Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 37 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar bo‘lsa, x ni toping. A) 5 B) -2 C) 2 D) -5 2 / 40 Bobur 14 m/s tezlik bilan 5 soat, 36 km/soat tezlik bilan 5 minut yugurgan bo’lsa , Boburning umumiy yurgan yo’li topilsin A) 670 km B) 456 km C) 255 km D) 13 km 3 / 40 Hisoblash natijasida hosil bo’lgan sondan 4 marta katta sonning natural bo’luvchilari soni a bo’lsa , a ning butun bo’luvchilari sonini toping. A) 32 B) 8 C) 16 D) 24 4 / 40 Arifmetik progressiyada an+1=an+2 va a4=4 bo'lsa, uning dastlabki 12 ta hadini yig'indisini toping. A) 96 B) 114 C) 126 D) 108 5 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 26 B) 48 C) 32 D) 27 6 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,6 m yoki 60 cm B) 0,7 m yoki 70 cm C) 0,9 m yoki 90 cm D) 0,5 m yoki 50 cm 7 / 40 AM||KL , ∠BCD=70°,∠CDE=40°, ∠DEF =45°,∠EFG=80°, ∠FGK=70°∠MBC=x ga teng bo`lsa x ni toping ? A) 20° B) 10° C) 40° D) 30° 8 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 16 B) 64/5 C) 10 D) 48/5 9 / 40 Quyida berilgan holatda stol va uni atrofida qo’yiladigan stullarning holati berilgan va raqamlangan k-holatda stullarning raqamlari yig`indisi 351 taga teng bo`lsa, k ni toping ? A) 12 B) 11 C) 10 D) 13 10 / 40 Tenglamalar sistemasidan foydalanib x + y + z ni toping: A) 8 B) 10 C) berilganlar yetarli emas D) 6 11 / 40 ni hisoblang. A) 2 B) 3 C) 0 D) 1 12 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 9 B) 6 C) 3 D) 12 13 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 2 D) 4 14 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) √3tg50° tg70° C) √3ctg40° tg70° D) 2√3tg50° tg70° 15 / 40 Hisoblang: A) -√3/2 B) 1/32 C) -1/2 D) 0 16 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 3 B) 4 C) 2 D) 1 17 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 6 D) 5 18 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) 5 C) -6 D) -4 19 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) BD = BC D) DC < AD 20 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 30° C) 40° D) 50° 21 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (2; 3) C) (9; 0), (2; 7) D) (7; 2), (28; -1) 22 / 40 Hisoblang: A) cos50° B) sin10° C) 1 D) cos10° 23 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 100 C) 105 D) 25 24 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 5 C) 10 D) 11 25 / 40 √3 A) 21/10 B) 5/5 C) 3/2 D) 7/3 26 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 4√7 C) 8 D) 6√7 27 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 14 C) 10 D) 12 28 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 2 C) 1 D) 3 29 / 40 Hisoblang: A) 19/20 B) 20/21 C) 10/11 D) 9/10 30 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 8(π+2) C) 16(π-2) D) 64 31 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 8 C) 10 D) 6 32 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 121 C) 22 D) 11 33 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 5 B) 8 C) -2 D) 3 34 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 6 B) 3√2 C) 4√3 D) 4√2 35 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 35 D) 14 36 / 40 Tenglamani yeching: A) 6; -5 B) -6 C) -6; 5 D) 5 37 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) 1 D) bc/d 38 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 4√3 B) 3√2 C) 2√2 D) 2√3 39 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(2) C) 0,0(4) D) 0,04 40 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 28 C) 24 D) 30 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
