11-sinf Matematika olimpiada №2 Iyul 17, 2022Avgust 19, 2024 da chop etilgan InfoMaster tomonidan 11-sinf Matematika olimpiada №2 ga 3 fikr bildirilgan 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! Tomonidan yaratilgan InfoMaster 11-sinf Matematika olimpiada №2 2019-yil tuman bosqichida tushgan savollar 1 / 25 1. ko‘phadning barcha koeffitsientlari va ozod hadining yig‘indisini toping. A) 125 B) 245 C) -238 D) -247 2 / 25 2. tenglamaning ildizlari yig‘indisini toping. A) 10 B) -2 C) -6 D) 6 3 / 25 3. Agar f(g(x))= − x+13 bo`lsa, f(x) va g(x) to`g`ri chiziqlar orasidagi burchakni toping . A) 0 B) π/4 C) π/2 D) π/3 4 / 25 4. Tengsizlikni yeching. A) (2/3;2) B) (1/2;∞) C) (4/3;3) D) (5/3;2) 5 / 25 5. Perimetri 4 ga o`tkir burchagi 30oga va shu burchak qarshisidagi tomoni √3 ga teng bo`lgan uchburchakka ichki chizlgan aylana radiusini toping. A) 7-4√3 B) 4√3+7 C) (√3-1)/2 D) (1+√3)/2 6 / 25 6. |x²+2x-8|=3a tenglama a ning qanday qiymatlarida 3 ta haqiqiy yechimga ega bo`ladi. A) (0;3) B) a=3 C) 1 D) a>3, a=0 7 / 25 7. a+b=−1 a+c=6 va b+c=1 bo`lsa, a² (3b+3c+2a)+b² (3a+3c+2b)+c² (3a+3b+2c) ning son qiymatini toping. A) 216 B) 27 C) 100 D) 45 8 / 25 8. funksiyaning boshlang`ich funksiyasini toping. A) I B) III C) II D) IV 9 / 25 9. y=6sin2x+sin12x funksiyaning hosilasini toping. A) 24sin7xsin5x B) 24cos7xcos5x C) −24sin7xcos5x D) 24sin5xcos7x 10 / 25 10. ni hisoblang. A) -12 B) 12 C) 13 D) -13 11 / 25 11. Ifodani soddalashtiring: A) 1−√(a-1) B) 1+√(a+1) C) 0 D) √(a²-1) 12 / 25 12. f(x)=x³/3-x²-35x+2 funksiya uchun f `(x)=0 bo`lsa x ni toping. A) −5 va 7 B) −7 va 5 C) 5 va 7 D) −7 va −5 13 / 25 13. Agar 2a =27, 3c=16 bo’lsa a ∙ ? ning qiymatini toping. A) 13 B) 11 C) 12 D) 10 14 / 25 14. ifodani soddalshtiring A) cosα B) 2cosα C) 1 D) 2sinα 15 / 25 15. f(x)=70cosxcos6x uchun boshlang`ich funksiya toping. A) 7sin5x−5sin7x+c B) 7cos5x−5cos7x+c C) 7sin5x+5sin7x+C D) −7cos5x−5cos7x+c 16 / 25 16. funksiyaning aniqlanish sohasini toping. A) (2/3;∞) B) (-∞;4/3)∪(4/3;∞) C) (-∞;2/3)∪(2/3;∞) D) (-∞;4/3) 17 / 25 17. Bir savdogar 1 mеtrini 1200 tiyindan olgan matosini yuvib, kuritgandan so`ng 1800 tiyindan sotyapti. Mato yuvilib kuritilganidan so`ng 20 foizi qisqardi. Bularga ko`ra savdogar nеcha foiz foyda ko`radi? A) 18 B) 15 C) 10 D) 20 18 / 25 18. Bitta tekislikda yotuvchi n ta turli tog`ri chiziq o`tkazilgan. Ularning ixtiyoriy ikkitasi parallel emas va ixtiyoriy uchtasi bitta nuqtadan o`tmaydi ,ya`ni bitta nuqtada kesishmaydi. Bu to`g`ri chiziqlar tekislikni 1276 qismga ajratadi. n ni aniqlang? A) 52 B) 49 C) 50 D) 51 19 / 25 19. Agar lg5=a va lg3=b bo`lsa, log308 ni toping. A) (1−a)(1+b) B) 1+b C) 3(1−a) D) (3(1-a))/(1+b) 20 / 25 20. Poyezd 3 minutda 7 kilometrmasofani , motosikl 5 minutda 7 kilometrmasofanibosibo`tdi. Mototsikltezligipoyezdtezliginingnecha % initashkilqiladi? A) 71% B) 60% C) 61% D) 70% 21 / 25 21. 3cos2x-3 sin2x=0 trigonometrik tenglamani yeching. A) π/6+πk; k∈Z B) π/12+πk/2; k∈Z) C) π/12+2πk; k∈Z D) π/12+πk; k∈Z 22 / 25 22. GH kesmani O nuqta, G nuqtadan boshlab hisoblaganda, 5 : 7 kabi, P nuqtaesa 5:11 kabi nisbatda bo’ladi. O va P nuqtalar orasidagi masofa 30 sm bo’lsa, GH kesmaning uzunligini toping. A) 288 B) 234 C) 72 D) 18 23 / 25 23. Tenglamani yeching: |x²-3x-2|=x²+3|x+2|+4 A) [2;∞) B) [−2;∞) C) [−2;0] D) (−∞;−2] 24 / 25 24. ABCD tetraedrning D uchidagi barcha yassi burchaklari to`g`ri. Shu tetraedrda kub shunday ichki chizilganki, kubning bitta uchi D nuqtada, unga qarama−qarshi uchi esa ABC yoqda yotibdi. Agar DA=5, DB=6 va DC=10 bo`lsa, kub qirrasining uzunligini toping. A) 2 B) 15/7 C) 25/12 D) 2√2 25 / 25 25. Tenglamani yeching: A) arccos0,8+2πk; k∈Z B) π −arcctg4+πk; k∈Z C) πk; −arcctg4+πk; k∈Z D) πk; π−arcctg4+πk; k∈Z 0% Testni qayta ishga tushiring tomonidan Wordpress Quiz plugin Matematika olimpiada, Tuman 2019-2020 o'quv yili
