Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 180 gramm suvga 70 gramm tuz aralashtrildi. Hosil bo‘lgan aralashmaninmg necha foizi suvdan iborat? A) 78 B) 72 C) 75 D) 70 2 / 40 ko’paytmani hisoblang. A) 86420000 B) 0 C) 480000 D) 10000 3 / 40 Agar ni hisoblang. A) 8 B) Cheksiz C) 0 D) 9 4 / 40 Hisoblang: A) 9 B) 27 C) 7 D) 4 5 / 40 funksiyaning qiymatlar to'plamini toping. A) (-2√2;√2) B) [-√2;-1)∪(-1;1)∪(1;√2] C) [-√2;√2] D) [-√2;0)∪(0;√2] 6 / 40 Tengsizlikni yeching. A) [-2;1]∪{-3} B) [-3;-2] C) [-3;2]∪{1} D) (-∞;-2] 7 / 40 Soddalashtiring. A) (b+2)/(1-b) B) (a+1)/(-a-3) C) (a-1)/(1-b) D) (a-1)/(a-3) 8 / 40 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 20 km B) 2 km C) 0,2km D) 200 km 9 / 40 x ni toping ? A) 5 B) 3 C) 4 D) 6 10 / 40 sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan? A) 4 B) 1 C) 3 D) 2 11 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 1,5R B) 3R C) √3R(2-√3) D) R(√3-√2) 12 / 40 Yig‘indini toping. A) 1/12 B) 1/4 C) 1/6 D) 1/9 13 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (7; 2), (28; -1) D) (2; 3) 14 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,04 C) 0,0(4) D) 0,0(2) 15 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 6 C) 5 D) 11 16 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 17 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 6 C) 3 yoki –8 D) 4 yoki –12 18 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) π/4+πk, k∈Z C) 0 D) Ø 19 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 2 C) 1 D) 4 20 / 40 bo‘lsa, A) 2 B) 2/3 C) 3/2 D) 1 21 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 4√3 D) 2√3 22 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) bc/d D) 1 23 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 10 D) 8 24 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) BC > AD D) AB = BC 25 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 22 C) berilganlar yetarli emas D) 11 26 / 40 Hisoblang: A) sin10° B) 1 C) cos10° D) cos50° 27 / 40 √3 A) 21/10 B) 7/3 C) 3/2 D) 5/5 28 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 12 D) 10 29 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 3 C) -2 D) 5 30 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 13 C) 15 D) 14 31 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 24 D) 30 32 / 40 Hisoblang: A) 0 B) -1/2 C) 1/32 D) -√3/2 33 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 48 C) 32 D) 64 34 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 35 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 10 D) 11 36 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 30° D) 40° 37 / 40 Hisoblang: A) 19/20 B) 9/10 C) 10/11 D) 20/21 38 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 4√7 C) 8 D) 10 39 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 20 D) 8 40 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 14 D) 12 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
