Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 144 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 7 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 A) 2 B) 1 C) √6 D) 0 2 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 3 B) 2 C) 1 D) 4 3 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 25 B) 15 C) 30 D) 12 4 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [-2;4]v{6} B) [2;4]v{2}v[3;∞) C) (-∞;-6]v{2}v[12;∞) D) [1;6] 5 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 5 B) 6 C) 7 D) 4 6 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 2 B) 1, 3 C) 3 D) 1, 2 7 / 30 y= funksiyaning aniqlanish sohasini toping A) (-∞;0])v[2;∞) B) (2;∞) C) (-∞;0)v(2;∞) D) (0,2) 8 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 11 B) 14 C) 10 D) 12 9 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 30 B) 25 C) 28 D) 20 10 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,25 B) -0,5 C) -0,75 D) -1 11 / 30 bo’lsa, ni x orqali ifodalang. A) 25/x B) 2-x C) 2/x D) x/25 12 / 30 Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping. A) 6 π B) 12π C) 10 π D) 7 π 13 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √32 B) 3 C) √37 D) 6 14 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 2019 B) cheksiz ko’p C) 1 D) 0 15 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1]v[10;∞) B) 1; 10 C) (-∞;1] D) [10;∞) 16 / 30 tenglamalar sistemasini yeching A) (4;–3) B) (–4;3) C) (3;–4) D) (4;3) 17 / 30 Soddalashtiring. A) 2018a/a+1 B) a+1 C) 2019 D) 2018 18 / 30 funktsiyaning aniqlanish sohasini toping. A) (1;2) B) (-∞;1)v(2;∞) C) [1;2] D) (-∞;1]v[2;∞) 19 / 30 Hisoblang: A) 1 B) 3 C) -1 D) 2 20 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2 C) 4 D) 2√2 21 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 22222222220 C) 222220175 D) 2222222175 22 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 3π/4 B) 3π/2 C) 2π/3 D) 4π/3 23 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5 B) 135√3/4 C) 48√3 D) 67,5√3 24 / 30 Tengsizlikni yeching. A) (0;+∞) B) to'g'ri javob yo'q C) (-1/³ √2 ;0) D) 0 25 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 3 B) 18 C) 12 D) 6 26 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 6 B) 10 C) 8 D) 7 27 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) teng tomonli uchburchak B) o’tkir burchakli uchburchak C) o’tmas burchakli uchburchak D) to’gri burchakli uchburchak 28 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 231 B) 228 C) 147 D) 150 29 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 5 B) 7 C) 3 D) 4 30 / 30 Hisoblang A) 2√3 B) 3√3 C) 1 D) √3 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
