Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 24 B) 12 C) 30 D) 18 2 / 40 Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ? A) 12 B) 14 C) 9 D) 6 3 / 40 Merganning nishonga tekkizish ehtimoli 0,8 ga teng. U ishonga 2 marta o‘q uzganda o‘qlardan biri nishonga tegishining ehtimolligini toping. A) 0,8 B) 0,5 C) 0,16 D) 0,32 4 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (0; ∞) B) (-2; ∞) C) [-1; ∞) D) (-1; ∞) 5 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 0 B) 1 C) 2 D) 3 6 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 3 B) 4 C) 7,5 D) 4,5 7 / 40 Hisoblang: A) 2 B) 3 C) 1 D) 4 8 / 40 Soddalashtiring: A) 1 B) 3 C) Aniqlab bo`lmaydi D) 2 9 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUB B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUB 3-EKUK D) 1-EKUB 2-EKUK 3-EKUK 10 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 14° B) 17° C) 24° D) 7° 11 / 40 Integralni hisoblang: A) 1 B) 4 C) 2 D) 3 12 / 40 Funksiyaning aniqlanish sohasini toping. A) [-3;2] B) (-∞;3]∪[2;∞) C) (-∞;0)∪(0;∞) D) x∈R 13 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 2 D) 4 14 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BD = BC C) DC < AD D) BC > AD 15 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 121 C) berilganlar yetarli emas D) 11 16 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 23 D) 14 17 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 1/32 D) 0 18 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 19 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 8 C) 6√7 D) 10 20 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 2 D) 3 21 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) π/4+πk, k∈Z C) Ø D) 0 22 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 64 D) 42 23 / 40 √3 A) 5/5 B) 21/10 C) 7/3 D) 3/2 24 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 10 D) 20 25 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 4√2 C) 3√2 D) 6 26 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 25 D) 100 27 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) 5 D) -2 28 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 6 C) 12 D) 10 29 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 32 C) 30 D) 24 30 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√3 C) 2√2 D) 4√3 31 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 8 D) 6 32 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 50° C) 20° D) 40° 33 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 11 D) 4 34 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 3 D) 2 35 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 14 C) 10 D) 20 36 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 3 C) 2 D) 4 37 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,0(4) C) 0,04 D) 0,(04) 38 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) 1 C) cd/b D) bc/d 39 / 40 Hisoblang: A) cos50° B) 1 C) sin10° D) cos10° 40 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 3 yoki –8 C) 4 yoki –12 D) 6 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
