Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, ning qiymatini toping. A) 0,5 B) 0,7 C) 2 D) 1 2 / 40 ko’paytmani hisoblang. A) 86420000 B) 10000 C) 480000 D) 0 3 / 40 Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping. A) 20 B) 18 C) aniqlab bo‘lmaydi D) 16 4 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,9 m yoki 90 cm B) 0,7 m yoki 70 cm C) 0,6 m yoki 60 cm D) 0,5 m yoki 50 cm 5 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 13 B) 5,75 C) 9,25 D) 6 6 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 2 B) 4 C) 1 D) 3 7 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 9 C) 8 D) 6 8 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 5 B) 4 C) 6 D) 3 9 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 3 B) 2 C) 4 D) 1 10 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) 6 B) 8 C) 10 D) berilganlar yetarli emas 11 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 5 B) 1 C) 4 D) 2 12 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 1 B) 4 C) 3 D) 2 13 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 8 C) 4√7 D) 6√7 14 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) berilganlar yetarli emas C) 22 D) 121 15 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 2 C) 1 D) 3 16 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (2; 7) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 17 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 64 C) 32 D) 8(π+2) 18 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 5 C) 11 D) 4 19 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 6 D) 5 20 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 4 D) 2 21 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 110 C) 112 D) 116 22 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,04 D) 0,0(2) 23 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 10 C) 12 D) 9 24 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√3 C) 4√2 D) 3√2 25 / 40 bo‘lsa, A) 3/2 B) 2 C) 2/3 D) 1 26 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) -6 D) 6; -5 27 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 3 C) 8 D) 5 28 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) 1 D) bd/c 29 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) 5 C) -6 D) -3 30 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 10 C) 7 D) 5 31 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 2√3 D) 4√3 32 / 40 √3 A) 7/3 B) 21/10 C) 5/5 D) 3/2 33 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 34 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 13 C) 14 D) 12 35 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 30° C) 50° D) 20° 36 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) DC < AD C) BC > AD D) BD = BC 37 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 4 D) 2 38 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 20 C) 15 D) 8 39 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 6 C) 4 yoki –12 D) 5 yoki –15 40 / 40 Hisoblang: A) sin10° B) cos10° C) 1 D) cos50° O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
