Matematika attestatsiya №12 Aprel 8, 2022Aprel 8, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №12 ga 3 fikr bildirilgan 0% 4 12345678910111213141516171819202122232425262728293031323334353637383940 OMAD YOR BO'LSIN! Matematika fanidan attestatsiya savollari №12 28.03.2022 da Toshkentda tushgan savollar DIQQAT! Endi siz o'z bilmingizni sinab ko'rish bilan birga sertifikatga ham ega bo'lishingiz mumkin. Sertifikat olish uchun barcha ma'lumotlarni to'g'ri kiriting! e-mail manzilini to'g'ri kriting, barcha ma'lumotlar sizga yuboriladi. Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling. 1 / 40 x²-(sinα)x - 1/4cos²α =0 tenglamaning ildizlaridan biri 2/3 bo‘lsa, sinα= ? A) 1/3 B) 5/3,1/3 C) 2/5 D) 1,1/3 2 / 40 n ning nechta butun qiymatida kasr butun son bo‘ladi? A) 3 B) 10 C) 9 D) 8 3 / 40 Hisoblang. A) 1 B) -1 C) 0 D) 2 4 / 40 Soddalashtiring A) -x(x+y)/x-y B) -x(x-y)/x+y C) x(x-y)/x+y D) (x-y)/(x+y) 5 / 40 1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin? A) 49 B) 47 C) 51 D) 48 6 / 40 Tengsizlikni yeching: 3 · 9x –10 · 21x + 7 · 49 x ≤ 0 A) [-1;0] B) [-1;0) C) [-1;1] D) (-1;3] 7 / 40 f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari. A) 36 B) 38 C) 40 D) 42 8 / 40 Agar bo'lsa f(x)=? A) x²+2 B) x²-1 C) x²-2 D) 2x²-1 9 / 40 ABCD parallelogramm va SKBCE = 18 bo'lsa, SABCD =? A) 48 B) 56 C) 54 D) 62 10 / 40 Tenglamani yeching. A) 2 B) 5 C) 1 D) 0 11 / 40 Hisoblang. A) 24-3b B) 24+3b C) 26-3b D) 14-2b 12 / 40 To'g'ri burchakli uchburchakning yuzi 96 ga, perimetri esa 48 ga teng bo'lsa, gipatenuza uzunligini toping. A) 18 B) 20 C) 21 D) 23 13 / 40 |x²-2x|≤x yengsizlikni yeching. A) {0}∪[1;3) B) {0}∪[1;3] C) {0}∪(1;3] D) (-2;0)∪[1;3] 14 / 40 Tenglamani yeching: A) 2 B) 2,5 C) 6 D) 5,5 15 / 40 Tenglamani yeching. A) 4 B) 1 C) 2 D) 3 16 / 40 Hisoblang. A) 131 B) 133 C) 121 D) 135 17 / 40 Hisoblang A) 36 B) 9 C) 12 D) 6 18 / 40 Arimetik progerssiyada s12=354, P=a1+a2+...+a11 , Q=a2+a4+...+a12 va P/Q=32/27 ga teng bo'lsa, d ni toping. A) -3 B) -6 C) -5 D) -4 19 / 40 (tgx-2ctgx)⁴ yoyilmaning ozod hadini toping. A) 25 B) 24 C) 6 D) 58 20 / 40 Hisoblang. A) 6 B) 1 C) 2 D) 3 21 / 40 Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping. A) 2 B) 2/3 C) 1/2 D) 1 22 / 40 5-x ≤ 0,04 x ning eng kichik butun qiymatini toping. A) 2 B) 3 C) -1 D) 0 23 / 40 Agar cos4x = acos⁴x+bcos2²x+1 bo'lsa, a+b=? A) 0 B) 2 C) -1 D) 1 24 / 40 Hisoblang. A) -47/24 B) 51/29 C) 49/25 D) -47/25 25 / 40 Hisoblang. A) 9/13 B) 0 C) 7/11 D) 9/11 26 / 40 Hisoblang. A) 0 B) 2 C) -1 D) 1 27 / 40 Tenglamaning [0;π] kesmadagi ildizlari soni 3 tadan ko'pmi? A) Ha B) Yo'q 28 / 40 Hisoblang. A) 1 B) 0 C) 2 D) -1 29 / 40 Hisoblang. cos²10° + cos²30° + cos²80° A) 7/4 B) 3/7 C) 7/3 D) 0 30 / 40 Agar bo'lsa, ni toping. A) 2,5 B) 5,2 C) 3 D) 0 31 / 40 Hisoblang. A) 2019 B) 2021 C) 1 D) 2020 32 / 40 Tengsizlikni yeching. A) x∈[0;1000] B) x∈(10;1000) C) x∈(0;1000) D) x∈(1;1000] 33 / 40 Tangga besh martta tashlanganda 2 martta gerb chiqishi ehtimolini toping. A) 9/16 B) 7/16 C) 5/13 D) 5/16 34 / 40 Noaniq integralni toping. ∫(sin²x+cos²x)dx A) c B) x+c C) 2x+c D) 4x+c 35 / 40 Hisoblang. A) 94 B) 32 C) 98 D) 96 36 / 40 Tenglama ildizlari yig'indisini toping. A) 4 B) 2 C) 0 D) -1 37 / 40 Hisoblang. A) 4 B) 2 C) 1 D) 3 38 / 40 Hisoblang. A) 2/3 B) 3/5 C) 5/3 D) 3/2 39 / 40 Chizmada nechta uchburchak tasvirlangan? A) 54 B) 48 C) 52 D) 50 40 / 40 Hisoblang. A) 5 B) 6 C) 3 D) 4 0% Testni qayta ishga tushiring Baholash mezoni - 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”; - 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”; - 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”; - 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”; - 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin” - 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”; - 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin” Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya