Matematika abituriyent testi №1 Iyun 22, 2021Aprel 5, 2022 da chop etilgan InfoMaster tomonidan Matematika abituriyent testi №1 ga fikr bildirilmagan. 110 Vaqtingiz tugadi! Matematika abituriyentlar uchun №1 1 / 30 To’rtburchakning uchi M (0, 4) ; N(-4,0) ; P(-3;2) uchlari berilgan. Agar bo’lsa, Q uchining koordinatalarini toping. A) (4; -3) B) (-7; 1) C) (-7;-1) D) (7; 1) 2 / 30 Bir vaqtning o’zida 9,13, . . . ,405 va 15,21, . . . ,255 ketma–ketliklarning hadlari bo’lgan sonlarning eng kattasi va eng kichigining ayirmasini toping A) 228 B) 231 C) 147 D) 150 3 / 30 Tomoni 25 ga diagonallaridan biri 4 ga teng bo’lgan rombning yuzini toping. A) 32 B) 8√5 C) 16 D) 24√5 4 / 30 Markazi nuqtada bo‘lgan aylanaga va urinmalar o‘tkazilgan bo’lib, va nuqtalar urinish nuqtalari bo’lsin. Aylanadagi Q nuqtadan o‘tkazilgan uchinchi urinma va kesmalarni X va Y nuqtalarda kesib o‘tadi. Agar uchburchakning perimetri 48 va aylana radiusi 7 ga teng bo‘lsa, u holda kesma uzunligini toping A) 15 B) 25 C) 12 D) 30 5 / 30 Hisoblang A) √3 B) 2√3 C) 3√3 D) 1 6 / 30 x(t)=t2+6t+5 qonuniyat bo’yicha harakatlanayotgan moddiy nuqta harakat boshlangandan necha sekund o’tgach boshlang’ich nuqtaga nisbatan 77 metr masofaga siljiydi? A) 6 B) 7 C) 10 D) 8 7 / 30 y= funksiyaning aniqlanish sohasini toping A) (-∞;0)v(2;∞) B) (0,2) C) (-∞;0])v[2;∞) D) (2;∞) 8 / 30 To’g’ri to’rtburchakning perimetri 50 ga teng. Bir tomoni boshqa tomonidan 5 ga ko’p. To’g’ri to’rtburchakning yuzini toping. A) 150 B) 50 C) 60 D) 225 9 / 30 (-3;4) nuqtaga absissa, ordinata o’qlariga va koordinata boshiga nisbatan simmetrik bo’lgan nuqtalarni tutashtirishdan hosil bo’lgan uchburchakning eng kata tomonini toping. A) 14 B) 10 C) 24 D) 12 10 / 30 Tenglamaning nechta ildizi bor? |x+1|=|2x-1| A) 4 B) 3 C) 1 D) 2 11 / 30 7 sonini uchta natural sonlar yig’indisi ko’rinishida necha xil usulda yozish mumkin? A) 3 B) 5 C) 4 D) 6 12 / 30 Quyidagilardan qaysi biri barcha lar uchun ma’noga ega (aniqlangan)? A) ²ᴷ⁺⁴v2k+1/k²+1 B) (512-1/2⁻⁹)° C) ⁴ᴷ⁺³√-√2k+1 D) 4k+1/1/8:7-1/56 13 / 30 AA1A2A3A4A5A6 muntazam oltiburchakli piramidaning hajmi ga va balandligi 2 ga teng bo‘lsa, u holda AA2A6 kesim yuzini toping. A) 3 B) 2 C) √5 D) √15 14 / 30 m ning qanday eng katta butun qiymatida y=2x-mx-5+m funksiyaning grafigi 1,3,4 –choraklarda yotadi? A) 2 B) 1 C) 3 D) 5 15 / 30 To‘g‘ri to‘rtburchakning eni 25% ga orttirildi, bo‘yi esa 25% ga kamaytirildi. Natijada uning yuzi qanday o‘zgardi? A) 2,5% ga ortadi B) 6,25% ga kamayadi C) o‘zgarmaydi D) 6,25% ga ortadi 16 / 30 Perimetri 60 ga teng bo’lgan parallelogrammning tomonlari nisbati 2:3 ga, o’tkir burchagi esa 300 ga teng. Parallelogrammning yuzini toping. A) 54 B) 108 C) 48√3 D) 52√3 17 / 30 tenglamalar sistemasini yeching A) (4;–4) B) (-4;-4) C) (4;4) D) (-4;4) 18 / 30 sistema yagona yechimga ega bo’ladigan a ning barcha qiymatlari to’plamini toping. A) {-1;3} B) {1;2} C) {2;4} D) {-1;2} 19 / 30 Tengsizlikni yeching. A) (-1/³ √2 ;0) B) 0 C) (0;+∞) D) to'g'ri javob yo'q 20 / 30 Quyidagi 2x-y+3z=2018 va x+5y+z=2019 tekisliklarning holatini aniqlang. A) ayqash B) aniqlab bo’lmaydi C) o’zaro parallel D) o’zaro perpendikulyar 21 / 30 Tomoni 2 ga teng kvadratga tashqi chizilgan aylana uzunligini toping. A) 2π B) 2π/3 C) 3π D) 4π 22 / 30 bo’lsa, ni x orqali ifodalang. A) 25/x B) x/25 C) 2-x D) 2/x 23 / 30 Radiuslari orasidagi burchagi 36o va radiusi 5 ga teng bo`lgan sektor yoyining uzunligini toping. A) 2π/3 B) π C) π/2 D) 2π 24 / 30 Tenglamaning ildizlari yig`indisini toping. A) 5 B) 4 C) 6 D) 3 25 / 30 To’g’ri burchakli uchburchakning gipotenuzasi 5 ga, bir katetining gipotenuzadagi proyeksiyasi 1,6 ga teng. Ikkinchi katetning kvadratini toping. A) 16 B) 17 C) 18 D) 14 26 / 30 Ifodani soddalashtiring. [ln(ln x)-ln(loge10)].log10e A) ln(lg x) B) lg(lg x) C) ln(ln x) D) lg(ln x) 27 / 30 A) 0 B) 2 C) 1 D) √6 28 / 30 x2-5|x|-6=0 tenglama ildizini toping A) -1;6 B) ±;±6 C) -1;-6 D) ±6 29 / 30 Hisoblang: A) 2 B) 3 C) 1 D) -1 30 / 30 ABC muntazam uchburchak ichidan ixtiyoriy P nuqta olinib, undan BC, CA va AB tomonlarga mos ravishda PD, PE va PF perpendikulyarlar tushirilgan bo’lsa,ni toping. A) 0,5 B) 1/√2 C) 1/√3 D) 1 0% Testni qayta ishga tushiring Baholash mezoni To'g'ri javob uchun 3,1 ball. Fikr-mulohaza yuboring Author: InfoMaster Matematika abituriyent