Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 109 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Soddalashtiring. A) a+1 B) 2018 C) 2019 D) 2018a/a+1 2 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2√2 C) 4 D) 2 3 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 2π B) 4π C) 2π/3 D) 3π 4 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) √5/2 B) 1 C) 1,5 D) √3/2 5 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 4S B) 2S C) 0,5S D) 3S 6 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(cos2x) B) -4sin2x*cos(cos2x) C) -4sin2x*cos(2cos2x) D) 4sin2x*cos(2cos2x) 7 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 3 B) 6 C) 4 D) 5 8 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 8 C) 12 D) 6 9 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 3,5 B) 4 C) 2 D) 3 10 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 12 B) 6 C) 3 D) 18 11 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) teng yonli uchburchak B) muntazam uchburchak C) ixtiyoriy uchburchak D) to`g`ri burchakli uchburchak 12 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 54 C) 52 D) 108 13 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 1/3 B) 1/2 C) 2/5 D) -1/2 14 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 2000 B) 2100 C) 1900 D) 2200 15 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 14 B) 18 C) 17 D) 16 16 / 30 A) 2 B) 1 C) 0 D) √6 17 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 4√3π B) 12π C) 3π D) 2√3π 18 / 30 Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping. A) e⁻⁵⁰⁵⁰ B) e⁻⁴⁹⁵⁰ C) e⁵⁰⁵⁰ D) e⁴⁹⁵⁰ 19 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) (-∞;1]v[2;∞) C) [1;2] D) (1;2) 20 / 30 ifodaning qiymatini toping. A) -0,5 B) 0,5 C) 0 D) -2 21 / 30 sistemada xy ning qiymatini toping. A) 80 B) 60 C) 75 D) 64 22 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 30 B) 15 C) 25 D) 12 23 / 30 A) 3 B) 2 C) 5 D) 1 24 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 2,5% ga ortadi B) 6,25% ga kamayadi C) 6,25% ga ortadi D) o‘zgarmaydi 25 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) 1 B) ab C) ab/c D) abc 26 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) 2 B) √7 C) √37 D) bunday to’gri to’rtburchak mavjud emas 27 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) √2e B) 1 C) e D) 3e 28 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) juft ham emas, toq ham emas funksiya B) bunday funksiya mavjud emas C) toq funksiya D) juft funksiya 29 / 30 Ostki asosining yuzi 16π ga va ustki asosining yuzi 4π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning hajmini toping. A) 64√2π/3 B) 8√2π/5 C) (5√3+3)π/3 D) 3√2π/4 30 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1-2sinα/4sin²) B) πa²(1+2cosα/4sin²) C) πa²/4sin²α D) πa²/4cos²α 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
