Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №3 Matematika olimpiadaViloyat 2021-2022 o'quv yili 10-sinf Matematika olimpiada №3 InfoMaster Avgust 19, 2024 12 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №3 2021-2022 o'quv yili viloyat bosqichida tushgan savollar. 1 / 25 1. tengsizlikning eng katta butun yechimini toping. A) 1 B) 2 C) 4 D) 3 2 / 25 2. 7(kx−2)=7k+2(x−8) tenglama k ning qanday qiymatlarida ildizga ega bo`lmaydi? A) k=2/7 B) (2/7; ∞) C) (−∞; 2/7) D) ∅ 3 / 25 3. ABC – gipotenuzasi AB bo‘lgan to‘g‘ri burchakli uchburchak. Gipotenuzaning ikki tomon davomida AB to‘g‘ri chiziqda AK = AC va BM = BC shartlar bilan kesmalar ajratilgan. KCM burchakni toping. A) 90° B) 135° C) 120° D) 150° 4 / 25 4. Agar bo‘lsa, ?(0) − ?(5) ayirmani toping. A) -24 B) -26 C) -27 D) -25 5 / 25 5. bo‘lsa ? ning qiymatini toping. A) 25 B) 12 C) 40 D) 37 6 / 25 6. Tenglamalar sistemasi nechta yechimga ega? A) 10 B) 8 C) 12 D) 6 7 / 25 7. ?/? kasr (?, ? −natural sonlar)— qisqarmas kasr va (7?+6?)/(3?+2?) kasr esa qisqaradi. Ushbu kasr qanday songa qisqaradi? A) 5 B) 2 C) 8 D) 3 8 / 25 8. Agar bo‘lsa, |xyz| ni toping. A) 1000 B) 800 C) 500 D) 100 9 / 25 9. Agar ? > 0, ? + ?² = 7,25; ?² − ? = 2 va ?² = √(? − 1) ∙ √(2 − ?) bo‘lsa, ?(√(? − 1) + √(2 − ?)) ning qiymatini toping. A) 7 B) 5 C) 4 D) 6 10 / 25 10. 102022 − 22021 ayirmani 24 ga bo‘lgandagi qoldiqni toping. A) 12 B) 8 C) 0 D) 16 11 / 25 11. ?(? − 1) = 2?(5? + 4) va ?(2? − 1) = 4? + 4 bo‘lsa, ?(?) ni toping A) 20x+50 B) 0 C) x+25 D) 20x+48 12 / 25 12. Agar A) π B) 0 C) 3π/2 D) π/2 13 / 25 13. Qavariq to‘rtburchakning diagonallari 3 va 4 ga teng. Agar qarama qarshi tomonlarining o‘rtalarini tutashtirishdan hosil bo‘lgan kesmalar uzunliklari o‘zaro teng bo‘lsa, qavariq to‘rtburchakning yuzini toping. A) 7 B) 6 C) 5 D) 8 14 / 25 14. tenglama nechta yechimga ega, agar x ∈ (0; 50)? A) 17 B) 16 C) 15 D) 14 15 / 25 15. ABCD to‘rtburchakda А va В burchaklar- to‘g‘ri, tg∠D = 3/4 va ВС = AD/2 = АВ + 2 bo‘lsa, АС ni toping. A) 15 B) 8 C) 10 D) 9 16 / 25 16. ?² + |? − 3| ≤ |?2 + ?| − 3 tengsizlikni yeching. A) x<0 B) x>3 C) 3 ≤ x D) x ≤ 3 17 / 25 17. Ayirmasi noldan farqli bo‘lgan arifmetik progressiyaning 4-hadidan boshlab 14- hadigacha bo‘lgan hadlar yig‘indisi 77 ga teng. Progressiyaning 7 ga teng bo‘lgan had nomerini toping. A) 9 B) 10 C) 8 D) 11 18 / 25 18. Soddalashtiring: (4cos² 9° −3)(4cos² 27° −3)·ctg9° A) 2cos² 9° B) 1 C) sin18° D) tg9° 19 / 25 19. Agar ni toping. A) 0.9 B) 0.81 C) 0.96 D) 0.8 20 / 25 20. Agar ?1 = 6? − 6 va у2//?1 hamda у2 to‘g‘ri chiziq ?(6; 6) nuqtadan o‘tsa, ?2 ni toping. A) −6? + 6 B) 6? − 30 C) −6? + 42 D) 6? − 24 21 / 25 21. Tenglamani yeching: 3x+3 + 8·3x+2 = 33 A) -2 B) 0 C) -1 D) 1 22 / 25 22. Agar cos ∠A = 1/5 va sin∠B = 1/2 bo‘lsa, АВС uchburchakning mos ravishda А va В uchlaridan tushirilgan balandliklar nisbatini toping. A) 5√3/12 B) 5√2/5 C) 2/5 D) 5√6/24 23 / 25 23. (?² − 2? + 3)(?² + 6? + 12) = 6 bo‘lsa, ? + ? ni toping. A) 2 B) -3 C) -2 D) 3 24 / 25 24. ABCD to‘rtburchakda АВ = CD = 9 va bu to‘rtburchakka radiusi 4 ga teng aylana ichki chizilgan. ABCD to‘rtburchak yuzini toping. A) 144 B) 72 C) 81 D) 36 25 / 25 25. x, y sonlari (x² + 1)(y² + 1) + 2(x − y)(1 − xy) = 4(1 + xy) tenglikni qanoatlantiradi |1 + x| ∙ |1 − y| ni toping. A) 3 B) 9 C) 1 D) 2 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
