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Matematika attestatsiya №5

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Yanvar 24, 2022

22 Ko'rishlar 1 izoh

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

y=4cos 2x+cos8x funksiyaning hosilasini toping

A) -16cos3x*sin5x

B) 16sin3x*cos5x

C) 16sin3x*sin5x

D) 16cos3x*cos5x

2 / 40

To’g’ri turt burchakning bo’yining perimetriga nisbatini toping.

A) 5/3

B) 3/18

C) 1/2

D) -452/18

3 / 40

ko’paytmani hisoblang.

A) 10000

B) 86420000

C) 0

D) 480000

4 / 40

f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping.

A) 13cosx-cos13x + C

B) 13sinx-sin13x + C

C) -13cosx- cos13 x +C

D) 13sinx+sin13x + C

5 / 40

Aniq integralni hisoblang:

A) 0,5

B) 0

C) 2

D) 3

6 / 40

Hisoblang:

A) 4

B) 7

C) 27

D) 9

7 / 40

n ning qanday qiymatida tenglik to`g`ri bo’ladi? (7³)=7¹⁵

A) 5

B) 1

C) 12

D) 7

8 / 40

Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ?

A) 20 km

B) 200 km

C) 2 km

D) 0,2km

9 / 40

DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ?

A) 100°

B) 120°

C) 130°

D) 110°

10 / 40

Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping.

A) 1

B) 8

C) 0

D) 5

11 / 40

Integralni hisoblang:

A) 4

B) 2

C) 3

D) 1

12 / 40

Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin.

A) 1,5R

B) 3R

C) √3R(2-√3)

D) R(√3-√2)

13 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 5

B) 11

C) 7

D) 10

14 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (28; -1)

B) (7; 2), (28; -1)

C) (2; 3)

D) (9; 0), (2; 7)

15 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) -π/4+πk, k∈Z

B) π/4+πk, k∈Z

C) 0

D) Ø

16 / 40

Rasmdagi shakl perimetrini toping.

A) 28

B) 30

C) 32

D) 24

17 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 110

B) 116

C) 112

D) 115

18 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 12

B) 10

C) 14

D) 20

19 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) -2

B) 8

C) 3

D) 5

20 / 40

Chizmadan foydalanib α ni toping.

A) 30°

B) 20°

C) 50°

D) 40°

21 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BC > AD

B) DC < AD

C) AB = BC

D) BD = BC

22 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) bc/d

B) cd/b

C) 1

D) bd/c

23 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 15

B) 12

C) 13

D) 14

24 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -6

B) -3

C) 5

D) -4

25 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 20

B) 8

C) 15

D) 10

26 / 40

Hisoblang:

A) sin10°

B) cos50°

C) 1

D) cos10°

27 / 40

Ifodaning qiymatini toping.

A) 0,0(2)

B) 0,0(4)

C) 0,(04)

D) 0,04

28 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 8

B) 7

C) 6

D) 5

29 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 4

B) 2

C) 1

D) 3

30 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) 4 √3tg50° tg70°

B) √3ctg40° tg70°

C) 2√3tg50° tg70°

D) √3tg50° tg70°

31 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 8

C) 10

D) 6√7

32 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 4

B) 1

C) 2

D) 3

33 / 40

√3

A) 3/2

B) 5/5

C) 21/10

D) 7/3

34 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 6

B) 10

C) 12

D) 8

35 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 23

B) 24

C) 14

D) 35

36 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√2

B) 4√3

C) 2√3

D) 3√2

37 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 100

B) 105

C) 25

D) 96

38 / 40

Hisoblang: