Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 36 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, x + y ni toping. A) 16 B) 18 C) 17 D) 20 2 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) aniqlab bo‘lmaydi B) 2 C) 3 D) 4 3 / 40 Merganning nishonga tekkizish ehtimoli 0,8 ga teng. U ishonga 2 marta o‘q uzganda o‘qlardan biri nishonga tegishining ehtimolligini toping. A) 0,5 B) 0,8 C) 0,32 D) 0,16 4 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 3 B) 1 C) 4 D) 2 5 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 96 B) 108 C) 114 D) 126 6 / 40 Tengsizlikni yeching. A) (-∞;-2] B) [-3;-2] C) [-3;2]∪{1} D) [-2;1]∪{-3} 7 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 1 B) 4 C) 3 D) 2 8 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 12 B) 5 C) 7 D) 1 9 / 40 Soddalshtiring. A) -1 B) 1 C) 2 D) 6 10 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 2 B) 1 C) 4 D) 5 11 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 4 B) 5 C) 2 D) 6 12 / 40 tenglama intervalda nechta ildizga ega? A) 4 B) 2 C) 3 D) 1 13 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -4 C) -3 D) -6 14 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 10 C) 14 D) 20 15 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 10 C) 11 D) 5 16 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 96 C) 25 D) 105 17 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 4√3 D) 3√2 18 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (9; 0), (28; -1) 19 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,04 D) 0,0(2) 20 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 6 C) 7 D) 5 21 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) bc/d D) 1 22 / 40 Hisoblang: A) 10/11 B) 9/10 C) 19/20 D) 20/21 23 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 30° D) 20° 24 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 4√7 D) 10 25 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 5 yoki –15 D) 3 yoki –8 26 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3ctg40° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 27 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 11 C) 9 D) 12 28 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 2 D) 1 29 / 40 Tenglamani yeching: A) 5 B) -6; 5 C) -6 D) 6; -5 30 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 10 C) 6 D) 12 31 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 4√2 C) 6 D) 3√2 32 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 115 C) 112 D) 110 33 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 2 C) 1 D) 4 34 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 16(π-2) C) 8(π+2) D) 64 35 / 40 Hisoblang: A) cos10° B) cos50° C) 1 D) sin10° 36 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 42 D) 48 37 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 2 C) 1 D) 4 38 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 30 D) 24 39 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) -2 C) 5 D) 8 40 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) -π/4+πk, k∈Z C) π/4+πk, k∈Z D) 0 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
