Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 41 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ni qanoatlantiruvchi yechimlar nechta? A) 3 B) 0 C) 2 D) 1 2 / 40 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 28 B) 24 C) 21 D) 32 3 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2 B) 4 C) 3 D) 2,5 4 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 2 B) 0 C) 3 D) 1 5 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 3 B) 1 C) 2 D) 4 6 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 1 B) 9 C) 7 D) 3 7 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 7 B) 12 C) 1 D) 5 8 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 32 B) 40 C) 34 D) 36 9 / 40 Soddalshtiring. A) 6 B) 2 C) 1 D) -1 10 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 5050 B) 600 C) 4800 D) 3600 11 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -4 B) 4 C) -√17 D) √17 12 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 10 B) 8 C) 9 D) 6 13 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 64 C) 32 D) 8(π+2) 14 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 42 D) 64 15 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) DC < AD C) AB = BC D) BD = BC 16 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 100 D) 25 17 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 4 C) 6 D) 11 18 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 30° C) 40° D) 50° 19 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 20 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 24 C) 14 D) 23 21 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,0(4) C) 0,04 D) 0,(04) 22 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 1 C) 2 D) 4 23 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 24 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 8 C) 6 D) 12 25 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) √3tg50° tg70° C) 2√3tg50° tg70° D) 4 √3tg50° tg70° 26 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 14 D) 10 27 / 40 √3 A) 7/3 B) 3/2 C) 5/5 D) 21/10 28 / 40 Hisoblang: A) cos10° B) 1 C) cos50° D) sin10° 29 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 1 C) 3 D) 2 30 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 5 C) 7 D) 11 31 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 2 C) 4 D) 1 32 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 4 D) 2 33 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 115 C) 116 D) 110 34 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 0 D) 1/32 35 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 22 D) 11 36 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 32 C) 24 D) 28 37 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) -2 D) 3 38 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (9; 0), (28; -1) 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) 1 D) bc/d 40 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 4√3 D) 2√3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
