Matematika attestatsiya №6 Yanvar 30, 2022Yanvar 30, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №6 ga 1 fikr bildirilgan 0% 0 ovozlar, 0 o'rtacha 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №6 1 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 9 D) 11 2 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 10 C) 5 D) 11 3 / 40 Soddalashtiring. A) (a-1)/(1-b) B) (a+1)/(-a-3) C) (b+2)/(1-b) D) (a-1)/(a-3) 4 / 40 ni hisoblang. A) e+1 B) (e+1)/2 C) (e-1)/2 D) e-1 5 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bc/d C) bd/c D) cd/b 6 / 40 sonlarini taqqolsang. A) c B) a C) c D) b 7 / 40 √3 A) 5/5 B) 7/3 C) 3/2 D) 21/10 8 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 4√3 C) 2√3 D) 3√2 9 / 40 Tenglamani yeching: A) 5*4 B) 5/9 C) 6/5 D) 9/5 10 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) berilganlar yetarli emas C) 22 D) 11 11 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 5 C) 3 D) -2 12 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 10 B) 12 C) 13 D) 11 13 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 10 C) 20 D) 15 14 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 25 B) 50 C) 32 D) 41 15 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 96 C) 100 D) 105 16 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 126 B) 96 C) 114 D) 108 17 / 40 Hisoblang: A) cos10° B) 1 C) sin10° D) cos50° 18 / 40 Hisoblang: A) 0 B) 1/32 C) -√3/2 D) -1/2 19 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 6 C) 4√2 D) 4√3 20 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 3 C) 2 D) 1 21 / 40 Hisoblang: A) 10/11 B) 19/20 C) 20/21 D) 9/10 22 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,7 m yoki 70 cm B) 0,9 m yoki 90 cm C) 0,6 m yoki 60 cm D) 0,5 m yoki 50 cm 23 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 10 C) 20 D) 14 24 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 110 C) 112 D) 115 25 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 24 C) 23 D) 35 26 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 24 C) 30 D) 28 27 / 40 bo‘lsa, A) 2/3 B) 3/2 C) 2 D) 1 28 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -4 C) -3 D) 5 29 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 40° C) 50° D) 20° 30 / 40 Integralni hisoblang: A) 2 B) 4 C) 3 D) 1 31 / 40 tengsizlikni yeching. A) x∈(-∞;5)∪(-3;1) B) x∈(-3;1) C) x∈(-5;1) D) x∈(-∞;5) 32 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 6 D) 4 yoki –12 33 / 40 7/3 kasrning o‘nli kasr yoyilmasida verguldan keyingi 100- raqamni toping. A) 2 B) 5 C) 4 D) 1 34 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 16(π-2) C) 64 D) 32 35 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 8 C) 10 D) 6√7 36 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 42 D) 44 37 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 10 C) 12 D) 8 38 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (9; 0), (28; -1) 39 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,0(2) C) 0,(04) D) 0,04 40 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 42 D) 32 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya
