Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 221 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 8 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Hisoblang: A) 1 B) 3 C) 2 D) -1 2 / 30 integralning qiymatini toping. A) π/2 B) -π/2 C) π/4 D) 0 3 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2) B) [2;∞) C) (-∞;2)v(2;∞) D) (2;∞) 4 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 1/2 B) 2/5 C) 1/3 D) -1/2 5 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 30 B) 25 C) 12 D) 15 6 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 2, 3 B) 3, 4 C) 1, 3 D) 1,4 7 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) muntazam uchburchak B) to`g`ri burchakli uchburchak C) ixtiyoriy uchburchak D) teng yonli uchburchak 8 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 1900 B) 2000 C) 2200 D) 2100 9 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 8 B) 4 C) 12 D) 6 10 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 4 B) 5 C) 3 D) 6 11 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 5√3+3/3 B) 3√3+1/5 C) 2√2/3 D) 3√2+2/4 12 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusiga teng bo’lgan uchburchak qanday uchburchak deyiladi? A) to’gri burchakli uchburchak B) o’tkir burchakli uchburchak C) o’tmas burchakli uchburchak D) teng tomonli uchburchak 13 / 30 tenglamalar sistemasini yeching A) (–4;3) B) (4;–3) C) (4;3) D) (3;–4) 14 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(cos2x) B) 4sin2x*cos(2cos2x) C) -4sin2x*cos(2cos2x) D) -4sin2x*cos(cos2x) 15 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [0;1] B) [-1;1] C) [cos2;1] D) [0;cos2] 16 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 2√2 B) 4 C) √2 D) 2 17 / 30 Soddalashtiring. A) 2019 B) 2018 C) a+1 D) 2018a/a+1 18 / 30 Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang. A) o’zaro perpendikulyar B) o’zaro kesishadi C) o’zaro parallel D) ayqash to’gri chiziqlar 19 / 30 Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor? A) 1, 3 B) 1, 2 C) 3 D) 2 20 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 10 B) 50 C) 10 yoki 50 D) 2 yoki 50 21 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) π/2 C) 2π D) π 22 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) 10/27 B) -10/3 C) -10/27 D) 10/3 23 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 50 B) 225 C) 150 D) 60 24 / 30 Sin9x =4sin3x tenglamani yeching A) πn/3, n€Ζ B) πn, n€Ζ C) π/3+πn, n€Ζ D) π/2+πn, n€Ζ 25 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 2019 B) 1 C) cheksiz ko’p D) 0 26 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (-∞;2)v(2;∞) B) (2;∞) C) (-∞;2) D) (∞;∞) 27 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 100° B) 112,5° C) 113,5° D) 113° 28 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 11 B) 10 C) 9 D) 12 29 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 6 B) 18 C) 3 D) 12 30 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²(1+2cosα/4sin²) B) πa²/4sin²α C) πa²/4cos²α D) πa²(1-2sinα/4sin²) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
