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Matematika attestatsiya №5

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Yanvar 24, 2022

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping.

A) 3

B) 4

C) 2,5

D) 2

2 / 40

ko’paytmani hisoblang.

A) 86420000

B) 0

C) 10000

D) 480000

3 / 40

ni 9 ga bo’lgandagi qoldiqning kvadratini toping.

A) 25

B) 4

C) 16

D) 9

4 / 40

P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping.

A) 3x-2y+2=0

B) 3x+2y+2=0

C) 3x+2y-2=0

D) 3x-2y-2=0

5 / 40

funksiyaning [2; 3] kesmadagi eng katta qiymatini

A) 4

B) 3

C) 7,5

D) 4,5

6 / 40

a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping.

A) 6

B) 4

C) 2

D) 0

7 / 40

Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ?

A) 10

B) 12

C) 11

D) 13

8 / 40

Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ?

A) 6

B) 8

C) 9

D) 7

9 / 40

x ni toping ?

A) 3

B) 5

C) 4

D) 6

10 / 40

Hisoblang:

A) 0

B) 8

C) 6

D) 4

11 / 40

Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping.

A) 9

B) 6

C) 10

D) 8

12 / 40

tenglama intervalda nechta ildizga ega?

A) 4

B) 3

C) 1

D) 2

13 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√3

B) 6

C) 3√2

D) 4√2

14 / 40

Hisoblang:

A) 10/11

B) 9/10

C) 20/21

D) 19/20

15 / 40

Ifodaning qiymatini toping.

A) 0,04

B) 0,0(2)

C) 0,0(4)

D) 0,(04)

16 / 40

sonlarini taqqolsang.

A) c

B) b

C) c

D) a

17 / 40

Tenglamalar sistemani yeching:

A) (2; 3)

B) (7; 2), (28; -1)

C) (9; 0), (28; -1)

D) (9; 0), (2; 7)

18 / 40

P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping.

2¹ºº-1
(2¹ºº-1)x+2(2⁹⁹-1)
(2¹ºº-1)x-2(2⁹⁹-1)
2¹ººx-3·2¹⁰⁰

A) 4

B) 2

C) 1

D) 3

19 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) 11

B) 121

C) berilganlar yetarli emas

D) 22

20 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 42

B) 45

C) 43

D) 44

21 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 25

B) 100

C) 105

D) 96

22 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 115

B) 116

C) 110

D) 112

23 / 40

Rasmdagi shakl perimetrini toping.

A) 32

B) 30

C) 24

D) 28

24 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 35

B) 24

C) 23

D) 14

25 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) -2

B) 8

C) 3

D) 5

26 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 14

B) 12

C) 15

D) 13

27 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 10

B) 6√7

C) 8

D) 4√7

28 / 40

bo‘lsa,

A) 3/2

B) 2/3

C) 1

D) 2

29 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 3

B) 4

C) 1

D) 2

30 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BC > AD

B) DC < AD

C) BD = BC

D) AB = BC

31 / 40

Hisoblang:

A) 1

B) cos50°

C) sin10°

D) cos10°

32 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) bd/c

B) bc/d

C) 1

D) cd/b

33 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 3

B) 2

C) 1

D) 4

34 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -6

B) 5

C) -4

D) -3

35 / 40

Tenglamani yeching:

A) -6; 5

B) -6

C) 5

D) 6; -5

36 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 9

B) 10

C) 12

D) 11

37 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) Ø

B) π/4+πk, k∈Z

C) -π/4+πk, k∈Z

D) 0

38 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 10

B) 12

C) 8

D) 6

39 / 40

a+b+c=10, bo‘lsa, ni toping.