Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 225 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 Musobaqada 5 ta ishtirokchidan 3 tasiga 1, 2, 3-o’rinlarni necha xil usulda berish mumkin? A) 60 B) 47 C) 120 D) 18 2 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 108 B) 54 C) 48√3 D) 52√3 3 / 30 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakatning 200- metrida qanday tezlikka (m/s) erishadi? A) 42 B) 32 C) 36 D) 38 4 / 30 Soddalashtiring. (0<m<7) A) m B) 7-2m C) 7 D) 2m-7 5 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) 0 B) 1 C) cheksiz ko’p D) 2019 6 / 30 y= funksiyaning aniqlanish sohasini toping A) (-∞;0)v(2;∞) B) (0,2) C) (-∞;0])v[2;∞) D) (2;∞) 7 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) √2 B) 1 C) 2 D) √3 8 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 12 B) 15 C) 30 D) 25 9 / 30 a(x+2)=2x+1 tenglama a ning qanday qiymatida yechimga ega emas? A) (2;∞) B) (-∞;2) C) (∞;∞) D) (-∞;2)v(2;∞) 10 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 8 B) 7 C) 10 D) 6 11 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [cos2;1] B) [0;cos2] C) [0;1] D) [-1;1] 12 / 30 Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping. A) 3√2+2/4 B) 3√3+1/5 C) 5√3+3/3 D) 2√2/3 13 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 90° B) 60° C) 72° D) 30° 14 / 30 Hisoblang: A) 3 B) 1 C) 2 D) -1 15 / 30 tenglamani yeching. A) 0 B) 2018 C) 2017 D) 2019 16 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 12 B) 24 C) 14 D) 10 17 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) 2 B) √37 C) bunday to’gri to’rtburchak mavjud emas D) √7 18 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) 6 B) 3 C) √37 D) √32 19 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 4 B) 8 C) 6 D) 5 20 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 2 B) 2√2 C) √2 D) 4 21 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 40 B) 50 C) 36 D) 54 22 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln(|x+4*|x-1|)+c B) ln(|x+4+|x-1|)+c C) ln|x+4/x-1|+c D) ln|x-1/x+4|+c 23 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 5 B) 4 C) 6 D) 3 24 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 18 B) 6 C) 3 D) 12 25 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 12π B) 3π C) 2√3π D) 4√3π 26 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) 2π C) π D) π/2 27 / 30 Agar f(x)=sin2x va g(x)=cos2x bo’lsa, u holda f(g(x)) funksiyaning hosilasini toping. A) 4sin2x*cos(cos2x) B) -4sin2x*cos(cos2x) C) -4sin2x*cos(2cos2x) D) 4sin2x*cos(2cos2x) 28 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 48√3 B) 67,5 C) 67,5√3 D) 135√3/4 29 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) (1;2) C) (-∞;1]v[2;∞) D) [1;2] 30 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) -10/3 B) 10/3 C) 10/27 D) -10/27 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
