Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 38 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar bo'lsa ifodaning qiymatini toping. A) 13 B) 7 C) 9 D) 0 2 / 40 Qayiq daryo oqimga qarshi 48 km va oqim bo‘yicha ham shuncha yo‘l bosib, butun yo‘lga 5 soat vaqt sarfladi. Daryo oqimining tezligi 4 km/soat bo‘lsa, qayiqning xususiy tezligini toping. A) 18 B) 22 C) 20 D) 25 3 / 40 ni hisoblang. A) e+1 B) (e-1)/2 C) (e+1)/2 D) e-1 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5 C) 5 D) √5+5 5 / 40 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x+2y-2=0 B) 3x-2y+2=0 C) 3x-2y-2=0 D) 3x+2y+2=0 6 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 26 B) 48 C) 32 D) 27 7 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 100° B) 110° C) 130° D) 120° 8 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 4 B) 1 C) 3 D) 2 9 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 36 B) 40 C) 32 D) 34 10 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 192π B) 96π C) 144π D) 72π 11 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 14° B) 17° C) 24° D) 7° 12 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/8 B) √2/8 C) √3/4 D) 1/8 13 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 3 C) 2 D) 1 14 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 30° C) 20° D) 40° 15 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) berilganlar yetarli emas C) 121 D) 11 16 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (7; 2), (28; -1) 17 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -3 C) 5 D) -6 18 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) BD = BC D) DC < AD 19 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) 4 √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 20 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 42 D) 48 21 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 35 C) 24 D) 23 22 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 2 C) 1 D) 4 23 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 8 C) 15 D) 10 24 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 7 C) 8 D) 5 25 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√3 C) 6 D) 4√2 26 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 10 D) 20 27 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 2 C) 4 D) 1 28 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 105 C) 100 D) 96 29 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 10 C) 6 D) 12 30 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 3 C) 2 D) 1 31 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,0(4) C) 0,04 D) 0,(04) 32 / 40 bo‘lsa, A) 2/3 B) 3/2 C) 2 D) 1 33 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 5 C) 10 D) 7 34 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 4√7 C) 8 D) 6√7 35 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) 6; -5 D) -6 36 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 3 yoki –8 C) 5 yoki –15 D) 4 yoki –12 37 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 32 C) 64 D) 8(π+2) 38 / 40 Hisoblang: A) sin10° B) cos50° C) cos10° D) 1 39 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 28 C) 32 D) 30 40 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 3√2 D) 2√3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
