Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 56 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 x,y,z∈N A=6x+1=5y+1=4z+1, min(A)=? A) 58 B) 61 C) 60 D) 59 2 / 40 Agar bo'lsa ifodaning qiymatini toping. A) 9 B) 7 C) 13 D) 0 3 / 40 ni qanoatlantiruvchi yechimlar nechta? A) 2 B) 3 C) 1 D) 0 4 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;√2] B) [-√2;-1)∪(-1;1)∪(1;√2] C) (-2√2;√2) D) [-√2;0)∪(0;√2] 5 / 40 Uchlari A(4;5;1), B(2;3;0) va C(2;–1;–3) nuqtalarda joylashgan uchburchakning BD medianasi uzunligini toping. A) 2 B) √2 C) √3 D) 1 6 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) y=-a B) x=-a C) y=1-a D) x=a 7 / 40 Hisoblang? A) 4 B) 0,5 C) 2 D) 0,25 8 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 3 B) 2 C) 1 D) 4 9 / 40 Hisoblang: -121+(-135)-(-1)28 A) -1 B) -2 C) 0 D) -3 10 / 40 f(x)+f(3x)+f(5x)+...+f(39x)=(3x+10)4 bo'lsa, f'(0) ni toping. A) 10 B) 30 C) 0 D) 25 11 / 40 f(3x)=x+f(3x-3) va f(3)=1 bo'lsa, f(300) nechaga teng? A) 600 B) 4800 C) 5050 D) 3600 12 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 7 B) 15 C) 9 D) 12 13 / 40 bo‘lsa, A) 3/2 B) 1 C) 2 D) 2/3 14 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 20° C) 40° D) 30° 15 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 3 yoki –8 B) 5 yoki –15 C) 6 D) 4 yoki –12 16 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 116 D) 110 17 / 40 sonlarini taqqolsang. A) c B) a C) b D) c 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 9 D) 11 19 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 11 B) 22 C) berilganlar yetarli emas D) 121 20 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) 4 √3tg50° tg70° C) √3tg50° tg70° D) √3ctg40° tg70° 21 / 40 Rasmdagi shakl perimetrini toping. A) 24 B) 32 C) 30 D) 28 22 / 40 Hisoblang: A) 20/21 B) 10/11 C) 9/10 D) 19/20 23 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 25 B) 105 C) 96 D) 100 24 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 3√2 C) 6 D) 4√3 25 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (2; 7) C) (9; 0), (28; -1) D) (7; 2), (28; -1) 26 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 1 B) 4 C) 3 D) 2 27 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 42 D) 64 28 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 14 C) 20 D) 12 29 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 42 D) 44 30 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 8 C) 15 D) 20 31 / 40 Tenglamani yeching: A) 6; -5 B) -6; 5 C) -6 D) 5 32 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 2 C) 1 D) 4 33 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 8 C) 6 D) 10 34 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 7 C) 5 D) 10 35 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 8 B) 4√7 C) 10 D) 6√7 36 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) bc/d D) 1 37 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 2 D) 3 38 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 3√2 C) 2√3 D) 4√3 39 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 6 C) 5 D) 11 40 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -3 C) 5 D) -4 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
