Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 158 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 1 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Anvar tub son o’yladi va o’ylagan sonini 5 ga ko’paytirib, 8 ni ayirgan edi, yana tub son hosil bo’ldi. Anvar qanday son o’ylagan? A) aniqlab bo’lmaydi B) 2 C) 374389 D) 412967 2 / 30 |x2-5x-14|+20≥5|x+2|+4|x-7| tengsizlikni yeching. A) [2;4]v{2}v[3;∞) B) (-∞;-6]v{2}v[12;∞) C) [1;6] D) [-2;4]v{6} 3 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 38 B) 36 C) 42 D) 32 4 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 108 B) 48 C) 54 D) 52 5 / 30 n ning qanday qiymatida ushbu 81 .82 .83 .….8n=51222 tenglik o’rinli bo’ladi? A) 11 B) 14 C) 10 D) 12 6 / 30 y= funksiyaning aniqlanish sohasini toping A) (2;∞) B) (-∞;0])v[2;∞) C) (-∞;0)v(2;∞) D) (0,2) 7 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 3√2+2/4 B) 3√3+1/5 C) 5√3+3/3 D) 2√2/3 8 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 2 B) 1 C) 5 D) 3 9 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) π B) 2π/3 C) 2π D) π/2 10 / 30 Tenglamani yeching. |x2-11x+10|=x2-11x+10 A) (-∞;1] B) 1; 10 C) [10;∞) D) (-∞;1]v[10;∞) 11 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) ayqash B) o’zaro perpendikulyar C) o’zaro parallel D) aniqlab bo’lmaydi 12 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 18 B) 60 C) 120 D) 47 13 / 30 sistemadan x+y+z ning qiymatini toping. A) 139/41 B) -139/41 C) 140/41 D) 150/41 14 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -3 B) -6 C) 9 D) 6 15 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) b>a>c>d>e B) b>c>a>d>e C) e>b>a>d>c D) a>b>c>d>e 16 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 25 B) 28 C) 30 D) 20 17 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 8 B) 4 C) 5 D) 6 18 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 24 B) 20 C) 16 D) 32 19 / 30 Hisoblang A) √3/2 B) 1/2 C) √3 D) 2 20 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 2 B) 1 C) 3 D) 4 21 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) cheksiz ko’p C) 1 D) 2019 22 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -4 B) -10 C) -12 D) -14 23 / 30 tenglamalar sistemasini yeching A) (-4;4) B) (4;–4) C) (-4;-4) D) (4;4) 24 / 30 Hisoblang: A) -1 B) 3 C) 1 D) 2 25 / 30 Tengsizlikni yeching. A) (-1/³ √2 ;0) B) to'g'ri javob yo'q C) 0 D) (0;+∞) 26 / 30 bo’lsa, ni x orqali ifodalang. A) 2-x B) 25/x C) 2/x D) x/25 27 / 30 Qaysi javobda faqat juft funksiyalar ko’rsatilgan? A) 1, 3 B) 2, 3 C) 3, 4 D) 1,4 28 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 150 B) 225 C) 60 D) 50 29 / 30 Soddalashtiring. A) 2018a/a+1 B) a+1 C) 2018 D) 2019 30 / 30 tenglamalar sistemasini yeching A) (4;3) B) (3;–4) C) (4;–3) D) (–4;3) 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
