Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 44 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 1:(2:3) son 1:2:3 sonidan qanchaga katta? A) 3 B) 4/3 C) 6 D) 9 2 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 59 B) 60 C) 61 D) 58 3 / 40 va bo'lsa x-y=? A) 9 B) 7 C) 8 D) 5 4 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) -13cosx- cos13 x +C B) 13cosx-cos13x + C C) 13sinx+sin13x + C D) 13sinx-sin13x + C 5 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 1 B) 3 C) 0 D) 2 6 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 27 B) 26 C) 48 D) 32 7 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (29π)/3 B) (28π)/3 C) 11π D) (32π)/3 8 / 40 Soddalashtiring: A) Aniqlab bo`lmaydi B) 2 C) 1 D) 3 9 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 13 B) 11 C) 12 D) 10 10 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) 4 B) -√17 C) √17 D) -4 11 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 25 B) 30 C) 10 D) 0 12 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 4 B) 1 C) 2 D) 3 13 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,04 D) 0,0(2) 14 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 1 D) 3 15 / 40 sonlarini taqqolsang. A) c B) b C) c D) a 16 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 22 C) berilganlar yetarli emas D) 121 17 / 40 Hisoblang: A) 9/10 B) 20/21 C) 19/20 D) 10/11 18 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 30° D) 50° 19 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 6 D) 5 20 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 20 D) 10 21 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 25 C) 100 D) 96 22 / 40 bo‘lsa, A) 2/3 B) 2 C) 3/2 D) 1 23 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) -2 D) 3 24 / 40 Hisoblang: A) cos10° B) sin10° C) cos50° D) 1 25 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -3 C) -6 D) 5 26 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 11 C) 12 D) 9 27 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 42 D) 64 28 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 0 D) 1/32 29 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 110 C) 116 D) 112 30 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 4 C) 1 D) 2 31 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 10 D) 8 32 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 44 C) 43 D) 45 33 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) DC < AD D) BC > AD 34 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 6 D) 4 yoki –12 35 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 24 D) 35 36 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) cd/b C) bd/c D) bc/d 37 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 20 D) 8 38 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 8 D) 10 39 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) π/4+πk, k∈Z C) Ø D) 0 40 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (2; 3) D) (9; 0), (2; 7) O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
