Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 113 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. a ning qanday qiymatlarida 3 soni tenglamaning ildizlari oralig‘ida bo‘ladi? A) a>10/7 B) a>11/7 C) a<10/9 D) a>10/9 2 / 25 2. Agar f(g(x))=x²-6x+6 va f(x)=x−3 funksiyalar berilgan bo`lsa, g(x) funksiya ko`rinishini aniqlang. A) (x-3)² B) (x+3)² C) x²+12x+3 D) x²-12-3 3 / 25 3. Tenglamalar sistemasi nechta yechimga ega? A) 8 B) 12 C) 10 D) 6 4 / 25 4. Agar ni toping. A) 0.9 B) 0.96 C) 0.81 D) 0.8 5 / 25 5. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 16 B) 17 C) 15 D) 14 6 / 25 6. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 2cos² 9° B) tg9° C) sin18° D) 1 7 / 25 7. bo‘lsa ? ning qiymatini toping. A) 25 B) 40 C) 37 D) 12 8 / 25 8. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 120° B) 135° C) 90° D) 150° 9 / 25 9. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 2 B) 5 C) 3 D) 8 10 / 25 10. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) −6? + 42 B) −6? + 6 C) 6? − 30 D) 6? − 24 11 / 25 11. Tenglama nechta yechimga ega? A) 5 B) 2 C) 4 D) 3 12 / 25 12. Agar bo‘lsa, |xyz| ni toping. A) 500 B) 100 C) 800 D) 1000 13 / 25 13. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 35 B) √21 C) 2√21 D) 4√21 14 / 25 14. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 1 B) 0 C) -1 D) 3 15 / 25 15. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 1 B) 0 C) -1 D) -2 16 / 25 16. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 6 B) 7 C) 5 D) 8 17 / 25 17. Agar A) 3π/2 B) 0 C) π D) π/2 18 / 25 18. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 9 B) 10 C) 15 D) 12 19 / 25 19. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) √2 B) 2√2 C) √3 D) 1 20 / 25 20. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -24 B) -26 C) -27 D) -25 21 / 25 21. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) -2 B) -3 C) 2 D) 3 22 / 25 22. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 0 B) 20x+50 C) 20x+48 D) x+25 23 / 25 23. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 2 B) 3 C) 1 D) 9 24 / 25 24. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 12 B) 16 C) 0 D) 8 25 / 25 25. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 9 B) 8 C) 15 D) 10 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
