Matematika attestatsiya №2 Yanvar 13, 2022Yanvar 13, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №2 ga 1 fikr bildirilgan 0% 2 ovozlar, 4.5 o'rtacha 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №2 1 / 40 tengsizlikni yeching. A) x∈(-5;1) B) x∈(-∞;5) C) x∈(-∞;5)∪(-3;1) D) x∈(-3;1) 2 / 40 Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping. A) 8 B) 16 C) 24 D) 32 3 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) a>c>b B) b>a>c C) c>a>b D) a>b>c 4 / 40 bo‘lsa, y = ? A) 2 B) 8 C) 3 D) 26 5 / 40 Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ? A) 6 B) 12 C) 9 D) 14 6 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 2 B) 4 C) 3 D) 5 7 / 40 bo‘lsa, ning qiymatini toping. A) 0,7 B) 1 C) 0,5 D) 2 8 / 40 funksiyaning eng kichik musbat davrini toping. A) 18 B) 12 C) 24 D) 26 9 / 40 Berilgan sonlarning yig’indisini toping. A) 2/4 B) 3/18 C) -452/18 D) 1/4 10 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 4 B) 25 C) 16 D) 9 11 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) x=-a B) y=-a C) x=a D) y=1-a 12 / 40 tenglamani yeching. A) log(5/3)2 B) 3 C) log(3/5)2 D) 5 13 / 40 Tenglama ildizlari ayirmasining modulini toping. A) √5+5 B) 2√5 C) 5 D) √5 14 / 40 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 1/4 B) 4 C) 1/3 D) 1/5 15 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 1 B) 7 C) 9 D) 3 16 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 1 B) 4 C) 3 D) 2 17 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 4,5 B) 4 C) 7,5 D) 3 18 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13sinx-sin13x + C B) 13sinx+sin13x + C C) 13cosx-cos13x + C D) -13cosx- cos13 x +C 19 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (-2; ∞) B) (-1; ∞) C) [-1; ∞) D) (0; ∞) 20 / 40 Aniq integralni hisoblang: A) 2 B) 3 C) 0 D) 0,5 21 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 114 B) 126 C) 108 D) 96 22 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln3 B) ln2 C) ln4 D) ln5 23 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 40 B) 44 C) 46 D) 50 24 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) 1 B) √2 C) 2 D) √3 25 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 1 B) 3 C) 4 D) 2 26 / 40 P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping. A) 3x+2y+2=0 B) 3x-2y+2=0 C) 3x+2y-2=0 D) 3x-2y-2=0 27 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 8 B) 6 C) 2 D) 4 28 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 6 B) 9,25 C) 5,75 D) 13 29 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;0)∪(0;√2] B) [-√2;√2] C) (-2√2;√2) D) [-√2;-1)∪(-1;1)∪(1;√2] 30 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)=x²+3x+7 B) f(x)=x²-4 C) f(x)=x²-x+5 D) f(x)+2x²-1 31 / 40 Hisoblang: A) 27 B) 4 C) 7 D) 9 32 / 40 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 4 B) 6 C) 2 D) 0 33 / 40 Tengsizlikni yeching. A) [-3;2]∪{1} B) [-2;1]∪{-3} C) (-∞;-2] D) [-3;-2] 34 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 3 B) 2 C) 1 D) 0 35 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,6 m yoki 60 cm B) 0,9 m yoki 90 cm C) 0,7 m yoki 70 cm D) 0,5 m yoki 50 cm 36 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 11/5 B) 67/15 C) 31/85 D) 68/15 37 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 26 B) 27 C) 48 D) 32 38 / 40 Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) 18 B) √6+√14 C) 16 D) 2√14+√6 39 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 4 B) 2 C) 1 D) 3 40 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 35/6 B) 6 C) 8 D) 25/3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika attestatsiya
