Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 37 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 24 B) 12 C) 30 D) 18 2 / 40 180 gramm suvga 70 gramm tuz aralashtrildi. Hosil bo‘lgan aralashmaninmg necha foizi suvdan iborat? A) 72 B) 78 C) 70 D) 75 3 / 40 ko’paytmani hisoblang. A) 86420000 B) 480000 C) 10000 D) 0 4 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 3 B) 1 C) 9 D) 7 5 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 5 B) √5 C) √5+5 D) 2√5 6 / 40 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x-2y-2=0 B) 3x-2y+2=0 C) 3x+2y+2=0 D) 3x+2y-2=0 7 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 120° B) 100° C) 130° D) 110° 8 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 8 C) 9 D) 6 9 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 13 B) 10 C) 11 D) 12 10 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 28 B) 48 C) 40 D) 52 11 / 40 Hisoblang: A) 4 B) 6 C) 0 D) 8 12 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 12 B) 9 C) 7 D) 15 13 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 7 C) 8 D) 5 14 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 3 D) 2 15 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 7 C) 11 D) 5 16 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 25 C) 96 D) 105 17 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 42 D) 64 18 / 40 Hisoblang: A) 1/32 B) -1/2 C) 0 D) -√3/2 19 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 11 D) 4 20 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 21 / 40 bo‘lsa, A) 3/2 B) 2 C) 2/3 D) 1 22 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) π/4+πk, k∈Z C) 0 D) Ø 23 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 6 D) 3 yoki –8 24 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 3√2 C) 4√3 D) 2√2 25 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,(04) D) 0,0(4) 26 / 40 Hisoblang: A) 10/11 B) 20/21 C) 19/20 D) 9/10 27 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) berilganlar yetarli emas C) 11 D) 121 28 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 2 C) 1 D) 4 29 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 2 D) 1 30 / 40 √3 A) 3/2 B) 5/5 C) 7/3 D) 21/10 31 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 3√2 C) 4√3 D) 6 32 / 40 Hisoblang: A) 1 B) sin10° C) cos50° D) cos10° 33 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 110 D) 115 34 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 30° D) 50° 35 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 30 C) 32 D) 24 36 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 37 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 24 C) 35 D) 14 38 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 42 D) 44 39 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 9 C) 10 D) 12 40 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 12 D) 13 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
