Barcha fanlardan online testlar

11-sinf Matematika 4-chorak

InfoMaster

Aprel 20, 2021

264 Ko'rishlar 83 izohlar

SaqlashSaqlanganOlib tashlandi 4

OMAD YOR BO'LSIN!

11-sinf Matematika 4-chorak

Testni Salomov Sardor tayyorladi.

1 / 25

Bir burchagi 60⁰ bo’lgan to’g’ri burchakli uchburchakka tomoni 6 ga teng romb shunday ichki chizilganki, 60⁰ li burchak ular uchun umumiy, rombning barcha uchlari uchburchakning tomonlarida yotadi. Uchburchak yuzini toping

A) (8√3)/2

B) (81√3)/2

C) √3/2

D) (1√3)/2

2 / 25

Voleybol jamoasi 9 ta o’yinchidan iborat. Boshlang’ich tarkibga 6 ta o’yinchini nechta usul bilan tanlab olish mumkin

A) 168

B) 84

C) 21

D) 42

3 / 25

Massasi 735 gr va konsentratsiyasi 16% bo’lgan yodning spirtdagi eritmasiga qancha toza spirt qo’shilsa, uning konsentratsiyasi 10% bo’ladi

A) 420

B) 441

C) 252

D) 256

4 / 25

y=x²-│2x-4│ funksiya grafigiga x=3 va

x= -3 nuqtalarda o’tkazilgan urinmalar kesishish nuqtasi ordinatasini toping

A) -9

B) -5

C) -12

D) -6

5 / 25

2cosx+sinx=-2 tenglamaning [-π;π] kesmada nechta ildizi bor

A) 3

B) 1

C) Ø

D) 2

6 / 25

$y=6^{ln(x^{2}+5)}$ funksiyasining kamayish oralig’ini toping

A) ∅

B) (-√5;√5)

C) (0;+∞)

D) (-∞;0]

7 / 25

B,C,D,E nuqtalar aylanadagi, A esa aylanadan tashqaridagi nuqtalar. D nuqta AE kesmada, B esa AC kesmada yotadi. Agar AE=12 va AC=16 bo’lsa, BE vatar uzunligining CD vatar uzunligiga nisbatini toping

A) 1

B) 3/4

C) 4

D) 3

8 / 25

x=1, y=2^x va y=2^-x chiziqlari bilan chegaralangan sohaning yuzini toping

A) log₃e

B) ln4

C) ln3

D) log₄e

9 / 25

Tomoni 4 ga teng bo’lgan teng tomonli uchburchak ichiga uchburchakning tomonlariga urinuvchi uchta teng doira joylashtirilgan. O’zaro urunuvchi doiralar yoylaridan hosil bo’lgan egri chiziqli uchburchakning yuzini toping

A) 2√3-π

B) (2-√3)(2-π)

C) (4-√3)(2√3-π)

D) (2-√3)(2√3-π)

10 / 25

$f(x)=x^3-2x^2+3x-2$ funksiya grafigiga x=4 abssissali nuqtada o`tkazilgan urinma tenglamasini tuzing

A) y=35x

B) y=35x+30

C) y=20x+20

D) y=10x

11 / 25

$\lim_{x\rightarrow -1}(5-2x)$ limitni hisoblang

A) 7

B) 6

C) 0

D) 5

12 / 25

f(x)=2x+3 funksiyasi uchun A(1;5) nuqtadan o’tuvchi boshlang’ich funksiyasini toping.

A) F(x)=x²+3x+1

B) F(x)=x²-3x+1

C) F(x)=x²-3x-1

D) F(x)=x²+3x-1

13 / 25

Funksiya hosilasini toping: $f(x)=7x^3-5x^2+4$

A) 12x²-12

B) 21x²-10x

C) 14x+12

D) 12x+12

14 / 25

Murakkab funksiyaning hosilasini toping. y=x²sinx

A) y’=x²cosx-2xsinx

B) y’=2xsinx-x²

C) y’=-2xsinx+x²

D) y’=2xsinx+x²cosx

15 / 25

Uchlari A(2;-3;4) va B(-2;4;5) nuqtalarda bo’lgan AB kesmasining uzunligini toping

A) √55

B) √19

C) √66

D) √24

16 / 25

f(x)=3x²-5x+4 va g(x)=4x-5 funksiyalarining urinmalari parallel bo’ladigan nuqtalarini toping.

A) 0

B) 2

C) 0.5

D) 1.5

17 / 25

Uchlari A(2;3;4) va B(-4;-5;-6) nuqtalarda bo’lgan AB kesmasining o’rtasining koordinatalarini toping.

A) (-2;-4;-1)

B) (-1;-1;-4)

C) (-1;-1;-1)

D) (-1;-3;-1)

18 / 25

cos(2arctg(1/2)) ni hisoblang

A) -37/35

B) 35/37

C) -35/37

D) 37/35

19 / 25

Muntazam uchburchak tomoni 3 ga teng. Uchburchak tomonlari o’rtalari tutashtirilib, muntazam uchburchaklar hosil qilindi. Ichma-ich joylashgan uchburchaklar yuzlari yig’indisini toping

A) 2

B) 3

C) 2√3

D) 3√3

20 / 25

sin3x+ $\sqrt{3}$ cos3x≥0 tengsizligini yeching

A) ø

B) (-π/2+n π;- π/2+n π)

C) [-π/9+n π/3;2 π/9+n π/3]

D) [-π/9+2πn/3; 2π/9+2πn/3]

21 / 25

f(x)=e^xcosx funksiyasi uchun f ’(π/2) ni aniqlang.

A. e^-0.5π B. e^0,5π C. e^π D. e^-π

A) e^(0.5π)

B) e^(-0.5π)

C) e^(-π)

D) e^(π)

22 / 25

f(x)=sin2x funksiyasining barcha boshlang’ich funksiyalarini toping.

A) F(x)=2sin4x+c

B) F(x)=-0,5cos2x+C

C) F(x)=0,5cos2x+C

D) F(x)=-2cos2x+C

23 / 25

Kub to’la sirtining yuzi 105,84 sm² bo’lsa, uning har bir yog’i yuzini va qirrasining uzunligini toping.

A) 17,64 dm²; 4,9 dm

B) 17,64 dm; 4,2 dm

C) 17,64 dm²; 4,2 dm

D) 17,68 dm²; 4,2 dm

24 / 25

Tandirdan olingan nonning temperaturasi 20 minut ichida 100⁰ dan 60⁰ gacha pasayadi. Tashqi muhit temperaturasi 25⁰. Nonning temperaturasi qancha vaqtda 30⁰ gacha pasayadi?

A) 41

B) 61

C) 51

D) 71

25 / 25

Moddiy nuqta qonuniyat bilan harakatlanmoqda, eng katta tezlanishga erishiladigan vaqtni toping.