Matematika attestatsiya №8

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №8

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Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling.

1 / 40

bo‘lsa, x + y ni toping.

2 / 40

Tengsizlikni yeching.

3 / 40

Standart shaklda yozing 0,000000000000013

  1. 1,3·10-12
  2. 1,3·10-13
  3. 1,3·10-14
  4. 1,3·10-15

4 / 40

tenglama intervalda nechta ildizga ega?

5 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

6 / 40

Quyidagilardan qaysi birlari to‘g‘ri?

7 / 40

x tomon uzunligini toping.

8 / 40

ABCD to‘g‘ri to‘rtburchakda AB = 20, BC = 10. CD tomondan shunday E nuqta olinganki, bunda ∠CBE = 15° . AE kesma uzunligini toping.

9 / 40

ABCD to‘g‘ri to‘rtburchakda CD tomonining o‘rtasi E nuqta, EA kesmaning o‘rtasi esa F nuqta.  AB=4 va bu to‘g‘ri to‘rtburchakning yuzi 8 ga teng bo‘lsa, BF/FA nisbat nechiga teng bo‘ladi?

10 / 40

22022 raqamlar yig‘indisidan hosil bo‘lgan sonning raqamlar yig‘indisidan hosil bo‘lgan sonning  raqamlar yig‘indisi hosil qilindi va hokazo. Oxirida bitta raqam qolgan bo‘lsa, shu raqamni toping.

11 / 40

Quyidagilardan qaysi biri to‘g‘ri?

12 / 40

Uchburchakning 10 ga teng balandligi uning asosini 4 va 10 ga teng kesmalarga ajratadi. Uchburchakning qolgan ikki tomonidan kichigiga o‘tkazilgan mediana uzunligini uchdan birini toping.

13 / 40

f (x) = (x² )1−logxa funksiya uchun, f (3x+1) = ax−1 bo`lsa, a parametr quyidagilardan qaysi biriga teng?

14 / 40

Agar a,b>0 sonlari uchun f(a·b) = f(a) + f(b) tengligi, p – tub sonlari uchun esa  f(p)=p tengligi
qanoatlantirilsa, u holda f(25/11) ning qiymatini toping.

15 / 40

Agar Sn arifmetik progressiyaning birinchi n ta hadining yig‘indisi bo‘lsa, Sn+3 − 3Sn+2 + 3Sn+1 − Sn ni hisoblang.

16 / 40

x, y, z sonlari uchun x > y > z va x + y + z + 18 munosabatlar o‘rinli. Bu 3 ta son bir-biridan 1, 2 va 3 sonlariga farq qiladi. Shunga ko‘ra x ning mumkin bo‘lgan barcha qiymatlari yig‘indisini
toping.

17 / 40

Birinchi va oxirgi raqami juft bo‘lgan va 1000 ga bo‘linmaydigan barcha to‘rtxonali sonlar nechta?

18 / 40

x>0 da x + √x = 3 bo'lsa,  √x -3/√x  ifodaning qiymatini toping.

19 / 40

Agar bo‘lsa, √200 ni x orqali ifodalang.

20 / 40

ABCD trapetsiyaning yuzi 24 ga teng asoslari DC = 6, AB = 2, BC tomondan E nuqta olingan bo‘lib, BE = 2EC bo‘lsa, ADE uchburchakning yuzini toping.

21 / 40

Arifmetik progressiyada a3+a6+a9+....+a3n=80 bo‘lsa,  a2n-3+an+6=16 bo‘lsa, n ning qiymatini toping.

22 / 40

To‘g‘ri burchakli uchburchakning gipotenuzasidan olingan nuqtadan uning katetlariga parallel qilib o‘tkazilgan to‘g‘ri chiziqlar uchburchakdan bitta kvadrat va ikkita kichkina to‘g‘ri burchakli uchburchak ajratadi. Agar shu uchburchaklardan birining yuzining kvadrat yuziga nisbati m ga teng bo‘lsa, ikkinchi uchburchak yuzining shu kvadrat yuziga nisbatini toping.

23 / 40

y=sin²(x/2-π/4)  + 2cos2x  funksiyaning eng kichik musbat davrini toping

24 / 40

5x-3=23x-2 bo‘lsa, (2,56)x-2 soni necha xonali son bo‘ladi?

25 / 40

Kubning diagonalidan ushbu diagonal bilan kesishmaydigan qirrasigacha bo‘lgan masofa 4 ga teng. Kubning hajmini toping.

26 / 40

Agar n = 2018 bo‘lsa,  ifodaning qiymatini toping.

27 / 40

Agar N = 34·34·63·270 sonning toq bo‘luvchilari yig‘indisining, juft bo‘luvchilari yig‘indisiga nisbatini toping.

28 / 40

a va b natural sonlar. 10! = a · 2b tenglikda b ning qabul qilishi mumkin bo‘lgan qiymatlari yig‘indisini toping.

29 / 40

Ushbu {1, 2, 3, 4, …, 37} to‘plamdan shunday ikkita son tanlanganki, ularning ko‘paytmasi qolgan 35 ta sonning yig‘indisiga teng. Shu ikki sonning farqini toping.

30 / 40

Agar ning qiymatini toping.

31 / 40

ABCD to‘g‘ri to‘rtburchak bo‘lib, DM kesma to‘rtburchak tekisligiga perpendikulyar. Agar DM kesmaning uzunligi butun son bo‘lib, MA, MC va MB kesma uzunliklari mos ravsihda ketma-ket kelgan toq sonlar bo‘lsa, u holda MABCD piramida hajmini toping.

32 / 40

Hisoblang.

33 / 40

Diagonallari 6 va 8 ga teng bo‘lgan rombga ichki aylana chizilgan. Aylananing romb tomoni bilan urinish nuqtasidan katta diagonalgacha bo‘lgan masofani toping.

34 / 40

sin²(π/4-x) = 1/8 tenglikdan foydalanib sin2x ni toping.

35 / 40

∇ABC da ∠BAC = 30° , AC = f ′(3) va AB = f (3) bo‘lsa, ∇ABC ning yuzini toping. Bunda f(x) = x³ - 5x -4

36 / 40

Tenglamani ildizlari yig’indisini toping. |x + 3| + |x −1| + |x − 4| = 6

37 / 40

I, M , O - turli natural sonlar uchun I·M·O = 2022 bo‘lsa, I + M+O yig‘indining mumkin bo‘lgan eng katta va eng kichik qiymatlari yig‘indisini toping.

38 / 40

(a²+b²+9)x²+2(a+b+3)x+3 = 0 tenglama haqiqiy yechimlarga ega bo‘lsa, 3a – b ni toping.

39 / 40

ni hisoblang.

40 / 40

ABC to‘g‘ri burchakli uchburchakda ∠B =90° , BC = 28, AC =100 va AB tomonda D nuqta shunday olinganki BD = 21 bo‘ladi. sin (∠ACD) ?

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Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”

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