Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 67 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 2 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 203 B) 289 C) 201 D) 200 2 / 40 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 28 B) 24 C) 32 D) 21 3 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16sin3x*sin5x B) -16cos3x*sin5x C) 16sin3x*cos5x D) 16cos3x*cos5x 4 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 6 B) 35/6 C) 8 D) 25/3 5 / 40 f(x-1)+f(x+2)=2(x²+7) ekani ma‟lum bo'lsa, f(x) ko'phadni toping. A) f(x)+2x²-1 B) f(x)=x²-x+5 C) f(x)=x²+3x+7 D) f(x)=x²-4 6 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln2 B) ln5 C) ln4 D) ln3 7 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 12 B) 5 C) 1 D) 7 8 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 101 B) 99 C) 100 D) 98 9 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) b B) b,d C) a,b D) )a,b,d 10 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 1 B) 9 C) 0 D) 5 11 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 2 B) 1 C) 3 D) 4 12 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 12 B) 3 C) 9 D) 6 13 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 10 C) 5 D) 11 14 / 40 Hisoblang: A) 1/32 B) -1/2 C) -√3/2 D) 0 15 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (7; 2), (28; -1) C) (9; 0), (2; 7) D) (9; 0), (28; -1) 16 / 40 Hisoblang: A) 10/11 B) 9/10 C) 19/20 D) 20/21 17 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 64 C) 48 D) 32 18 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 8 C) 6 D) 12 19 / 40 sonlarini taqqolsang. A) c B) a C) b D) c 20 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 11 C) 12 D) 9 21 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 25 C) 100 D) 105 22 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3ctg40° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 23 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,(04) C) 0,0(4) D) 0,0(2) 24 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 14 D) 35 25 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 11 D) 4 26 / 40 bo‘lsa, A) 3/2 B) 2 C) 2/3 D) 1 27 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) berilganlar yetarli emas D) 22 28 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 10 C) 4√7 D) 8 29 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) AB = BC D) DC < AD 30 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 3√2 D) 2√2 31 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) π/4+πk, k∈Z C) 0 D) Ø 32 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 10 D) 20 33 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 1 C) 2 D) 4 34 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 14 C) 12 D) 10 35 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 32 C) 16(π-2) D) 8(π+2) 36 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 37 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 2 D) 3 38 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 45 C) 43 D) 42 39 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) -4 C) -6 D) 5 40 / 40 Tenglamani yeching: A) 6; -5 B) -6 C) 5 D) -6; 5 O'rtacha ball 34% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
