Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 221 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 8 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Tenglamani yeching. (x+2)+(x+4)+(x+6)+…+(x+100)=2800 A) 5 B) 3 C) 4 D) 7 2 / 30 Hisoblang A) 1 B) 2 C) -1 D) 0 3 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1,4 B) 1, 3 C) 2, 3 D) 3, 4 4 / 30 integralning qiymatini toping. A) π/2 B) 0 C) -π/2 D) π/4 5 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) teng yonli uchburchak B) to`g`ri burchakli uchburchak C) muntazam uchburchak D) ixtiyoriy uchburchak 6 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) 4k+1/1/8:7-1/56 B) ²ᴷ⁺⁴v2k+1/k²+1 C) (512-1/2⁻⁹)° D) ⁴ᴷ⁺³√-√2k+1 7 / 30 Hisoblang: A) 2 B) -1 C) 3 D) 1 8 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 38 B) 32 C) 36 D) 42 9 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √3 B) 1 C) √2 D) 2 10 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;6 B) ±;±6 C) ±6 D) -1;-6 11 / 30 sistemadan x+y ning qiymatini toping. A) 6 B) 35/4 C) -12 D) 12 12 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 3 B) 1, 3 C) 1, 2 D) 2 13 / 30 Tengsizlik nechta butun yechimga ega? A) 3 B) cheksiz ko’p C) 1 D) 4 14 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro perpendikulyar B) o’zaro kesishadi C) o’zaro parallel D) ayqash to’gri chiziqlar 15 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 2√2/3 B) 5√3+3/3 C) 3√2+2/4 D) 3√3+1/5 16 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) cheksiz ko’p B) 1 C) 0 D) 2019 17 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) 1; 10 B) [10;∞) C) (-∞;1]v[10;∞) D) (-∞;1] 18 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) (-∞;-6]v{2}v[12;∞) B) [-2;4]v{6} C) [1;6] D) [2;4]v{2}v[3;∞) 19 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 60 B) 150 C) 50 D) 225 20 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 10 B) 12 C) 14 D) 24 21 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 4 B) 6 C) 8 D) 5 22 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4+|x-1|)+c B) ln(|x+4*|x-1|)+c C) ln|x-1/x+4|+c D) ln|x+4/x-1|+c 23 / 30 tenglamalar sistemasini yeching A) (4;–3) B) (3;–4) C) (–4;3) D) (4;3) 24 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠5 B) a ning bunday qiymati yo’q C) a=12 D) a≠12 25 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 16 B) 18 C) 17 D) 14 26 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) 11 B) √46 C) 10 D) 12 27 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1+2cosα/4sin²) B) πa²(1-2sinα/4sin²) C) πa²/4cos²α D) πa²/4sin²α 28 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 6900 B) 7200 C) 6200 D) 7000 29 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 2 C) 2√2 D) 4 30 / 30 bo’lsa, ni x orqali ifodalang. A) 2-x B) x/25 C) 2/x D) 25/x 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz