Uy » Abituriyent » Matematika abituriyent » Matematika abituriyent testi №1 Matematika abituriyent Matematika abituriyent testi №1 InfoMaster Aprel 5, 2022 84 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0 Vaqtingiz tugadi! Matematika abituriyentlar uchun №1 1 / 30 Rombning yuzi 96 ga, dioganallaridan biri 16 ga teng. Romb tomonini toping. A) 12 B) 11 C) 10 D) 9 2 / 30 Tengsizlik nechta butun yechimga ega? A) cheksiz ko’p B) 4 C) 3 D) 1 3 / 30 Agar bank qo`yilgan pulga 40% yillik foyda bersa, qo`yilgan 5000 so`m pul bir yildan keyin qancha bo`ladi ? A) 7000 B) 7200 C) 6900 D) 6200 4 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 3, 4, 5, 6 ga teng bo’lsa, u holda AB tomon uzunligini toping. A) 2 B) √7 C) bunday to’gri to’rtburchak mavjud emas D) √37 5 / 30 Arifmetik progressiyada a17=33 va a45=89. Progressiyaning birinchi hadi hamda ayirmasining o’rta geometrigini toping. A) 2√2 B) 2 C) √2 D) 4 6 / 30 bo’lsa ni toping. Bunda funksiya f(x) ga teskari funksiya. A) -14 B) -12 C) -4 D) -10 7 / 30 Konsert zalining birinchi qatorida 40 ta o’rindiq bor. Har bir keyingi qatordagi o’rindiqlar soni oldingi qatordan 4 ga ko’p. Agar konsert zalida jami 40 ta qator bo’lsa, u holda shu zaldagi barcha o’rindiqlar sonini toping. A) 4716 B) 4760 C) 4720 D) 4680 8 / 30 y= funktsiyaning aniqlanish sohasini toping. A) (-∞;2) B) [2;∞) C) (2;∞) D) (-∞;2)v(2;∞) 9 / 30 bo’lsa, ni x orqali ifodalang. A) 2/x B) 2-x C) 25/x D) x/25 10 / 30 Tomoni 12 ga teng bo`lgan teng tomonli uchburchakga ichki chizilgan aylana uzunligini toping. A) 12π B) 4√3π C) 2√3π D) 3π 11 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 60 B) 50 C) 225 D) 150 12 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) o‘zgarmaydi B) 6,25% ga kamayadi C) 6,25% ga ortadi D) 2,5% ga ortadi 13 / 30 Agar sinx+cosx=a bo’lsa, ning qiymatini toping. A) 1/3 B) -1/2 C) 1/2 D) 2/5 14 / 30 sistemadan x+y+z ning qiymatini toping. A) -139/41 B) 150/41 C) 139/41 D) 140/41 15 / 30 A) 2 B) 5 C) 3 D) 1 16 / 30 ABCD to’gri to’rtburchak ichidan olingan O nuqtadan A, B, C, D uchlarigacha bo’lgan masofalar mos ravishda 1; 2; 1,5; 1,2 ga teng bo’ladigan barcha to’g’ri to’rtburchaklar sonini toping A) 2 B) 1 C) cheksiz ko’p D) 0 17 / 30 a ning qanday qiymatlarida ushbu 7x-a-13=(a-5)(x+7) tenglama yagona yechimga ega A) a ning bunday qiymati yo’q B) a≠12 C) a=12 D) a≠5 18 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 231 B) 228 C) 147 D) 150 19 / 30 Hisoblang A) 2 B) 1 C) -1 D) 0 20 / 30 Tenglamaning ildizlari yig`indisini toping. A) 6 B) 3 C) 4 D) 5 21 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π B) 2π/3 C) π/2 D) π 22 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 4 B) 5 C) 6 D) 3 23 / 30 a=sin 1; b=sin 2; c=sin 3; d=sin 4 va e=sin 5 sonlarni kamayish tartibida joylashtiring. A) a>b>c>d>e B) b>a>c>d>e C) b>c>a>d>e D) e>b>a>d>c 24 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 18 B) 17 C) 14 D) 16 25 / 30 Agar f(x)=4x3-6x2-2x+3x .log3e bo’lsa, u holda ni toping. A) 1 B) √2e C) 3e D) e 26 / 30 “Tutgan balig‘ining og‘irligi qancha?” degan savolga baliqchi: “Baliqning dumi 3 kg, boshi uning dumi hamda tanasi yarmining og‘irligiga teng, tanasi esa boshi va dumining og‘irligiga teng”, deb javob berdi. Baliqning og‘irligini (kg) toping. A) 3 B) 12 C) 18 D) 6 27 / 30 Teng yonli uchburchakning tomonlari 5, 5 va 6 ga teng. Bu uchburchakning bissektiritsalari va medianalari kesishgan nuqtalar A) 1 B) 1/6 C) 1/2 D) 1,2 28 / 30 y=cos(2sinx) funksiyaning qiymatlar sohasini toping. A) [-1;1] B) [0;cos2] C) [cos2;1] D) [0;1] 29 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 108 B) 54 C) 52√3 D) 48√3 30 / 30 Teng yonli trpetsiyaning asoslari 15 va 25 ga balandligi esa 15 ga teng trapetsiyaning dioganalini toping A) 28 B) 25 C) 30 D) 20 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz
