Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 64 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 289 B) 203 C) 200 D) 201 2 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16sin3x*sin5x B) 16sin3x*cos5x C) -16cos3x*sin5x D) 16cos3x*cos5x 3 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 4 B) 9 C) 25 D) 16 4 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 3 B) 4 C) 2 D) 1 5 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,7 m yoki 70 cm B) 0,6 m yoki 60 cm C) 0,5 m yoki 50 cm D) 0,9 m yoki 90 cm 6 / 40 Hisoblang: A) 4 B) 7 C) 27 D) 9 7 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 13 B) 12 C) 10 D) 11 8 / 40 Hisoblang? A) 0,25 B) 2 C) 4 D) 0,5 9 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 40° B) 10° C) 20° D) 30° 10 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 48 B) 40 C) 52 D) 28 11 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) 1/8 B) √3/4 C) √3/8 D) √2/8 12 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 5 B) 8 C) 1 D) 0 13 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 10 D) 6√7 14 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 20° C) 40° D) 50° 15 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 4 yoki –12 D) 6 16 / 40 sonlarini taqqolsang. A) a B) b C) c D) c 17 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 44 C) 45 D) 42 18 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 4 C) 5 D) 11 19 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 12 C) 10 D) 11 20 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 25 C) 100 D) 105 21 / 40 Hisoblang: A) 10/11 B) 9/10 C) 19/20 D) 20/21 22 / 40 √3 A) 21/10 B) 3/2 C) 7/3 D) 5/5 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 6 C) 4√2 D) 3√2 24 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 25 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) -6 D) 6; -5 26 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 22 C) 121 D) berilganlar yetarli emas 27 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) √3tg50° tg70° C) 2√3tg50° tg70° D) 4 √3tg50° tg70° 28 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 13 D) 12 29 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(2) C) 0,04 D) 0,0(4) 30 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 7 C) 11 D) 5 31 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 7 D) 6 32 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 24 C) 23 D) 14 33 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 2 C) 1 D) 4 34 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 110 D) 116 35 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bc/d C) bd/c D) cd/b 36 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 42 D) 32 37 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) -π/4+πk, k∈Z C) π/4+πk, k∈Z D) 0 38 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 8(π+2) C) 64 D) 32 39 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 3 D) 2 40 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) 5 C) -4 D) -6 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
