Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 28 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ni hisoblang. A) e-1 B) e+1 C) (e+1)/2 D) (e-1)/2 2 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 59 B) 61 C) 60 D) 58 3 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 201 B) 200 C) 289 D) 203 4 / 40 Tengsizlikni yeching. A) [-2;1]∪{-3} B) [-3;-2] C) (-∞;-2] D) [-3;2]∪{1} 5 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,6 m yoki 60 cm B) 0,9 m yoki 90 cm C) 0,7 m yoki 70 cm D) 0,5 m yoki 50 cm 6 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 5,75 B) 13 C) 6 D) 9,25 7 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 64/5 B) 48/5 C) 10 D) 16 8 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 11 B) 10 C) 12 D) 13 9 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b,d B) )a,b,d C) b D) a,b 10 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 41 B) 50 C) 32 D) 25 11 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 72π B) 192π C) 96π D) 144π 12 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 4 B) 5 C) 6 D) 2 13 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 32 C) 64 D) 48 14 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,04 C) 0,(04) D) 0,0(2) 15 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 9 C) 10 D) 12 16 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) 2√3tg50° tg70° C) √3tg50° tg70° D) √3ctg40° tg70° 17 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 1 C) 2 D) 3 18 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 6 C) 5 D) 4 19 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 64 C) 8(π+2) D) 16(π-2) 20 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (2; 7) C) (7; 2), (28; -1) D) (9; 0), (28; -1) 21 / 40 Hisoblang: A) 20/21 B) 10/11 C) 9/10 D) 19/20 22 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) 5 C) -3 D) -6 23 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 43 C) 42 D) 45 24 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 3 C) 2 D) 4 25 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 26 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) bd/c D) 1 27 / 40 √3 A) 7/3 B) 5/5 C) 21/10 D) 3/2 28 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 5 C) 8 D) 6 29 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 35 C) 14 D) 24 30 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 24 D) 28 31 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 6 D) 3 yoki –8 32 / 40 bo‘lsa, A) 3/2 B) 1 C) 2/3 D) 2 33 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 115 D) 110 34 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 8 D) 10 35 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 4√3 D) 2√3 36 / 40 Hisoblang: A) 0 B) 1/32 C) -√3/2 D) -1/2 37 / 40 Hisoblang: A) 1 B) sin10° C) cos10° D) cos50° 38 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 8 D) 10 39 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 5 C) 3 D) 8 40 / 40 sonlarini taqqolsang. A) c B) c C) b D) a O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
