Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №4 Matematika attestatsiya Matematika attestatsiya №4 InfoMaster Yanvar 21, 2022 46 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 1 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №4 1 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 2 B) 3 C) 1 D) 4 2 / 40 Agar bo'lsa, x ni toping. A) -5 B) 2 C) -2 D) 5 3 / 40 ko’paytmani hisoblang. A) 10000 B) 0 C) 86420000 D) 480000 4 / 40 Yig’indi quydagilardan qaysi biriga teng? A) 40560,8 B) 45,0608 C) 450,608 D) 4506,08 5 / 40 bo‘lsa, x + y ni toping. A) 18 B) 17 C) 16 D) 20 6 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 13 B) 6 C) 9,25 D) 5,75 7 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,9 m yoki 90 cm B) 0,5 m yoki 50 cm C) 0,6 m yoki 60 cm D) 0,7 m yoki 70 cm 8 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 2 B) 1 C) 3 D) 4 9 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 3 B) 4 C) 2 D) 1 10 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 2√5 B) 5 C) √5+5 D) √5 11 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 5 C) 6 D) 3 12 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 4 B) 2 C) 3 D) 1 13 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 40° B) 30° C) 10° D) 20° 14 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 64/5 C) 16 D) 48/5 15 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 3 B) 2 C) 4 D) 1 16 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) -4 B) √17 C) 4 D) -√17 17 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 4 B) 2 C) 1 D) 3 18 / 40 Funksiyaning aniqlanish sohasini toping. A) [-3;2] B) (-∞;3]∪[2;∞) C) x∈R D) (-∞;0)∪(0;∞) 19 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 100 B) 90 C) 80 D) 120 20 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 12 B) 9 C) 7 D) 15 21 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 9 B) 0 C) 5 D) 1 22 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 5 B) 1 C) 0 D) 8 23 / 40 Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi? A) dastlab kamayadi, keyin o‘sadi B) dastlab o‘sadi, keyin kamayadi C) qat’iy o‘suvchi D) qat’iy kamayuvchi 24 / 40 Tenglamani yeching: A) 9/5 B) 6/5 C) 5/9 D) 5*4 25 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 6 B) 9 C) 10 D) 8 26 / 40 Hisoblang: A) 0 B) 4 C) 6 D) 8 27 / 40 Integralni hisoblang: A) 2 B) 1 C) 3 D) 4 28 / 40 Raqamlari yig‘indisi 10 bo‘lgan nechta turli 3 xonali son bor? A) 0,216 B) 0,288 C) 0,432 D) 0,144 29 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 50 B) 25 C) 41 D) 32 30 / 40 ABC o‘tkir burchakli uchburchakda sinA=4/5 va sinB=15/13 bo'lsa, sinC ni qiymatini toping. A) 40/63 B) 56/65 C) 48/65 D) 36/65 31 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 96π B) 72π C) 144π D) 192π 32 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 6√5 B) 8√3 C) 9√5 D) 12√3 33 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 2 B) 5 C) 6 D) 4 34 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) 1/8 B) √3/8 C) √3/4 D) √2/8 35 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 7° B) 24° C) 17° D) 14° 36 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) √3R(2-√3) B) R(√3-√2) C) 3R D) 1,5R 37 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 8/15 B) 1/3 C) 5/6 D) 1/2 38 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 52 B) 48 C) 28 D) 40 39 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 35 B) 20 C) 40 D) 25 40 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 5 B) 2 C) 4 D) 1 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
