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Matematika attestatsiya №5

InfoMaster

Yanvar 24, 2022

41 Ko'rishlar 1 izoh

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping.

A) 24

B) 32

C) 16

D) 8

2 / 40

ni 9 ga bo’lgandagi qoldiqning kvadratini toping.

A) 25

B) 4

C) 16

D) 9

3 / 40

Qayiq daryo oqimga qarshi 48 km va oqim bo‘yicha ham shuncha yo‘l bosib, butun yo‘lga 5 soat vaqt sarfladi. Daryo oqimining tezligi 4 km/soat bo‘lsa, qayiqning xususiy tezligini toping.

A) 25

B) 20

C) 22

D) 18

4 / 40

x⁴+8x³+ax²+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping.

A) 26

B) 32

C) 48

D) 27

5 / 40

Tengsizlikni yeching.

A) [-3;-2]

B) (-∞;-2]

C) [-3;2]∪{1}

D) [-2;1]∪{-3}

6 / 40

y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=?

A) 1/5

B) 1/3

C) 4

D) 1/4

7 / 40

Quyidakilardan qaysi biri juft:

2009⁵⁶+2008⁵⁵
3121⁰+0!
55!+87⁷
2²²+3³³+44⁴⁴

A) 3

B) 2

C) 4

D) 1

8 / 40

Soddalshtiring.

A) 1

B) -1

C) 2

D) 6

9 / 40

Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ?

A) 12

B) 10

C) 13

D) 11

10 / 40

Hisoblang:

A) 4

B) 0

C) 6

D) 8

11 / 40

Agar x²-6x+7=0 bo‘lsa, ni toping.

A) 48

B) 52

C) 40

D) 28

12 / 40

Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping.

A) 25

B) 35

C) 20

D) 40

13 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 3

B) 2

C) 4

D) 1

14 / 40

bo‘lsa,

A) 2

B) 3/2

C) 1

D) 2/3

15 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) 0

B) Ø

C) -π/4+πk, k∈Z

D) π/4+πk, k∈Z

16 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 3

B) 1

C) 2

D) 4

17 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 3

B) 2

C) 1

D) 4

18 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) √3ctg40° tg70°

B) √3tg50° tg70°

C) 4 √3tg50° tg70°

D) 2√3tg50° tg70°

19 / 40

Tenglamalar sistemani yeching:

A) (2; 3)

B) (9; 0), (2; 7)

C) (7; 2), (28; -1)

D) (9; 0), (28; -1)

20 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√3

B) 4√3

C) 3√2

D) 2√2

21 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 115

B) 116

C) 110

D) 112

22 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 4

B) 1

C) 3

D) 2

23 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -3

B) -4

C) 5

D) -6

24 / 40

Rasmdagi shakl perimetrini toping.

A) 32

B) 30

C) 24

D) 28

25 / 40

sonlarini taqqolsang.

A) c

B) c

C) b

D) a

26 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 14

B) 15

C) 13

D) 12

27 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 6√7

B) 4√7

C) 10

D) 8

28 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 121

B) 22

C) 11

D) berilganlar yetarli emas

29 / 40

Hisoblang:

A) 10/11

B) 9/10

C) 20/21

D) 19/20

30 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 12

B) 20

C) 14

D) 10

31 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) bc/d

B) cd/b

C) 1

D) bd/c

32 / 40

√3

A) 3/2

B) 21/10

C) 5/5

D) 7/3

33 / 40

Hisoblang:

A) cos10°

B) sin10°

C) 1

D) cos50°

34 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 45

B) 43

C) 42

D) 44

35 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 48

B) 64

C) 32

D) 42

36 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) AB = BC

B) BC > AD

C) DC < AD

D) BD = BC

37 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 4

B) 11

C) 5

D) 6

38 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 5

C) 6

D) 8

39 / 40

Chizmadan foydalanib α ni toping.

A) 50°

B) 30°

C) 40°

D) 20°

40 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 6

B) 12

C) 10

D) 8