Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 160 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 2 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster Matematika abituriyentlar uchun №1 1 / 30 tenglamalar sistemasini yeching A) (3;–4) B) (4;3) C) (–4;3) D) (4;–3) 2 / 30 To’rtburchakli muntazam piramidaning yon qirrasidagi ikki yoqli burchak 120 ga teng. Diagonal kesimining yuzasi S ga teng bo’lsa, uning yon sirtini toping. A) 4S B) 3S C) 0,5S D) 2S 3 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 14 B) 18 C) 16 D) 17 4 / 30 sonning oxirgi raqamini toping. A) 6 B) 8 C) 2 D) 4 5 / 30 Tengsizlikni yeching. A) (2;4) B) (-4;2)v(2;3) C) (-3;2)v(2;4) D) (-3;2) 6 / 30 Agar va b-a=4 bo’lsa, a+b ni toping. A) 4 B) 2 C) 3,5 D) 3 7 / 30 Bekzodda 50 so’m va Sobirda 70 so’m pul bor edi. Anvar Bekzodga o’z pulining 10 foizini bergandan so’ng, Bekzod Sobirga pulining yarmini berdi. So’ng Sobir Anvarga pulining 10 foizini berdi. Anvar o’zidagi pullarini hisoblab, pullari dastlabki holdagi puli bilan teng ekanligini bildi. Anvarda qancha pul bo’lgan? A) 375 B) 127 C) 400 D) 100 8 / 30 bo’lsa, ni x orqali ifodalang. A) 2/x B) 25/x C) 2-x D) x/25 9 / 30 A) √6 B) 0 C) 2 D) 1 10 / 30 Soddalashtiring. (0<m<7) A) m B) 7-2m C) 7 D) 2m-7 11 / 30 Agar arctga+ arctgb + arctgc= bo’lsa, a+b+c ni toping. A) ab/c B) abc C) ab D) 1 12 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) √2 B) 4 C) 2 D) 2√2 13 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2)v(2;∞) B) (-∞;2) C) (2;∞) D) [2;∞) 14 / 30 funktsiyaning aniqlanish sohasini toping. A) (-∞;1)v(2;∞) B) [1;2] C) (-∞;1]v[2;∞) D) (1;2) 15 / 30 ifodaning qiymatini toping. A) -0,5 B) 0,5 C) 0 D) -2 16 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 12 B) 24 C) 14 D) 10 17 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;6 B) -1;-6 C) ±;±6 D) ±6 18 / 30 Tenglamaning ildizlari yig’indisi va ko’paytmasining yig’indisini toping. |x+1|.|x-4|=5 A) -6 B) 9 C) 6 D) -3 19 / 30 a ning 7x-a-13=(a-5)(x+7) tenglama yechimga ega bo’lmaydigan qiymatining natural bo’luvchilar sonini toping. A) 12 B) 6 C) 8 D) 4 20 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (4;4) C) (-4;4) D) (-4;-4) 21 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1/2 B) 1 C) 1/6 D) 1,2 22 / 30 Parallelogrammning yuzi 213 ga, tomonlaridan biri 7 ga va o’tkir burchagi 600 ga teng bo’lsa, ikkinchi tomonini toping A) 5 B) 6 C) 8 D) 4 23 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 52√3 B) 54 C) 108 D) 48√3 24 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (7; 1) B) (-7;-1) C) (4; -3) D) (-7; 1) 25 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) π C) 2π D) π/2 26 / 30 Hisoblang. A) 2/17 B) 15/34 C) 17/34 D) 2/34 27 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a≠5 B) a=12 C) a ning bunday qiymati yo’q D) a≠12 28 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) 0 B) cheksiz ko’p C) 2 D) 1 29 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 10 B) 9 C) 12 D) 11 30 / 30 To’g’ri burchakli uchburchakning yuzi 24 ga, katetlaridan biri 6 ga teng bo’lsa, gipotenuzasini toping A) √46 B) 12 C) 11 D) 10 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
