Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, x + y ni toping. A) 16 B) 17 C) 20 D) 18 2 / 40 bo‘lsa, ning qiymatini toping. A) 1 B) 0,7 C) 2 D) 0,5 3 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2,5 B) 4 C) 2 D) 3 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) √5 B) √5+5 C) 5 D) 2√5 5 / 40 Tengsizlikni yeching. A) [-2;1]∪{-3} B) (-∞;-2] C) [-3;2]∪{1} D) [-3;-2] 6 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 8 B) 6 C) 2 D) 4 7 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 36 B) 40 C) 34 D) 32 8 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUB B) 1-EKUB 2-EKUK 3-EKUK C) 1-EKUB 2-EKUB 3-EKUK D) 1-EKUB 2-EKUB 3-EKUB 9 / 40 Hisoblang: -121+(-135)-(-1)28 A) -2 B) -3 C) -1 D) 0 10 / 40 ABC o‘tkir burchakli uchburchakda sinA=4/5 va sinB=15/13 bo'lsa, sinC ni qiymatini toping. A) 48/65 B) 40/63 C) 56/65 D) 36/65 11 / 40 Tenglamani yeching: A) 6/5 B) 9/5 C) 5/9 D) 5*4 12 / 40 tenglama intervalda nechta ildizga ega? A) 1 B) 2 C) 4 D) 3 13 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 14 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 64 D) 42 15 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 16 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 42 C) 45 D) 44 17 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 2 D) 1 18 / 40 Hisoblang: A) 1/32 B) 0 C) -1/2 D) -√3/2 19 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 20 / 40 bo‘lsa, A) 2/3 B) 3/2 C) 1 D) 2 21 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) 4 √3tg50° tg70° C) √3ctg40° tg70° D) √3tg50° tg70° 22 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 11 D) 22 23 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√3 C) 2√2 D) 4√3 24 / 40 Hisoblang: A) cos10° B) 1 C) cos50° D) sin10° 25 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 5 C) 11 D) 10 26 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 5 C) 8 D) 3 27 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 6 C) 8 D) 12 28 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 1 C) 2 D) 4 29 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 1 C) 4 D) 3 30 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) 1 C) cd/b D) bd/c 31 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 35 D) 24 32 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) Ø D) -π/4+πk, k∈Z 33 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 4 yoki –12 C) 6 D) 5 yoki –15 34 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 24 C) 30 D) 28 35 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 10 C) 12 D) 20 36 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 10 D) 4√7 37 / 40 √3 A) 3/2 B) 5/5 C) 21/10 D) 7/3 38 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 64 C) 8(π+2) D) 32 39 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) DC < AD C) AB = BC D) BD = BC 40 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 5 C) 11 D) 4 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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