Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 13 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. Hisoblang: A) -0,5 B) -1 C) 1 D) 2 2 / 25 2. Uchburchakning ikkita burchagi mos ravishda 38o va 52oga teng. Uchinchi burchagi uchidan tushirilgan bissektrisa va mediana orasidagi burchakni toping. A) 7° B) 10° C) 17° D) 14° 3 / 25 3. ABC uchburchakning AC tomonida D nuqta olingan, bunda ∠ABC = ∠BDC. Agar AD = 10, CD = 8 bo‘lsa, BC ni toping. A) 12 B) 10 C) 15 D) 9 4 / 25 4. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 15 B) 16 C) 14 D) 17 5 / 25 5. Tenglama nechta yechimga ega? A) 5 B) 2 C) 3 D) 4 6 / 25 6. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 0 B) 20x+50 C) 20x+48 D) x+25 7 / 25 7. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 135° B) 120° C) 150° D) 90° 8 / 25 8. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -27 B) -26 C) -25 D) -24 9 / 25 9. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 6? + 2 B) 4? + 2 C) 10? + 2 D) 8? + 2 10 / 25 10. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 2cos² 9° B) sin18° C) 1 D) tg9° 11 / 25 11. Tenglamalar sistemasi nechta yechimga ega? A) 6 B) 8 C) 10 D) 12 12 / 25 12. Agar A) 3π/2 B) 0 C) π D) π/2 13 / 25 13. Agar ni toping. A) 0.96 B) 0.8 C) 0.81 D) 0.9 14 / 25 14. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 10 B) 11 C) 8 D) 9 15 / 25 15. bo‘lsa ? ning qiymatini toping. A) 12 B) 40 C) 37 D) 25 16 / 25 16. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) 4√21 B) 2√21 C) √21 D) 35 17 / 25 17. Agar bo‘lsa, |xyz| ni toping. A) 100 B) 800 C) 500 D) 1000 18 / 25 18. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 2 B) 9 C) 1 D) 3 19 / 25 19. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 6 B) 4 C) 7 D) 5 20 / 25 20. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 7 B) 6 C) 5 D) 8 21 / 25 21. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) −6? + 42 B) −6? + 6 C) 6? − 30 D) 6? − 24 22 / 25 22. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) 0 B) -2 C) -1 D) 1 23 / 25 23. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x<0 B) x>3 C) 3 ≤ x D) x ≤ 3 24 / 25 24. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 8 B) 16 C) 12 D) 0 25 / 25 25. a,b,c−ABC uchburchakning tomonlari. Agar a4 + b4 + c4 + 32 = 2(a²b² + b²c² + a²c²) bo‘lsa, ABC uchburchak yuzini toping. A) 1 B) √2 C) √3 D) 2√2 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
