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Matematika attestatsiya №12

InfoMaster

Aprel 8, 2022

163 Ko'rishlar 1 izoh

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

x>0 da x + √x = 3 bo'lsa, √x -3/√x ifodaning qiymatini toping.

A) -2

B) -1

C) 0

D) 1

2 / 40

Bir nechta natural sonlardan tuzilgan S to‘plam berilgan. Bu sonlarning o‘rta
arifmetigi eng kattasini hisobga olmaganda 32 ga, eng kichigini hisobga olmaganda 40 ga, eng kattasini ham eng kichigini ham hisobga olmaganda esa 35 ga teng. Agar eng katta son eng kichigidan 72 ga ortiq bo‘lsa, u holda S to‘plamdagi barcha sonlarning o‘rta arifmetigini toping.

A) 36,2

B) 36,8

C) 36,4

D) 36,6

3 / 40

a²·b·c<0, (a·b)>0 va a·c³<0 tengsizliklardan foydalanib a,b,c larning ishoralarini aniqlang:

A) -, -, +

B) -, -, -

C) -, +, -

D) +, -, +

4 / 40

Agar f(x)=x^sin2x bo'lsa, f'(π/4) toping.

A) π/4

B) 0

C) π/2

D) 1

5 / 40

Hisoblang.

A) -47/24

B) 49/25

C) -47/25

D) 51/29

6 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 52

B) 54

C) 48

D) 50

7 / 40

ABCD parallelogramm va S_KBCE= 18 bo'lsa, S_ABCD=?

A) 62

B) 54

C) 48

D) 56

8 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 5

B) 4

C) 3

D) 6

9 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) 2x+c

C) c

D) 4x+c

10 / 40

Hisoblang.

A) 24+3b

B) 24-3b

C) 26-3b

D) 14-2b

11 / 40

Agar bo'lsa, ni toping.

A) 3

B) 5,2

C) 0

D) 2,5

12 / 40

Hisoblang.

A) 1

B) 2

C) 4

D) 0

13 / 40

Tenglama ildizlari yig'indisini toping.

A) 2

B) 0

C) 4

D) -1

14 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) 2

B) 0

C) -1

D) 3

15 / 40

Hisoblang.

A) 2

B) 1

C) 0

D) -1

16 / 40

Tenglamani yeching:

A) 5,5

B) 2

C) 2,5

D) 6

17 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 6700/13

B) 7500/13

C) 7551/15

D) 15

18 / 40

Tangga besh martta tashlanganda 2 martta gerb chiqishi ehtimolini toping.

A) 5/16

B) 9/16

C) 7/16

D) 5/13

19 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 7/3

B) 3/7

C) 7/4

D) 0

20 / 40

Hisoblang.

A) 3/5

B) 2/3

C) 5/3

D) 3/2

21 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;0]

B) (-1;3]

C) [-1;0)

D) [-1;1]

22 / 40

Hisoblang.

A) 2

B) 3

C) 1

D) 6

23 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -4

B) -6

C) -5

D) -3

24 / 40

To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping.

A) 21

B) 18

C) 20

D) 23

25 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 28

B) 35

C) 42

D) 48

26 / 40

|x²-2x|≤x yengsizlikni yeching.

A) (-2;0)∪[1;3]

B) {0}∪[1;3)

C) {0}∪[1;3]

D) {0}∪(1;3]

27 / 40

y=xlnx funksiyani hosilasini toping.

A) 2lnx-1

B) 1

C) lnx/2+1

D) lnx+1

28 / 40

Tengsizlikni yeching.

A) x∈(0;1000)

B) x∈(1;1000]

C) x∈[0;1000]

D) x∈(10;1000)

29 / 40

Tenglamani yeching.

A) 4

B) 1

C) 3

D) 2

30 / 40

Hisoblang.

A) 0

B) 9/13

C) 9/11

D) 7/11

31 / 40

Hisoblang.

A) 121

B) 135

C) 133

D) 131

32 / 40

Hisoblang.

A) 2

B) -1

C) 1

D) 0

33 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotadi

B) Yotmaydi

34 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) 2√7

B) 3√7

C) 4√5

D) √7

35 / 40

a=1^0,(6), b=8^0,(3) , c=2^0,(9) bo'lsa, (a+b)^c=?

A) 16

B) 0

C) 9

D) 25

36 / 40

Hisoblang

A) 12

B) 36

C) 6

D) 9

37 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x+c

B) 2x+c

C) 4x+c

D) x/2+c

38 / 40

f(x)+(x-2)·g(x)=x²+5, f(3)=10 bo'lsa, g^-1=(4) ni toping. Bunda g^-1(x) g(x) ga teskari funksiya.

A) 5

B) 4

C) 3

D) 6

39 / 40

Tengsizlikni yeching.

A) [-7;-3) u [-1;∞)

B) [-7;3 u [-1;∞)

C) [-7;-3] u [-1;∞)

D) [-7;-5) u [-1;∞)

40 / 40

Hisoblang.

A) 4

B) 1

C) 2

D) 3

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”