Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 203 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 4 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping. A) 3π/4 B) 4π/3 C) 2π/3 D) 3π/2 2 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 6900 B) 7200 C) 7000 D) 6200 3 / 30 Ifodani soddalashtiring. 2 cos55o.cos40o.sin55o+cos110o.sin40o A) 0 B) 2 C) 1 D) 0,5 4 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 B) 10 yoki 50 C) 2 yoki 50 D) 50 5 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 1900 B) 2000 C) 2200 D) 2100 6 / 30 ifodaning qiymatini toping. A) -2 B) -0,5 C) 0 D) 0,5 7 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 48√3 B) 54 C) 108 D) 52√3 8 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 113° B) 112,5° C) 100° D) 113,5° 9 / 30 sistemadan x+y+z ning qiymatini toping. A) -139/41 B) 140/41 C) 139/41 D) 150/41 10 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 1 B) 3 C) 2 D) 0 11 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) π/2 C) π D) 2π 12 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 0,5S B) 3S C) 4S D) 2S 13 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) e B) √2e C) 3e D) 1 14 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4+|x-1|)+c B) ln|x-1/x+4|+c C) ln|x+4/x-1|+c D) ln(|x+4*|x-1|)+c 15 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 52 B) 54 C) 108 D) 48 16 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 2 B) 3 C) 2 D) 1, 3 17 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -10 B) -12 C) -14 D) -4 18 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping A) 4 B) 7 C) 5 D) 6 19 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 17 B) 18 C) 16 D) 14 20 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 3 B) 2 C) 3,5 D) 4 21 / 30 A) 5 B) 3 C) 2 D) 1 22 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 18 B) 120 C) 60 D) 47 23 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) o’tkir burchakli uchburchak B) to’gri burchakli uchburchak C) teng tomonli uchburchak D) o’tmas burchakli uchburchak 24 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 12 B) 30 C) 25 D) 15 25 / 30 Tenglamaning ildizlari yig`indisini toping. A) 3 B) 6 C) 4 D) 5 26 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) cheksiz ko’p B) 2019 C) 1 D) 0 27 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 2,5% ga ortadi C) 6,25% ga kamayadi D) 6,25% ga ortadi 28 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) aniqlab bo’lmaydi B) 374389 C) 412967 D) 2 29 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2) B) (2;∞) C) (∞;∞) D) (-∞;2)v(2;∞) 30 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) aniqlab bo’lmaydi B) ayqash C) o’zaro perpendikulyar D) o’zaro parallel 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
