Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 56 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Jamshid bir kunda 70,5 kgdan paxta tersa, 8460 kg paxtani necha kunda terib bo’ladi ? A) 100 kun B) 130 kun C) 120 kun D) 140 kun 2 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) c>a>b B) b>a>c C) a>c>b D) a>b>c 3 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 3 B) aniqlab bo‘lmaydi C) 2 D) 4 4 / 40 Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) √6+√14 B) 16 C) 18 D) 2√14+√6 5 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 8 B) 35/6 C) 6 D) 25/3 6 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) √5 C) √5+5 D) 5 7 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 10 B) 13 C) 11 D) 12 8 / 40 Soddalashtiring: A) Aniqlab bo`lmaydi B) 3 C) 1 D) 2 9 / 40 Hisoblang: -121+(-135)-(-1)28 A) -1 B) -3 C) 0 D) -2 10 / 40 Hisoblang: A) 0 B) 6 C) 4 D) 8 11 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 2 B) 5 C) 1 D) 4 12 / 40 Yig‘indini toping. A) 1/6 B) 1/9 C) 1/12 D) 1/4 13 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 6√7 C) 8 D) 4√7 14 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 3√2 D) 2√2 15 / 40 Hisoblang: A) -√3/2 B) 1/32 C) -1/2 D) 0 16 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) -2 D) 8 17 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 12 C) 14 D) 10 18 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 64 D) 42 19 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 50° C) 20° D) 30° 20 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 44 D) 42 21 / 40 √3 A) 21/10 B) 5/5 C) 7/3 D) 3/2 22 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 3√2 C) 6 D) 4√2 24 / 40 sonlarini taqqolsang. A) b B) c C) a D) c 25 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 105 C) 100 D) 96 26 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 10 D) 20 27 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 64 C) 32 D) 8(π+2) 28 / 40 Hisoblang: A) sin10° B) 1 C) cos10° D) cos50° 29 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) 1 C) cd/b D) bd/c 30 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) 0 D) -π/4+πk, k∈Z 31 / 40 Hisoblang: A) 19/20 B) 9/10 C) 10/11 D) 20/21 32 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 33 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 32 C) 28 D) 30 34 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) 4 √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 35 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) DC < AD D) BD = BC 36 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 6 D) 8 37 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,0(2) C) 0,04 D) 0,(04) 38 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 39 / 40 bo‘lsa, A) 2/3 B) 2 C) 3/2 D) 1 40 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 22 C) 121 D) 11 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16