Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 34 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 2 B) 4 C) 3 D) 5 2 / 40 ni qanoatlantiruvchi yechimlar nechta? A) 2 B) 0 C) 1 D) 3 3 / 40 bo‘lsa, x + y ni toping. A) 18 B) 16 C) 20 D) 17 4 / 40 Aniq integralni hisoblang: A) 0,5 B) 3 C) 0 D) 2 5 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 35/6 B) 25/3 C) 6 D) 8 6 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 2 B) 4 C) 3 D) 1 7 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 16 B) 48/5 C) 10 D) 64/5 8 / 40 Quyidagi rasmda konus va silindr zaytun moyi bilanto`ldirilmoqda . Ikkala shaklning balandliklari va taglik doiralarining radiuslari teng uzunlikda 2sm . Shunga ko`ra idishga jami necha ?m³ A) (32π)/3 B) (28π)/3 C) 11π D) (29π)/3 9 / 40 Hisoblang: A) 3 B) 4 C) 2 D) 1 10 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 9 B) 8 C) 6 D) 10 11 / 40 Agar bo‘lsa, m/n ni toping. A) (1+√5)/2 B) 3 C) 2 D) 4 12 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 100 B) 90 C) 120 D) 80 13 / 40 √3 A) 21/10 B) 7/3 C) 5/5 D) 3/2 14 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 3√2 C) 4√3 D) 6 15 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (9; 0), (28; -1) 16 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 28 C) 24 D) 32 17 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 5 C) 7 D) 10 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 10 C) 11 D) 12 19 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 42 C) 48 D) 64 20 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 14 C) 20 D) 10 21 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 50° C) 30° D) 40° 22 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 8 D) 3 23 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 3 D) 2 24 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 14 C) 13 D) 15 25 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) AB = BC D) DC < AD 26 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 27 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 3 C) 1 D) 2 28 / 40 Tenglamani yeching: A) 6; -5 B) 5 C) -6 D) -6; 5 29 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,(04) D) 0,0(4) 30 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 7 D) 6 31 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 115 D) 110 32 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 35 C) 14 D) 24 33 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 10 D) 8 34 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 3 D) 1 35 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 1 C) 4 D) 3 36 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 44 D) 45 37 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) berilganlar yetarli emas C) 11 D) 121 38 / 40 Hisoblang: A) 1 B) cos10° C) cos50° D) sin10° 39 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 4√3 C) 2√2 D) 3√2 40 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 4√7 D) 10 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
