Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 41 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 2 B) 3 C) 4 D) 1 2 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) aniqlab bo‘lmaydi B) 4 C) 2 D) 3 3 / 40 ko’paytmani hisoblang. A) 10000 B) 86420000 C) 0 D) 480000 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5 C) 5 D) √5+5 5 / 40 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x-2y+2=0 B) 3x-2y-2=0 C) 3x+2y-2=0 D) 3x+2y+2=0 6 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,9 m yoki 90 cm B) 0,7 m yoki 70 cm C) 0,5 m yoki 50 cm D) 0,6 m yoki 60 cm 7 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 7 B) 1 C) 5 D) 12 8 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 1 C) 4 D) 3 9 / 40 Hisoblang? A) 2 B) 4 C) 0,5 D) 0,25 10 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 10 B) 30 C) 25 D) 0 11 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 138° B) 132° C) 135° D) 142° 12 / 40 Yig‘indini toping. A) 1/4 B) 1/9 C) 1/12 D) 1/6 13 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,(04) C) 0,0(4) D) 0,0(2) 14 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 3 C) -2 D) 5 15 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 45 D) 44 16 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 4 D) 6 17 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 3 D) 1 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 10 D) 12 19 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 6 C) 8 D) 5 20 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 13 C) 15 D) 14 21 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) 0 22 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 116 C) 115 D) 112 23 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 14 C) 23 D) 24 24 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 32 C) 48 D) 64 25 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 100 C) 25 D) 105 26 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 20 C) 12 D) 10 27 / 40 Tenglamani yeching: A) 6; -5 B) 5 C) -6; 5 D) -6 28 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 2 C) 4 D) 3 29 / 40 Hisoblang: A) -√3/2 B) 1/32 C) 0 D) -1/2 30 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 40° D) 30° 31 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) cd/b C) bd/c D) bc/d 32 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 4√3 D) 3√2 33 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 64 C) 16(π-2) D) 8(π+2) 34 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 3 D) 4 35 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 8 C) 6 D) 12 36 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (2; 7) C) (7; 2), (28; -1) D) (9; 0), (28; -1) 37 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -3 C) 5 D) -6 38 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√2 C) 4√3 D) 6 39 / 40 sonlarini taqqolsang. A) b B) c C) a D) c 40 / 40 Hisoblang: A) 19/20 B) 20/21 C) 10/11 D) 9/10 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
