Matematika attestatsiya №6 Yanvar 30, 2022Yanvar 30, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №6 ga 1 fikr bildirilgan 0% 0 ovozlar, 0 o'rtacha 1 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Agar bo‘lsa, x ni toping. A) -2 B) 2 C) -5 D) 5 2 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 289 B) 203 C) 200 D) 201 3 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 3 B) 0 C) 1 D) 2 4 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 5,75 B) 6 C) 13 D) 9,25 5 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 110° B) 120° C) 100° D) 130° 6 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 3 B) 5 C) 4 D) 6 7 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 3R B) √3R(2-√3) C) R(√3-√2) D) 1,5R 8 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 138° B) 132° C) 142° D) 135° 9 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 6√5 B) 8√3 C) 12√3 D) 9√5 10 / 40 tenglama intervalda nechta ildizga ega? A) 3 B) 2 C) 1 D) 4 11 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 32 C) 28 D) 30 12 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 4 D) 6 13 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 2 C) 4 D) 3 14 / 40 Hisoblang: A) cos10° B) 1 C) cos50° D) sin10° 15 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(4) C) 0,0(2) D) 0,(04) 16 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 17 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 8 C) 10 D) 4√7 18 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 10 C) 14 D) 12 19 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 43 D) 44 20 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 8(π+2) C) 16(π-2) D) 32 21 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 22 / 40 Hisoblang: A) 9/10 B) 20/21 C) 19/20 D) 10/11 23 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 1 C) 2 D) 3 24 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 8 D) 10 25 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 14 C) 35 D) 23 26 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 27 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 30° D) 40° 28 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 2 D) 4 29 / 40 bo‘lsa, A) 2 B) 3/2 C) 2/3 D) 1 30 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 10 D) 8 31 / 40 Hisoblang: A) 0 B) -1/2 C) -√3/2 D) 1/32 32 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 42 D) 48 33 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 3√2 D) 2√3 34 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 11 C) berilganlar yetarli emas D) 22 35 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 7 C) 5 D) 6 36 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 11 C) 9 D) 10 37 / 40 Tenglamani yeching: A) -6 B) 5 C) -6; 5 D) 6; -5 38 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 7 D) 5 39 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) -2 C) 5 D) 8 40 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) 5 C) -3 D) -6 O'rtacha ball 30% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika attestatsiya