11-sinf Matematika 4-chorak Aprel 17, 2021Aprel 20, 2021 da chop etilgan InfoMaster tomonidan 11-sinf Matematika 4-chorak ga fikr bildirilmagan. 16 OMAD YOR BO'LSIN! 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) √2 B) √22 C) 2 D) 1 2 / 25 Kub to’la sirtining yuzi 105,84 sm2 bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping. A) 17,68 dm²; 4,2 dm B) 17,64 dm²; 4,2 dm C) 17,64 dm²; 4,9 dm D) 17,64 dm; 4,2 dm 3 / 25 Funksiyaning aniqlanish sohasini toping : y=logx-2(x2+7x-8) A) (-∞;-1)U(8;+∞) B) (2;3)U(3;+∞) C) (8;+∞) D) (-∞;-8)U(2;3)U(3;+∞) 4 / 25 Uchburchakli muntazam prizma asosining radiusi ga va balandligi 2 ga teng bo’lgan silindrga ichki chizilgan. Prizma yon sirtining yuzini toping A) 3 B) 335 C) 36 D) 4 5 / 25 B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping A) 3/4 B) 1 C) 4 D) 3 6 / 25 integralni hisoblang A) 5ln4e B) 5ln3e³ C) 5 D) 5ln2e 7 / 25 x=1, y=2x va y=2-x chiziqlari bilan chegaralangan sohaning yuzini toping A) log₃e B) log₄e C) ln4 D) ln3 8 / 25 Funksiya hosilasini toping: A) 21x²-10x B) 12x+12 C) 12x²-12 D) 14x+12 9 / 25 Murakkab funksiyaning hosilasini toping. y=x2sinx A) y’=-2xsinx+x² B) y’=2xsinx-x² C) y’=x²cosx-2xsinx D) y’=2xsinx+x²cosx 10 / 25 Tekislikdagi 1 m masofada yotgan nuqtadan ikkita teng og’ma o’tkazilgan. Agar og’malar perpendikulyar va tekislikka o’tkazilgan perpendikulyar bilan 600 ga teng burchaklar tashkil etsa, og’malarning asoslari orasidagi masofani toping A) 4√2 B) 2√3 C) 2√2 D) 1 11 / 25 y=x2-│2x-4│ funksiya grafigiga x=3 va x= -3 nuqtalarda o’tkazilgan urinmalar kesishish nuqtasi ordinatasini toping A) -6 B) -5 C) -12 D) -9 12 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 14400 B) 8100 C) 19600 D) 25600 13 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,623 B) 0,3265 C) 0,0282 D) 0,0321 14 / 25 Qavariq ko’pburchakning har bir uchidan uchtadan qirra chiqadi. Agar bu ko’pyoqning qirralari soni 12 ta bo’lsa, uning nechta uchi va yog’i mavjud? A) 4;11 B) 4;10 C) 4;18 D) 8;10 15 / 25 Funksiyaning statsionar nuqtalarini toping A) x=-1, x=3 B) x=0, x=2 C) x=3, x=2 D) x=-1, x=2 16 / 25 sin3x+cos3x≥0 tengsizligini yeching A) ø B) [-π/9+n π/3;2 π/9+n π/3] C) [-π/9+2πn/3; 2π/9+2πn/3] D) (-π/2+n π;- π/2+n π) 17 / 25 A) 20 B) 13 C) 18 D) 14 18 / 25 Hisoblang: cos2330+cos2450-sin2600+cos2570 A) 2,25 B) 1,5 C) 0,5 D) 0,75 19 / 25 f(x)=3x2-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping. A) 0 B) 0.5 C) 2 D) 1.5 20 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=0.5cos(5x+12) B) f(x)=-0,5sin(5x+12) C) f(x)=-cos(5x+12) D) f(x)=cos(5x+12) 21 / 25 f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping. A) F(x)=x²+3x+1 B) F(x)=x²+3x-1 C) F(x)=x²-3x+1 D) F(x)=x²-3x-1 22 / 25 Koordinatalar boshidan y=x2-4x+3 parabolaning simmetriya o’qigacha bo’lgan masofani toping. A) 1 B) 2 C) 3 D) 4 23 / 25 Funksiya hosilasini toping: f(x)=5 A) 0 B) x C) 5 D) 10 24 / 25 A(-4;3;6) nuqtaning Oxz tekisligiga nisbatan simmrtrik nuqtasini toping. A) (-4;-6;6) B) (-4;-3;6) C) (-8;-3;6) D) (-4;-3;9) 25 / 25 Uchlari soni 14 ta, qirralari soni esa 21 ta bo’lgan ko’pyoqning yoqlari sonini toping. A) 9 B) 16 C) 4 D) 8 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Author: InfoMaster Matematika choraklik Teglar:11-sinf, matematika
