Matematika attestatsiya №5 Yanvar 24, 2022Yanvar 24, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №5 ga fikr bildirilmagan. 0% 2 ovozlar, 1 o'rtacha 12 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin? A) 7 B) 27 C) 6 D) 9 2 / 40 |x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping. A) 0 B) 7 C) 5 D) 6 3 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16cos3x*cos5x B) 16sin3x*cos5x C) -16cos3x*sin5x D) 16sin3x*sin5x 4 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 4 B) 1 C) 2 D) 3 5 / 40 tenglamani yeching. A) log(5/3)2 B) 3 C) log(3/5)2 D) 5 6 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 13 B) 9,25 C) 5,75 D) 6 7 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 10 B) 11 C) 12 D) 13 8 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 3 B) 2 C) 4 D) 1 9 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 99 B) 100 C) 98 D) 101 10 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 3 B) 2 C) 1 D) 4 11 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 135° B) 132° C) 138° D) 142° 12 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) √3R(2-√3) B) 3R C) 1,5R D) R(√3-√2) 13 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -6 C) 5 D) -4 14 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 13 C) 15 D) 12 15 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 10 C) 14 D) 20 16 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 42 D) 64 17 / 40 Hisoblang: A) -√3/2 B) 0 C) -1/2 D) 1/32 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 10 C) 12 D) 11 19 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,(04) C) 0,0(2) D) 0,0(4) 20 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 11 C) 4 D) 5 21 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 121 C) 11 D) berilganlar yetarli emas 22 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) 8 D) -2 23 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 50° D) 30° 24 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 2√3 D) 3√2 25 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 30 C) 32 D) 28 26 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 4 yoki –12 D) 6 27 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 2 C) 3 D) 1 28 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 6 C) 5 D) 8 29 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 2 C) 4 D) 3 30 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 31 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 15 C) 8 D) 20 32 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 2 D) 1 33 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BC > AD C) BD = BC D) AB = BC 34 / 40 Hisoblang: A) 10/11 B) 9/10 C) 20/21 D) 19/20 35 / 40 √3 A) 21/10 B) 3/2 C) 7/3 D) 5/5 36 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) 0 37 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 11 D) 10 38 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 4√7 C) 6√7 D) 8 39 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 25 C) 105 D) 96 40 / 40 sonlarini taqqolsang. A) c B) b C) c D) a O'rtacha ball 77% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya