10-sinf Matematika olimpiada №3 Oktabr 3, 2022Avgust 19, 2024 da chop etilgan InfoMaster tomonidan 10-sinf Matematika olimpiada №3 ga 1 fikr bildirilgan 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. tengsizlikning yechimlari joylashgan interval uzunligini toping. A) 1,15 B) 1,45 C) 1,25 D) 1,35 2 / 25 2. Ta`lim muassasida barcha o`quvchilar kamida bitta ingliz yoki nemis tilida so`zlashа oladilar. Ayrimlari ikkala tilni ham biladilar. O`quvchilarning 85%i ingliz tilini, 75%i nemis tilini biladilar. Ikkala tilni ham biladigan o`quvchilar barcha o`quvchilarning necha % ini tashkil etadi. A) 70% B) 50% C) 65% D) 60% 3 / 25 3. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 1 B) 3 C) 2 D) 9 4 / 25 4. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 0 B) -1 C) -2 D) 1 5 / 25 5. Tenglamalar sistemasi nechta yechimga ega? A) 6 B) 8 C) 10 D) 12 6 / 25 6. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 0 B) 1 C) 3 D) -1 7 / 25 7. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 1 B) tg9° C) sin18° D) 2cos² 9° 8 / 25 8. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 6? + 2 B) 8? + 2 C) 10? + 2 D) 4? + 2 9 / 25 9. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 15 B) 9 C) 12 D) 10 10 / 25 10. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -26 B) -24 C) -27 D) -25 11 / 25 11. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x>3 B) x<0 C) 3 ≤ x D) x ≤ 3 12 / 25 12. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) 6? − 30 B) −6? + 42 C) −6? + 6 D) 6? − 24 13 / 25 13. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 16 B) 0 C) 8 D) 12 14 / 25 14. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 4 B) 6 C) 7 D) 5 15 / 25 15. Agar A) π B) 0 C) 3π/2 D) π/2 16 / 25 16. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 150° B) 120° C) 90° D) 135° 17 / 25 17. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 5 B) 2 C) 8 D) 3 18 / 25 18. Agar bo‘lsa, |xyz| ni toping. A) 1000 B) 800 C) 500 D) 100 19 / 25 19. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 11 B) 10 C) 8 D) 9 20 / 25 20. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) √2 B) 1 C) √3 D) 2√2 21 / 25 21. bo‘lsa ? ning qiymatini toping. A) 40 B) 12 C) 37 D) 25 22 / 25 22. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 2/5 B) 5√6/24 C) 5√2/5 D) 5√3/12 23 / 25 23. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 15 B) 10 C) 8 D) 9 24 / 25 24. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 4√21 B) 35 C) 2√21 D) √21 25 / 25 25. Tenglama nechta yechimga ega? A) 4 B) 2 C) 5 D) 3 0% Testni qayta ishga tushiring tomonidan Wordpress Quiz plugin Matematika olimpiada, Viloyat 2021-2022 o'quv yili
