Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 12 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. Hisoblang: A) 3 B) 2 C) 4 D) 1 2 / 25 2. Ta`lim muassasida barcha o`quvchilar kamida bitta ingliz yoki nemis tilida so`zlashа oladilar. Ayrimlari ikkala tilni ham biladilar. O`quvchilarning 85%i ingliz tilini, 75%i nemis tilini biladilar. Ikkala tilni ham biladigan o`quvchilar barcha o`quvchilarning necha % ini tashkil etadi. A) 60% B) 70% C) 50% D) 65% 3 / 25 3. Tenglama nechta yechimga ega? A) 3 B) 5 C) 2 D) 4 4 / 25 4. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -26 B) -24 C) -25 D) -27 5 / 25 5. Agar bo‘lsa, |xyz| ni toping. A) 500 B) 1000 C) 800 D) 100 6 / 25 6. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) 6? − 30 B) −6? + 42 C) 6? − 24 D) −6? + 6 7 / 25 7. englikni qanoatlantiradigan ? ning eng kichik qiymatini toping. A) -1 B) 3 C) 1 D) 0 8 / 25 8. Agar ni toping. A) 0.8 B) 0.81 C) 0.9 D) 0.96 9 / 25 9. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 20x+48 B) x+25 C) 20x+50 D) 0 10 / 25 10. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 1 B) 9 C) 3 D) 2 11 / 25 11. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 1 B) tg9° C) 2cos² 9° D) sin18° 12 / 25 12. bo‘lsa ? ning qiymatini toping. A) 25 B) 40 C) 12 D) 37 13 / 25 13. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 4 B) 7 C) 6 D) 5 14 / 25 14. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 144 B) 81 C) 72 D) 36 15 / 25 15. ?(?) = ?5 − 7?4 + 3?3 − ? + 2 ko‘phadni ?2 + ? ga bo‘lgandagi qoldiqni aniqlang. A) 8? + 2 B) 4? + 2 C) 6? + 2 D) 10? + 2 16 / 25 16. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x>3 B) x<0 C) x ≤ 3 D) 3 ≤ x 17 / 25 17. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 8 B) 9 C) 10 D) 11 18 / 25 18. Uchburchak tomonlarining uzunliklari berilgan tenglamaning ildizlariga mos keladi. ?³ − 24?² + 183? − 440 = 0. Uchburchakning yuzini hisoblang. A) √21 B) 2√21 C) 4√21 D) 35 19 / 25 19. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 12 B) 16 C) 8 D) 0 20 / 25 20. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√3/12 B) 2/5 C) 5√6/24 D) 5√2/5 21 / 25 21. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 9 B) 8 C) 15 D) 10 22 / 25 22. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 8 B) 6 C) 5 D) 7 23 / 25 23. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) -2 B) 1 C) 0 D) -1 24 / 25 24. Agar A) π B) π/2 C) 0 D) 3π/2 25 / 25 25. Tenglamalar sistemasi nechta yechimga ega? A) 12 B) 6 C) 10 D) 8 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz