Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 121 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 11 B) √46 C) 12 D) 10 2 / 30 200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi. A) 12 B) 8 C) 16 D) 4 3 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 12 B) 18 C) 6 D) 3 4 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 6 B) 4 C) 8 D) 12 5 / 30 Tenglamaning ildizlari yig`indisini toping. A) 4 B) 5 C) 6 D) 3 6 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 3 B) √15 C) 2 D) √5 7 / 30 Tengsizlik nechta butun yechimga ega? A) 3 B) 4 C) 1 D) cheksiz ko’p 8 / 30 Hisoblang A) 2 B) 1 C) 0 D) -1 9 / 30 Hisoblang: A) 2 B) -1 C) 3 D) 1 10 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠12 B) a≠5 C) a=12 D) a ning bunday qiymati yo’q 11 / 30 Hisoblang A) 1 B) 3√3 C) 2√3 D) √3 12 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 60 B) 47 C) 120 D) 18 13 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6) B) 6 C) (-∞;6])v[6;∞) D) (2;∞) 14 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √37 B) 2 C) √7 D) bunday to’gri to’rtburchak mavjud emas 15 / 30 A) 1 B) √6 C) 2 D) 0 16 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √37 B) 6 C) 3 D) √32 17 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) x=y/3=z/2 B) -x-y+z=0 C) x-1/2=y-2/3=z-3/4 D) 2x+3y+z=0 18 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 3 B) 2 C) 3,5 D) 4 19 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) √3/2 B) √5/2 C) 1,5 D) 1 20 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 22222222220 B) 222222222222 C) 2222222175 D) 222220175 21 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,25 B) -1 C) -0,5 D) -0,75 22 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -4 B) -10 C) -12 D) -14 23 / 30 x2-5|x|-6=0 tenglama ildizini toping A) ±6 B) ±;±6 C) -1;6 D) -1;-6 24 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 12 B) 11 C) 10 D) 9 25 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁵⁰⁵⁰ B) e⁴⁹⁵⁰ C) e⁻⁴⁹⁵⁰ D) e⁻⁵⁰⁵⁰ 26 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 18 B) 17 C) 16 D) 14 27 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 2/5 B) 1/3 C) 1/2 D) -1/2 28 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (4; -3) B) (-7;-1) C) (-7; 1) D) (7; 1) 29 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 135√3/4 B) 67,5 C) 67,5√3 D) 48√3 30 / 30 sistemada xy ning qiymatini toping. A) 60 B) 80 C) 64 D) 75 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz