Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 3 B) 4 C) 2 D) 5 2 / 40 Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping. A) aniqlab bo‘lmaydi B) 20 C) 18 D) 16 3 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) Birinchi yo'l B) To'rtinchi yo'l C) Uchunchi yo'l D) Ikkinchi yo'l 4 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 1 B) 0 C) 3 D) 2 5 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) √2 B) 2 C) 1 D) √3 6 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 1 B) 3 C) 4 D) 2 7 / 40 Soddalashtiring. A) (a-1)/(a-3) B) (a-1)/(1-b) C) (a+1)/(-a-3) D) (b+2)/(1-b) 8 / 40 Hisoblang? A) 2 B) 4 C) 0,5 D) 0,25 9 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (29π)/3 B) (28π)/3 C) (32π)/3 D) 11π 10 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 0 B) 9 C) 1 D) 5 11 / 40 tenglama intervalda nechta ildizga ega? A) 4 B) 3 C) 2 D) 1 12 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) √3R(2-√3) B) 3R C) 1,5R D) R(√3-√2) 13 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (7; 2), (28; -1) C) (9; 0), (2; 7) D) (9; 0), (28; -1) 14 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 12 D) 14 15 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 42 C) 45 D) 44 16 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(2) C) 0,04 D) 0,0(4) 17 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) BC > AD D) DC < AD 18 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 105 C) 25 D) 96 19 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 3 C) 5 D) 8 20 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 6 C) 4 yoki –12 D) 5 yoki –15 21 / 40 sonlarini taqqolsang. A) c B) c C) b D) a 22 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 23 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 50° D) 30° 24 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 6 C) 8 D) 5 25 / 40 Hisoblang: A) 9/10 B) 19/20 C) 10/11 D) 20/21 26 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 22 D) 11 27 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 28 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 9 C) 12 D) 11 29 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√3 C) 6 D) 4√2 30 / 40 √3 A) 21/10 B) 7/3 C) 5/5 D) 3/2 31 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 11 C) 5 D) 6 32 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 14 C) 23 D) 24 33 / 40 Hisoblang: A) sin10° B) cos50° C) 1 D) cos10° 34 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 8 C) 10 D) 4√7 35 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) -π/4+πk, k∈Z C) π/4+πk, k∈Z D) Ø 36 / 40 Hisoblang: A) 1/32 B) -√3/2 C) 0 D) -1/2 37 / 40 Tenglamani yeching: A) -6 B) 6; -5 C) -6; 5 D) 5 38 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 2√2 D) 3√2 39 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -3 C) 5 D) -4 40 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 16(π-2) C) 32 D) 64 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
