Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 31 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 12 B) 30 C) 24 D) 18 2 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 3 B) 1 C) 4 D) 2 3 / 40 bo‘lsa, ning qiymatini toping. A) 2 B) 0,7 C) 0,5 D) 1 4 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13sinx+sin13x + C B) 13sinx-sin13x + C C) 13cosx-cos13x + C D) -13cosx- cos13 x +C 5 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 3 B) 1 C) 7 D) 9 6 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,5 m yoki 50 cm B) 0,6 m yoki 60 cm C) 0,9 m yoki 90 cm D) 0,7 m yoki 70 cm 7 / 40 Soddalashtiring: A) 1 B) 3 C) 2 D) Aniqlab bo`lmaydi 8 / 40 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 200 km B) 20 km C) 2 km D) 0,2km 9 / 40 Hisoblang? A) 0,5 B) 4 C) 2 D) 0,25 10 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 50 B) 32 C) 25 D) 41 11 / 40 a,b,c -1 dan katta musbat sonlar uchun a³=b² va a4=c5 bo'lsa, logbc ni toping. A) 1/2 B) 5/6 C) 8/15 D) 1/3 12 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/4 B) √3/8 C) 1/8 D) √2/8 13 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 115 C) 112 D) 116 14 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 5 C) 7 D) 11 15 / 40 sonlarini taqqolsang. A) b B) c C) a D) c 16 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 20 C) 8 D) 10 17 / 40 bo‘lsa, A) 2/3 B) 1 C) 2 D) 3/2 18 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) cd/b C) bc/d D) bd/c 19 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 10 D) 9 20 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -4 C) 5 D) -6 21 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 4 C) 5 D) 6 22 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 30 C) 24 D) 32 23 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) -2 D) 8 24 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 44 D) 43 25 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 4 C) 1 D) 3 26 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 30° D) 20° 27 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 15 D) 14 28 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 12 C) 10 D) 8 29 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,0(4) D) 0,(04) 30 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) DC < AD C) BC > AD D) BD = BC 31 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 4√3 C) 2√2 D) 3√2 32 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 3 D) 2 33 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 2 D) 1 34 / 40 Hisoblang: A) 19/20 B) 9/10 C) 20/21 D) 10/11 35 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 5 D) 6 36 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 32 C) 8(π+2) D) 64 37 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 5 D) 6; -5 38 / 40 Hisoblang: A) cos50° B) cos10° C) sin10° D) 1 39 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (2; 3) C) (9; 0), (28; -1) D) (9; 0), (2; 7) 40 / 40 Hisoblang: A) 0 B) -1/2 C) -√3/2 D) 1/32 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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