Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 2 B) 4 C) 1 D) 3 2 / 40 Bobur 14 m/s tezlik bilan 5 soat, 36 km/soat tezlik bilan 5 minut yugurgan bo’lsa , Boburning umumiy yurgan yo’li topilsin A) 456 km B) 670 km C) 255 km D) 13 km 3 / 40 1:(2:3) son 1:2:3 sonidan qanchaga katta? A) 6 B) 3 C) 9 D) 4/3 4 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,9 m yoki 90 cm B) 0,5 m yoki 50 cm C) 0,6 m yoki 60 cm D) 0,7 m yoki 70 cm 5 / 40 Aniq integralni hisoblang: A) 0 B) 0,5 C) 2 D) 3 6 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 3 B) 4 C) 2 D) 1 7 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 3 B) 2 C) 1 D) 4 8 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 110° B) 120° C) 100° D) 130° 9 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUB 3-EKUB B) 1-EKUB 2-EKUB 3-EKUK C) 1-EKUB 2-EKUK 3-EKUK D) 1-EKUB 2-EKUK 3-EKUB 10 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 9 B) 5 C) 1 D) 0 11 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 20 B) 35 C) 25 D) 40 12 / 40 Hisoblang: A) 4 B) 8 C) 6 D) 0 13 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) -π/4+πk, k∈Z C) Ø D) π/4+πk, k∈Z 14 / 40 Hisoblang: A) -1/2 B) 0 C) -√3/2 D) 1/32 15 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) berilganlar yetarli emas D) 121 16 / 40 Tenglamani yeching: A) 6; -5 B) -6; 5 C) -6 D) 5 17 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 10 D) 4√7 18 / 40 √3 A) 21/10 B) 3/2 C) 5/5 D) 7/3 19 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 3√2 C) 2√2 D) 2√3 20 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 100 C) 96 D) 25 21 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 50° C) 20° D) 40° 22 / 40 sonlarini taqqolsang. A) c B) a C) c D) b 23 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 24 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 12 C) 14 D) 20 25 / 40 bo‘lsa, A) 2 B) 3/2 C) 1 D) 2/3 26 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 5 C) 4 D) 11 27 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) BC > AD D) AB = BC 28 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) cd/b C) bd/c D) bc/d 29 / 40 Hisoblang: A) cos50° B) cos10° C) sin10° D) 1 30 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 7 D) 6 31 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 32 C) 30 D) 28 32 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 23 C) 35 D) 24 33 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) 4 √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 34 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 4 yoki –12 D) 6 35 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,04 C) 0,(04) D) 0,0(4) 36 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 3 D) 2 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 10 C) 6 D) 8 38 / 40 Hisoblang: A) 19/20 B) 9/10 C) 20/21 D) 10/11 39 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 5 C) 10 D) 11 40 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 4 C) 2 D) 3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
