Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, y = ? A) 8 B) 2 C) 26 D) 3 2 / 40 Jaloliddin uyiga tezroq qaytish uchun qaysi yo’lni tanlash kerak. A) Uchunchi yo'l B) To'rtinchi yo'l C) Birinchi yo'l D) Ikkinchi yo'l 3 / 40 Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping. A) aniqlab bo‘lmaydi B) 20 C) 16 D) 18 4 / 40 Bir odam shunday vasiyat qildi: “Naqd 10 dirham pulim bor. Bir kishiga qarz ham berganman. Qarzning miqdori o'g'lim oladigan merosga teng. Ikkala o'g'lim barobar meros olishsin. Ukamga jami merosning 0,2 qismini va yana 1 dirham beringlar”. U kishining o'g'illari necha dirhamdan meros olishgan? A) 6 B) 8 C) 35/6 D) 25/3 5 / 40 Hisoblang: A) 7 B) 4 C) 27 D) 9 6 / 40 Aniq integralni hisoblang: A) 3 B) 2 C) 0 D) 0,5 7 / 40 Hisoblang: A) 4 B) 3 C) 2 D) 1 8 / 40 Soddalashtiring. A) (a+1)/(-a-3) B) (a-1)/(a-3) C) (b+2)/(1-b) D) (a-1)/(1-b) 9 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 1 B) 4 C) 2 D) 3 10 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 9 B) 12 C) 7 D) 15 11 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 3 B) 9 C) 6 D) 12 12 / 40 Radiusi 25/4 bo‘lgan sferaga balandligi 8 ga teng bo‘lgan konus ichki chizilgan. Konusning hajmini toping. A) 192π B) 72π C) 144π D) 96π 13 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 64 C) 42 D) 32 14 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 8 B) 15 C) 10 D) 20 15 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 3 D) 2 16 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 10 C) 11 D) 12 17 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 18 / 40 Hisoblang: A) 0 B) 1/32 C) -1/2 D) -√3/2 19 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 6; -5 D) 5 20 / 40 Hisoblang: A) 1 B) cos50° C) sin10° D) cos10° 21 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (28; -1) C) (2; 3) D) (9; 0), (2; 7) 22 / 40 Hisoblang: A) 10/11 B) 9/10 C) 20/21 D) 19/20 23 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 10 D) 6√7 24 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 4√3 C) 3√2 D) 6 25 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) -2 B) 3 C) 8 D) 5 26 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 42 C) 44 D) 43 27 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 3 D) 2 28 / 40 sonlarini taqqolsang. A) b B) c C) c D) a 29 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 105 C) 100 D) 25 30 / 40 Chizmadan foydalanib α ni toping. A) 40° B) 20° C) 30° D) 50° 31 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) 1 D) cd/b 32 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 32 C) 8(π+2) D) 16(π-2) 33 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 4 C) 2 D) 1 34 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 112 C) 115 D) 116 35 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 2√3 C) 3√2 D) 2√2 36 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 10 C) 6 D) 8 37 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 14 C) 10 D) 12 38 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 24 D) 28 39 / 40 Ifodaning qiymatini toping. A) 0,0(2) B) 0,04 C) 0,(04) D) 0,0(4) 40 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) AB = BC C) BC > AD D) DC < AD O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16