Matematika attestatsiya №5 Yanvar 24, 2022Yanvar 24, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №5 ga fikr bildirilmagan. 0% 2 ovozlar, 1 o'rtacha 3 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, y = ? A) 26 B) 8 C) 3 D) 2 2 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 4 B) 2 C) aniqlab bo‘lmaydi D) 3 3 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 2 B) 4 C) 1 D) 3 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) √5+5 B) √5 C) 5 D) 2√5 5 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-1; ∞) B) (-2; ∞) C) [-1; ∞) D) (0; ∞) 6 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 40 B) 50 C) 44 D) 46 7 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 100° B) 120° C) 130° D) 110° 8 / 40 Soddalshtiring. A) 6 B) -1 C) 2 D) 1 9 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 3 B) 4 C) 1 D) 2 10 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 32 B) 64 C) 16 D) 48 11 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 10 B) 8 C) 6 D) 9 12 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 4 B) 3 C) 2 D) 1 13 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 14 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 14 D) 23 15 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 32 C) 48 D) 64 16 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 20 D) 8 17 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 11 C) 4 D) 5 18 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 10 D) 8 19 / 40 Hisoblang: A) 19/20 B) 9/10 C) 20/21 D) 10/11 20 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (9; 0), (2; 7) D) (2; 3) 21 / 40 Hisoblang: A) -√3/2 B) 0 C) -1/2 D) 1/32 22 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 10 C) 11 D) 7 23 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 11 C) 22 D) 121 24 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) DC < AD D) AB = BC 25 / 40 √3 A) 3/2 B) 7/3 C) 5/5 D) 21/10 26 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 4 C) 3 D) 2 27 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 3 C) 1 D) 2 28 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 40° D) 30° 29 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 2√3 C) 3√2 D) 4√3 30 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 6√7 C) 4√7 D) 8 31 / 40 Tenglamani yeching: A) 6; -5 B) 5 C) -6; 5 D) -6 32 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 33 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 34 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 6 C) 4√2 D) 4√3 35 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 105 C) 96 D) 100 36 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 3 yoki –8 C) 4 yoki –12 D) 6 37 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 45 D) 44 38 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,04 C) 0,0(2) D) 0,0(4) 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) 1 D) cd/b 40 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 5 C) -2 D) 8 O'rtacha ball 48% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya