Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 56 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ko’paytmani hisoblang. A) 480000 B) 0 C) 10000 D) 86420000 2 / 40 Agar bo'lsa ifodaning qiymatini toping. A) 7 B) 13 C) 0 D) 9 3 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 30 B) 12 C) 18 D) 24 4 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) x=a B) x=-a C) y=-a D) y=1-a 5 / 40 Tengsizlikni yeching. A) [-2;1]∪{-3} B) [-3;-2] C) [-3;2]∪{1} D) (-∞;-2] 6 / 40 Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) √6+√14 B) 2√14+√6 C) 16 D) 18 7 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 5 C) 3 D) 6 8 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 7 B) 1 C) 12 D) 5 9 / 40 Hisoblang: -121+(-135)-(-1)28 A) 0 B) -3 C) -1 D) -2 10 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 40 B) 20 C) 25 D) 35 11 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 10 B) 25 C) 30 D) 0 12 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 6 B) 8 C) 10 D) 9 13 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 48 C) 64 D) 32 14 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 5 C) 8 D) 3 15 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 44 C) 45 D) 43 16 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 20 C) 12 D) 14 17 / 40 bo‘lsa, A) 3/2 B) 2/3 C) 2 D) 1 18 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3ctg40° tg70° C) √3tg50° tg70° D) 2√3tg50° tg70° 19 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (2; 3) C) (9; 0), (2; 7) D) (7; 2), (28; -1) 20 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 8 D) 10 21 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 4 C) 11 D) 5 22 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 23 C) 24 D) 14 23 / 40 Hisoblang: A) 10/11 B) 9/10 C) 19/20 D) 20/21 24 / 40 Hisoblang: A) 1 B) cos50° C) cos10° D) sin10° 25 / 40 √3 A) 21/10 B) 5/5 C) 3/2 D) 7/3 26 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 27 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 4 C) 2 D) 3 28 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 29 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 64 C) 16(π-2) D) 32 30 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,0(4) C) 0,(04) D) 0,04 31 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 50° C) 30° D) 40° 32 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 11 D) 10 33 / 40 Hisoblang: A) 1/32 B) -1/2 C) 0 D) -√3/2 34 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 12 D) 10 35 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 3 yoki –8 C) 6 D) 5 yoki –15 36 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) berilganlar yetarli emas C) 11 D) 121 37 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 96 C) 100 D) 105 38 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) 5 C) -6 D) -3 39 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 1 C) 4 D) 3 40 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 6 C) 5 D) 8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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