Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 73 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 18 B) 24 C) 30 D) 12 2 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 25 B) 9 C) 4 D) 16 3 / 40 bo‘lsa, x + y ni toping. A) 17 B) 18 C) 16 D) 20 4 / 40 funksiyaning qiymatlar to'plamini toping. A) (-2√2;√2) B) [-√2;-1)∪(-1;1)∪(1;√2] C) [-√2;0)∪(0;√2] D) [-√2;√2] 5 / 40 Aniq integralni hisoblang: A) 2 B) 3 C) 0,5 D) 0 6 / 40 tenglamaning ildizlari yig'indisini(agar ildizi bitta bo'lsa, o'zini) toping. A) 0 B) 1 C) 2 D) 3 7 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 9 B) 6 C) 7 D) 8 8 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 99 B) 100 C) 101 D) 98 9 / 40 Hisoblang: A) 4 B) 1 C) 2 D) 3 10 / 40 tenglama intervalda nechta ildizga ega? A) 1 B) 3 C) 2 D) 4 11 / 40 x>0 bo‘lsa, 128x+1/x² yig‘indining eng kichik qiymatini toping. A) 32 B) 48 C) 16 D) 64 12 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;3]∪[2;∞) B) x∈R C) [-3;2] D) (-∞;0)∪(0;∞) 13 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 4√3 C) 4√2 D) 3√2 14 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) AB = BC D) DC < AD 15 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) 5 C) -4 D) -6 16 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3ctg40° tg70° C) 2√3tg50° tg70° D) √3tg50° tg70° 17 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 9 C) 12 D) 11 18 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 35 D) 24 19 / 40 bo‘lsa, A) 2 B) 1 C) 2/3 D) 3/2 20 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 10 C) 6 D) 12 21 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) 8 C) 5 D) -2 22 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) 0 C) π/4+πk, k∈Z D) -π/4+πk, k∈Z 23 / 40 Hisoblang: A) 9/10 B) 20/21 C) 10/11 D) 19/20 24 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,04 C) 0,(04) D) 0,0(4) 25 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 4 C) 2 D) 3 26 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 1 D) 3 27 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 8 C) 6 D) 7 28 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 42 D) 44 29 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√3 C) 4√3 D) 2√2 30 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 8(π+2) C) 32 D) 64 31 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 3 C) 4 D) 1 32 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 14 D) 15 33 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (9; 0), (2; 7) C) (7; 2), (28; -1) D) (2; 3) 34 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 25 C) 100 D) 105 35 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 42 C) 32 D) 64 36 / 40 Hisoblang: A) 1/32 B) -1/2 C) 0 D) -√3/2 37 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 50° C) 30° D) 40° 38 / 40 Hisoblang: A) cos50° B) cos10° C) 1 D) sin10° 39 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 6 C) 11 D) 5 40 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 20 D) 10 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
