Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 68 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 2 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) Ikkinchi yo'l B) Birinchi yo'l C) Uchunchi yo'l D) To'rtinchi yo'l 2 / 40 Agar bo'lsa ifodaning qiymatini toping. A) 0 B) 9 C) 13 D) 7 3 / 40 bo‘lsa, x + y ni toping. A) 20 B) 18 C) 16 D) 17 4 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 2 B) 8 C) 4 D) 6 5 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) √3 B) 2 C) 1 D) √2 6 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 2 B) 1 C) 3 D) 4 7 / 40 Soddalashtiring. A) (b+2)/(1-b) B) (a-1)/(1-b) C) (a+1)/(-a-3) D) (a-1)/(a-3) 8 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 34 B) 36 C) 40 D) 32 9 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 100° B) 130° C) 120° D) 110° 10 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) √3R(2-√3) B) 3R C) 1,5R D) R(√3-√2) 11 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 5050 B) 600 C) 4800 D) 3600 12 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √2/8 B) √3/4 C) 1/8 D) √3/8 13 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 6 D) 5 14 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 2 C) 4 D) 3 15 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 14 C) 35 D) 23 16 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 30° D) 50° 17 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) 0 C) π/4+πk, k∈Z D) Ø 18 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 8 C) 5 D) 3 19 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 3 C) 1 D) 2 20 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 10 C) 15 D) 20 21 / 40 sonlarini taqqolsang. A) a B) c C) c D) b 22 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 1/32 D) 0 23 / 40 bo‘lsa, A) 1 B) 2 C) 2/3 D) 3/2 24 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 6 D) 5 25 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 3 C) 1 D) 2 26 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 42 C) 32 D) 64 27 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 28 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) 4 √3tg50° tg70° C) √3tg50° tg70° D) √3ctg40° tg70° 29 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 6√7 D) 10 30 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 31 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (9; 0), (28; -1) 32 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 44 C) 42 D) 43 33 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) 1 D) bc/d 34 / 40 Hisoblang: A) cos10° B) cos50° C) 1 D) sin10° 35 / 40 Hisoblang: A) 10/11 B) 20/21 C) 9/10 D) 19/20 36 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -3 C) 5 D) -4 37 / 40 Tenglamani yeching: A) 6; -5 B) -6 C) -6; 5 D) 5 38 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 4 C) 3 D) 2 39 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 22 C) 121 D) berilganlar yetarli emas 40 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) DC < AD C) AB = BC D) BC > AD O'rtacha ball 34% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
