Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 214 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 7 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 5 B) 1 C) 3 D) 2 2 / 30 Agar f(x)=ax3-5x2+b va bo’lsa, a ni toping. A) 3 B) 1 C) 0 D) 2 3 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakka ichki chizilgan aylana markazi bo‘lsa, u holda burchakni toping. A) 60° B) 30° C) 90° D) 72° 4 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 2 yoki 50 B) 10 C) 10 yoki 50 D) 50 5 / 30 x(t)=t2+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi? A) 36 B) 54 C) 40 D) 50 6 / 30 O’q kesimining diagonallari o’zaro perpendikulyar bo’lgan kesik konus yasovchisi va asos tekisligi orasidagi burchak ga teng. Agar o’q kesimining diagonali ga teng bo’lsa, kesik konus asosining yuzini toping. A) πa²/4cos²α B) πa²/4sin²α C) πa²(1+2cosα/4sin²) D) πa²(1-2sinα/4sin²) 7 / 30 integralning qiymatini toping. A) π/2 B) 0 C) -π/2 D) π/4 8 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,75 B) -1 C) -0,5 D) -0,25 9 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 54 B) 48 C) 108 D) 52 10 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 32 B) 24 C) 16 D) 20 11 / 30 ABCD kvadrat ichidan olingan O nuqtadan A, B, C uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5 ga teng bo’lsa, u holda OD kesma uzunligini toping. A) √37 B) √32 C) 3 D) 6 12 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) π B) π/2 C) 2π D) 2π/3 13 / 30 Sin9x =4sin3x tenglamani yeching A) πn/3, n€Ζ B) π/2+πn, n€Ζ C) πn, n€Ζ D) π/3+πn, n€Ζ 14 / 30 Tengsizlikni yeching. A) 0 B) (0;+∞) C) to'g'ri javob yo'q D) (-1/³ √2 ;0) 15 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) √3/2 B) 1,5 C) 1 D) √5/2 16 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 10 B) 14 C) 24 D) 12 17 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 20 B) 30 C) 25 D) 28 18 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;-6 B) -1;6 C) ±6 D) ±;±6 19 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 3S B) 2S C) 4S D) 0,5S 20 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 2 B) √3 C) 1 D) √2 21 / 30 Ag ar tgα=2 bo’lsa, u holda ni hisoblang A) -10/3 B) 10/27 C) 10/3 D) -10/27 22 / 30 Bankda qo`yilgan pul bir yildan kegin foydasi bilan 2600 so`m bo`ldi; Agar bank yillik 30% foyda to`lasa, boshida qancha pul qo`yilgan bo`ladi ? A) 2100 B) 2200 C) 2000 D) 1900 23 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 4 B) 2√5 C) 3√3 D) 2√3 24 / 30 Tengsizlik nechta butun yechimga ega? A) 4 B) 3 C) cheksiz ko’p D) 1 25 / 30 Hisoblang A) 0 B) 1 C) 2 D) -1 26 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 135√3/4 B) 48√3 C) 67,5 D) 67,5√3 27 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) cheksiz ko’p B) 2019 C) 1 D) 0 28 / 30 funktsiyaning aniqlanish sohasini toping. A) (1;2) B) (-∞;1)v(2;∞) C) [1;2] D) (-∞;1]v[2;∞) 29 / 30 Soddalashtiring. A) a+1 B) 2018a/a+1 C) 2018 D) 2019 30 / 30 funksiya uchun quyidagi mulohazalardan qaysi biri o’rinli? A) juft funksiya B) bunday funksiya mavjud emas C) toq funksiya D) juft ham emas, toq ham emas funksiya 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
