Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ni qanoatlantiruvchi yechimlar nechta? A) 0 B) 3 C) 1 D) 2 2 / 40 Yig’indi quydagilardan qaysi biriga teng? A) 45,0608 B) 4506,08 C) 450,608 D) 40560,8 3 / 40 bo‘lsa, ning qiymatini toping. A) 1 B) 0,5 C) 0,7 D) 2 4 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 46 B) 44 C) 40 D) 50 5 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 25/3 B) 35/6 C) 8 D) 6 6 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,9 m yoki 90 cm B) 0,7 m yoki 70 cm C) 0,5 m yoki 50 cm D) 0,6 m yoki 60 cm 7 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 10° B) 40° C) 20° D) 30° 8 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUK B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUK 3-EKUB D) 1-EKUB 2-EKUB 3-EKUK 9 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 4 B) 3 C) 2 D) 1 10 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 15 B) 7 C) 9 D) 12 11 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) x∈R C) (-∞;3]∪[2;∞) D) [-3;2] 12 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 1/2 B) 1/3 C) 5/6 D) 8/15 13 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 48 D) 32 14 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 115 C) 112 D) 116 15 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 12 D) 13 16 / 40 Hisoblang: A) 19/20 B) 20/21 C) 10/11 D) 9/10 17 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 3 C) 2 D) 1 18 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) Ø C) 0 D) π/4+πk, k∈Z 19 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 50° D) 30° 20 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 25 D) 100 21 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 12 C) 10 D) 11 22 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) -2 D) 8 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√2 C) 6 D) 4√3 24 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) 1 C) bd/c D) cd/b 25 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 1 D) 4 26 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 24 D) 30 27 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (2; 3) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 28 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 6 C) 8 D) 5 29 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 24 D) 35 30 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) √3ctg40° tg70° C) 2√3tg50° tg70° D) 4 √3tg50° tg70° 31 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 0 D) 1/32 32 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 8 C) 15 D) 10 33 / 40 bo‘lsa, A) 2 B) 1 C) 3/2 D) 2/3 34 / 40 sonlarini taqqolsang. A) a B) c C) c D) b 35 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 6; -5 D) 5 36 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 6 C) 5 D) 4 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 10 C) 12 D) 6 38 / 40 Hisoblang: A) cos50° B) sin10° C) 1 D) cos10° 39 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 3 C) 4 D) 2 40 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 7 C) 11 D) 5 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
