Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 28 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. tengsizlikning eng katta butun yechimini toping. A) 3 B) 2 C) 1 D) 4 2 / 25 2. bo'lsa kasrning qiymatini hisoblang. A) 2-√11 B) √11-2 C) √11-1 D) √11+1 3 / 25 3. Tenglamalar sistemasi nechta yechimga ega? A) 6 B) 10 C) 12 D) 8 4 / 25 4. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 16 B) 8 C) 0 D) 12 5 / 25 5. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) 6? − 30 B) −6? + 6 C) 6? − 24 D) −6? + 42 6 / 25 6. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 6 B) 7 C) 5 D) 8 7 / 25 7. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 20x+48 B) x+25 C) 0 D) 20x+50 8 / 25 8. bo‘lsa ? ning qiymatini toping. A) 40 B) 12 C) 37 D) 25 9 / 25 9. Agar ni toping. A) 0.8 B) 0.81 C) 0.96 D) 0.9 10 / 25 10. Agar bo‘lsa, |xyz| ni toping. A) 1000 B) 800 C) 100 D) 500 11 / 25 11. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 3 B) -3 C) -2 D) 2 12 / 25 12. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 2√21 B) 4√21 C) √21 D) 35 13 / 25 13. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 8 B) 15 C) 9 D) 10 14 / 25 14. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 9 B) 10 C) 8 D) 11 15 / 25 15. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 5 B) 7 C) 4 D) 6 16 / 25 16. Agar A) π B) 3π/2 C) π/2 D) 0 17 / 25 17. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 12 B) 10 C) 9 D) 15 18 / 25 18. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 14 B) 15 C) 16 D) 17 19 / 25 19. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 9 B) 1 C) 2 D) 3 20 / 25 20. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x<0 B) x ≤ 3 C) x>3 D) 3 ≤ x 21 / 25 21. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) 3 B) -1 C) 1 D) 0 22 / 25 22. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√2/5 B) 2/5 C) 5√6/24 D) 5√3/12 23 / 25 23. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 0 B) 1 C) -2 D) -1 24 / 25 24. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 72 B) 36 C) 81 D) 144 25 / 25 25. Tenglama nechta yechimga ega? A) 5 B) 4 C) 3 D) 2 0% Testni qayta ishga tushiring Author: InfoMaster Foydali bo'lsa mamnunmiz
