Uy » Online olimpiada » Matematika olimpiada » 10-sinf Matematika olimpiada №2 Matematika olimpiadaTuman 2019-2020 o'quv yili 10-sinf Matematika olimpiada №2 InfoMaster Avgust 19, 2024 10 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 1 0 12345678910111213141516171819202122232425 Vaqtingiz tugadi! 10-sinf Matematika olimpiada №2 2019-yil tuman bosqichida tushgan savollar 1 / 25 1. tenglamalar sistemasining yechimlari bo‘lsin. ayirmani toping. A) -3 B) -5 C) -4 D) 4 2 / 25 2. tenglamaning ildizi qaysi oraliqda joylashgan? A) [2;4] B) [4;9] C) [0;2] D) [-2;0] 3 / 25 3. Korxona xom−ashyuo qimmatlashgani sababli maxsulot narxi 20% ga oshirildi, biroq mijojlar soni 20 % ga kamayib ketdi. Shunda korxona narxni qanchadir foizga kamaytirib mijozlari sonini 25% ga oshirishga erishdi. Shundan keyin korxona tushumi narx o`zgarmasdan oldingi tushumga qaraganda 8% ga oshgan bo`lsa, yangi narx necha foizga kamaytirilgan? A) 20 B) 4 C) 12 D) 10 4 / 25 4. bo'lsa kasrning qiymatini hisoblang. A) √11-1 B) 2-√11 C) √11-2 D) √11+1 5 / 25 5. Hisoblang: A) 1/8 B) 1/4 C) -1/4 D) -1/8 6 / 25 6. Agar f(x+1) =7+3x funksiya uchun f (a)=2 tenglik o`rinli bo`lsa, a ning qiymatini toping. A) 10 B) -2/3 C) 8 D) 12 7 / 25 7. Tenglamaning ildizini nimchoragi nechaga teng ? A) 0,125 B) 20/69 C) 0,5 D) 0,25 8 / 25 8. 7(kx−2)=7k+2(x−8) tenglama k ning qanday qiymatlarida ildizga ega bo`lmaydi? A) k=2/7 B) (−∞; 2/7) C) ∅ D) (2/7; ∞) 9 / 25 9. Ko`paytmani hisoblang. cos12°cos24°cos36°cos48°cos60°cos72°cos84° A) 1/64 B) 1/128 C) 1/16 D) 1/32 10 / 25 10. Berilgan funksiyaga teskari funksiyani aniqlang. f(x)=x2f2(x)+f(x) A) III B) I C) II D) IV 11 / 25 11. Uchburchakning tomonlari 7 va 11 ga, uchinchi tomonining medianasi √21 ga teng. Uchburchakning uchunchi tomonini toping. A) 14 B) 16 C) 15 D) 12 12 / 25 12. Tengsizlikni yeching: A) (2/3;2) B) (5/3;2) C) (4/3;3) D) (1/2;∞) 13 / 25 13. Funksiyaning aniqlanish sohasini toping. A) (3/4;4) B) (3/4;7) C) [3/4;7] D) (-∞;3/4)∪(4; 7] 14 / 25 14. trigonometrik tenglamani yeching. A) π/12+πk/2; k∈Z B) π/12+πk; k∈Z C) π/6+πk; k∈Z D) π/12+2πk; k∈Z 15 / 25 15. Beshta a1, a2, a3, a4, a5 tub sonlar ayirmasi 6 ga teng bo`lgan arifmetik progressiyani tashkil qiladi. 2a2+a3 ni toping. A) 31 B) 39 C) 43 D) 40 16 / 25 16. Uchburchakning ikki tomoni 12 va 13 sm ga, ular orasidagi burchak kosinusi 5/13 ga teng bo`lsa, uning yuzini toping. A) 60 B) 70 C) 72 D) 71 17 / 25 17. tengsizlik yechimi bo`la oladigan tub sonlar nechta? A) 3 B) 4 C) 5 D) 2 18 / 25 18. Agar f(g(x))=x²-6x+6 va f(x)=x−3 funksiyalar berilgan bo`lsa, g(x) funksiya ko`rinishini aniqlang. A) x²+12x+3 B) (x-3)² C) (x+3)² D) x²-12-3 19 / 25 19. Ta`lim muassasida barcha o`quvchilar kamida bitta ingliz yoki nemis tilida so`zlashа oladilar. Ayrimlari ikkala tilni ham biladilar. O`quvchilarning 85%i ingliz tilini, 75%i nemis tilini biladilar. Ikkala tilni ham biladigan o`quvchilar barcha o`quvchilarning necha % ini tashkil etadi. A) 65% B) 50% C) 70% D) 60% 20 / 25 20. ifodani soddalshtiring A) cosα B) 2cosα C) 1 D) 2sinα 21 / 25 21. Agar x²(a²+b²+9)+2(a+b+3)x+3=0 tenglama haqiqiy yechimga ega bo`lsa, a+b ni toping. A) 4 B) 3 C) 6 D) 2 22 / 25 22. 2x²-2ax+1=0 kvadrat tenglama ildizlari uchun tengliko`rinlibo`lsa, a ni toping. A) -1 B) -3 C) 1 D) 7 23 / 25 23. [2x-1]=x tenglamani butun yechimlar sonini toping. Bu yerda [a]− a sonining butun qismi. A) 2 ta B) 4 ta C) 3 ta D) 1 ta 24 / 25 24. f(x)=x²-4x va f(x)=-2x²+8x-p funksiyalar umumiy uchga ega bo`lsa, p ning qiymatini toping. A) 24 B) 12 C) 18 D) 6 25 / 25 25. Uchburchakning ikkita burchagi mos ravishda 38o va 52oga teng. Uchinchi burchagi uchidan tushirilgan bissektrisa va mediana orasidagi burchakni toping. A) 10° B) 17° C) 14° D) 7° 0% Testni qayta ishga tushiring Tomonidan Wordpress Quiz plugin Author: InfoMaster Foydali bo'lsa mamnunmiz