Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 funksiyaning eng kichik musbat davrini toping. A) 24 B) 12 C) 26 D) 18 2 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 16 B) 25 C) 9 D) 4 3 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 58 B) 60 C) 61 D) 59 4 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln5 B) ln4 C) ln2 D) ln3 5 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 6 B) 8 C) 35/6 D) 25/3 6 / 40 Hisoblang: A) 4 B) 9 C) 27 D) 7 7 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 16 C) 48/5 D) 64/5 8 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 8 B) 9 C) 7 D) 6 9 / 40 x ni toping ? A) 4 B) 6 C) 3 D) 5 10 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) R(√3-√2) B) 3R C) 1,5R D) √3R(2-√3) 11 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 72π B) 144π C) 192π D) 96π 12 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 10 B) 8 C) 9 D) 6 13 / 40 Hisoblang: A) 9/10 B) 20/21 C) 10/11 D) 19/20 14 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) BD = BC D) DC < AD 15 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 50° C) 40° D) 20° 16 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 2 C) 3 D) 1 17 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3tg50° tg70° C) √3ctg40° tg70° D) 4 √3tg50° tg70° 18 / 40 sonlarini taqqolsang. A) a B) c C) b D) c 19 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 24 C) 14 D) 35 20 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) 121 D) berilganlar yetarli emas 21 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 3 C) 4 D) 1 22 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 2 C) 3 D) 1 23 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 105 C) 96 D) 25 24 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 32 C) 42 D) 48 25 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) Ø 26 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 32 C) 16(π-2) D) 8(π+2) 27 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 45 C) 44 D) 43 28 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 5 yoki –15 C) 3 yoki –8 D) 6 29 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 10 C) 12 D) 8 30 / 40 Tenglamani yeching: A) -6; 5 B) -6 C) 5 D) 6; -5 31 / 40 Hisoblang: A) 1/32 B) -1/2 C) 0 D) -√3/2 32 / 40 √3 A) 7/3 B) 3/2 C) 21/10 D) 5/5 33 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,(04) C) 0,0(4) D) 0,0(2) 34 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 115 C) 116 D) 110 35 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 5 C) 7 D) 11 36 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 10 C) 12 D) 11 37 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 6√7 D) 10 38 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 14 C) 20 D) 12 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) 1 C) bd/c D) bc/d 40 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 3√2 C) 6 D) 4√3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
