Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 30 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ni hisoblang. A) (e+1)/2 B) (e-1)/2 C) e-1 D) e+1 2 / 40 Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping. A) 8 B) 32 C) 24 D) 16 3 / 40 Bobur 14 m/s tezlik bilan 5 soat, 36 km/soat tezlik bilan 5 minut yugurgan bo’lsa , Boburning umumiy yurgan yo’li topilsin A) 670 km B) 255 km C) 456 km D) 13 km 4 / 40 tenglamani yeching. A) 5 B) log(5/3)2 C) log(3/5)2 D) 3 5 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 35/6 B) 25/3 C) 6 D) 8 6 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 1 B) 4 C) 2 D) 3 7 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 1 B) 4 C) 3 D) 2 8 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) )a,b,d B) a,b C) b,d D) b 9 / 40 x ni toping ? A) 6 B) 3 C) 5 D) 4 10 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 12√3 B) 6√5 C) 8√3 D) 9√5 11 / 40 Funksiyaning aniqlanish sohasini toping. A) [-3;2] B) (-∞;3]∪[2;∞) C) (-∞;0)∪(0;∞) D) x∈R 12 / 40 Agar bo‘lsa, m/n ni toping. A) (1+√5)/2 B) 4 C) 3 D) 2 13 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 16(π-2) C) 8(π+2) D) 32 14 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 15 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 30° D) 40° 16 / 40 bo‘lsa, A) 3/2 B) 2 C) 1 D) 2/3 17 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -4 C) -6 D) -3 18 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 12 C) 6 D) 8 19 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) AB = BC C) BC > AD D) BD = BC 20 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 3 D) 2 21 / 40 Hisoblang: A) 0 B) -1/2 C) -√3/2 D) 1/32 22 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) 1 C) cd/b D) bc/d 23 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 3 yoki –8 C) 4 yoki –12 D) 5 yoki –15 24 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 25 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 96 C) 100 D) 25 26 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 8 C) 6√7 D) 4√7 27 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 6 C) 7 D) 8 28 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 29 / 40 Hisoblang: A) 19/20 B) 9/10 C) 10/11 D) 20/21 30 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 6 D) 4 31 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) 0 32 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 33 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 11 C) 10 D) 5 34 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 14 D) 23 35 / 40 Tenglamani yeching: A) 5 B) -6; 5 C) -6 D) 6; -5 36 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 3 C) 2 D) 4 37 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 30 C) 32 D) 28 38 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 110 D) 115 39 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 48 C) 64 D) 32 40 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 2 C) 1 D) 3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
