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Matematika attestatsiya №5

InfoMaster

Yanvar 24, 2022

33 Ko'rishlar 1 izoh

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

bo‘lsa, ning qiymatini toping.

A) 0,7

B) 2

C) 0,5

D) 1

2 / 40

tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin.

A) 28

B) 24

C) 21

D) 32

3 / 40

Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi?

A) 4

B) 2

C) 1

D) 3

4 / 40

funksiyaning [2; 3] kesmadagi eng katta qiymatini

A) 4,5

B) 3

C) 7,5

D) 4

5 / 40

funksiyaning qiymatlar to'plamini toping.

A) [-√2;-1)∪(-1;1)∪(1;√2]

B) [-√2;√2]

C) [-√2;0)∪(0;√2]

D) (-2√2;√2)

6 / 40

f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping.

A) f(x)+2x²-1

B) f(x)=x²+3x+7

C) f(x)=x²-4

D) f(x)=x²-x+5

7 / 40

Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor?

A) 48/5

B) 16

C) 10

D) 64/5

8 / 40

Soddalashtiring.

A) (b+2)/(1-b)

B) (a-1)/(1-b)

C) (a-1)/(a-3)

D) (a+1)/(-a-3)

9 / 40

Hisoblang 200−199+198−197+⋯+4−3

A) 101

B) 99

C) 98

D) 100

10 / 40

Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1.

A) 25

B) 41

C) 32

D) 50

11 / 40

Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping.

A) 5

B) 0

C) 8

D) 1

12 / 40

tenglama intervalda nechta ildizga ega?

A) 2

B) 3

C) 4

D) 1

13 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) 0

B) Ø

C) -π/4+πk, k∈Z

D) π/4+πk, k∈Z

14 / 40

Ifodaning qiymatini toping.

A) 0,0(2)

B) 0,0(4)

C) 0,(04)

D) 0,04

15 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 4 yoki –12

B) 5 yoki –15

C) 3 yoki –8

D) 6

16 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -4

B) -3

C) 5

D) -6

17 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 3√2

B) 6

C) 4√3

D) 4√2

18 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 4

B) 11

C) 5

D) 6

19 / 40

Kvadratlarning yuzlari yig‘indisini toping.

A) berilganlar yetarli emas

B) 22

C) 121

D) 11

20 / 40

Hisoblang:

A) 0

B) -1/2

C) 1/32

D) -√3/2

21 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 32

B) 8(π+2)

C) 16(π-2)

D) 64

22 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 4

B) 3

C) 1

D) 2

23 / 40

Hisoblang:

A) 20/21

B) 9/10

C) 19/20

D) 10/11

24 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 105

B) 100

C) 25

D) 96

25 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 42

B) 48

C) 32

D) 64

26 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 3

B) 8

C) -2

D) 5

27 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) √3ctg40° tg70°

B) √3tg50° tg70°

C) 4 √3tg50° tg70°

D) 2√3tg50° tg70°

28 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 15

B) 10

C) 8

D) 20

29 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 2

B) 3

C) 4

D) 1

30 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 10

B) 11

C) 7

D) 5

31 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 35

B) 14

C) 24

D) 23

32 / 40

Hisoblang:

A) cos10°

B) 1

C) sin10°

D) cos50°

33 / 40

Tenglamani yeching:

A) -6; 5

B) -6

C) 6; -5

D) 5

34 / 40

bo‘lsa,

A) 3/2

B) 1

C) 2/3

D) 2

35 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (2; 7)

B) (2; 3)

C) (9; 0), (28; -1)

D) (7; 2), (28; -1)

36 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 14

B) 12

C) 15

D) 13

37 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 10

B) 6

C) 8

D) 12

38 / 40

Tengsizlik nechta butun juft yechimga
ega?