Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №3 Matematika attestatsiya Matematika attestatsiya №3 InfoMaster Yanvar 15, 2022 105 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 8 ovozlar, 3.8 avg 0 123456789101112131415161718192021222324252627282930313233343536373839 Matematika fanidan attestatsiya savollari №3 1 / 39 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 4 B) 3 C) 2 D) aniqlab bo‘lmaydi 2 / 39 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 2 B) 1 C) 4 D) 3 3 / 39 1:(2:3) son 1:2:3 sonidan qanchaga katta? A) 9 B) 3 C) 6 D) 4/3 4 / 39 Qayiq daryo oqimga qarshi 48 km va oqim bo‘yicha ham shuncha yo‘l bosib, butun yo‘lga 5 soat vaqt sarfladi. Daryo oqimining tezligi 4 km/soat bo‘lsa, qayiqning xususiy tezligini toping. A) 18 B) 22 C) 20 D) 25 5 / 39 |x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping. A) 0 B) 7 C) 6 D) 5 6 / 39 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5+5 C) √5 D) 5 7 / 39 Aniq integralni hisoblang: A) 2 B) 0,5 C) 3 D) 0 8 / 39 cosx=0,2x tenglama nechta yechimga ega? A) 4 B) 1 C) 2 D) 3 9 / 39 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 2 B) 8 C) 6 D) 4 10 / 39 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,5 m yoki 50 cm B) 0,6 m yoki 60 cm C) 0,7 m yoki 70 cm D) 0,9 m yoki 90 cm 11 / 39 Hisoblang: A) 7 B) 27 C) 9 D) 4 12 / 39 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) x=a B) y=-a C) x=-a D) y=1-a 13 / 39 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)=x²+3x+7 B) f(x)=x²-4 C) f(x)+2x²-1 D) f(x)=x²-x+5 14 / 39 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 11/5 B) 67/15 C) 31/85 D) 68/15 15 / 39 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-2; ∞) B) [-1; ∞) C) (0; ∞) D) (-1; ∞) 16 / 39 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 7 B) 12 C) 1 D) 5 17 / 39 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b B) b,d C) a,b D) )a,b,d 18 / 39 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 5 B) 4 C) 6 D) 3 19 / 39 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 11 B) 12 C) 13 D) 14 20 / 39 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUK B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUK 3-EKUB D) 1-EKUB 2-EKUB 3-EKUK 21 / 39 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 3 B) 4 C) 2 D) 1 22 / 39 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 0,2km B) 2 km C) 200 km D) 20 km 23 / 39 Soddalshtiring. A) -1 B) 1 C) 6 D) 2 24 / 39 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 13 B) 10 C) 11 D) 12 25 / 39 Hisoblang: A) 1 B) 2 C) 3 D) 4 26 / 39 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 36 B) 40 C) 32 D) 34 27 / 39 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 3 B) 1 C) 4 D) 2 28 / 39 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 16 C) 64/5 D) 48/5 29 / 39 Soddalashtiring: A) 2 B) Aniqlab bo`lmaydi C) 3 D) 1 30 / 39 Hisoblang: -121+(-135)-(-1)28 A) -2 B) -1 C) 0 D) -3 31 / 39 Hisoblang? A) 0,25 B) 2 C) 0,5 D) 4 32 / 39 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 30° B) 20° C) 40° D) 10° 33 / 39 Hisoblang 200−199+198−197+⋯+4−3 A) 99 B) 101 C) 100 D) 98 34 / 39 Soddalashtiring. A) (a-1)/(a-3) B) (a+1)/(-a-3) C) (a-1)/(1-b) D) (b+2)/(1-b) 35 / 39 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 1 B) 3 C) 4 D) 2 36 / 39 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 8 C) 6 D) 9 37 / 39 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) 11π B) (28π)/3 C) (29π)/3 D) (32π)/3 38 / 39 x ni toping ? A) 6 B) 5 C) 3 D) 4 39 / 39 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 110° B) 130° C) 120° D) 100° O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
