Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №4 Matematika attestatsiya Matematika attestatsiya №4 InfoMaster Yanvar 21, 2022 62 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 1 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №4 1 / 40 Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping. A) 32 B) 16 C) 8 D) 24 2 / 40 |x+1|=2|x–2| tenglamaning ildizlari yig’indisini toping. A) 5 B) 6 C) 0 D) 7 3 / 40 va bo'lsa x-y=? A) 7 B) 9 C) 5 D) 8 4 / 40 Merganning nishonga tekkizish ehtimoli 0,8 ga teng. U ishonga 2 marta o‘q uzganda o‘qlardan biri nishonga tegishining ehtimolligini toping. A) 0,16 B) 0,32 C) 0,5 D) 0,8 5 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 3 B) 5 C) 4 D) 2 6 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 46 B) 40 C) 50 D) 44 7 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (0; ∞) B) (-2; ∞) C) (-1; ∞) D) [-1; ∞) 8 / 40 Tengsizlikni yeching. A) (-∞;-2] B) [-2;1]∪{-3} C) [-3;-2] D) [-3;2]∪{1} 9 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 3 B) 4,5 C) 4 D) 7,5 10 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 3 B) 2 C) 4 D) 1 11 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 3 B) 5 C) 6 D) 4 12 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 11 B) 12 C) 13 D) 10 13 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 34 B) 36 C) 40 D) 32 14 / 40 Hisoblang: A) 4 B) 2 C) 1 D) 3 15 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 4 B) 1 C) 2 D) 3 16 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 25 B) 30 C) 0 D) 10 17 / 40 Yig‘indini toping. A) 1/6 B) 1/12 C) 1/4 D) 1/9 18 / 40 Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping. A) √6 B) 2,5 C) √5 D) 2,4 19 / 40 Funksiyaning aniqlanish sohasini toping. A) x∈R B) [-3;2] C) (-∞;0)∪(0;∞) D) (-∞;3]∪[2;∞) 20 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 2 B) 6 C) 4 D) 5 21 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 6 B) 12 C) 3 D) 9 22 / 40 Tenglamani yeching: A) 9/5 B) 6/5 C) 5/9 D) 5*4 23 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 41 B) 32 C) 50 D) 25 24 / 40 ni hisoblang. A) 1 B) 2 C) 0 D) 3 25 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 2 B) 4 C) 1 D) 5 26 / 40 Hisoblang: A) 6 B) 8 C) 0 D) 4 27 / 40 Agar bo‘lsa, m/n ni toping. A) 3 B) 2 C) 4 D) (1+√5)/2 28 / 40 Agar bo'lsa, ni m orqali ifodalang. A) (m+1)/2 B) (m+4)/4 C) (4-m)/4 D) 2/m 29 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 20 C) 35 D) 40 30 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 9 B) 15 C) 12 D) 7 31 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/4 B) √2/8 C) 1/8 D) √3/8 32 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 32 B) 48 C) 64 D) 16 33 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 8 B) 6 C) 9 D) 10 34 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 8 B) 1 C) 0 D) 5 35 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 17° B) 7° C) 14° D) 24° 36 / 40 Integralni hisoblang: A) 2 B) 3 C) 1 D) 4 37 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 40 B) 52 C) 28 D) 48 38 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 2 B) 3 C) 1 D) 4 39 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,216 B) 0,144 C) 0,432 D) 0,288 40 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 1 B) 4 C) 3 D) 2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
