Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 198 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 tenglamani yeching. A) 2017 B) 2018 C) 0 D) 2019 2 / 30 Ushbu arifmetik progressiyaning manfiy hadlari yig’indisini toping. A) -0,75 B) -0,5 C) -1 D) -0,25 3 / 30 A(2;-2,5) nuqtadan y= - 4x parabolagacha bo’lgan eng qisqa masofani toping. A) 1 B) 1,5 C) √5/2 D) √3/2 4 / 30 Uchburchakning balandligi 12 ga teng bo’lib, u asosni 5:16 nidbatda bo’ladi. Agar asosning uzunligi 21 ga teng bo’lsa, uchburchakning perimetrini toping A) 48 B) 54 C) 52 D) 108 5 / 30 Bog’bon uch kun davomida o’nta daraxt ko’chati o’tqazishi lozim. Agar bog’bon bir kunda eng kamida bitta ko’chat o’tqazadigan bo’lsa, u shu ishni kunlar bo’yicha necha xil usul bilan taqsimlashi mumkin? A) 36 B) 25 C) 32 D) 30 6 / 30 Agar bank qo’yilgan pulga 40% yillik bersa, qo’yilgan 4500 so’m pul bir yildan so’ng qancha bo’ladi? A) 6100 B) 6000 C) 6200 D) 6300 7 / 30 Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping. A) 2√5 B) 4 C) 3√3 D) 2√3 8 / 30 Markazi O nuqtada bo‘lgan aylanaga PA va PB urinmalar o‘tkazilgan bo’lib, A va B nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma PA va PB kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar XQ=YQ bo‘lsa, u holda PXY uchburchak qanday uchburchak bo‘ladi? A) to`g`ri burchakli uchburchak B) muntazam uchburchak C) ixtiyoriy uchburchak D) teng yonli uchburchak 9 / 30 Ushbu funksiyaning boshlang’ich funksiyasini toping. A) ln|x-1/x+4|+c B) ln|x+4/x-1|+c C) ln(|x+4+|x-1|)+c D) ln(|x+4*|x-1|)+c 10 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) o’zaro perpendikulyar B) ayqash C) o’zaro parallel D) aniqlab bo’lmaydi 11 / 30 Tengsizlikni yeching. A) (-3;2)v(2;4) B) (-3;2) C) (-4;2)v(2;3) D) (2;4) 12 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 4 B) 12 C) 8 D) 6 13 / 30 Agar geometrik progressiyaning ketma–ket dastlabki uchta hadining yig’indisi 62 ga, ularning o’nli logarifmlari yig’indisi 3 ga teng bo’lsa, shu geometrik progressiyaning birinchi hadini toping. A) 2 yoki 50 B) 10 C) 10 yoki 50 D) 50 14 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (-7; 1) B) (7; 1) C) (-7;-1) D) (4; -3) 15 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {2;4} B) {1;2} C) {-1;3} D) {-1;2} 16 / 30 sistemada xy ning qiymatini toping. A) 60 B) 75 C) 64 D) 80 17 / 30 A) 3 B) 5 C) 1 D) 2 18 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 11 B) 12 C) 9 D) 10 19 / 30 tenglamalar sistemasini yeching A) (–4;3) B) (4;3) C) (4;–3) D) (3;–4) 20 / 30 Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping A) 20 B) 24 C) 16 D) 32 21 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 6,25% ga kamayadi B) 6,25% ga ortadi C) o‘zgarmaydi D) 2,5% ga ortadi 22 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4716 B) 4680 C) 4720 D) 4760 23 / 30 200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi. A) 4 B) 12 C) 8 D) 16 24 / 30 Ikki burchagi graduslari yig’indisi uchinchi burchagi gradusidan katta bo’lgan uchburchaklar sonini toping. A) cheksiz ko’p B) 2019 C) 0 D) 1 25 / 30 Parallelogrammning tomonlari nisbati 3:5 kabi. Agar parallelogrmmning perimetri 48 ga burchaklaridan biri 1200 ga teng bo’lsa, uning yuzini toping. A) 67,5√3 B) 67,5 C) 135√3/4 D) 48√3 26 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) √46 B) 11 C) 10 D) 12 27 / 30 sistema a ning qanday qiymatida cheksiz ko’p yechimga ega? A) 6 B) (2;∞) C) (-∞;6) D) (-∞;6])v[6;∞) 28 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -4 B) -10 C) -14 D) -12 29 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) lg(lg x) B) lg(ln x) C) ln(ln x) D) ln(lg x) 30 / 30 Agar x,y sonlar (x+5)2+(y-12)2=142 tenglikni qanoatlantirsa, x2+y2 ifodaning eng kichik qiymatini toping. A) 1 B) √3 C) √2 D) 2 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
