Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №3 Matematika attestatsiya Matematika attestatsiya №3 InfoMaster Yanvar 15, 2022 101 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 8 ovozlar, 3.8 avg 0 123456789101112131415161718192021222324252627282930313233343536373839 Matematika fanidan attestatsiya savollari №3 1 / 39 bo‘lsa, x + y ni toping. A) 20 B) 18 C) 17 D) 16 2 / 39 tenglamalar sistemasi yechimga ega bo‘ladigan a ning barcha qiymatlari to‘plamini toping. A) 1 B) 4 C) 3 D) 2 3 / 39 Agar va bo'lsa f(4) ning qiymatini toping. A) 35 B) 12 C) 11 D) 4 4 / 39 Agar bo'lsa ifodaning qiymatini toping. A) 0 B) 9 C) 7 D) 13 5 / 39 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 28 B) 21 C) 24 D) 32 6 / 39 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13sinx-sin13x + C B) -13cosx- cos13 x +C C) 13cosx-cos13x + C D) 13sinx+sin13x + C 7 / 39 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/4 B) 1/3 C) 4 D) 1/5 8 / 39 Hisoblang: A) 27 B) 7 C) 4 D) 9 9 / 39 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)=x²-4 B) f(x)=x²+3x+7 C) f(x)=x²-x+5 D) f(x)+2x²-1 10 / 39 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 1 B) 2 C) 3 D) 4 11 / 39 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 50 B) 44 C) 40 D) 46 12 / 39 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 68/15 B) 67/15 C) 11/5 D) 31/85 13 / 39 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln3 B) ln5 C) ln2 D) ln4 14 / 39 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5 C) √5+5 D) 5 15 / 39 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 2 B) 4 C) 8 D) 6 16 / 39 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 20° B) 30° C) 40° D) 10° 17 / 39 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 130° B) 110° C) 100° D) 120° 18 / 39 Soddalashtiring. A) (b+2)/(1-b) B) (a-1)/(a-3) C) (a+1)/(-a-3) D) (a-1)/(1-b) 19 / 39 Soddalshtiring. A) 6 B) 2 C) -1 D) 1 20 / 39 Hisoblang: -121+(-135)-(-1)28 A) 0 B) -1 C) -2 D) -3 21 / 39 Hisoblang: A) 3 B) 1 C) 2 D) 4 22 / 39 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 34 B) 40 C) 32 D) 36 23 / 39 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 6 C) 8 D) 9 24 / 39 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 64/5 B) 16 C) 10 D) 48/5 25 / 39 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) 11π B) (32π)/3 C) (29π)/3 D) (28π)/3 26 / 39 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 4 B) 3 C) 1 D) 2 27 / 39 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 3 B) 2 C) 4 D) 1 28 / 39 Soddalashtiring: A) 2 B) 3 C) Aniqlab bo`lmaydi D) 1 29 / 39 x ni toping ? A) 5 B) 6 C) 3 D) 4 30 / 39 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b,d B) a,b C) b D) )a,b,d 31 / 39 Hisoblang? A) 0,5 B) 0,25 C) 4 D) 2 32 / 39 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 7 B) 5 C) 12 D) 1 33 / 39 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 5 B) 6 C) 3 D) 4 34 / 39 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 12 B) 13 C) 11 D) 14 35 / 39 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 11 B) 12 C) 10 D) 13 36 / 39 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 3 B) 4 C) 2 D) 1 37 / 39 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 2 km B) 200 km C) 0,2km D) 20 km 38 / 39 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUB 3-EKUK B) 1-EKUB 2-EKUK 3-EKUK C) 1-EKUB 2-EKUB 3-EKUB D) 1-EKUB 2-EKUK 3-EKUB 39 / 39 Hisoblang 200−199+198−197+⋯+4−3 A) 98 B) 99 C) 101 D) 100 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16