Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №3 Matematika attestatsiya Matematika attestatsiya №3 InfoMaster Yanvar 15, 2022 76 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 8 ovozlar, 3.8 avg 0 123456789101112131415161718192021222324252627282930313233343536373839 Matematika fanidan attestatsiya savollari №3 1 / 39 bo‘lsa, x + y ni toping. A) 16 B) 20 C) 18 D) 17 2 / 39 Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ? A) 6 B) 14 C) 9 D) 12 3 / 39 180 gramm suvga 70 gramm tuz aralashtrildi. Hosil bo‘lgan aralashmaninmg necha foizi suvdan iborat? A) 75 B) 78 C) 70 D) 72 4 / 39 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 4 B) aniqlab bo‘lmaydi C) 3 D) 2 5 / 39 Agar bo‘lsa, x ni toping. A) -2 B) 5 C) -5 D) 2 6 / 39 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,7 m yoki 70 cm B) 0,6 m yoki 60 cm C) 0,5 m yoki 50 cm D) 0,9 m yoki 90 cm 7 / 39 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 7 B) 1 C) 3 D) 9 8 / 39 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 108 B) 96 C) 126 D) 114 9 / 39 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 3 B) 1 C) 2 D) 4 10 / 39 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) -13cosx- cos13 x +C B) 13cosx-cos13x + C C) 13sinx-sin13x + C D) 13sinx+sin13x + C 11 / 39 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/3 B) 1/4 C) 4 D) 1/5 12 / 39 Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) 16 B) 2√14+√6 C) √6+√14 D) 18 13 / 39 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)+2x²-1 B) f(x)=x²-x+5 C) f(x)=x²+3x+7 D) f(x)=x²-4 14 / 39 Aniq integralni hisoblang: A) 3 B) 2 C) 0 D) 0,5 15 / 39 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x-2y+2=0 B) 3x-2y-2=0 C) 3x+2y+2=0 D) 3x+2y-2=0 16 / 39 Hisoblang 200−199+198−197+⋯+4−3 A) 101 B) 99 C) 100 D) 98 17 / 39 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 4 B) 3 C) 1 D) 2 18 / 39 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 13 B) 11 C) 12 D) 14 19 / 39 Soddalashtiring: A) 2 B) 1 C) 3 D) Aniqlab bo`lmaydi 20 / 39 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b B) a,b C) )a,b,d D) b,d 21 / 39 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 1 B) 5 C) 12 D) 7 22 / 39 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUB B) 1-EKUB 2-EKUB 3-EKUK C) 1-EKUB 2-EKUK 3-EKUK D) 1-EKUB 2-EKUB 3-EKUB 23 / 39 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 200 km B) 2 km C) 20 km D) 0,2km 24 / 39 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) 11π B) (32π)/3 C) (28π)/3 D) (29π)/3 25 / 39 x ni toping ? A) 6 B) 3 C) 4 D) 5 26 / 39 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 8 B) 7 C) 9 D) 6 27 / 39 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 130° B) 100° C) 110° D) 120° 28 / 39 Hisoblang: -121+(-135)-(-1)28 A) -2 B) -1 C) 0 D) -3 29 / 39 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 3 B) 4 C) 2 D) 1 30 / 39 Soddalashtiring. A) (a-1)/(1-b) B) (a-1)/(a-3) C) (a+1)/(-a-3) D) (b+2)/(1-b) 31 / 39 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 16 C) 64/5 D) 48/5 32 / 39 Hisoblang? A) 2 B) 0,5 C) 0,25 D) 4 33 / 39 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 11 B) 10 C) 12 D) 13 34 / 39 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 10° B) 20° C) 30° D) 40° 35 / 39 Hisoblang: A) 1 B) 2 C) 3 D) 4 36 / 39 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 2 B) 1 C) 3 D) 4 37 / 39 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 34 B) 32 C) 40 D) 36 38 / 39 Soddalshtiring. A) 1 B) -1 C) 6 D) 2 39 / 39 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 3 C) 5 D) 6 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
