Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ? A) 14 B) 6 C) 9 D) 12 2 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n = 0, k > 0 B) n < 0, k = 0 C) n = 0, k < 0 D) n > 0, k = 0 3 / 40 180 gramm suvga 70 gramm tuz aralashtrildi. Hosil bo‘lgan aralashmaninmg necha foizi suvdan iborat? A) 75 B) 72 C) 78 D) 70 4 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 4 B) 2 C) 1 D) 3 5 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 4 B) 2 C) 1 D) 3 6 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 31/85 B) 68/15 C) 67/15 D) 11/5 7 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (29π)/3 B) (32π)/3 C) 11π D) (28π)/3 8 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 3 C) 5 D) 6 9 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 2 B) 3 C) 4 D) 1 10 / 40 sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan? A) 3 B) 4 C) 1 D) 2 11 / 40 Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi? A) dastlab kamayadi, keyin o‘sadi B) dastlab o‘sadi, keyin kamayadi C) qat’iy kamayuvchi D) qat’iy o‘suvchi 12 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 9 B) 3 C) 6 D) 12 13 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 32 C) 64 D) 8(π+2) 14 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,0(2) C) 0,(04) D) 0,04 15 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -3 C) 5 D) -4 16 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 2 C) 3 D) 1 17 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 23 D) 14 18 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 8 D) 3 19 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 20 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 96 C) 105 D) 100 21 / 40 Tenglamani yeching: A) -6; 5 B) 6; -5 C) 5 D) -6 22 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bd/c C) cd/b D) bc/d 23 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 7 D) 6 24 / 40 √3 A) 21/10 B) 5/5 C) 3/2 D) 7/3 25 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 4 yoki –12 C) 6 D) 3 yoki –8 26 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 15 C) 8 D) 20 27 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 64 C) 32 D) 48 28 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√2 C) 2√3 D) 3√2 29 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 8 C) 10 D) 12 30 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 30° D) 50° 31 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 6√7 C) 4√7 D) 8 32 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 11 C) 9 D) 12 33 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 115 C) 110 D) 112 34 / 40 sonlarini taqqolsang. A) a B) b C) c D) c 35 / 40 Hisoblang: A) 9/10 B) 20/21 C) 10/11 D) 19/20 36 / 40 bo‘lsa, A) 2 B) 2/3 C) 3/2 D) 1 37 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 12 D) 14 38 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 39 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 14 C) 12 D) 15 40 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 4 C) 2 D) 1 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
