Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 57 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 2 B) 3 C) 4 D) 1 2 / 40 Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping. A) 18 B) aniqlab bo‘lmaydi C) 20 D) 16 3 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 58 B) 59 C) 61 D) 60 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) √5+5 B) 5 C) 2√5 D) √5 5 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;√2] B) [-√2;-1)∪(-1;1)∪(1;√2] C) (-2√2;√2) D) [-√2;0)∪(0;√2] 6 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 1 B) 9 C) 3 D) 7 7 / 40 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 13 B) 12 C) 14 D) 11 8 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 8 C) 9 D) 6 9 / 40 Hisoblang: A) 4 B) 1 C) 2 D) 3 10 / 40 Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping. A) √6 B) 2,5 C) √5 D) 2,4 11 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 3 B) 2 C) 1 D) 4 12 / 40 Integralni hisoblang: A) 4 B) 3 C) 1 D) 2 13 / 40 √3 A) 7/3 B) 3/2 C) 21/10 D) 5/5 14 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 15 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 24 D) 30 16 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 43 C) 42 D) 45 17 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(4) C) 0,(04) D) 0,0(2) 18 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 14 C) 12 D) 20 19 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 5 D) 6 20 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 2 D) 4 21 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 6√7 C) 8 D) 10 22 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 48 C) 42 D) 64 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√3 C) 4√2 D) 6 24 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 2√3 D) 4√3 25 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 23 C) 35 D) 24 26 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 11 C) 10 D) 5 27 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 105 C) 96 D) 25 28 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 2 C) 4 D) 1 29 / 40 Hisoblang: A) 1/32 B) 0 C) -1/2 D) -√3/2 30 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 40° D) 30° 31 / 40 sonlarini taqqolsang. A) b B) c C) a D) c 32 / 40 Hisoblang: A) sin10° B) 1 C) cos10° D) cos50° 33 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) 2√3tg50° tg70° C) √3ctg40° tg70° D) √3tg50° tg70° 34 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 5 D) 6; -5 35 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 6 C) 7 D) 5 36 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 37 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 10 D) 20 38 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 39 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -4 C) -3 D) -6 40 / 40 Hisoblang: A) 10/11 B) 9/10 C) 20/21 D) 19/20 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
