Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №4 Matematika attestatsiya Matematika attestatsiya №4 InfoMaster Yanvar 21, 2022 46 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 1 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №4 1 / 40 Agar bo'lsa, x ni toping. A) -5 B) 5 C) 2 D) -2 2 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) c>a>b B) b>a>c C) a>b>c D) a>c>b 3 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 3 B) 2 C) 1 D) 4 4 / 40 Berilgan sonlarning yig’indisini toping. A) -452/18 B) 3/18 C) 2/4 D) 1/4 5 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 4 B) 2,5 C) 3 D) 2 6 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 6 B) 35/6 C) 8 D) 25/3 7 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 108 B) 96 C) 114 D) 126 8 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 1 B) 2 C) 4 D) 3 9 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 13 B) 9,25 C) 6 D) 5,75 10 / 40 Aniq integralni hisoblang: A) 0,5 B) 0 C) 2 D) 3 11 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 3 B) 4 C) 5 D) 6 12 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 36 B) 34 C) 32 D) 40 13 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 2 B) 3 C) 1 D) 4 14 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUB B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUB 3-EKUK D) 1-EKUB 2-EKUK 3-EKUK 15 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) a,b B) b,d C) )a,b,d D) b 16 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 17° B) 7° C) 24° D) 14° 17 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 5 B) 0 C) 8 D) 1 18 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) 8 B) berilganlar yetarli emas C) 10 D) 6 19 / 40 Hisoblang: A) 0 B) 6 C) 4 D) 8 20 / 40 ni hisoblang. A) 1 B) 2 C) 0 D) 3 21 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -√17 B) √17 C) 4 D) -4 22 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 80 B) 120 C) 100 D) 90 23 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √2/8 B) √3/4 C) 1/8 D) √3/8 24 / 40 Tenglamani yeching: A) 6/5 B) 9/5 C) 5/9 D) 5*4 25 / 40 Agar bo‘lsa, m/n ni toping. A) 2 B) 3 C) 4 D) (1+√5)/2 26 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 2 B) 4 C) 5 D) 1 27 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 35 C) 40 D) 20 28 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 41 B) 25 C) 50 D) 32 29 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 96π B) 144π C) 192π D) 72π 30 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 64 B) 16 C) 48 D) 32 31 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 1/3 B) 1/2 C) 5/6 D) 8/15 32 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) (-∞;3]∪[2;∞) C) x∈R D) [-3;2] 33 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 5 B) 9 C) 0 D) 1 34 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) R(√3-√2) B) 3R C) √3R(2-√3) D) 1,5R 35 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 8√3 B) 6√5 C) 12√3 D) 9√5 36 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,144 B) 0,288 C) 0,432 D) 0,216 37 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 2 B) 1 C) 4 D) 3 38 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 9 B) 12 C) 6 D) 3 39 / 40 sin a = x va 1+cos a= y bo‘lsa, x va y o‘zaro qanday bog‘langan? A) 2 B) 4 C) 3 D) 1 40 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 40 B) 52 C) 28 D) 48 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
