Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 70 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 3 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 1 B) 3 C) 4 D) 2 2 / 40 Agar va bo'lsa f(4) ning qiymatini toping. A) 11 B) 4 C) 35 D) 12 3 / 40 Yig’indi quydagilardan qaysi biriga teng? A) 4506,08 B) 40560,8 C) 450,608 D) 45,0608 4 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 2 B) 1 C) 3 D) 0 5 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 7 B) 1 C) 3 D) 9 6 / 40 Hisoblang: A) 27 B) 4 C) 9 D) 7 7 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 10 B) 11 C) 12 D) 13 8 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 34 B) 32 C) 36 D) 40 9 / 40 Soddalshtiring. A) 6 B) 1 C) 2 D) -1 10 / 40 Yig‘indini toping. A) 1/9 B) 1/6 C) 1/4 D) 1/12 11 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 8√3 B) 6√5 C) 12√3 D) 9√5 12 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 20 C) 40 D) 35 13 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 100 D) 25 14 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (2; 7) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 15 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 3√2 D) 4√3 16 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 4 yoki –12 D) 6 17 / 40 Hisoblang: A) 10/11 B) 19/20 C) 20/21 D) 9/10 18 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) π/4+πk, k∈Z C) Ø D) -π/4+πk, k∈Z 19 / 40 √3 A) 5/5 B) 21/10 C) 3/2 D) 7/3 20 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 3 C) 2 D) 1 21 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 44 C) 45 D) 43 22 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 32 C) 16(π-2) D) 8(π+2) 23 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 4 C) 1 D) 3 24 / 40 Tenglamani yeching: A) -6 B) 6; -5 C) -6; 5 D) 5 25 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 1 D) 2 26 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -3 D) -4 27 / 40 bo‘lsa, A) 2 B) 3/2 C) 1 D) 2/3 28 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 13 C) 14 D) 12 29 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 4√3 C) 2√3 D) 2√2 30 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 6√7 C) 10 D) 4√7 31 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 32 C) 28 D) 24 32 / 40 Hisoblang: A) -1/2 B) 0 C) 1/32 D) -√3/2 33 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 12 C) 8 D) 6 34 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 42 C) 48 D) 64 35 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) -2 C) 3 D) 5 36 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 37 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 20 C) 14 D) 10 38 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 121 C) 22 D) berilganlar yetarli emas 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) 1 D) cd/b 40 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 5 C) 7 D) 10 O'rtacha ball 35% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
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