Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 85 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Matematika abituriyentlar uchun №1 1 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 60 B) 50 C) 225 D) 150 2 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) π B) 2π C) π/2 D) 2π/3 3 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) 6 B) 9 C) -6 D) -3 4 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 17 B) 14 C) 16 D) 18 5 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 3 B) 1 C) 2 D) 5 6 / 30 integralning qiymatini toping. A) 0 B) π/2 C) π/4 D) -π/2 7 / 30 Tengsizlikni yeching. A) (-1/³ √2 ;0) B) 0 C) to'g'ri javob yo'q D) (0;+∞) 8 / 30 sistemada xy ning qiymatini toping. A) 64 B) 80 C) 60 D) 75 9 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 7 B) 4 C) 6 D) 5 10 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 B) 50 C) 10 yoki 50 D) 2 yoki 50 11 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) 10/27 B) -10/27 C) 10/3 D) -10/3 12 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2)v(2;∞) B) (2;∞) C) (-∞;2) D) [2;∞) 13 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1] B) (-∞;1]v[10;∞) C) [10;∞) D) 1; 10 14 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [2;4]v{2}v[3;∞) B) (-∞;-6]v{2}v[12;∞) C) [-2;4]v{6} D) [1;6] 15 / 30 Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping. A) 72π B) 56π C) 100π D) 96π 16 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 228 B) 150 C) 147 D) 231 17 / 30 Hisoblang. A) 2/17 B) 17/34 C) 15/34 D) 2/34 18 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4+|x-1|)+c B) ln|x-1/x+4|+c C) ln(|x+4*|x-1|)+c D) ln|x+4/x-1|+c 19 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1 B) √5/2 C) √3/2 D) 1,5 20 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 100 B) 127 C) 400 D) 375 21 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 32 B) 42 C) 38 D) 36 22 / 30 sonning oxirgi raqamini toping. A) 8 B) 4 C) 2 D) 6 23 / 30 Tengsizlik nechta butun yechimga ega? A) 4 B) 1 C) cheksiz ko’p D) 3 24 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 12π B) 7 π C) 6 π D) 10 π 25 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 14 B) 10 C) 12 D) 24 26 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1,4 B) 2, 3 C) 1, 3 D) 3, 4 27 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 6200 B) 7200 C) 6900 D) 7000 28 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 20 B) 16 C) 24 D) 32 29 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 8 B) 4 C) 6 D) 12 30 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,75 B) -0,25 C) -1 D) -0,5 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
