Matematika attestatsiya №6 Yanvar 30, 2022Yanvar 30, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №6 ga 1 fikr bildirilgan 0% 0 ovozlar, 0 o'rtacha 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b B) b,d C) )a,b,d D) a,b 2 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 1 C) 4 D) 3 3 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 5 yoki –15 C) 6 D) 3 yoki –8 4 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) Ø C) π/4+πk, k∈Z D) 0 5 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 43 C) 42 D) 45 6 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 142° B) 135° C) 138° D) 132° 7 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 192π B) 144π C) 72π D) 96π 8 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 9 B) 4 C) 16 D) 25 9 / 40 Hisoblang: A) 4 B) 7 C) 9 D) 27 10 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 6√7 C) 10 D) 8 11 / 40 bo‘lsa, ning qiymatini toping. A) 0,5 B) 1 C) 0,7 D) 2 12 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) 3 D) -2 13 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 15 B) 9 C) 7 D) 12 14 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) 1 C) bd/c D) bc/d 15 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 13 C) 15 D) 12 16 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 1 C) 4 D) 2 17 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 4√3 D) 2√3 18 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 1 B) 5 C) 9 D) 0 19 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√3 C) 4√2 D) 3√2 20 / 40 Hisoblang: A) sin10° B) cos10° C) cos50° D) 1 21 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,0(4) D) 0,(04) 22 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 5 D) 6; -5 23 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 110 C) 115 D) 112 24 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 1 C) 3 D) 4 25 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 7 D) 6 26 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 14 D) 12 27 / 40 Hisoblang: A) 19/20 B) 9/10 C) 20/21 D) 10/11 28 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 5 C) 6 D) 11 29 / 40 Soddalashtiring: A) 2 B) 1 C) 3 D) Aniqlab bo`lmaydi 30 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) -6 C) -3 D) 5 31 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 5 C) 11 D) 7 32 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 6 C) 10 D) 12 33 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 34 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BC > AD C) BD = BC D) AB = BC 35 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (7; 2), (28; -1) D) (2; 3) 36 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 30° C) 50° D) 40° 37 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 11 C) berilganlar yetarli emas D) 22 38 / 40 √3 A) 21/10 B) 7/3 C) 3/2 D) 5/5 39 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 2 B) 8 C) 6 D) 4 40 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 4 C) 1 D) 3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya
