Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 37 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ko’paytmani hisoblang. A) 86420000 B) 10000 C) 0 D) 480000 2 / 40 tengsizlikni yeching. A) 4 B) 3 C) 1 D) 2 3 / 40 Agar bo‘lsa, x ni toping. A) -2 B) 2 C) 5 D) -5 4 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 67/15 B) 31/85 C) 68/15 D) 11/5 5 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 2 B) 1 C) 4 D) 3 6 / 40 funksiyaning qiymatlar to'plamini toping. A) (-2√2;√2) B) [-√2;0)∪(0;√2] C) [-√2;-1)∪(-1;1)∪(1;√2] D) [-√2;√2] 7 / 40 Hisoblang? A) 0,25 B) 4 C) 0,5 D) 2 8 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 4 B) 3 C) 2 D) 1 9 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 98 B) 100 C) 99 D) 101 10 / 40 tenglama intervalda nechta ildizga ega? A) 1 B) 4 C) 2 D) 3 11 / 40 Tenglamaning natural ildizining butun bo‘luvchilari nechta? A) 2 B) 4 C) 5 D) 6 12 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 7 B) 12 C) 9 D) 15 13 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) berilganlar yetarli emas D) 121 14 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 10 D) 8 15 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 5 C) 8 D) -2 16 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 4 D) 6 17 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 96 C) 105 D) 25 18 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 4 C) 2 D) 3 19 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 10 D) 20 20 / 40 Hisoblang: A) 20/21 B) 19/20 C) 9/10 D) 10/11 21 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√2 C) 4√3 D) 6 22 / 40 √3 A) 3/2 B) 7/3 C) 5/5 D) 21/10 23 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 9 C) 11 D) 12 24 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 5 yoki –15 D) 3 yoki –8 25 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 2 D) 3 26 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 16(π-2) C) 8(π+2) D) 32 27 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 6 C) 8 D) 5 28 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 13 C) 12 D) 15 29 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 2√3 D) 4√3 30 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 44 D) 42 31 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,(04) C) 0,0(4) D) 0,04 32 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 30° D) 40° 33 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 6√7 C) 10 D) 8 34 / 40 Hisoblang: A) -√3/2 B) 0 C) 1/32 D) -1/2 35 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) 1 C) cd/b D) bc/d 36 / 40 Hisoblang: A) cos50° B) sin10° C) 1 D) cos10° 37 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) π/4+πk, k∈Z B) Ø C) 0 D) -π/4+πk, k∈Z 38 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 30 D) 24 39 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) AB = BC C) BD = BC D) BC > AD 40 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 35 D) 24 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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