Uy » Choraklik online testlar » Matematika choraklik » 11-sinf Matematika 4-chorak Matematika choraklik 11-sinf Matematika 4-chorak InfoMaster Aprel 20, 2021 280 Ko'rishlar 83 izohlar SaqlashSaqlanganOlib tashlandi 4 0 OMAD YOR BO'LSIN! 11-sinf Matematika 4-chorak Testni Salomov Sardor tayyorladi. 1 / 25 Aylanaga o’tkazilgan vatar uni 5:7 nisbatda bo’ladi. Ushbu vatarga tiralgan, aylanaga ichki chizilgan katta burchakni toping A) 105° B) 55° C) 75° D) 125° 2 / 25 Silindr shaklidagi idishga 6 sm3 suv solindi. Idishga detal to’liq cho’ktirilganda, suv sathi 1,5 marta ko’tarildi. Detal hajmini aniqlang A) 3 B) 14 C) 23 D) 1 3 / 25 cos(2arctg(1/2)) ni hisoblang A) -37/35 B) -35/37 C) 37/35 D) 35/37 4 / 25 (x2+23x+23)(x2+x+23)=23x2 tenglama haqiyqiy ildizlari yig’indisini toping A) 23 B) -24 C) -23 D) 24 5 / 25 y>0 bo’lsin. To’g’riburchakning uchlari to’g’ri burchakli koordinatalar sistemasida qyuidagicha berilgan: A(0;0), B(0;y), C(-9;y) va D(-11;0). To’rtburchak diagonallarining o’tralari orasidagi masofani toping A) 2 B) 1 C) √2 D) √22 6 / 25 Trapetsiyaning kichik asosi 6 ga va yon tomoni 5 va 7 ga teng. Uning kata asosi ham butun son bo’lsa, perimetri eng ko’pi bilan nechaga teng bo’lishi mumkin A) 3√2 B) 4 C) 3 D) 1 7 / 25 Ushbu funksiyasining boshlang’ich funksiyasini toping A) lnI(x-2)(x-3)I B) ln(|x+2|*|x+1|) C) (x+2)(x+1) D) lnIx-1I 8 / 25 To’g’riburchakli parallelepiped asosining tomonlari 7:24 nisbatda, diagonal kesimining yuzi 50dm2 ga teng. Yon sirtining yuzini toping. A) 135 dm² B) 124 dm C) 124 dm² D) 224 dm² 9 / 25 To’g’riburchakli parallelepiped bir uchidan chiquvchi uchta qirralari uzunliklari 4,6 va 9 ga teng. Unga tengdosh kub qirrasining uzunligini toping. A) 8 B) 6 C) 7 D) 6 10 / 25 F(x)=0.2sin(5x+12) funksiyasi uchun f(x) ni toping A) f(x)=cos(5x+12) B) f(x)=-cos(5x+12) C) f(x)=-0,5sin(5x+12) D) f(x)=0.5cos(5x+12) 11 / 25 To’g’ri to’rtburchak shaklidagi yer maydoninig atrofini o’rashmoqchi. 480 m panjara yordamida eng ko’pi bilan necha kvadrat metr yer maydonni o’rash mumkin? A) 25600 B) 19600 C) 14400 D) 8100 12 / 25 Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping A) √24 B) √55 C) √19 D) √66 13 / 25 Karim 3 minutda 213ta so`zni terib , 6ta imloviy xatoga yo`l qo`ydi. Karimning matn terish sifatini toping. A) 0,623 B) 0,0282 C) 0,3265 D) 0,0321 14 / 25 funksiya uchun y=2x-1 to`g`ri chiziqqa parallel bo`lgan urinma tenglamasini yozing A) y=2x B) y=2x-2,25 C) y=2x+3 D) y=3x-2,2 15 / 25 limitni hisoblang A) 0 B) 7 C) 5 D) 6 16 / 25 funksiyaning [-4;1] kesmadagi eng kata qiymatini toping. A) -13 B) 13 C) 131 D) -4 17 / 25 y=-3x3+2x2-4x+5 funksiyaga x0=-1 nuqtada o’tkazilgan urinma tenglamasining burchak koeffitsiyentini toping. A) 15 B) -13 C) -17 D) 17 18 / 25 funksiya grafigiga x=1 abssisssali nuqtadao`tkazilgan urinma tenglamasini yozing A) y=-x B) y= 2x C) y=x D) y=1/2 19 / 25 Funksiya hosilasini toping: A) 12x²-12 B) 21x²-10x C) 14x+12 D) 12x+12 20 / 25 A) 18 B) 14 C) 20 D) 13 21 / 25 funksiyasining kamayish oralig’ini toping. A) (-∞;-1) B) (-1/3;+∞) C) [-1;-1/3] D) (-1;1/3) 22 / 25 Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping A) (2-√3)(2√3-π) B) (2-√3)(2-π) C) (4-√3)(2√3-π) D) 2√3-π 23 / 25 y=x2-│2x-4│ funksiya grafigiga x=3 va x= -3 nuqtalarda o’tkazilgan urinmalar kesishish nuqtasi ordinatasini toping A) -9 B) -6 C) -5 D) -12 24 / 25 Agar f(x)=6+5tg22x bo’lsa, f '(π) ni toping A) 3 B) 1 C) 5 D) 0 25 / 25 Funksiyaning aniqlanish sohasini toping : y=logx-2(x2+7x-8) A) (-∞;-1)U(8;+∞) B) (8;+∞) C) (-∞;-8)U(2;3)U(3;+∞) D) (2;3)U(3;+∞) 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz