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Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

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Matematika abituriyentlar uchun №1

1 / 30

Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping.

A) 2 yoki 50

B) 50

C) 10

D) 10 yoki 50

2 / 30

sistema a ning qanday qiymatida cheksiz ko’p yechimga ega?

A) 6

B) (-∞;6)

C) (2;∞)

D) (-∞;6])v[6;∞)

3 / 30

Hisoblang

A) 1

B) 0

C) -1

D) 2

4 / 30

Radiusi 1 ga teng aylana uchta yoyga bo`lingan. Ularga mos markaziy burchaklar 1, 2 va 6 sonlariga proporsional. Yoylardan eng kattasining uzunligini toping.

A) 2π/3

B) 4π/3

C) 3π/2

D) 3π/4

5 / 30

Rasmda ko‘rsatilgan ko‘pyoqlardan qaysi birida 4 ta yoq, 6 ta qirra bor?

A) 1, 2

B) 3

C) 1, 3

D) 2

6 / 30

n ning qanday qiymatida ushbu

8^{1 .}8^{2 .}8^{3 .}…^.8ⁿ=512²² tenglik o’rinli bo’ladi?

A) 11

B) 14

C) 10

D) 12

7 / 30

Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 60⁰ ga teng bo’lsa, ikkinchi tomonini toping

A) 5

B) 6

C) 8

D) 4

8 / 30

Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping.

A) e⁴⁹⁵⁰

B) e⁵⁰⁵⁰

C) e⁻⁵⁰⁵⁰

D) e⁻⁴⁹⁵⁰

9 / 30

Ushbu funksiyaning boshlang’ich funksiyasini toping.

A) ln|x+4/x-1|+c

B) ln(|x+4*|x-1|)+c

C) ln(|x+4+|x-1|)+c

D) ln|x-1/x+4|+c

10 / 30

Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 120⁰ ga teng bo’lsa, uning yuzini toping.

A) 48√3

B) 67,5

C) 135√3/4

D) 67,5√3

11 / 30

Hisoblang

A) √3/2

B) 2

C) 1/2

D) √3

12 / 30

ifodaning qiymatini toping.

A) -0,5

B) 0,5

C) -2

D) 0

13 / 30

Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar

A) 1

B) 1,2

C) 1/2

D) 1/6

14 / 30

Quyidagi va to’g’ri chiziqlarning o’zaro holatini aniqlang.

A) o’zaro parallel

B) o’zaro kesishadi

C) ayqash to’gri chiziqlar

D) o’zaro perpendikulyar

15 / 30

Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping

A) 20

B) 16

C) 32

D) 24

16 / 30

O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping.

A) 1/60

B) 6/720

C) 5/24

D) 5/720

17 / 30

A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping.

A) 1,5

B) 1

C) √5/2

D) √3/2

18 / 30

integralning qiymatini toping.

A) 0

B) -π/2

C) π/4

D) π/2

19 / 30

200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi.

A) 12

B) 4

C) 16

D) 8

20 / 30

Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 30⁰ ga teng. Parallelogrammning yuzini toping.

A) 52√3

B) 48√3

C) 54

D) 108

21 / 30

Soddalashtiring. (0<m<7)

A) 2m-7

B) m

C) 7

D) 7-2m

22 / 30

Ifodani soddalashtiring.

2 cos55^o.cos40^o.sin55^o+cos110^o.sin40^o

A) 0

B) 0,5

C) 2

D) 1

23 / 30

Soddalashtiring.

A) 2018a/a+1

B) a+1

C) 2019

D) 2018

24 / 30

Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping.

A) 12π

B) 4√3π

C) 3π

D) 2√3π

25 / 30

Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping.

A) 10

B) 9

C) 12

D) 11

26 / 30

Sin9x =4sin3x tenglamani yeching

A) π/2+πn, n€Ζ

B) π/3+πn, n€Ζ

C) πn, n€Ζ

D) πn/3, n€Ζ

27 / 30

Agar bank qo’yilgan pulga 40% yillik bersa, qo’yilgan 4500 so’m pul bir yildan so’ng qancha bo’ladi?

A) 6200

B) 6300

C) 6000

D) 6100

28 / 30

ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping.

A) 1/√2

B) 1/√3

C) 1

D) 0,5

29 / 30

y=cos(2sinx) funksiyaning qiymatlar sohasini toping.

A) [cos2;1]

B) [0;cos2]

C) [-1;1]

D) [0;1]

30 / 30

O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping.

A) πa²(1+2cosα/4sin²)

B) πa²(1-2sinα/4sin²)

C) πa²/4sin²α

D) πa²/4cos²α