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Matematika attestatsiya №5

InfoMaster

Yanvar 24, 2022

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

Agar $f(g(x))=x^2-5x+6$ va $g(x)=x-2$ bo'lsa f(4) ning qiymatini toping.

A) 4

B) 11

C) 35

D) 12

2 / 40

y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak?

A) n = 0, k < 0

B) n < 0, k = 0

C) n = 0, k > 0

D) n > 0, k = 0

3 / 40

To’g’ri turt burchakning bo’yining perimetriga nisbatini toping.

A) 1/2

B) 3/18

C) -452/18

D) 5/3

4 / 40

f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping.

A) 13sinx-sin13x + C

B) -13cosx- cos13 x +C

C) 13sinx+sin13x + C

D) 13cosx-cos13x + C

5 / 40

Ushbu sistemaga ko'ra (ac+bd)² ni toping.

A) 4

B) 3

C) 2

D) 1

6 / 40

Umumiy hadi x_n=3+5n-n² formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam?

A) 5,75

B) 9,25

C) 6

D) 13

7 / 40

Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi

Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak

A) 1-EKUB 2-EKUB 3-EKUK

B) 1-EKUB 2-EKUK 3-EKUB

C) 1-EKUB 2-EKUK 3-EKUK

D) 1-EKUB 2-EKUB 3-EKUB

8 / 40

Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor?

A) 10

B) 16

C) 48/5

D) 64/5

9 / 40

Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ?

A) 20 km

B) 200 km

C) 0,2km

D) 2 km

10 / 40

Tenglamalar sistemasidan foydalanib x + y + z ni toping:

A) 10

B) 6

C) 8

D) berilganlar yetarli emas

11 / 40

Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping.

A) √5

B) 2,4

C) 2,5

D) √6

12 / 40

Integralni hisoblang:

A) 2

B) 1

C) 4

D) 3

13 / 40

√3

A) 7/3

B) 3/2

C) 5/5

D) 21/10

14 / 40

To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping.

A) 42

B) 32

C) 64

D) 48

15 / 40

Hisoblang:

A) 9/10

B) 10/11

C) 19/20

D) 20/21

16 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 23

B) 24

C) 35

D) 14

17 / 40

Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng.

3¹⁹·2⁵
3¹⁶·2⁸
3¹³·2⁸
32⁹·2⁸

A) 2

B) 3

C) 1

D) 4

18 / 40

Sonlarining o‘rta geometrik qiymatini toping.

A) 2√2

B) 2√3

C) 3√2

D) 4√3

19 / 40

P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng?

A) -4

B) -3

C) -6

D) 5

20 / 40

Tenglamalar sistemani yeching:

A) (9; 0), (2; 7)

B) (9; 0), (28; -1)

C) (2; 3)

D) (7; 2), (28; -1)

21 / 40

tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping.

A) 5

B) -2

C) 8

D) 3

22 / 40

Ifodaning qiymatini toping.

A) 0,(04)

B) 0,04

C) 0,0(2)

D) 0,0(4)

23 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 6

B) 8

C) 5

D) 7

24 / 40

Hisoblang:

A) 1

B) cos10°

C) cos50°

D) sin10°

25 / 40

sonlarini taqqolsang.

A) a

B) c

C) b

D) c

26 / 40

x²-√11x+1=0 0 bo‘lsa,

A) 10

B) 12

C) 11

D) 9

27 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.

A) 8(π+2)

B) 64

C) 32

D) 16(π-2)

28 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 4

B) 2

C) 1

D) 3

29 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 112

B) 116

C) 115

D) 110

30 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 12

B) 10

C) 20

D) 14

31 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) 4 √3tg50° tg70°

B) 2√3tg50° tg70°

C) √3tg50° tg70°

D) √3ctg40° tg70°

32 / 40

bo‘lsa,

A) 3/2

B) 2

C) 2/3

D) 1

33 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 13

B) 15

C) 12

D) 14

34 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 12

B) 6

C) 10

D) 8

35 / 40

vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping.

A) 1

B) 3

C) 4

D) 2

36 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) DC < AD

B) BD = BC

C) BC > AD

D) AB = BC

37 / 40

Hisoblang: