Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 40 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping. A) 20 B) 16 C) aniqlab bo‘lmaydi D) 18 2 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 4 B) 1 C) 2 D) 3 3 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 4 B) 3 C) aniqlab bo‘lmaydi D) 2 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) √5 B) √5+5 C) 5 D) 2√5 5 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 1 B) 2 C) 3 D) 4 6 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) 1 B) 2 C) √3 D) √2 7 / 40 Soddalshtiring. A) 1 B) -1 C) 2 D) 6 8 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 64/5 C) 48/5 D) 16 9 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 30° B) 40° C) 10° D) 20° 10 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/8 B) √3/4 C) 1/8 D) √2/8 11 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 16 B) 32 C) 64 D) 48 12 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) x∈R C) [-3;2] D) (-∞;3]∪[2;∞) 13 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 42 D) 32 14 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 42 C) 43 D) 44 15 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 2 C) 3 D) 1 16 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 35 C) 14 D) 24 17 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 7 D) 6 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 11 C) 9 D) 12 19 / 40 Hisoblang: A) 1 B) cos10° C) sin10° D) cos50° 20 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 25 D) 100 21 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 2√3 C) 3√2 D) 4√3 22 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) 4 √3tg50° tg70° C) √3ctg40° tg70° D) √3tg50° tg70° 23 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 10 C) 5 D) 11 24 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 4√7 D) 10 25 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 64 C) 8(π+2) D) 16(π-2) 26 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 3√2 C) 4√3 D) 4√2 27 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (7; 2), (28; -1) D) (2; 3) 28 / 40 Hisoblang: A) 20/21 B) 9/10 C) 19/20 D) 10/11 29 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) cd/b C) bd/c D) bc/d 30 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 22 C) 11 D) 121 31 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 3 yoki –8 D) 5 yoki –15 32 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 116 C) 112 D) 115 33 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 30° C) 50° D) 40° 34 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 10 D) 8 35 / 40 Hisoblang: A) -√3/2 B) 1/32 C) -1/2 D) 0 36 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 37 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 20 C) 10 D) 8 38 / 40 bo‘lsa, A) 2/3 B) 2 C) 3/2 D) 1 39 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 40 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 32 C) 28 D) 24 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
