Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 38 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin? A) 6 B) 9 C) 27 D) 7 2 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 4 B) 3 C) 1 D) 2 3 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n = 0, k > 0 B) n = 0, k < 0 C) n > 0, k = 0 D) n < 0, k = 0 4 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 3 B) 1 C) 2 D) 0 5 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 2 B) 4 C) 3 D) 1 6 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 4 B) 4,5 C) 7,5 D) 3 7 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 1 B) 2 C) 4 D) 3 8 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 6 B) 4 C) 5 D) 3 9 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) 11π B) (29π)/3 C) (28π)/3 D) (32π)/3 10 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 9 B) 10 C) 6 D) 8 11 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) (-∞;3]∪[2;∞) C) x∈R D) [-3;2] 12 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) R(√3-√2) B) √3R(2-√3) C) 3R D) 1,5R 13 / 40 Hisoblang: A) cos10° B) sin10° C) cos50° D) 1 14 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 7 C) 5 D) 11 15 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 64 C) 8(π+2) D) 16(π-2) 16 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 30° C) 40° D) 20° 17 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 32 D) 48 18 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 96 C) 25 D) 100 19 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3ctg40° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 20 / 40 Hisoblang: A) 20/21 B) 19/20 C) 10/11 D) 9/10 21 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 3 yoki –8 D) 5 yoki –15 22 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 14 D) 35 23 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 5 C) 6 D) 11 24 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√3 C) 2√2 D) 4√3 25 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 6 B) 8 C) 7 D) 5 26 / 40 √3 A) 3/2 B) 21/10 C) 5/5 D) 7/3 27 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 1 C) 3 D) 4 28 / 40 bo‘lsa, A) 2/3 B) 1 C) 3/2 D) 2 29 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -6 D) -4 30 / 40 sonlarini taqqolsang. A) a B) c C) c D) b 31 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 20 C) 10 D) 12 32 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 3 D) 4 33 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) 0 34 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(4) C) 0,04 D) 0,0(2) 35 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 2 C) 1 D) 4 36 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 12 C) 6 D) 10 37 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 2 C) 3 D) 1 38 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) cd/b C) 1 D) bd/c 39 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 10 C) 20 D) 8 40 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 44 C) 43 D) 42 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
