Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, ning qiymatini toping. A) 0,7 B) 2 C) 0,5 D) 1 2 / 40 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 28 B) 24 C) 21 D) 32 3 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 4 B) 2 C) 1 D) 3 4 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 4,5 B) 3 C) 7,5 D) 4 5 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;-1)∪(-1;1)∪(1;√2] B) [-√2;√2] C) [-√2;0)∪(0;√2] D) (-2√2;√2) 6 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)+2x²-1 B) f(x)=x²+3x+7 C) f(x)=x²-4 D) f(x)=x²-x+5 7 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 48/5 B) 16 C) 10 D) 64/5 8 / 40 Soddalashtiring. A) (b+2)/(1-b) B) (a-1)/(1-b) C) (a-1)/(a-3) D) (a+1)/(-a-3) 9 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 101 B) 99 C) 98 D) 100 10 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 25 B) 41 C) 32 D) 50 11 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 5 B) 0 C) 8 D) 1 12 / 40 tenglama intervalda nechta ildizga ega? A) 2 B) 3 C) 4 D) 1 13 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) Ø C) -π/4+πk, k∈Z D) π/4+πk, k∈Z 14 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,0(4) C) 0,(04) D) 0,04 15 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 5 yoki –15 C) 3 yoki –8 D) 6 16 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -3 C) 5 D) -6 17 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 6 C) 4√3 D) 4√2 18 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 11 C) 5 D) 6 19 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 22 C) 121 D) 11 20 / 40 Hisoblang: A) 0 B) -1/2 C) 1/32 D) -√3/2 21 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 8(π+2) C) 16(π-2) D) 64 22 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 3 C) 1 D) 2 23 / 40 Hisoblang: A) 20/21 B) 9/10 C) 19/20 D) 10/11 24 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 100 C) 25 D) 96 25 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 48 C) 32 D) 64 26 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) -2 D) 5 27 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) √3tg50° tg70° C) 4 √3tg50° tg70° D) 2√3tg50° tg70° 28 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 8 D) 20 29 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 4 D) 1 30 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 7 D) 5 31 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 14 C) 24 D) 23 32 / 40 Hisoblang: A) cos10° B) 1 C) sin10° D) cos50° 33 / 40 Tenglamani yeching: A) -6; 5 B) -6 C) 6; -5 D) 5 34 / 40 bo‘lsa, A) 3/2 B) 1 C) 2/3 D) 2 35 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (2; 3) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 36 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 12 C) 15 D) 13 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 6 C) 8 D) 12 38 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 39 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 5 C) 6 D) 8 40 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 43 D) 44 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16