Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 2 B) 4 C) 1 D) 3 2 / 40 Agar bo'lsa, x ni toping. A) 2 B) -2 C) 5 D) -5 3 / 40 tengsizlikni yeching. A) 3 B) 2 C) 4 D) 1 4 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) √2 B) 2 C) 1 D) √3 5 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13sinx+sin13x + C B) 13sinx-sin13x + C C) 13cosx-cos13x + C D) -13cosx- cos13 x +C 6 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;√2] B) [-√2;-1)∪(-1;1)∪(1;√2] C) [-√2;0)∪(0;√2] D) (-2√2;√2) 7 / 40 Hisoblang: -121+(-135)-(-1)28 A) -2 B) -1 C) -3 D) 0 8 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 20° B) 10° C) 30° D) 40° 9 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (28π)/3 B) 11π C) (29π)/3 D) (32π)/3 10 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 132° B) 135° C) 142° D) 138° 11 / 40 Tenglamani yeching: A) 5/9 B) 5*4 C) 9/5 D) 6/5 12 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 72π B) 96π C) 192π D) 144π 13 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 14 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 42 D) 32 15 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 4 D) 6 16 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 110 C) 115 D) 116 17 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 50° D) 30° 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 11 C) 9 D) 10 19 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 44 C) 42 D) 43 20 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 13 C) 14 D) 12 21 / 40 √3 A) 7/3 B) 5/5 C) 21/10 D) 3/2 22 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 35 C) 14 D) 24 23 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 3√2 C) 2√2 D) 4√3 24 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) cd/b C) 1 D) bd/c 25 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 3 C) 4 D) 2 26 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,(04) C) 0,0(4) D) 0,0(2) 27 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) 2√3tg50° tg70° C) 4 √3tg50° tg70° D) √3tg50° tg70° 28 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 30 C) 24 D) 32 29 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -3 C) -6 D) 5 30 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 1 C) 2 D) 4 31 / 40 bo‘lsa, A) 1 B) 3/2 C) 2 D) 2/3 32 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 5 C) 8 D) -2 33 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 34 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 4 yoki –12 C) 5 yoki –15 D) 6 35 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 4 D) 3 36 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 6 C) 7 D) 5 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 12 C) 8 D) 6 38 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 12 D) 14 39 / 40 Hisoblang: A) -1/2 B) 1/32 C) -√3/2 D) 0 40 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 11 C) 10 D) 5 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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