Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) Birinchi yo'l B) Uchunchi yo'l C) To'rtinchi yo'l D) Ikkinchi yo'l 2 / 40 180 gramm suvga 70 gramm tuz aralashtrildi. Hosil bo‘lgan aralashmaninmg necha foizi suvdan iborat? A) 78 B) 75 C) 72 D) 70 3 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 25 B) 4 C) 9 D) 16 4 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 9 B) 7 C) 3 D) 1 5 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 2 B) 6 C) 8 D) 4 6 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 4 B) 7,5 C) 4,5 D) 3 7 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 6 B) 8 C) 9 D) 7 8 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 64/5 B) 10 C) 48/5 D) 16 9 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 11 B) 10 C) 13 D) 12 10 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 20 C) 40 D) 35 11 / 40 1, 1, 2, 3, 5, 8, 13, … ketma-ketlikning umumiy hadi an bo‘lsa, quyidagilardan qaysi biri to‘g‘ri? A) 1 B) 3 C) 2 D) 4 12 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;3]∪[2;∞) B) x∈R C) (-∞;0)∪(0;∞) D) [-3;2] 13 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 48 C) 32 D) 64 14 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 14 C) 23 D) 24 15 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 4 C) 6 D) 11 16 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 30° C) 20° D) 40° 17 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 12 C) 9 D) 10 18 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 2 C) 3 D) 4 19 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 116 C) 110 D) 112 20 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,04 C) 0,0(4) D) 0,(04) 21 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (2; 3) C) (9; 0), (2; 7) D) (9; 0), (28; -1) 22 / 40 sonlarini taqqolsang. A) b B) a C) c D) c 23 / 40 Hisoblang: A) 10/11 B) 19/20 C) 20/21 D) 9/10 24 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) 5 D) -2 25 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) Ø C) 0 D) π/4+πk, k∈Z 26 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 1 D) 3 27 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 100 C) 25 D) 105 28 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) -6 D) 6; -5 29 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 42 C) 45 D) 43 30 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 0 D) 1/32 31 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 6 C) 7 D) 8 32 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 11 C) 121 D) 22 33 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) DC < AD D) BC > AD 34 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 6 C) 10 D) 8 35 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 2√3 C) 4√3 D) 3√2 36 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 32 C) 24 D) 30 37 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 32 C) 64 D) 16(π-2) 38 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 13 C) 14 D) 12 39 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 1 D) 4 40 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) cd/b C) 1 D) bc/d O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
