Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) aniqlab bo‘lmaydi B) 2 C) 3 D) 4 2 / 40 tenglikni qanoatlantiruvchi x va y sonlari uchun 19y²+99x ni toping. A) 203 B) 201 C) 200 D) 289 3 / 40 Agar bo'lsa, x ni toping. A) -2 B) 2 C) -5 D) 5 4 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,5 m yoki 50 cm B) 0,7 m yoki 70 cm C) 0,9 m yoki 90 cm D) 0,6 m yoki 60 cm 5 / 40 Hisoblang: A) 7 B) 4 C) 27 D) 9 6 / 40 Teng yonli trapetsiyaning diagonallari o'zaro perpendikulyar hamda yuzi 32 ga teng bo'lsa, uning diagonali uzunligini toping. A) 8 B) 4 C) 2 D) 6 7 / 40 Soddalashtiring. A) (b+2)/(1-b) B) (a-1)/(1-b) C) (a+1)/(-a-3) D) (a-1)/(a-3) 8 / 40 Quyidagi berilgan qoldiqli bo`lishlardan qaysi biri to`g`ribajarilgan ? a)76 : 9 = 7 (qoldiq 13); b)20 : 7 = 2 (qoldiq 6); d)54 : 15 = 4 (qoldiq 1) A) a,b B) b,d C) b D) )a,b,d 9 / 40 x ni toping ? A) 3 B) 5 C) 4 D) 6 10 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 12 B) 6 C) 3 D) 9 11 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √2/8 B) √3/4 C) √3/8 D) 1/8 12 / 40 Agar tenglamaning ildizi m/n bo‘lsa, m+ n ni toping. Bunda EKUB(m; n)=1. A) 25 B) 41 C) 50 D) 32 13 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 14 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 1 B) 4 C) 3 D) 2 15 / 40 sonlarini taqqolsang. A) a B) b C) c D) c 16 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 35 B) 23 C) 24 D) 14 17 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) Ø C) π/4+πk, k∈Z D) -π/4+πk, k∈Z 18 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 10 B) 8 C) 20 D) 15 19 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 42 C) 32 D) 64 20 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 10 C) 11 D) 9 21 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 20° C) 50° D) 40° 22 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 14 B) 12 C) 10 D) 20 23 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 4 B) 1 C) 3 D) 2 24 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 42 C) 44 D) 43 25 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BD = BC B) BC > AD C) DC < AD D) AB = BC 26 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 100 C) 105 D) 25 27 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 6 C) 4 yoki –12 D) 3 yoki –8 28 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 24 D) 28 29 / 40 Hisoblang: A) 20/21 B) 9/10 C) 19/20 D) 10/11 30 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 10 C) 6 D) 12 31 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 1 B) 4 C) 3 D) 2 32 / 40 a+b+c=10, bo‘lsa, ni toping. A) 5 B) 4 C) 11 D) 6 33 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 8(π+2) C) 16(π-2) D) 32 34 / 40 √3 A) 3/2 B) 5/5 C) 21/10 D) 7/3 35 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 10 C) 7 D) 5 36 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (9; 0), (28; -1) C) (2; 3) D) (7; 2), (28; -1) 37 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 4√7 B) 8 C) 6√7 D) 10 38 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3ctg40° tg70° B) √3tg50° tg70° C) 2√3tg50° tg70° D) 4 √3tg50° tg70° 39 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bc/d C) bd/c D) cd/b 40 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 0 D) 1/32 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
