Uy » Choraklik online testlar » Matematika choraklik » 5-sinf Matematika 3-chorak yuzasidan TEST Matematika choraklik 5-sinf Matematika 3-chorak yuzasidan TEST InfoMaster Mart 26, 2021 879 Ko'rishlar 23 izohlar SaqlashSaqlanganOlib tashlandi 7 0 OMAD YOR BO'LSIN! 5-sinf Matematika 3-chorak 1 / 25 ≤th≥ …≤th≥– juft teglarining vazifasi qanday? A) jadvalga sarlavha qo‘shish B) jadval qatoriga katakcha qo‘shish C) jadval qatorini qo‘shish D) jadval yaratish teglari 2 / 25 ≤table≥ tegining width atributi qiymatining vazifasini toping. A) jadvalning ramka qalinligi o‘rnatilgan bo‘lsa (border), jadval katagi bilan tashqi chegara ramkasi orasidagi masofani o‘rnatish. B) jadval balandligini o‘rnatish. Qiymat piksel yoki foizlarda berilishi mumkin. 3 / 25 ≤table≥…≤/table≥ – juft teglarining vazifasi qanday? A) jadval yaratish teglari B) jadval qatorini qo‘shish 4 / 25 ≤form≥ tegining method atributi qiymatining vazifasini toping. A) sonli ifoda B) harfiy ifoda C) forma ma’lumotlarini jo‘natish usuli. D) formada har xil ko‘rinishdagi elementlarni hosil qiladi. E) qavsli misol F) formaga nom berish (bu nom skriptlar yozishda ishlatiladi) G) forma orqali jo‘natilayotgan ma’lumotlar qaysi sahifada qayta ishlanishi kerakligi beriladi. H) a va b javoblar 5 / 25 ≤input≥…≤/input≥ – juft teglarining vazifasi qanday? A) jadvalga sarlavha qo‘shish B) jadval qatoriga katakcha qo‘shish C) veb-sahifaga forma joylashtirish uchun qo‘llaniladi D) 3365 E) 33065 F) 303065 G) tegi turli xil forma elementlarini yaratish uchun ishlatiladi, ya’ni formaning asosi hisoblanadi. H) 3398 6 / 25 ≤form≥…≤/form≥– juft teglarining vazifasi qanday? A) 30 B) jadvalga sarlavha qo‘shish C) 33 D) 29 E) veb-sahifaga forma joylashtirish uchun qo‘llaniladi F) tegi turli xil forma elementlarini yaratish uchun ishlatiladi, ya’ni formaning asosi hisoblanadi. G) 27 H) jadval qatoriga katakcha qo‘shish 7 / 25 form elementida har doim qaysi atributi ishtirok etishi lozim? A) 1 m2=100 dm2 B) valign C) 1 m2=1000dm2 D) aling E) height F) 1 m2=100000 dm2 G) 1 m2=10 dm2 H) action 8 / 25 Tushirib qoldirilgan sonni ayting; … : 3 = 13 A) 56 B) 59 C) 48 D) 39 9 / 25 Qo’sh tengsizlik ko’rinishida ifodalang. 44 soni 55 sonidan kichik, lekin 33 sonida katta; A) 44<55<33 B) 55<44<33 C) 3344 D) 33<44<55 10 / 25 Hisoblang: 15*(128:4)+12 A) 577 B) 470 C) 677 D) 492 11 / 25 Bo’lishni bajaring: 1980 : 36 A) 65 B) 35 C) 55 D) 45 12 / 25 Kubning hajmini 216 bo'lsa uning qirrasini toping. A) 6 B) 4 C) 5 D) 8 13 / 25 To'g'ri burchakli parallelepipedning a=3, b=4, c=5 tamonlari berilgan bo'lsa uning sirtini yuzini toping. A) 56 B) 72 C) 94 D) 92 14 / 25 Sonlarni yig’indisi toping. 112, 85, 2333; A) 2530 B) 3446 C) 2624 D) 4940 15 / 25 AB kesmani C nuqta AC va CB qismlarga ajratadi. Agar AC kesma uzunligi 56 sm bo’lib, u BC kesmadan 23 sm qisqa bo’lsa, AB kesma uzunligini toping. A) 233 sm B) 125 sm C) 135 sm D) 129 sm 16 / 25 Harfli ifodaning qiymatini toping. 128 – b; b=59 A) 79 B) 53 C) 69 D) 75 17 / 25 Amallarni bajaring: A) 5,4/7 B) 8,4/7 C) 6,4/7 D) 7,4/7 18 / 25 Amallarni bajaring: (232 + 8) : 10 + 124 ; A) 129 B) 602 C) 308 D) 148 19 / 25 To'g'ri burchakli parallelepipedning asoning yuzi 15 dm^2, hadmi 60 dm^3 bo'lsa uning balandligini toping. A) 8 B) 2 C) 4 D) 45 20 / 25 Tenglamani yeching: 21 * x = 903 A) 54 B) 43 C) 28 D) 36 21 / 25 Amudaryoning uzunligi 2540 km . Sirdaryo unga qaraganda 479 km uzun. Sirdaryoning uzunligini toping. A) 3019 km B) 18128 km C) 2061 km D) 4765 km 22 / 25 To'g'ri burchakli parallelepipedning hajmini topish formulasini ko'rsating. A) V=a^2 B) V=a^3 C) S=6a^2 D) V=abc 23 / 25 To’g’ri to’rtburchakning enini toping. A) 3,15/13 B) 4,11/13 C) 2,11/13 D) 2,14/13 24 / 25 Yig’indini toping: A) 8,19/14 B) 8,20/14 C) 8,22/14 D) 8,21/14 25 / 25 441 559 soni 109 sonidan necha marta katta? A) 4051 B) 3261 C) 1642 D) 4050 0% Testni qayta ishga tushiring Baholash mezoni 86%-100% 5 baho 71%-85% 4 baho 56%-70% 3 baho 55% va kamiga 2 baho Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz