Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 40 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar ning qiymatini toping. A) 23/25 B) 3 C) 75/23 D) 23/75 2 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16cos3x*cos5x B) 16sin3x*cos5x C) 16sin3x*sin5x D) -16cos3x*sin5x 3 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 289 B) 201 C) 203 D) 200 4 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13cosx-cos13x + C B) 13sinx+sin13x + C C) 13sinx-sin13x + C D) -13cosx- cos13 x +C 5 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 3 B) 0 C) 1 D) 2 6 / 40 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 0 B) 2 C) 4 D) 6 7 / 40 Soddalashtiring: A) 1 B) 2 C) 3 D) Aniqlab bo`lmaydi 8 / 40 Soddalashtiring. A) (a+1)/(-a-3) B) (b+2)/(1-b) C) (a-1)/(1-b) D) (a-1)/(a-3) 9 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 10° B) 20° C) 40° D) 30° 10 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 135° B) 138° C) 132° D) 142° 11 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/4 B) √3/8 C) √2/8 D) 1/8 12 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 96π B) 192π C) 144π D) 72π 13 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 12 C) 14 D) 10 14 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 43 C) 42 D) 44 15 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 2 D) 1 16 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 105 C) 96 D) 25 17 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -6 D) -4 18 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 30° D) 40° 19 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 8 C) 6 D) 12 20 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (9; 0), (2; 7) D) (2; 3) 21 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 3 yoki –8 D) 6 22 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 7 C) 10 D) 5 23 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 15 C) 12 D) 14 24 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 22 C) berilganlar yetarli emas D) 11 25 / 40 √3 A) 7/3 B) 5/5 C) 21/10 D) 3/2 26 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) cd/b C) bd/c D) 1 27 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√2 C) 4√3 D) 3√2 28 / 40 Hisoblang: A) -√3/2 B) 1/32 C) 0 D) -1/2 29 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 42 D) 32 30 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 11 D) 9 31 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) BC > AD D) AB = BC 32 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 32 C) 30 D) 24 33 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 6√7 C) 10 D) 8 34 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 35 C) 23 D) 24 35 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 5 C) 4 D) 11 36 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,04 C) 0,0(4) D) 0,(04) 37 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 3√2 D) 2√2 38 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 115 C) 116 D) 110 39 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) -6 D) 6; -5 40 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) -π/4+πk, k∈Z C) π/4+πk, k∈Z D) Ø O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
