Uy » Python » Python dasturlash tili №-5 Python Python dasturlash tili №-5 InfoMaster Aprel 9, 2021 242 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 1 0 12345678910111213141516171819202122232425 Tomonidan yaratilgan InfoMaster Python dasturlash tili №-5 Testni Salomov Sardor tayyorladi. 1 / 25 buyruqlar_bloki if operatoridan keyingi satrda xat boshidan nechta probel qoldirib, keyin yoziladi. A) 6 B) 7 C) 5 D) 4 2 / 25 Masalada faqatgina bitta shart tekshirilsa, qaysi operatordan foydalaniladi? A) elif B) else C) while D) if 3 / 25 a=3 b=15 if a>b: c=a elif b>a: c=b*a else: c=0 print(c) quyidagi dastur natijasini toping A) 45 B) 18 C) 4 D) 12 4 / 25 x = 5 if x > 6: y = x-3 else: y=x print(y) quydagi dastur natijasini toping. A) 6 B) 4 C) 5 D) 7 5 / 25 a=12 b=12 if a>b: c=ab elif b>a: c=b*a else: c=20 print(c) quyidagi dastur natijasini toping A) 10 B) 20 C) 24 D) 0 6 / 25 a=10 b=a*4 a*3>=b–5 quydagi dastur natijasini toping. A) True B) False C) 10 D) 14 7 / 25 a = 66 b = 22 c = 7 not((a > b) or (b < c)) quydagi dastur natijasini toping. A) or B) True C) False D) not 8 / 25 x = 15 if x > 6: y = x-3 else: y=x print(y) quydagi dastur natijasini toping. A) 5 B) 12 C) 6 D) 4 9 / 25 Shartni tekshirish uchun qaysi operatordan foydalaniladi? A) else operatordan B) if operatordan C) elif operatordan D) wile operatordan 10 / 25 a = 20 c = False a > 17 or c quydagi dastur natijasini toping. A) True B) 20 C) False D) or 11 / 25 Python dasturlash tilida a = True b = True c = False not(a and c) and (a or b) or c dastur natijasini toping. A) True B) not C) and D) False 12 / 25 Python dasturlash tilida x = 10 if x > 6: y = x-3 else: y=x print(y) quydagi dastur natijasini toping. A) 7 B) 4 C) 6 D) 5 13 / 25 x = 11111111 if x > 6: y = x-3 else: y=x print(y) quydagi dastur natijasini toping. A) 11111108 B) 11111111 C) 4 D) 11111114 14 / 25 a=45 b=15 if a>b: c=a\b elif b>a: c=b^a else: c=b*2 print(c) quyidagi dastur natijasini toping A) 45 B) 3 C) 3575 D) 15 15 / 25 Tarmoqlanuvchi algoritm deb nimaga aytiladi? A) shartga ko‘ra buyruqlar ketmaketligining bajarilishi yoki bajarilmasligini belgilovchi algoritm B) buyruqlar ketmaketligining bajarilmasligini algoritm C) shartga ko‘ra buyruqlar ketmaketligining bajarilmasligini belgilovchi algoritm D) buyruqlarni ketmaketligi bajariladi 16 / 25 a=2 b=13 if a>b: c=a*b elif b>a: c=b^2 else: c=4 print(c) quyidagi dastur natijasini toping A) 16 B) 4 C) 169 D) 2 17 / 25 from math import * a=144 b=12 if a>b: c=sqrt(a) elif b>a: c=b else: c=a print(c) quyidagi dastur natijasini toping A) 12 B) 16 C) 4 D) 144 18 / 25 a=4 b=4 if a>b: c=a^b elif b>a: c=b\a else: c=b^3 print(c) quyidagi dastur natijasini toping A) 12 B) 64 C) 8 D) 9 19 / 25 a=12 b=2 if a>b: c=a^b elif b>a: c=b*a else: c=12 print(c) quyidagi dastur natijasini toping A) 12 B) 144 C) 14 D) 24 20 / 25 Ko‘p shartli masalalarni yechish uchun qaysi operatoridan foydalaniladi. A) else B) if C) elif D) while 21 / 25 CASE operatori bu…………? A) bunday operator mavjud emas B) if operatorining takomillashgan ko‘rinishi C) else operatorining takomillashgan ko‘rinishi D) elif operatorining takomillashgan ko‘rinishi 22 / 25 a=6 b=6,5 if a>b: c=a\b elif b>a: c=b*a else: c=200 print(c) quyidagi dastur natijasini toping A) 200 B) 12 C) 39 D) 120 23 / 25 Python dasturlash tilida “ if ” operatori bu……………? A) to’g’ri javob yo’q B) faqat berilgan shart rost bo‘lgandagina muayyan buyruqlar to‘plamini bajaradi C) buyruqlar alohida qatorda yoki bitta qatorda to‘plamini bajaradi D) buyruqlar to‘plamini bajaradigan shartli operator 24 / 25 a=12 b=2 if a>b: c=a\b elif b>a: c=ba else: c=1 print(c) quyidagi dastur natijasini toping A) 6 B) 10 C) 24 D) 5 25 / 25 a = 20 c = False not a > 17 or not c quydagi dastur natijasini toping. A) True B) not C) False D) 20 0% Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
