Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Berilgan sonlarning yig’indisini toping. A) 2/4 B) 3/18 C) 1/4 D) -452/18 2 / 40 Abdulla, Samandar va Jamshid 3 ta stulga necha xil usulda utirishi mumkin? A) 7 B) 9 C) 6 D) 27 3 / 40 ko’paytmani hisoblang. A) 0 B) 10000 C) 480000 D) 86420000 4 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 31/85 B) 68/15 C) 11/5 D) 67/15 5 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln5 B) ln4 C) ln3 D) ln2 6 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 35/6 B) 8 C) 6 D) 25/3 7 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) 11π B) (28π)/3 C) (32π)/3 D) (29π)/3 8 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) )a,b,d B) b,d C) b D) a,b 9 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 3 B) 5 C) 6 D) 4 10 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 5 B) 2 C) 4 D) 6 11 / 40 Tenglamani yeching: A) 9/5 B) 6/5 C) 5/9 D) 5*4 12 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 1/2 B) 1/3 C) 5/6 D) 8/15 13 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3ctg40° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 14 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 10 C) 6 D) 8 15 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,04 C) 0,0(2) D) 0,0(4) 16 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 3√2 C) 4√3 D) 4√2 17 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 23 C) 35 D) 24 18 / 40 bo‘lsa, A) 2/3 B) 1 C) 3/2 D) 2 19 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) -π/4+πk, k∈Z C) 0 D) Ø 20 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 10 D) 20 21 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 115 D) 110 22 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 3 yoki –8 C) 5 yoki –15 D) 4 yoki –12 23 / 40 sonlarini taqqolsang. A) c B) a C) b D) c 24 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 4 D) 1 25 / 40 Hisoblang: A) -1/2 B) -√3/2 C) 0 D) 1/32 26 / 40 Hisoblang: A) 10/11 B) 9/10 C) 19/20 D) 20/21 27 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 20° C) 40° D) 50° 28 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 29 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 44 D) 42 30 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 25 C) 100 D) 96 31 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 64 C) 16(π-2) D) 32 32 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 24 C) 30 D) 28 33 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 32 D) 48 34 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 3 D) 8 35 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 6 D) 7 36 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 10 C) 12 D) 20 37 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 22 C) berilganlar yetarli emas D) 11 38 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 1 C) 3 D) 4 39 / 40 Tenglamani yeching: A) 5 B) -6; 5 C) -6 D) 6; -5 40 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 6 C) 5 D) 4 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
