Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 139 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 5 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 ifodaning qiymatini toping. A) 0,5 B) -2 C) 0 D) -0,5 2 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;-6 B) ±6 C) -1;6 D) ±;±6 3 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) √2e B) 3e C) e D) 1 4 / 30 A) √6 B) 2 C) 1 D) 0 5 / 30 tenglamani yeching. A) 2017 B) 2018 C) 0 D) 2019 6 / 30 sonning oxirgi raqamini toping. A) 6 B) 2 C) 4 D) 8 7 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 5√3+3/3 B) 3√2+2/4 C) 2√2/3 D) 3√3+1/5 8 / 30 y= funksiyaning aniqlanish sohasini toping A) (2;∞) B) (-∞;0)v(2;∞) C) (-∞;0])v[2;∞) D) (0,2) 9 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 3 B) 2 C) 1 D) 4 10 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (2;∞) B) (-∞;2) C) [2;∞) D) (-∞;2)v(2;∞) 11 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) e>b>a>d>c B) b>c>a>d>e C) a>b>c>d>e D) b>a>c>d>e 12 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -3 B) 6 C) -6 D) 9 13 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (4; -3) B) (-7; 1) C) (-7;-1) D) (7; 1) 14 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) ab B) ab/c C) abc D) 1 15 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) (-∞;6])v[6;∞) B) 6 C) (2;∞) D) (-∞;6) 16 / 30 Agar bank qo’yilgan pulga 40% yillik bersa, qo’yilgan 4500 so’m pul bir yildan so’ng qancha bo’ladi? A) 6100 B) 6200 C) 6300 D) 6000 17 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 16 B) 24√5 C) 8√5 D) 32 18 / 30 Hisoblang. 11+192+1993+19994+199995+1999996+19999997+199999998+1999999999 A) 222222222222 B) 222220175 C) 22222222220 D) 2222222175 19 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x+4/x-1|+c B) ln(|x+4*|x-1|)+c C) ln(|x+4+|x-1|)+c D) ln|x-1/x+4|+c 20 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 4 B) 2 C) 2√2 D) √2 21 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) cheksiz ko’p C) 2019 D) 1 22 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga ortadi B) 2,5% ga ortadi C) 6,25% ga kamayadi D) o‘zgarmaydi 23 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√3 B) 2√5 C) 3√3 D) 4 24 / 30 sistemada xy ning qiymatini toping. A) 80 B) 60 C) 64 D) 75 25 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1,5 B) √5/2 C) 1 D) √3/2 26 / 30 Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing. A) x-1/2=y-2/3=z-3/4 B) 2x+3y+z=0 C) -x-y+z=0 D) x=y/3=z/2 27 / 30 tenglamalar sistemasini yeching A) (3;–4) B) (–4;3) C) (4;–3) D) (4;3) 28 / 30 Soat 3:37 bo’lganda minut va soat millari orasidagi burchakni toping. A) 112,5° B) 100° C) 113° D) 113,5° 29 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 6 B) 7 C) 8 D) 10 30 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) juft ham emas, toq ham emas funksiya B) bunday funksiya mavjud emas C) toq funksiya D) juft funksiya 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz