Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 31 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 To’g’ri turt burchakning bo’yining perimetriga nisbatini toping. A) 3/18 B) 1/2 C) -452/18 D) 5/3 2 / 40 Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin? A) 27 B) 9 C) 6 D) 7 3 / 40 Berilgan sonlarning yig’indisini toping. A) 3/18 B) -452/18 C) 1/4 D) 2/4 4 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 96 B) 108 C) 126 D) 114 5 / 40 Hisoblang: A) 27 B) 4 C) 7 D) 9 6 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-1; ∞) B) [-1; ∞) C) (0; ∞) D) (-2; ∞) 7 / 40 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 12 B) 14 C) 11 D) 13 8 / 40 x ni toping ? A) 6 B) 4 C) 3 D) 5 9 / 40 Hisoblang? A) 0,5 B) 2 C) 0,25 D) 4 10 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 600 B) 5050 C) 3600 D) 4800 11 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 8 B) 9 C) 6 D) 10 12 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) 6 B) berilganlar yetarli emas C) 8 D) 10 13 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 14 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 15 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 7 C) 10 D) 5 16 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 6 D) 8 17 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) 0 18 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 32 C) 64 D) 48 19 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 4 C) 2 D) 3 20 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 20° D) 30° 21 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 44 D) 43 22 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 11 C) 9 D) 10 23 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 3√2 D) 2√3 24 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 12 D) 13 25 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 4 C) 2 D) 3 26 / 40 Tenglamani yeching: A) -6 B) 5 C) -6; 5 D) 6; -5 27 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 11 C) 4 D) 6 28 / 40 bo‘lsa, A) 2 B) 1 C) 3/2 D) 2/3 29 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 10 C) 14 D) 20 30 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BD = BC C) BC > AD D) DC < AD 31 / 40 Hisoblang: A) sin10° B) cos10° C) 1 D) cos50° 32 / 40 √3 A) 5/5 B) 3/2 C) 7/3 D) 21/10 33 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) berilganlar yetarli emas C) 11 D) 22 34 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) bc/d C) 1 D) cd/b 35 / 40 Hisoblang: A) 0 B) -1/2 C) -√3/2 D) 1/32 36 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 8 D) 10 37 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 30 C) 28 D) 32 38 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 25 C) 105 D) 100 39 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 3 C) 2 D) 1 40 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 4 D) 2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16