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Matematika attestatsiya №5

InfoMaster

Yanvar 24, 2022

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

Merganning nishonga tekkizish ehtimoli 0,8 ga teng. U ishonga 2 marta o‘q uzganda o‘qlardan biri nishonga tegishining ehtimolligini toping.

A) 0,5

B) 0,32

C) 0,16

D) 0,8

2 / 40

y=4cos 2x+cos8x funksiyaning hosilasini toping

A) 16cos3x*cos5x

B) -16cos3x*sin5x

C) 16sin3x*cos5x

D) 16sin3x*sin5x

3 / 40

bo‘lsa, y = ?

A) 8

B) 2

C) 3

D) 26

4 / 40

funksiyaning qiymatlar to'plamini toping.

A) [-√2;0)∪(0;√2]

B) (-2√2;√2)

C) [-√2;-1)∪(-1;1)∪(1;√2]

D) [-√2;√2]

5 / 40

tenglamani yeching.

A) 5

B) log(3/5)2

C) log(5/3)2

D) 3

6 / 40

cosx=0,2x tenglama nechta yechimga ega?

A) 3

B) 4

C) 1

D) 2

7 / 40

Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor?

A) 64/5

B) 48/5

C) 16

D) 10

8 / 40

Quyidakilardan qaysi biri juft:

2009⁵⁶+2008⁵⁵
3121⁰+0!
55!+87⁷
2²²+3³³+44⁴⁴

A) 4

B) 3

C) 2

D) 1

9 / 40

Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ?

A) 2 km

B) 20 km

C) 200 km

D) 0,2km

10 / 40

Funksiyaning aniqlanish sohasini toping.

A) (-∞;3]∪[2;∞)

B) x∈R

C) [-3;2]

D) (-∞;0)∪(0;∞)

11 / 40

cos75° ·cos 45° ·cos15° ni hisoblang.

A) √3/4

B) √2/8

C) √3/8

D) 1/8

12 / 40

Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1.

A) 32

B) 50

C) 25

D) 41

13 / 40

b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi?

A) 3 yoki –8

B) 6

C) 4 yoki –12

D) 5 yoki –15

14 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 9

B) 11

C) 12

D) 10

15 / 40

sonlarini taqqolsang.

A) c

B) b

C) a

D) c

16 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 1

B) 4

C) 3

D) 2

17 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (2; 7)

B) (9; 0), (28; -1)

C) (2; 3)

D) (7; 2), (28; -1)

18 / 40

bo‘lsa,

A) 2/3

B) 2

C) 1

D) 3/2

19 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 6√7

C) 8

D) 10

20 / 40

kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping.

A) 7

B) 5

C) 11

D) 10

21 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) DC < AD

B) BC > AD

C) BD = BC

D) AB = BC

22 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 35

B) 14

C) 24

D) 23

23 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 4√2

B) 6

C) 3√2

D) 4√3

24 / 40

Rasmdagi shakl perimetrini toping.

A) 28

B) 30

C) 32

D) 24

25 / 40

Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d)

A) cd/b

B) bd/c

C) 1

D) bc/d

26 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 3

B) 1

C) 2

D) 4

27 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 4

B) 1

C) 3

D) 2

28 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 12

B) 13

C) 14

D) 15

29 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 112

B) 116

C) 110

D) 115

30 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 7

B) 8

C) 6

D) 5

31 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 42

B) 44

C) 45

D) 43

32 / 40

Hisoblang:

A) 9/10

B) 10/11

C) 20/21

D) 19/20

33 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) 0

B) Ø

C) π/4+πk, k∈Z

D) -π/4+πk, k∈Z

34 / 40

√3

A) 7/3

B) 5/5

C) 3/2

D) 21/10

35 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 48

B) 42

C) 32

D) 64

36 / 40

A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping.

A) 15

B) 20

C) 10

D) 8

37 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 100

B) 25

C) 105

D) 96

38 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 8

B) 12

C) 6

D) 10

39 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.