Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Jamshid bir kunda 70,5 kgdan paxta tersa, 8460 kg paxtani necha kunda terib bo’ladi ? A) 130 kun B) 100 kun C) 120 kun D) 140 kun 2 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 4 B) 2 C) 3 D) 2,5 3 / 40 Agar ni hisoblang. A) 0 B) Cheksiz C) 9 D) 8 4 / 40 Tenglama ildizlari ayirmasining modulini toping. A) 5 B) √5 C) √5+5 D) 2√5 5 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;-1)∪(-1;1)∪(1;√2] B) [-√2;√2] C) (-2√2;√2) D) [-√2;0)∪(0;√2] 6 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) [-1; ∞) B) (-2; ∞) C) (-1; ∞) D) (0; ∞) 7 / 40 n ning qanday qiymatida tenglik to`g`ri bo’ladi? (73)=715 A) 1 B) 12 C) 7 D) 5 8 / 40 Hisoblang: A) 4 B) 3 C) 2 D) 1 9 / 40 Soddalshtiring. A) 6 B) 1 C) -1 D) 2 10 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 138° B) 135° C) 132° D) 142° 11 / 40 Agar x =17 bo‘lsa, quyidagi ifodaning qiymatini toping. A) √17 B) -4 C) 4 D) -√17 12 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 192π B) 144π C) 96π D) 72π 13 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 32 D) 42 14 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 10 C) 20 D) 12 15 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 8 C) 5 D) 3 16 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 16(π-2) C) 32 D) 64 17 / 40 √3 A) 21/10 B) 5/5 C) 3/2 D) 7/3 18 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√2 C) 4√3 D) 2√3 19 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 20 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 11 C) 4 D) 6 21 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 50° D) 30° 22 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 4 C) 2 D) 1 23 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 10 D) 6√7 24 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 100 C) 105 D) 96 25 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 9 C) 10 D) 12 26 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 4 yoki –12 D) 6 27 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -3 D) -4 28 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 6 B) 8 C) 10 D) 12 29 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 44 C) 45 D) 42 30 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,(04) D) 0,0(4) 31 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 32 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 33 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) DC < AD C) AB = BC D) BD = BC 34 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 116 D) 115 35 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 13 C) 12 D) 14 36 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 1/32 D) 0 37 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 24 C) 28 D) 32 38 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) bc/d D) 1 39 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 11 C) 121 D) 22 40 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 8 C) 10 D) 15 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
