Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, x + y ni toping. A) 16 B) 20 C) 17 D) 18 2 / 40 funksiyaning eng kichik musbat davrini toping. A) 12 B) 24 C) 18 D) 26 3 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 203 B) 289 C) 200 D) 201 4 / 40 Tengsizlikni yeching. A) [-3;-2] B) [-3;2]∪{1} C) (-∞;-2] D) [-2;1]∪{-3} 5 / 40 Aniq integralni hisoblang: A) 0 B) 0,5 C) 2 D) 3 6 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 5 B) 2√5 C) √5 D) √5+5 7 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 6 C) 9 D) 8 8 / 40 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 200 km B) 20 km C) 2 km D) 0,2km 9 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (28π)/3 B) (29π)/3 C) (32π)/3 D) 11π 10 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 80 B) 90 C) 120 D) 100 11 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 6 B) 3 C) 9 D) 12 12 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) [-3;2] C) (-∞;3]∪[2;∞) D) x∈R 13 / 40 bo‘lsa, A) 2 B) 1 C) 2/3 D) 3/2 14 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (2; 3) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 15 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) berilganlar yetarli emas C) 121 D) 11 16 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 10 D) 20 17 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 2 C) 4 D) 1 18 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 19 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 6 D) 8 20 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) BD = BC D) DC < AD 21 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 30° D) 50° 22 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 16(π-2) C) 8(π+2) D) 32 23 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) 0 D) -π/4+πk, k∈Z 24 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 6 C) 4 yoki –12 D) 3 yoki –8 25 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 26 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 27 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 10 C) 6√7 D) 4√7 28 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 8 D) 10 29 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 4 C) 3 D) 2 30 / 40 Hisoblang: A) cos50° B) cos10° C) 1 D) sin10° 31 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 30 D) 24 32 / 40 Hisoblang: A) 19/20 B) 10/11 C) 9/10 D) 20/21 33 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) 1 D) bc/d 34 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 5 C) 3 D) -2 35 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 12 C) 10 D) 14 36 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 14 C) 23 D) 24 37 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 110 C) 116 D) 115 38 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 12 C) 13 D) 15 39 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 3 C) 4 D) 1 40 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,04 C) 0,0(2) D) 0,(04) O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
