Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 57 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 To’g’ri turt burchakning bo’yining perimetriga nisbatini toping. A) -452/18 B) 1/2 C) 5/3 D) 3/18 2 / 40 tenglamalar sistemasi yechimga ega bo‘ladigan a ning barcha qiymatlari to‘plamini toping. A) 4 B) 1 C) 3 D) 2 3 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) To'rtinchi yo'l B) Ikkinchi yo'l C) Uchunchi yo'l D) Birinchi yo'l 4 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 126 B) 114 C) 108 D) 96 5 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 4 B) 7,5 C) 3 D) 4,5 6 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 4 B) 2 C) 1 D) 3 7 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUB B) 1-EKUB 2-EKUK 3-EKUK C) 1-EKUB 2-EKUB 3-EKUK D) 1-EKUB 2-EKUB 3-EKUB 8 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 3 B) 1 C) 4 D) 2 9 / 40 x ni toping ? A) 3 B) 5 C) 4 D) 6 10 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 600 B) 3600 C) 4800 D) 5050 11 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 5 B) 1 C) 0 D) 9 12 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) 1/8 B) √2/8 C) √3/4 D) √3/8 13 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 14 D) 10 14 / 40 Hisoblang: A) 1 B) sin10° C) cos50° D) cos10° 15 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) -2 D) 5 16 / 40 √3 A) 3/2 B) 21/10 C) 5/5 D) 7/3 17 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 96 C) 100 D) 105 18 / 40 Hisoblang: A) 0 B) 1/32 C) -1/2 D) -√3/2 19 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 5 C) 7 D) 8 20 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 6 C) 5 D) 11 21 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 30° D) 20° 22 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 4√3 C) 2√3 D) 2√2 23 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 14 D) 35 24 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 3√2 C) 6 D) 4√3 25 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 11 D) 10 26 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 10 C) 15 D) 8 27 / 40 Tenglamani yeching: A) -6; 5 B) 6; -5 C) 5 D) -6 28 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 42 D) 32 29 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 30 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 12 C) 6 D) 10 31 / 40 Hisoblang: A) 10/11 B) 20/21 C) 9/10 D) 19/20 32 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 3 C) 2 D) 1 33 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 34 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 6 D) 4 yoki –12 35 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 115 C) 112 D) 116 36 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 3 C) 4 D) 1 37 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 38 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -6 C) -3 D) 5 39 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 121 C) 11 D) berilganlar yetarli emas 40 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,0(4) C) 0,(04) D) 0,04 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
