Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 41 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar ni hisoblang. A) 9 B) 8 C) 0 D) Cheksiz 2 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) c>a>b B) a>b>c C) b>a>c D) a>c>b 3 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 4 B) 2 C) 3 D) 1 4 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) 2 B) √3 C) √2 D) 1 5 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 48 B) 32 C) 26 D) 27 6 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 5,75 B) 6 C) 9,25 D) 13 7 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 12 B) 5 C) 7 D) 1 8 / 40 Soddalashtiring: A) 3 B) Aniqlab bo`lmaydi C) 1 D) 2 9 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 3 C) 4 D) 1 10 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) x∈R C) [-3;2] D) (-∞;3]∪[2;∞) 11 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) 4 B) √17 C) -4 D) -√17 12 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 20 B) 25 C) 35 D) 40 13 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 14 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 22 C) berilganlar yetarli emas D) 11 15 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 4 D) 3 16 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 24 C) 14 D) 23 17 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) cd/b C) bc/d D) bd/c 18 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 10 C) 20 D) 14 19 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 20 / 40 bo‘lsa, A) 2/3 B) 1 C) 3/2 D) 2 21 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 105 C) 96 D) 100 22 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 2√3tg50° tg70° C) 4 √3tg50° tg70° D) √3tg50° tg70° 23 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 8 D) 10 24 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 5 C) 7 D) 10 25 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 5 C) 8 D) -2 26 / 40 Tenglamani yeching: A) 6; -5 B) -6; 5 C) 5 D) -6 27 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 4√3 C) 2√2 D) 3√2 28 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 30° D) 50° 29 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 3 C) 2 D) 4 30 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) -π/4+πk, k∈Z C) π/4+πk, k∈Z D) 0 31 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(2) C) 0,04 D) 0,0(4) 32 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 33 / 40 Hisoblang: A) cos10° B) sin10° C) 1 D) cos50° 34 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 3 C) 1 D) 2 35 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 20 C) 15 D) 8 36 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 2 D) 1 37 / 40 √3 A) 3/2 B) 21/10 C) 7/3 D) 5/5 38 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 39 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 110 C) 115 D) 112 40 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 5 yoki –15 D) 3 yoki –8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
