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Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

192 Ko'rishlar 1 izoh

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Matematika abituriyentlar uchun №1

1 / 30

Tenglamaning ildizlari yig`indisini toping.

A) 3

B) 4

C) 5

D) 6

2 / 30

To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping.

A) 17

B) 16

C) 18

D) 14

3 / 30

Hisoblang

A) 3√3

B) 2√3

C) 1

D) √3

4 / 30

Soddalashtiring. (0<m<7)

A) 7-2m

B) 2m-7

C) 7

D) m

5 / 30

sistemadan x+y ning qiymatini toping.

A) 6

B) -12

C) 35/4

D) 12

6 / 30

Ifodani soddalashtiring.

2 cos55^o.cos40^o.sin55^o+cos110^o.sin40^o

A) 2

B) 1

C) 0,5

D) 0

7 / 30

Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 60⁰ ga teng bo’lsa, ikkinchi tomonini toping

A) 5

B) 8

C) 6

D) 4

8 / 30

Ifodani soddalashtiring. [ln(ln x)-ln(log_e10)]^.log₁₀e

A) lg(ln x)

B) lg(lg x)

C) ln(lg x)

D) ln(ln x)

9 / 30

Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping.

A) 3π

B) 12π

C) 4√3π

D) 2√3π

10 / 30

a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega

A) a ning bunday qiymati yo’q

B) a=12

C) a≠5

D) a≠12

11 / 30

A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping.

A) 1,5

B) √3/2

C) √5/2

D) 1

12 / 30

To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping.

A) (4; -3)

B) (-7;-1)

C) (7; 1)

D) (-7; 1)

13 / 30

Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar

A) 1,2

B) 1/2

C) 1

D) 1/6

14 / 30

Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 30⁰ ga teng. Parallelogrammning yuzini toping.

A) 108

B) 54

C) 48√3

D) 52√3

15 / 30

qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi?

A) 38

B) 42

C) 36

D) 32

16 / 30

ifodaning qiymatini toping.

A) 0

B) 0,5

C) -0,5

D) -2

17 / 30

tenglamalar sistemasini yeching

A) (4;–4)

B) (-4;4)

C) (4;4)

D) (-4;-4)

18 / 30

Arifmetik progressiyada a₁₇=33 va a₄₅=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping.

A) √2

B) 2

C) 2√2

D) 4

19 / 30

Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping.

A) 4π

B) 3π

C) 2π

D) 2π/3

20 / 30

x(t)=t²+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi?

A) 54

B) 50

C) 40

D) 36

21 / 30

Yuzasi 10 ga teng bo’lgan kvadratning ketma-ket ikki uchidan o’tuvchi aylana chizilgan. Uchinchi uchidan aylanaga urunma o’tkazilgan. Urunma tomondan ikki marta katta bo’lsa, aylana radiusini toping.

A) 6

B) 5

C) 10

D) 4

22 / 30

Hisoblang:

A) -1

B) 3

C) 2

D) 1

23 / 30

Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping.

A) 113,5°

B) 100°

C) 113°

D) 112,5°

24 / 30

Tengsizlikni yeching.

A) to'g'ri javob yo'q

B) (0;+∞)

C) 0

D) (-1/³ √2 ;0)

25 / 30

Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999

A) 222220175

B) 222222222222

C) 22222222220

D) 2222222175

26 / 30

Soddalashtiring.

A) 2019

B) 2018a/a+1

C) 2018

D) a+1

27 / 30

Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping.

A) 3√3+1/5

B) 3√2+2/4

C) 2√2/3

D) 5√3+3/3

28 / 30

Tomoni 6 ga teng bo`lgan teng tomonli uchburchakga tashqi chizilgan doiraning yuzini toping.

A) 12π

B) 6 π

C) 7 π

D) 10 π

29 / 30

Ushbu (y⁶+y³+1)(y³+1)(y³-1)-y⁶+y³+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor?