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Matematika attestatsiya №5

InfoMaster

Yanvar 24, 2022

55 Ko'rishlar 1 izoh

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2 ovozlar, 1 avg

Matematika fanidan attestatsiya savollari №5

1 / 40

Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping.

A) 12

B) 18

C) 24

D) 30

2 / 40

$y^4+9x^2-4y^2-30x+29=0$ tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping.

A) 203

B) 289

C) 200

D) 201

3 / 40

Agar ning qiymatini toping.

A) 23/25

B) 23/75

C) 3

D) 75/23

4 / 40

tenglamani yeching.

A) log(3/5)2

B) 3

C) 5

D) log(5/3)2

5 / 40

1·2·3· ... ·30 ko'paytmani tub ko'paytuvchilarga ajratganda ko'apytmada 2ⁿ, 3^m va 7^k lar ishtirok etsa, n+m+k ni toping.

A) 50

B) 44

C) 46

D) 40

6 / 40

P(-2;2) nuqtadan o'tuvchi va a(6;4)a vektorga perpendikulyar bo'lgan to'g'ri chiziq tenglamasini toping.

A) 3x-2y-2=0

B) 3x+2y-2=0

C) 3x-2y+2=0

D) 3x+2y+2=0

7 / 40

x ni toping ?

A) 6

B) 3

C) 5

D) 4

8 / 40

Hisoblang?

A) 0,25

B) 0,5

C) 2

D) 4

9 / 40

Hisoblang:

A) 3

B) 2

C) 4

D) 1

10 / 40

Tenglamaning natural ildizining butun bo‘luvchilari nechta?

A) 5

B) 4

C) 6

D) 2

11 / 40

Agar f(x) funksiya (-∞;∞) da qat’iy o‘suvchi funksiya bo‘lsa, y =3 f(x)-8 funksiya uchun quyidagi mulohazalardan qaysi biri to‘g‘ri bo‘ladi?

A) qat’iy kamayuvchi

B) dastlab kamayadi, keyin o‘sadi

C) dastlab o‘sadi, keyin kamayadi

D) qat’iy o‘suvchi

12 / 40

Funksiyaning aniqlanish sohasini toping.

A) (-∞;0)∪(0;∞)

B) (-∞;3]∪[2;∞)

C) [-3;2]

D) x∈R

13 / 40

Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi?

A) 42

B) 45

C) 44

D) 43

14 / 40

√3

A) 5/5

B) 3/2

C) 7/3

D) 21/10

15 / 40

sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping.

A) 24

B) 35

C) 14

D) 23

16 / 40

3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping.

A) 96

B) 25

C) 100

D) 105

17 / 40

Hisoblang:

A) 20/21

B) 10/11

C) 9/10

D) 19/20

18 / 40

Chizmadan foydalanib α ni toping.

A) 20°

B) 30°

C) 40°

D) 50°

19 / 40

Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping.

A) 4√7

B) 10

C) 6√7

D) 8

20 / 40

a+b+c=10, bo‘lsa, ni toping.

A) 6

B) 5

C) 4

D) 11

21 / 40

1+sin 2x = 7(sin x + cos x) tenglamani yeching.

A) 0

B) Ø

C) -π/4+πk, k∈Z

D) π/4+πk, k∈Z

22 / 40

Tenglamani yeching:

A) -6; 5

B) 5

C) -6

D) 6; -5

23 / 40

Hisoblang:

A) cos10°

B) cos50°

C) sin10°

D) 1

24 / 40

Tengsizlik nechta butun juft yechimga
ega?

A) 112

B) 110

C) 115

D) 116

25 / 40

Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng?

A) 4 √3tg50° tg70°

B) 2√3tg50° tg70°

C) √3tg50° tg70°

D) √3ctg40° tg70°

26 / 40

Rasmdagi shakl perimetrini toping.

A) 28

B) 32

C) 24

D) 30

27 / 40

Agar geometrik progressiyaning umumiy hadi b_n= 3·2ⁿ bo‘lsa, ni toping.

A) 1

B) 3

C) 4

D) 2

28 / 40

ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping.

A) 12

B) 10

C) 8

D) 6

29 / 40

a_n - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping:

A) 6

B) 5

C) 7

D) 8

30 / 40

Tenglamalar sistemasining ildizlari yig‘indisini toping.

A) 12

B) 14

C) 20

D) 10

31 / 40

ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping.

A) 6

B) 4√3

C) 3√2

D) 4√2

32 / 40

ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri?

A) BD = BC

B) DC < AD

C) BC > AD

D) AB = BC

33 / 40

6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang.

A) 13

B) 15

C) 12

D) 14

34 / 40

Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping.