Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 149 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) 2x+3y+z=0 B) x=y/3=z/2 C) -x-y+z=0 D) x-1/2=y-2/3=z-3/4 2 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 2√2/3 B) 3√3+1/5 C) 5√3+3/3 D) 3√2+2/4 3 / 30 Hisoblang: A) 2 B) 1 C) -1 D) 3 4 / 30 Soddalashtiring. A) 2019 B) 2018 C) a+1 D) 2018a/a+1 5 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) -1/2 B) 2/5 C) 1/2 D) 1/3 6 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 2222222175 C) 222220175 D) 22222222220 7 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 4 B) 3√3 C) 2√5 D) 2√3 8 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) √5/2 B) 1 C) √3/2 D) 1,5 9 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) π C) π/2 D) 2π 10 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) aniqlab bo’lmaydi B) 374389 C) 2 D) 412967 11 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) -4sin2x*cos(cos2x) B) 4sin2x*cos(cos2x) C) 4sin2x*cos(2cos2x) D) -4sin2x*cos(2cos2x) 12 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) √37 B) √7 C) 2 D) bunday to’gri to’rtburchak mavjud emas 13 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²/4cos²α B) πa²(1+2cosα/4sin²) C) πa²(1-2sinα/4sin²) D) πa²/4sin²α 14 / 30 Radiusi 25 bo’lgan doirada 48 ga teng vatar o’tkazilgan. Doira markazidan shu vatargacha masofani toping. A) 10 B) 8 C) 7 D) 9 15 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) a>b>c>d>e B) e>b>a>d>c C) b>c>a>d>e D) b>a>c>d>e 16 / 30 Sin9x =4sin3x tenglamani yeching A) πn, n€Ζ B) π/3+πn, n€Ζ C) πn/3, n€Ζ D) π/2+πn, n€Ζ 17 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) [1;2] C) (1;2) D) (-∞;1]v[2;∞) 18 / 30 sonning oxirgi raqamini toping. A) 8 B) 6 C) 2 D) 4 19 / 30 Soddalashtiring. (0<m<7) A) 2m-7 B) 7-2m C) 7 D) m 20 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 8 C) 12 D) 6 21 / 30 Ushbu (y6+y3+1)(y3+1)(y3-1)-y6+y3+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor? A) 1 B) 4 C) 2 D) 3 22 / 30 O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping. A) 5/720 B) 6/720 C) 5/24 D) 1/60 23 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 2 B) 3 C) √5 D) √15 24 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 11 B) √46 C) 12 D) 10 25 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [cos2;1] C) [0;cos2] D) [-1;1] 26 / 30 sistemada xy ning qiymatini toping. A) 75 B) 80 C) 60 D) 64 27 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 5 B) 7 C) 6 D) 4 28 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0,5 B) 2 C) 1 D) 0 29 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 6 B) 5 C) 4 D) 8 30 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 3 B) 2 C) 1, 2 D) 3 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
