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Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

213 Ko'rishlar 1 izoh

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Matematika abituriyentlar uchun №1

1 / 30

Hisoblang

A) √3

B) 1

C) 2√3

D) 3√3

2 / 30

Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping

A) 32

B) 20

C) 16

D) 24

3 / 30

tenglamalar sistemasini yeching

A) (4;–3)

B) (3;–4)

C) (4;3)

D) (–4;3)

4 / 30

sistemada xy ning qiymatini toping.

A) 60

B) 80

C) 75

D) 64

5 / 30

a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring.

A) a>b>c>d>e

B) b>c>a>d>e

C) b>a>c>d>e

D) e>b>a>d>c

6 / 30

sonning oxirgi raqamini toping.

A) 8

B) 6

C) 2

D) 4

7 / 30

Ostki asosining yuzi 32π va ustki asosining yuzi 18π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda sharning sirtini toping.

A) 72π

B) 96π

C) 56π

D) 100π

8 / 30

Radiuslari orasidagi burchagi 36^o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping.

A) 2π

B) 2π/3

C) π/2

D) π

9 / 30

Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang.

A) o’zaro parallel

B) aniqlab bo’lmaydi

C) o’zaro perpendikulyar

D) ayqash

10 / 30

Agar sinx+cosx=a bo’lsa, ning qiymatini toping.

A) 2/5

B) -1/2

C) 1/2

D) 1/3

11 / 30

Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping.

A) 11

B) 10

C) 9

D) 12

12 / 30

A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping.

A) 1

B) √5/2

C) √3/2

D) 1,5

13 / 30

y= $\sqrt{2x^{2}-4x}$ funksiyaning aniqlanish sohasini toping

A) (-∞;0)v(2;∞)

B) (2;∞)

C) (0,2)

D) (-∞;0])v[2;∞)

14 / 30

Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping.

A) ab/c

B) ab

C) 1

D) abc

15 / 30

200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi.

A) 12

B) 16

C) 8

D) 4

16 / 30

Hisoblang

A) 0

B) -1

C) 1

D) 2

17 / 30

Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping.

A) 32

B) 16

C) 8√5

D) 24√5

18 / 30

y=cos(2sinx) funksiyaning qiymatlar sohasini toping.

A) [cos2;1]

B) [0;cos2]

C) [-1;1]

D) [0;1]

19 / 30

Soddalashtiring. (0<m<7)

A) 2m-7

B) 7-2m

C) 7

D) m

20 / 30

Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping.

A) 112,5°

B) 100°

C) 113°

D) 113,5°

21 / 30

A) 5

B) 2

C) 3

D) 1

22 / 30

Tenglamaning ildizlari yig`indisini toping.

A) 4

B) 5

C) 6

D) 3

23 / 30

Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping

A) 231

B) 228

C) 150

D) 147

24 / 30

Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping.

A) 5√3+3/3

B) 2√2/3

C) 3√3+1/5

D) 3√2+2/4

25 / 30

(-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping.

A) 14

B) 12

C) 10

D) 24

26 / 30

O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping.

A) 5/720

B) 6/720

C) 5/24

D) 1/60

27 / 30

To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi?

A) 6,25% ga ortadi

B) 2,5% ga ortadi

C) o‘zgarmaydi

D) 6,25% ga kamayadi

28 / 30

Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 30⁰ ga teng. Parallelogrammning yuzini toping.