Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 180 gramm suvga 70 gramm tuz aralashtrildi. Hosil bo‘lgan aralashmaninmg necha foizi suvdan iborat? A) 78 B) 75 C) 70 D) 72 2 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) Birinchi yo'l B) To'rtinchi yo'l C) Uchunchi yo'l D) Ikkinchi yo'l 3 / 40 y=kx+n funksiyaning grafigi I va III chorakdan o‘tishi uchun k va n qanday bo‘lishi kerak? A) n > 0, k = 0 B) n = 0, k > 0 C) n = 0, k < 0 D) n < 0, k = 0 4 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 1 B) 9 C) 3 D) 7 5 / 40 1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2n, 3m va 7k lar ishtirok etsa, n+m+k ni toping. A) 40 B) 44 C) 50 D) 46 6 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,7 m yoki 70 cm B) 0,6 m yoki 60 cm C) 0,5 m yoki 50 cm D) 0,9 m yoki 90 cm 7 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 20° B) 30° C) 40° D) 10° 8 / 40 Tengsizlikni qanoatlantiradigan eng kichik ikkita butunsonning yig`indisini toping? A) 3 B) 6 C) 4 D) 5 9 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 1 B) 3 C) 4 D) 2 10 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 30 B) 0 C) 25 D) 10 11 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 7 B) 9 C) 12 D) 15 12 / 40 Integralni hisoblang: A) 1 B) 3 C) 2 D) 4 13 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) DC < AD C) BD = BC D) AB = BC 14 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 15 / 40 Hisoblang: A) 0 B) 1/32 C) -√3/2 D) -1/2 16 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 28 C) 32 D) 24 17 / 40 √3 A) 3/2 B) 5/5 C) 21/10 D) 7/3 18 / 40 Tenglamani yeching: A) -6 B) 5 C) -6; 5 D) 6; -5 19 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 6 C) 12 D) 10 20 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 21 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 4√3 C) 6 D) 3√2 22 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 42 B) 48 C) 64 D) 32 23 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) bc/d D) 1 24 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) -2 C) 3 D) 8 25 / 40 Hisoblang: A) 19/20 B) 20/21 C) 10/11 D) 9/10 26 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3ctg40° tg70° C) √3tg50° tg70° D) 2√3tg50° tg70° 27 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 100 D) 25 28 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 8 C) 4√7 D) 6√7 29 / 40 sonlarini taqqolsang. A) c B) b C) a D) c 30 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,04 C) 0,0(4) D) 0,(04) 31 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (9; 0), (2; 7) C) (7; 2), (28; -1) D) (2; 3) 32 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 3 C) 4 D) 1 33 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 2 C) 4 D) 3 34 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√3 B) 4√3 C) 3√2 D) 2√2 35 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 3 yoki –8 C) 5 yoki –15 D) 6 36 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 20 C) 15 D) 10 37 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) π/4+πk, k∈Z C) 0 D) -π/4+πk, k∈Z 38 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 14 C) 15 D) 12 39 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 24 C) 14 D) 23 40 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 2 D) 3 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
