Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 37 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 2 B) 3 C) 4 D) 1 2 / 40 Teng yonli trapetsiya asosidagi burchakning sinusi 0,6 ga, asoslarining ayirmasi 4 ga teng bo‘lsa, trapetsiyaning yon tomonini toping. A) 2 B) 3 C) 4 D) 2,5 3 / 40 Yig’indi quydagilardan qaysi biriga teng? A) 450,608 B) 40560,8 C) 4506,08 D) 45,0608 4 / 40 Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) √6+√14 B) 18 C) 2√14+√6 D) 16 5 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 1 B) 0 C) 2 D) 3 6 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 9 B) 3 C) 1 D) 7 7 / 40 Soddalashtiring: A) Aniqlab bo`lmaydi B) 2 C) 3 D) 1 8 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 5 C) 6 D) 3 9 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 7 B) 6 C) 8 D) 9 10 / 40 Burchagi 120° ga teng bo‘lgan doiraviy sektorga ichki doira chizilgan. Berilgan doiraning radiusi R ga teng bo‘lsa, yangi doiraning radiusi topilsin. A) 3R B) R(√3-√2) C) 1,5R D) √3R(2-√3) 11 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 72π B) 192π C) 96π D) 144π 12 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 50 B) 32 C) 25 D) 41 13 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√3 C) 2√2 D) 4√3 14 / 40 √3 A) 3/2 B) 5/5 C) 7/3 D) 21/10 15 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 16 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 17 / 40 Hisoblang: A) sin10° B) cos10° C) cos50° D) 1 18 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 100 C) 105 D) 96 19 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 7 C) 10 D) 11 20 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 3 D) 8 21 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 4 C) 11 D) 5 22 / 40 bo‘lsa, A) 2/3 B) 2 C) 3/2 D) 1 23 / 40 Tenglamani yeching: A) 6; -5 B) -6 C) -6; 5 D) 5 24 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 14 C) 12 D) 15 25 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,04 C) 0,0(2) D) 0,(04) 26 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 2 D) 1 27 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (2; 7) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 28 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 28 C) 30 D) 32 29 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 12 C) 10 D) 6 30 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 110 D) 116 31 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) berilganlar yetarli emas C) 121 D) 11 32 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 40° C) 20° D) 50° 33 / 40 Hisoblang: A) 19/20 B) 9/10 C) 10/11 D) 20/21 34 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 35 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 32 D) 48 36 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3tg50° tg70° C) 4 √3tg50° tg70° D) √3ctg40° tg70° 37 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 8 D) 6 38 / 40 Hisoblang: A) 1/32 B) -1/2 C) 0 D) -√3/2 39 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 1 C) 2 D) 4 40 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 6√7 B) 8 C) 10 D) 4√7 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
