C) 32 D) 16(π-2) 26 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 12 C) 13 D) 14 27 / 40 bo‘lsa, A) 2 B) 2/3 C) 1 D) 3/2 28 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) -6 D) 6; -5 29 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 14 C) 12 D) 10 30 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 2 D) 1 31 / 40 Hisoblang: A) 0 B) -√3/2 C) -1/2 D) 1/32 32 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 28 D) 24 33 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 34 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -4 C) 5 D) -3 35 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 5 C) 11 D) 4 36 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) 2√3tg50° tg70° D) √3ctg40° tg70° 37 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 2√3 D) 4√3 38 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 8 D) 10 39 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) DC < AD D) BC > AD 40 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 14 D) 35 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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