Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 36 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 y=4cos 2x+cos8x funksiyaning hosilasini toping A) 16sin3x*sin5x B) 16cos3x*cos5x C) 16sin3x*cos5x D) -16cos3x*sin5x 2 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 3 B) 2 C) 4 D) 1 3 / 40 Jamshid bir kunda 70,5 kgdan paxta tersa, 8460 kg paxtani necha kunda terib bo’ladi ? A) 140 kun B) 100 kun C) 120 kun D) 130 kun 4 / 40 Muntazam uchburchak ichidan olingan nuqtadan uchburchak tomonlarigacha bo'lgan masofalar mos holda c(2;3;1), b(1;2;1) va a(1;2;3) vektorlarning absolut qiymatlariga teng bo'lsa, uchburchakning balandligini toping. A) 16 B) √6+√14 C) 2√14+√6 D) 18 5 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 1 B) 2 C) 3 D) 4 6 / 40 Aniq integralni hisoblang: A) 3 B) 0,5 C) 0 D) 2 7 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 10 B) 12 C) 13 D) 11 8 / 40 Hisoblang: -121+(-135)-(-1)28 A) -1 B) -3 C) -2 D) 0 9 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 100 B) 99 C) 101 D) 98 10 / 40 Hisoblang: A) 8 B) 6 C) 4 D) 0 11 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 12 B) 6 C) 9 D) 3 12 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 4 B) 1 C) 2 D) 3 13 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -4 C) -3 D) 5 14 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 35 C) 24 D) 23 15 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 7 C) 5 D) 6 16 / 40 Hisoblang: A) 1 B) sin10° C) cos10° D) cos50° 17 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 50° C) 40° D) 20° 18 / 40 sonlarini taqqolsang. A) b B) c C) a D) c 19 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 10 C) 5 D) 7 20 / 40 Hisoblang: A) 20/21 B) 10/11 C) 9/10 D) 19/20 21 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) -π/4+πk, k∈Z D) Ø 22 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 14 D) 10 23 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) 1 D) bc/d 24 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 48 D) 32 25 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 12 C) 11 D) 10 26 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 96 C) 25 D) 100 27 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (2; 3) C) (9; 0), (2; 7) D) (9; 0), (28; -1) 28 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√3 C) 4√2 D) 3√2 29 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(4) C) 0,04 D) 0,0(2) 30 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 14 C) 13 D) 12 31 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 64 C) 16(π-2) D) 32 32 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 12 C) 6 D) 8 33 / 40 a+b+c=10, bo‘lsa, ni toping. A) 11 B) 5 C) 6 D) 4 34 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 2 D) 3 35 / 40 Tengsizlik nechta butun juft yechimga ega? A) 112 B) 110 C) 116 D) 115 36 / 40 bo‘lsa, A) 2/3 B) 3/2 C) 1 D) 2 37 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 2√2 C) 4√3 D) 3√2 38 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 4 D) 1 39 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 20 C) 15 D) 10 40 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 4√7 C) 6√7 D) 8 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
