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Matematika attestatsiya №12

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Aprel 8, 2022

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OMAD YOR BO'LSIN!

Matematika fanidan attestatsiya savollari №12

28.03.2022 da Toshkentda tushgan savollar

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1 / 40

Kubning diagonalidan ushbu diagonal bilan kesishmaydigan qirrasigacha bo‘lgan masofa 4 ga teng. Kubning hajmini toping.

A) 144√2

B) 128√2

C) 240√2

D) 180√2

2 / 40

Agar arifmetik progressiyada bo‘lsa, dastlabki 10 ta hadining yig‘indisini toping.

A) 150 yoki 245

B) 153 yoki 317

C) 160 yoki 317

D) 155 yoki 245

3 / 40

Agar x=2t+5, y=3t-1 va f(x)=y(x) bog’lanish mavjud bo’lsa, f(5) ning qiymatini toping

A) -2

B) 1

C) -1

D) 2

4 / 40

To‘g‘ri to‘rtburchakning simmetriya markazidan bir uchigacha bo‘lgan masofa 5 sm ga, tomonlar ayirmasi 2 sm ga teng bo‘lsa, uning perimetrini toping.

A) 28

B) 32

C) 48

D) 30

5 / 40

|x²-2x|≤x yengsizlikni yeching.

A) (-2;0)∪[1;3]

B) {0}∪[1;3)

C) {0}∪(1;3]

D) {0}∪[1;3]

6 / 40

y = x²+1-|sinx| funksiya grafigi OX o'qidan pastda yotadimi?

A) Yotmaydi

B) Yotadi

7 / 40

Hisoblang.

A) 2

B) 1

C) 4

D) 3

8 / 40

1, 2, 3, 4 raqamlaridan foydalanib 400 dan kichik kechta uc xonali son yasash mumkin?

A) 51

B) 48

C) 47

D) 49

9 / 40

To'g'ri burchakli uchburchakning gipotenuzasiga o'tkazilgan bissiktriksasi uni 20 va 30 ga teng kesmalarga ajratadi. To'g'ri burchakli uchburchak yuzini toping.

A) 7500/13

B) 7551/15

C) 15

D) 6700/13

10 / 40

Noaniq integralni toping. ∫(sin²x+cos²x)dx

A) x/2+c

B) 4x+c

C) x+c

D) 2x+c

11 / 40

Chizmada nechta uchburchak tasvirlangan?

A) 54

B) 50

C) 52

D) 48

12 / 40

Hisoblang. cos²10° + cos²30° + cos²80°

A) 0

B) 3/7

C) 7/4

D) 7/3

13 / 40

Agar bo'lsa f(x)=?

A) x²-1

B) x²+2

C) x²-2

D) 2x²-1

14 / 40

y=xlnx funksiyani hosilasini toping.

A) lnx/2+1

B) lnx+1

C) 1

D) 2lnx-1

15 / 40

Tenglamani yeching:

A) 2

B) 6

C) 2,5

D) 5,5

16 / 40

To'g'ri burchakli uchburchakka ichki va tashqi chizilgan aylanalar raduslari 6 va 15 ga teng bo'lsa, katetlar yig'indini toping.

A) 42

B) 28

C) 35

D) 48

17 / 40

Tengsizlikni yeching.

A) x∈[0;1000]

B) x∈(1;1000]

C) x∈(0;1000)

D) x∈(10;1000)

18 / 40

(tgx+ctgx)⁴ yoyilmaning ozod hadini toping.

A) 5

B) 4

C) 6

D) 3

19 / 40

Hisoblang.

A) -2 yoki -1

B) 0

C) -2 yoki 0

D) -2 yoki 2

20 / 40

f(x)+(x-2)·g(x)=x²+5, f(3)=10 bo'lsa, g^-1=(4) ni toping. Bunda g^-1(x) g(x) ga teskari funksiya.

A) 4

B) 6

C) 3

D) 5

21 / 40

Hisoblang.

A) 1

B) 6

C) 3

D) 2

22 / 40

Arimetik progerssiyada s₁₂=354, P=a₁+a₂+...+a₁₁, Q=a₂+a₄+...+a₁₂ va P/Q=32/27 ga teng bo'lsa, d ni toping.

A) -5

B) -4

C) -6

D) -3

23 / 40

Tenglamani yeching.

A) 0

B) 2

C) 1

D) 5

24 / 40

Hisoblang.

A) 2

B) 4

C) 1

D) 0

25 / 40

f(x) = x²-3x-2 bo'lsa. f(a+b+c)-f(abc)=? Bunda a, b, c - kvadrat funksiya koeffitsiyentlari.

A) 40

B) 38

C) 42

D) 36

26 / 40

(2; 3; -5) nuqtaning OX o'qiga nisbatan simmetrik nuqtasini toping.

A) (-2; 3; 5)

B) (2; 3; -5)

C) (2; -3; 5)

D) (2; -3; -5)

27 / 40

Ayirmasi d ga teng bo'lgan arifmetik progrssiya uchun ni toping.

A) 1/2

B) 1

C) 2

D) 2/3

28 / 40

Tengsizlikni yeching: 3 · 9^x–10 · 21^x+ 7 · 49 ^x ≤ 0

A) [-1;0)

B) (-1;3]

C) [-1;1]

D) [-1;0]

29 / 40

Agar bo'lsa, ni toping.

A) 3

B) 2,5

C) 0

D) 5,2

30 / 40

5^-x≤ 0,04 x ning eng kichik butun qiymatini toping.

A) 0

B) -1

C) 3

D) 2

31 / 40

Tenglamani yeching.

A) 4

B) 3

C) 2

D) 1

32 / 40

Hisoblang.

A) 9/11

B) 9/13

C) 7/11

D) 0

33 / 40

Tenglama ildizlari yig'indisini toping.

A) -1

B) 2

C) 0

D) 4

34 / 40

(tgx-2ctgx)⁴ yoyilmaning ozod hadini toping.

A) 58

B) 25

C) 24

D) 6

35 / 40

Tamonlarini ayirmasi 14 bo'lgan parallelogramning o'rmas burchagidan katta diagonaliga tushgan balandlik uni 12 va 30 ga teng kesmalarga ajratadi. Tamonlar uzunligini toping.

A) 34 va 20

B) 30 va 24

C) 32 va 22

D) 36 va 18

36 / 40

Hisoblang.

A) 3

B) 4

C) 5

D) 6

37 / 40

Hisoblang.

A) 133

B) 135

C) 131

D) 121

38 / 40

Hisoblang.

A) 24+3b

B) 26-3b

C) 14-2b

D) 24-3b

39 / 40

Hisoblang.

A) 98

B) 96

C) 32

D) 94

40 / 40

Agar va ular orasidagi burchak 120° bo'lsa, ni toping.

A) √7

B) 4√5

C) 3√7

D) 2√7

Baholash mezoni

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”;

- 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”;

- 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”;

- 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”;

- 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin”

- 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”;

- 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin”