Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 64 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Qavariq oltiburchakning 3 ta uchidan kesib olsak qanday shakl hosil bo’ladi ? A) 9 B) 6 C) 14 D) 12 2 / 40 va bo'lsa x-y=? A) 7 B) 8 C) 9 D) 5 3 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) b>a>c B) a>b>c C) a>c>b D) c>a>b 4 / 40 y=f(x) funksiya uchun tenglik o'rinli bo'lsa, f(π/4)=? A) 4 B) 1/3 C) 1/4 D) 1/5 5 / 40 Hisoblang: A) 7 B) 9 C) 4 D) 27 6 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 25/3 B) 6 C) 8 D) 35/6 7 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 40° B) 30° C) 20° D) 10° 8 / 40 Soddalshtiring. A) 6 B) 2 C) 1 D) -1 9 / 40 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 13 B) 11 C) 12 D) 14 10 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 8 B) 9 C) 10 D) 6 11 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 100 B) 120 C) 90 D) 80 12 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 3 B) 4 C) 2 D) 1 13 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 6 D) 4 14 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) √3ctg40° tg70° C) 2√3tg50° tg70° D) 4 √3tg50° tg70° 15 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 24 C) 35 D) 23 16 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 3√2 C) 4√2 D) 6 17 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) Ø C) -π/4+πk, k∈Z D) π/4+πk, k∈Z 18 / 40 Hisoblang: A) 1 B) cos10° C) cos50° D) sin10° 19 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 8(π+2) C) 32 D) 16(π-2) 20 / 40 √3 A) 21/10 B) 7/3 C) 5/5 D) 3/2 21 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (7; 2), (28; -1) D) (2; 3) 22 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 3 D) 1 23 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 5 yoki –15 C) 4 yoki –12 D) 3 yoki –8 24 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,(04) C) 0,0(4) D) 0,04 25 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 43 C) 44 D) 42 26 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 30° D) 20° 27 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 3 C) -2 D) 8 28 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 14 C) 12 D) 15 29 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 20 C) 15 D) 8 30 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 32 C) 42 D) 48 31 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 4 D) 2 32 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 9 C) 10 D) 11 33 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 34 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) BD = BC C) DC < AD D) AB = BC 35 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) 1 D) bd/c 36 / 40 Hisoblang: A) 10/11 B) 20/21 C) 19/20 D) 9/10 37 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 6 C) 7 D) 8 38 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) 6; -5 D) -6 39 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 11 D) 22 40 / 40 bo‘lsa, A) 2/3 B) 2 C) 1 D) 3/2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16