Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 44 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Yig’indi quydagilardan qaysi biriga teng? A) 40560,8 B) 450,608 C) 45,0608 D) 4506,08 2 / 40 Agar ni hisoblang. A) Cheksiz B) 0 C) 9 D) 8 3 / 40 funksiyaning eng kichik musbat davrini toping. A) 26 B) 18 C) 24 D) 12 4 / 40 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 4 B) 6 C) 2 D) 0 5 / 40 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x-2y-2=0 B) 3x+2y-2=0 C) 3x+2y+2=0 D) 3x-2y+2=0 6 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 32 B) 48 C) 27 D) 26 7 / 40 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 11 B) 13 C) 12 D) 14 8 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) )a,b,d B) b,d C) a,b D) b 9 / 40 Soddalashtiring. A) (a+1)/(-a-3) B) (a-1)/(1-b) C) (b+2)/(1-b) D) (a-1)/(a-3) 10 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 0 B) 8 C) 1 D) 5 11 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 3 B) 4 C) 2 D) 1 12 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 135° B) 132° C) 138° D) 142° 13 / 40 sonlarini taqqolsang. A) c B) c C) b D) a 14 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 4 C) 3 D) 2 15 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 48 D) 42 16 / 40 Hisoblang: A) cos10° B) 1 C) cos50° D) sin10° 17 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (2; 3) D) (7; 2), (28; -1) 18 / 40 √3 A) 5/5 B) 3/2 C) 7/3 D) 21/10 19 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 24 C) 35 D) 23 20 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) 2√3tg50° tg70° D) √3ctg40° tg70° 21 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 6; -5 D) 5 22 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 22 C) 121 D) berilganlar yetarli emas 23 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 40° C) 50° D) 20° 24 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,0(2) D) 0,04 25 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -6 D) -4 26 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 15 C) 20 D) 8 27 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 10 C) 8 D) 12 28 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 10 C) 12 D) 20 29 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 4 C) 2 D) 3 30 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 3 D) 8 31 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 3 yoki –8 D) 6 32 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) 0 C) -π/4+πk, k∈Z D) Ø 33 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 10 D) 6√7 34 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 3 C) 4 D) 2 35 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 6 C) 5 D) 4 36 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 14 C) 15 D) 13 37 / 40 bo‘lsa, A) 3/2 B) 2 C) 2/3 D) 1 38 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) BC > AD D) AB = BC 39 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 6 C) 5 D) 8 40 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) cd/b D) 1 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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