Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 8 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 203 B) 201 C) 289 D) 200 2 / 40 va bo'lsa x-y=? A) 8 B) 9 C) 7 D) 5 3 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n < 0, k = 0 B) n = 0, k < 0 C) n = 0, k > 0 D) n > 0, k = 0 4 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 8 B) 6 C) 4 D) 2 5 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-2; ∞) B) [-1; ∞) C) (0; ∞) D) (-1; ∞) 6 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 13 B) 9,25 C) 6 D) 5,75 7 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 120° B) 100° C) 130° D) 110° 8 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 2 B) 3 C) 4 D) 1 9 / 40 Soddalshtiring. A) 6 B) -1 C) 2 D) 1 10 / 40 Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi? A) dastlab kamayadi, keyin o‘sadi B) qat’iy kamayuvchi C) qat’iy o‘suvchi D) dastlab o‘sadi, keyin kamayadi 11 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,216 B) 0,144 C) 0,432 D) 0,288 12 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 135° B) 138° C) 132° D) 142° 13 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) Ø C) π/4+πk, k∈Z D) 0 14 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 10 D) 20 15 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 100 C) 25 D) 96 16 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 3 D) 1 17 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 12 D) 13 18 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 64 D) 42 19 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) DC < AD C) BC > AD D) BD = BC 20 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(4) C) 0,(04) D) 0,0(2) 21 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 4 D) 6 22 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 7 D) 6 23 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 9 C) 12 D) 10 24 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) berilganlar yetarli emas C) 121 D) 22 25 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 40° D) 30° 26 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 27 / 40 Hisoblang: A) 0 B) -√3/2 C) 1/32 D) -1/2 28 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 116 D) 110 29 / 40 Hisoblang: A) cos50° B) sin10° C) 1 D) cos10° 30 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 3√2 D) 4√3 31 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) bc/d C) 1 D) cd/b 32 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 3 C) 4 D) 2 33 / 40 Tenglamani yeching: A) 5 B) 6; -5 C) -6; 5 D) -6 34 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 16(π-2) C) 32 D) 8(π+2) 35 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 6 C) 8 D) 12 36 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 5 yoki –15 C) 3 yoki –8 D) 6 37 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 3 C) 5 D) -2 38 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -6 C) 5 D) -4 39 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 14 D) 35 40 / 40 sonlarini taqqolsang. A) c B) c C) b D) a O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
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