Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 70 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 3 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 funksiyaning eng kichik musbat davrini toping. A) 12 B) 18 C) 26 D) 24 2 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 3 B) 2 C) 4 D) aniqlab bo‘lmaydi 3 / 40 tenglamalar sistemasi yechimga ega bo‘ladigan a ning barcha qiymatlari to‘plamini toping. A) 4 B) 1 C) 2 D) 3 4 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)=x²+3x+7 B) f(x)+2x²-1 C) f(x)=x²-x+5 D) f(x)=x²-4 5 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 4 B) 4,5 C) 3 D) 7,5 6 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 4 B) 3 C) 2 D) 1 7 / 40 Soddalshtiring. A) 2 B) 1 C) 6 D) -1 8 / 40 Hisoblang: A) 3 B) 4 C) 2 D) 1 9 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 4 C) 1 D) 3 10 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 7 B) 9 C) 15 D) 12 11 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 32 B) 50 C) 25 D) 41 12 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 1 B) 9 C) 5 D) 0 13 / 40 Hisoblang: A) 1/32 B) -1/2 C) -√3/2 D) 0 14 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 8 D) 10 15 / 40 sonlarini taqqolsang. A) c B) a C) b D) c 16 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) 0 D) -π/4+πk, k∈Z 17 / 40 bo‘lsa, A) 3/2 B) 1 C) 2 D) 2/3 18 / 40 Tenglamani yeching: A) -6 B) 5 C) -6; 5 D) 6; -5 19 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 2 C) 4 D) 1 20 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 25 D) 100 21 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 4 D) 2 22 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (7; 2), (28; -1) C) (9; 0), (28; -1) D) (2; 3) 23 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 43 C) 42 D) 45 24 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 25 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 16(π-2) C) 64 D) 8(π+2) 26 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 23 D) 14 27 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) AB = BC C) BC > AD D) BD = BC 28 / 40 Hisoblang: A) 19/20 B) 20/21 C) 10/11 D) 9/10 29 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(4) C) 0,(04) D) 0,0(2) 30 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 4 √3tg50° tg70° C) √3tg50° tg70° D) 2√3tg50° tg70° 31 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 8 C) 5 D) 7 32 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) 8 D) -2 33 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 14 C) 20 D) 12 34 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 13 C) 15 D) 14 35 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 4 C) 11 D) 6 36 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) cd/b C) bd/c D) 1 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 10 D) 8 38 / 40 √3 A) 7/3 B) 5/5 C) 3/2 D) 21/10 39 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 64 D) 42 40 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 6 C) 4 yoki –12 D) 3 yoki –8 O'rtacha ball 35% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
