Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n = 0, k > 0 B) n = 0, k < 0 C) n < 0, k = 0 D) n > 0, k = 0 2 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 30 B) 12 C) 24 D) 18 3 / 40 ko’paytmani hisoblang. A) 0 B) 10000 C) 86420000 D) 480000 4 / 40 Tengsizlikni yeching. A) [-3;2]∪{1} B) [-2;1]∪{-3} C) (-∞;-2] D) [-3;-2] 5 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 6 B) 8 C) 2 D) 4 6 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 3 B) 0 C) 1 D) 2 7 / 40 x ni toping ? A) 3 B) 5 C) 4 D) 6 8 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 130° B) 100° C) 120° D) 110° 9 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 4 B) 2 C) 3 D) 1 10 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 17° B) 7° C) 14° D) 24° 11 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 50 B) 32 C) 41 D) 25 12 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 3 B) 6 C) 9 D) 12 13 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) AB = BC D) DC < AD 14 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 32 C) 64 D) 8(π+2) 15 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 16 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 6 C) 7 D) 8 17 / 40 Hisoblang: A) -1/2 B) 1/32 C) -√3/2 D) 0 18 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) 3 D) -2 19 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) -π/4+πk, k∈Z D) 0 20 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 10 C) 8 D) 6√7 21 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 3 D) 1 22 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 30° C) 20° D) 40° 23 / 40 Hisoblang: A) 1 B) sin10° C) cos50° D) cos10° 24 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 116 D) 110 25 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 24 C) 28 D) 30 26 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 10 D) 11 27 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (7; 2), (28; -1) C) (9; 0), (28; -1) D) (9; 0), (2; 7) 28 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 11 C) 9 D) 12 29 / 40 Hisoblang: A) 10/11 B) 19/20 C) 9/10 D) 20/21 30 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bc/d C) bd/c D) cd/b 31 / 40 Tenglamani yeching: A) -6 B) 5 C) -6; 5 D) 6; -5 32 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 3 yoki –8 C) 5 yoki –15 D) 6 33 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 2√2 D) 3√2 34 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 22 D) 11 35 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 2 C) 3 D) 4 36 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 20 D) 10 37 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 32 D) 42 38 / 40 sonlarini taqqolsang. A) c B) c C) a D) b 39 / 40 bo‘lsa, A) 2 B) 1 C) 2/3 D) 3/2 40 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 8 D) 10 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16