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Matematika attestatsiya №5

InfoMaster

Yanvar 24, 2022

60 Ko'rishlar 1 izoh

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

tenglamalar sistemasi yechimga ega bo‘ladigan a ning barcha qiymatlari to‘plamini toping.

A) 2

B) 3

C) 4

D) 1

2 / 40

ni qanoatlantiruvchi yechimlar nechta?

A) 0

B) 3

C) 1

D) 2

3 / 40

ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping.

A) 4

B) 3

C) 2

D) aniqlab bo‘lmaydi

4 / 40

P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping.

A) 1

B) 3

C) 4

D) 2

5 / 40

f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping.

A) f(x)=x²+3x+7

B) f(x)=x²-4

C) f(x)=x²-x+5

D) f(x)+2x²-1

6 / 40

x⁴+8x³+ax²+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping.

A) 32

B) 27

C) 26

D) 48

7 / 40

x ni toping ?

A) 4

B) 3

C) 5

D) 6

8 / 40

n ning qanday qiymatida tenglik to`g`ri bo’ladi? (7³)=7¹⁵

A) 12

B) 5

C) 7

D) 1

9 / 40

Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor?

A) 64/5

B) 10

C) 48/5

D) 16

10 / 40

Tenglamani yeching:

A) 5*4

B) 5/9

C) 9/5

D) 6/5

11 / 40

Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1.

A) 32

B) 50

C) 25

D) 41

12 / 40

Tenglamaning natural ildizining butun bo‘luvchilari nechta?

A) 2

B) 5

C) 4

D) 6

13 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) -2

B) 5

C) 3

D) 8

14 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 22

B) berilganlar yetarli emas

C) 11

D) 121

15 / 40

√3

A) 5/5

B) 21/10

C) 3/2

D) 7/3

16 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) √3tg50° tg70°

B) √3ctg40° tg70°

C) 2√3tg50° tg70°

D) 4 √3tg50° tg70°

17 / 40

Tenglamani yeching:

A) -6; 5

B) 6; -5

C) 5

D) -6

18 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 5 yoki –15

B) 6

C) 4 yoki –12

D) 3 yoki –8

19 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 5

B) 6

C) 7

D) 8

20 / 40

Ifodaning qiymatini toping.

A) 0,(04)

B) 0,04

C) 0,0(4)

D) 0,0(2)

21 / 40

bo‘lsa,

A) 2/3

B) 3/2

C) 1

D) 2

22 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 3√2

B) 4√3

C) 2√2

D) 2√3

23 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 44

B) 43

C) 42

D) 45

24 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 110

B) 112

C) 116

D) 115

25 / 40

sonlarini taqqolsang.

A) c

B) b

C) a

D) c

26 / 40

Hisoblang:

A) -1/2

B) 0

C) -√3/2

D) 1/32

27 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 10

B) 11

C) 12

D) 9

28 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) Ø

B) 0

C) -π/4+πk, k∈Z

D) π/4+πk, k∈Z

29 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 32

B) 16(π-2)

C) 64

D) 8(π+2)

30 / 40

Chizmadan foydalanib α ni toping.

A) 30°

B) 40°

C) 20°

D) 50°

31 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 11

B) 4

C) 5

D) 6

32 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) DC < AD

B) AB = BC

C) BC > AD

D) BD = BC

33 / 40

Tenglamalar sistemani yeching:

A) (2; 3)

B) (9; 0), (28; -1)

C) (9; 0), (2; 7)

D) (7; 2), (28; -1)

34 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√2

B) 4√3

C) 6

D) 3√2

35 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 25

B) 100

C) 105

D) 96

36 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 1

B) 4

C) 3

D) 2

37 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 6

B) 12

C) 10

D) 8

38 / 40

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