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Matematika abituriyent testi №1

InfoMaster

Aprel 5, 2022

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Matematika abituriyentlar uchun №1

1 / 30

Ifodani soddalashtiring. [ln(ln x)-ln(log_e10)]^.log₁₀e

A) ln(lg x)

B) ln(ln x)

C) lg(ln x)

D) lg(lg x)

2 / 30

bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya.

A) -4

B) -12

C) -14

D) -10

3 / 30

Hisoblang

A) 1/2

B) √3/2

C) 2

D) √3

4 / 30

tenglamalar sistemasini yeching

A) (–4;3)

B) (4;3)

C) (3;–4)

D) (4;–3)

5 / 30

Rombning balandligi 8 ga dioganallarining ko’paytmasi 80 ga teng. Rombning perimetrini toping

A) 24

B) 16

C) 32

D) 20

6 / 30

x(t)=t²+7t-6 qonuniyat bo’yicha harakatlanayotgan moddiy nuqtaning tezligi harakat boshlangandan necha sekund o’tgach 87 m/s ga teng bo’ladi?

A) 50

B) 36

C) 40

D) 54

7 / 30

a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping.

A) 12

B) 6

C) 8

D) 4

8 / 30

Ushbu (y⁶+y³+1)(y³+1)(y³-1)-y⁶+y³+1 ifodani soddalashtish natijasida ko’phad hosil qilindi. Uning nechta hadi bor?

A) 2

B) 4

C) 1

D) 3

9 / 30

y=cos(2sinx) funksiyaning qiymatlar sohasini toping.

A) [0;1]

B) [0;cos2]

C) [cos2;1]

D) [-1;1]

10 / 30

sistemadan x+y ning qiymatini toping.

A) 35/4

B) 12

C) -12

D) 6

11 / 30

To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping.

A) 4S

B) 3S

C) 0,5S

D) 2S

12 / 30

O’qishni bilmaydigan bola alifbening A,A,A, N,N, S- 6 ta harflarini ixtiyoriy ravishda terib chiqadi. Bunda ANANAS so’zining hosil bo’lish ehtimolini toping.

A) 6/720

B) 5/24

C) 5/720

D) 1/60

13 / 30

Fazoda (1;2;3) nuqtalardan o’tuvchi to’g’ri chiziq tenglamasini tuzing.

A) x-1/2=y-2/3=z-3/4

B) 2x+3y+z=0

C) x=y/3=z/2

D) -x-y+z=0

14 / 30

7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin?

A) 3

B) 6

C) 4

D) 5

15 / 30

Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping.

A) 11

B) 9

C) 12

D) 10

16 / 30

A) 3

B) 2

C) 1

D) 5

17 / 30

200 kishidan iborat turistlar guruxida 140 kishi ingliz tilini, 90 kishi nemis tilini va 46 kishi ikkala tilni biladi. Ikkala tilni xam bilmaydigan turistlar necha foizni tashkil qiladi.

A) 4

B) 16

C) 8

D) 12

18 / 30

Muntazam uchburchakli piramidaning yon qirrasi asos tekisligi bilan 45^o li burchak tashkil etgan bo‘lsa, u holda piramidaning yon sirti yuzining uning asosi yuziga nisbatini toping.

A) 3√3

B) 2√3

C) 4

D) 2√5

19 / 30

Agar funksiya berilgan bo’lsa, u holda M=ning qiymatini toping.

A) e⁻⁵⁰⁵⁰

B) e⁵⁰⁵⁰

C) e⁴⁹⁵⁰

D) e⁻⁴⁹⁵⁰

20 / 30

Soddalashtiring. (0<m<7)

A) 7-2m

B) 2m-7

C) m

D) 7

21 / 30

Ostki asosining yuzi 20π va ustki asosining yuzi 10π ga teng bo‘lgan kesik konus berilgan. Agar kesik konusga shar ichki chizilgan bo‘lsa, u holda kesik konus hajmining shar hajmiga nisbatini toping.

A) 3√2+2/4

B) 2√2/3

C) 5√3+3/3

D) 3√3+1/5

22 / 30

funktsiyaning aniqlanish sohasini toping.

A) (1;2)

B) (-∞;1]v[2;∞)

C) [1;2]

D) (-∞;1)v(2;∞)

23 / 30

Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 30⁰ ga teng. Parallelogrammning yuzini toping.

A) 52√3

B) 108

C) 48√3

D) 54

24 / 30

Tenglamani yeching.

|x²-11x+10|=x²-11x+10

A) 1; 10

B) (-∞;1]

C) [10;∞)

D) (-∞;1]v[10;∞)

25 / 30

To’g’ri burchakli uchburchakning gipotenuzasi 13 ga, katetlaridan biri 52 ga teng. Gipotenuzaga tushirilgan balandlik uzunligini toping

A) 4

B) 6

C) 7

D) 5

26 / 30

Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping

A) 150

B) 147

C) 228

D) 231

27 / 30

a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega

A) a≠5

B) a ning bunday qiymati yo’q

C) a=12

D) a≠12

28 / 30

To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi?