Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 18 B) 30 C) 12 D) 24 2 / 40 Agar bo'lsa, x ni toping. A) 2 B) 5 C) -2 D) -5 3 / 40 bo‘lsa, ning qiymatini toping. A) 1 B) 2 C) 0,5 D) 0,7 4 / 40 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/3 B) 1/5 C) 1/4 D) 4 5 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 1 B) 3 C) 4 D) 2 6 / 40 tenglamani yeching. A) 5 B) log(5/3)2 C) log(3/5)2 D) 3 7 / 40 Soddalashtiring. A) (a-1)/(1-b) B) (b+2)/(1-b) C) (a-1)/(a-3) D) (a+1)/(-a-3) 8 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 6 C) 5 D) 3 9 / 40 Hisoblang: -121+(-135)-(-1)28 A) -1 B) 0 C) -3 D) -2 10 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 16 B) 64 C) 48 D) 32 11 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 1/2 B) 8/15 C) 1/3 D) 5/6 12 / 40 Yig‘indini toping. A) 1/9 B) 1/6 C) 1/4 D) 1/12 13 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) 2√3tg50° tg70° C) √3ctg40° tg70° D) √3tg50° tg70° 14 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 5 D) 7 15 / 40 Hisoblang: A) cos10° B) sin10° C) cos50° D) 1 16 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 13 C) 15 D) 12 17 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -6 C) 5 D) -4 18 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 20 C) 8 D) 10 19 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 24 C) 14 D) 35 20 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 11 C) 6 D) 5 21 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 6 C) 7 D) 8 22 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 28 C) 30 D) 32 23 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 20° C) 40° D) 50° 24 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 14 D) 10 25 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 1 D) 3 26 / 40 Tenglamani yeching: A) -6; 5 B) 6; -5 C) 5 D) -6 27 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 8(π+2) C) 64 D) 32 28 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 44 C) 45 D) 43 29 / 40 Hisoblang: A) 0 B) 1/32 C) -1/2 D) -√3/2 30 / 40 √3 A) 3/2 B) 5/5 C) 7/3 D) 21/10 31 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 8 C) 5 D) 3 32 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 100 C) 105 D) 96 33 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) -π/4+πk, k∈Z C) 0 D) π/4+πk, k∈Z 34 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 35 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 9 D) 10 36 / 40 Hisoblang: A) 19/20 B) 20/21 C) 10/11 D) 9/10 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 8 D) 10 38 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 4√2 C) 6 D) 3√2 39 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 64 D) 42 40 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 3√2 C) 4√3 D) 2√2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
