Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, x + y ni toping. A) 18 B) 17 C) 16 D) 20 2 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 3 B) 2 C) 4 D) 5 3 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 2 B) 4 C) 3 D) 1 4 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 3 B) 4,5 C) 7,5 D) 4 5 / 40 Aniq integralni hisoblang: A) 0 B) 0,5 C) 2 D) 3 6 / 40 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 4 B) 0 C) 2 D) 6 7 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 13 B) 11 C) 12 D) 10 8 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 5 B) 7 C) 12 D) 1 9 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b B) a,b C) )a,b,d D) b,d 10 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 5 B) 6 C) 2 D) 4 11 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 4 B) 2 C) 1 D) 3 12 / 40 Agar bo'lsa, ni m orqali ifodalang. A) 2/m B) (m+1)/2 C) (4-m)/4 D) (m+4)/4 13 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) bc/d C) 1 D) cd/b 14 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 2√3 D) 3√2 15 / 40 Hisoblang: A) cos50° B) 1 C) cos10° D) sin10° 16 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 3 C) 4 D) 2 17 / 40 Hisoblang: A) 9/10 B) 19/20 C) 20/21 D) 10/11 18 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 5 D) 7 19 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 28 C) 30 D) 32 20 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 13 C) 12 D) 15 21 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 4√3 C) 3√2 D) 6 22 / 40 bo‘lsa, A) 1 B) 2 C) 2/3 D) 3/2 23 / 40 √3 A) 3/2 B) 5/5 C) 7/3 D) 21/10 24 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 1 C) 2 D) 4 25 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 1 C) 4 D) 3 26 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 1 C) 2 D) 3 27 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 3 C) 5 D) -2 28 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (2; 3) C) (7; 2), (28; -1) D) (9; 0), (28; -1) 29 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 0 D) 1/32 30 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 4 D) 11 31 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 8(π+2) C) 32 D) 64 32 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -6 C) -3 D) 5 33 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 10 D) 20 34 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,(04) C) 0,04 D) 0,0(4) 35 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 116 C) 112 D) 110 36 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 8 D) 10 37 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) BC > AD D) AB = BC 38 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 32 C) 42 D) 48 39 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 10 D) 6√7 40 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 4 √3tg50° tg70° C) 2√3tg50° tg70° D) √3tg50° tg70° O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
