Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 4 B) 2 C) 3 D) 1 2 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 60 B) 59 C) 61 D) 58 3 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n = 0, k > 0 B) n = 0, k < 0 C) n < 0, k = 0 D) n > 0, k = 0 4 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-2; ∞) B) (-1; ∞) C) [-1; ∞) D) (0; ∞) 5 / 40 Aniq integralni hisoblang: A) 3 B) 0 C) 2 D) 0,5 6 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 44 B) 40 C) 50 D) 46 7 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 1 C) 3 D) 4 8 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 30° B) 10° C) 20° D) 40° 9 / 40 Soddalshtiring. A) -1 B) 6 C) 2 D) 1 10 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,432 B) 0,216 C) 0,288 D) 0,144 11 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 80 B) 90 C) 100 D) 120 12 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) √3R(2-√3) B) 1,5R C) 3R D) R(√3-√2) 13 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 110 C) 115 D) 116 14 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 42 D) 64 15 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 10 C) 8 D) 6√7 16 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) cd/b D) 1 17 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 14 C) 35 D) 23 18 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 13 C) 15 D) 14 19 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 9 C) 10 D) 11 20 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 4 C) 3 D) 1 21 / 40 √3 A) 7/3 B) 3/2 C) 21/10 D) 5/5 22 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 10 D) 14 23 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (2; 7) C) (7; 2), (28; -1) D) (9; 0), (28; -1) 24 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) 22 D) berilganlar yetarli emas 25 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 96 C) 100 D) 25 26 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 2 C) 3 D) 4 27 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 20 D) 10 28 / 40 Hisoblang: A) cos50° B) 1 C) sin10° D) cos10° 29 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 8(π+2) C) 64 D) 16(π-2) 30 / 40 Hisoblang: A) 9/10 B) 19/20 C) 10/11 D) 20/21 31 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 6 D) 5 32 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 50° C) 20° D) 30° 33 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 10 C) 6 D) 8 34 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 4 D) 1 35 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 2 D) 3 36 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) 0 37 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 24 C) 28 D) 32 38 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 6 D) 8 39 / 40 bo‘lsa, A) 3/2 B) 2 C) 1 D) 2/3 40 / 40 sonlarini taqqolsang. A) c B) a C) c D) b O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
