Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 100 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 Savollar 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Qayiq daryo oqimga qarshi 48 km va oqim bo‘yicha ham shuncha yo‘l bosib, butun yo‘lga 5 soat vaqt sarfladi. Daryo oqimining tezligi 4 km/soat bo‘lsa, qayiqning xususiy tezligini toping. A) 22 B) 25 C) 20 D) 18 2 / 40 tengsizlikni yeching. A) x∈(-∞;5) B) x∈(-3;1) C) x∈(-∞;5)∪(-3;1) D) x∈(-5;1) 3 / 40 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 28 B) 32 C) 24 D) 21 4 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 7 B) 3 C) 9 D) 1 5 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)+2x²-1 B) f(x)=x²+3x+7 C) f(x)=x²-x+5 D) f(x)=x²-4 6 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 3 B) 4 C) 2 D) 1 7 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 64/5 C) 48/5 D) 16 8 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 100 B) 98 C) 99 D) 101 9 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 40° B) 20° C) 10° D) 30° 10 / 40 Integralni hisoblang: A) 1 B) 3 C) 2 D) 4 11 / 40 tenglama intervalda nechta ildizga ega? A) 2 B) 4 C) 1 D) 3 12 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 9 B) 3 C) 6 D) 12 13 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) DC < AD C) AB = BC D) BD = BC 14 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 1 D) 3 15 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 11 C) 6 D) 4 16 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 20 D) 8 17 / 40 √3 A) 7/3 B) 21/10 C) 5/5 D) 3/2 18 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 10 D) 14 19 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√3 C) 3√2 D) 4√2 20 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -3 C) 5 D) -6 21 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 22 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 4 yoki –12 C) 6 D) 5 yoki –15 23 / 40 sonlarini taqqolsang. A) c B) c C) a D) b 24 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 24 C) 32 D) 30 25 / 40 Hisoblang: A) cos50° B) sin10° C) cos10° D) 1 26 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 14 C) 23 D) 24 27 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 5 C) 8 D) -2 28 / 40 Tenglamani yeching: A) -6; 5 B) -6 C) 5 D) 6; -5 29 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 22 D) 11 30 / 40 bo‘lsa, A) 2 B) 2/3 C) 1 D) 3/2 31 / 40 Hisoblang: A) 10/11 B) 20/21 C) 19/20 D) 9/10 32 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(2) C) 0,04 D) 0,0(4) 33 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 3 C) 2 D) 1 34 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 3 C) 1 D) 2 35 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 16(π-2) C) 64 D) 8(π+2) 36 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) -π/4+πk, k∈Z D) 0 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 10 C) 8 D) 12 38 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 39 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 2 C) 4 D) 3 40 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 32 D) 42 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16