Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 60 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar va bo'lsa f(4) ning qiymatini toping. A) 11 B) 12 C) 4 D) 35 2 / 40 tengsizlikni yeching. A) x∈(-∞;5) B) x∈(-3;1) C) x∈(-5;1) D) x∈(-∞;5)∪(-3;1) 3 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 201 B) 203 C) 200 D) 289 4 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 13 B) 9,25 C) 6 D) 5,75 5 / 40 a va b musbat sonlari uchun alnb·blna+alnb +blna bo'lsa, (lna)·(lnb)=? A) ln5 B) ln4 C) ln3 D) ln2 6 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 48 B) 27 C) 32 D) 26 7 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 4 B) 6 C) 3 D) 5 8 / 40 x ni toping ? A) 4 B) 5 C) 6 D) 3 9 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 2 B) 3 C) 4 D) 1 10 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 9√5 B) 6√5 C) 12√3 D) 8√3 11 / 40 ni hisoblang. A) 2 B) 0 C) 1 D) 3 12 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 8 B) 10 C) 9 D) 6 13 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 14 C) 12 D) 15 14 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 5 C) 11 D) 10 15 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 24 C) 35 D) 23 16 / 40 bo‘lsa, A) 3/2 B) 1 C) 2 D) 2/3 17 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 4 C) 1 D) 3 18 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (7; 2), (28; -1) C) (9; 0), (28; -1) D) (9; 0), (2; 7) 19 / 40 √3 A) 5/5 B) 21/10 C) 7/3 D) 3/2 20 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 30° D) 50° 21 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 8 C) 6√7 D) 10 22 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 24 D) 30 23 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) -6 D) 6; -5 24 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) berilganlar yetarli emas C) 121 D) 11 25 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 44 C) 42 D) 45 26 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) BC > AD D) DC < AD 27 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 6 C) 11 D) 4 28 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,04 C) 0,(04) D) 0,0(4) 29 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 2 C) 4 D) 1 30 / 40 Hisoblang: A) cos10° B) 1 C) sin10° D) cos50° 31 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 4√3 C) 2√2 D) 2√3 32 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 116 C) 110 D) 112 33 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 5 C) 8 D) 3 34 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) bd/c D) 1 35 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 32 D) 48 36 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 10 C) 15 D) 20 37 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 7 D) 6 38 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3ctg40° tg70° C) 2√3tg50° tg70° D) √3tg50° tg70° 39 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) π/4+πk, k∈Z C) Ø D) 0 40 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 9 C) 11 D) 12 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
