Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №3 Matematika attestatsiya Matematika attestatsiya №3 InfoMaster Yanvar 15, 2022 78 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 8 ovozlar, 3.8 avg 0 123456789101112131415161718192021222324252627282930313233343536373839 Matematika fanidan attestatsiya savollari №3 1 / 39 bo‘lsa, x + y ni toping. A) 20 B) 16 C) 17 D) 18 2 / 39 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 25 B) 16 C) 9 D) 4 3 / 39 va bo'lsa x-y=? A) 5 B) 8 C) 9 D) 7 4 / 39 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2 B) 4 C) 3 D) 2,5 5 / 39 Berilgan sonlarning yig’indisini toping. A) 2/4 B) 1/4 C) 3/18 D) -452/18 6 / 39 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 108 B) 96 C) 114 D) 126 7 / 39 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) √3 B) 1 C) 2 D) √2 8 / 39 tenglamani yeching. A) 5 B) 3 C) log(3/5)2 D) log(5/3)2 9 / 39 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5+5 C) 5 D) √5 10 / 39 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)=x²-x+5 B) f(x)+2x²-1 C) f(x)=x²-4 D) f(x)=x²+3x+7 11 / 39 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln5 B) ln2 C) ln3 D) ln4 12 / 39 Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) 2√14+√6 B) √6+√14 C) 16 D) 18 13 / 39 cosx=0,2x tenglama nechta yechimga ega? A) 2 B) 4 C) 3 D) 1 14 / 39 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,5 m yoki 50 cm B) 0,9 m yoki 90 cm C) 0,6 m yoki 60 cm D) 0,7 m yoki 70 cm 15 / 39 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 0 B) 4 C) 2 D) 6 16 / 39 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 1 B) 5 C) 12 D) 7 17 / 39 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 40° B) 30° C) 20° D) 10° 18 / 39 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 5 B) 4 C) 3 D) 6 19 / 39 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 120° B) 110° C) 100° D) 130° 20 / 39 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 40 B) 32 C) 36 D) 34 21 / 39 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 2 B) 3 C) 1 D) 4 22 / 39 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 3 B) 2 C) 4 D) 1 23 / 39 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUK B) 1-EKUB 2-EKUB 3-EKUK C) 1-EKUB 2-EKUB 3-EKUB D) 1-EKUB 2-EKUK 3-EKUB 24 / 39 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 16 B) 64/5 C) 10 D) 48/5 25 / 39 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 20 km B) 200 km C) 2 km D) 0,2km 26 / 39 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 6 C) 8 D) 9 27 / 39 Soddalshtiring. A) 1 B) 6 C) -1 D) 2 28 / 39 Hisoblang: -121+(-135)-(-1)28 A) -1 B) 0 C) -2 D) -3 29 / 39 Soddalashtiring. A) (a-1)/(1-b) B) (b+2)/(1-b) C) (a+1)/(-a-3) D) (a-1)/(a-3) 30 / 39 x ni toping ? A) 6 B) 4 C) 3 D) 5 31 / 39 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 13 B) 12 C) 11 D) 10 32 / 39 Hisoblang 200−199+198−197+⋯+4−3 A) 101 B) 100 C) 99 D) 98 33 / 39 Hisoblang: A) 1 B) 4 C) 3 D) 2 34 / 39 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 3 B) 4 C) 1 D) 2 35 / 39 Soddalashtiring: A) 2 B) Aniqlab bo`lmaydi C) 3 D) 1 36 / 39 Hisoblang? A) 0,25 B) 2 C) 4 D) 0,5 37 / 39 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 11 B) 14 C) 13 D) 12 38 / 39 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (32π)/3 B) (29π)/3 C) 11π D) (28π)/3 39 / 39 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b,d B) )a,b,d C) a,b D) b O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
