Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 33 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ni qanoatlantiruvchi yechimlar nechta? A) 3 B) 1 C) 2 D) 0 2 / 40 Agar va bo'lsa f(4) ning qiymatini toping. A) 4 B) 11 C) 12 D) 35 3 / 40 To’g’ri turt burchakning bo’yining perimetriga nisbatini toping. A) 1/2 B) 5/3 C) -452/18 D) 3/18 4 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 26 B) 48 C) 32 D) 27 5 / 40 a va b raqamlar yig'indisi 7 ga qoldiqsiz bo'linadi. Agar ko'rinishdagi uch xonali sonlarning 7 ga bo'lganda bir xil qoldiq qolsa, shu qoldiqni toping. A) 0 B) 6 C) 4 D) 2 6 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (0; ∞) B) [-1; ∞) C) (-2; ∞) D) (-1; ∞) 7 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 48/5 B) 10 C) 64/5 D) 16 8 / 40 Quyida berilgan tizimda yonma - yon shakillardagisonlar ustida pasdagi ( EKUB yoki EKUK topish) amali bajariladi , natija amal pastigi shakilga yoziladi Shunga ko`ra 1 , 2 va 3 amallar EKUB yoki EKUK dan qaysi biri bo`lishi kerak A) 1-EKUB 2-EKUK 3-EKUB B) 1-EKUB 2-EKUB 3-EKUB C) 1-EKUB 2-EKUK 3-EKUK D) 1-EKUB 2-EKUB 3-EKUK 9 / 40 Hisoblang: -121+(-135)-(-1)28 A) -1 B) 0 C) -2 D) -3 10 / 40 ni hisoblang. A) 1 B) 2 C) 0 D) 3 11 / 40 Ayniyatdan foydalanib x + y + z ni toping: A) 12 B) 6 C) 3 D) 9 12 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 12 B) 15 C) 9 D) 7 13 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 5 C) 6 D) 8 14 / 40 bo‘lsa, A) 3/2 B) 1 C) 2/3 D) 2 15 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 25 C) 105 D) 96 16 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 2 C) 3 D) 1 17 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) -π/4+πk, k∈Z B) Ø C) 0 D) π/4+πk, k∈Z 18 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 4 C) 2 D) 1 19 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 28 D) 24 20 / 40 Tenglamalar sistemani yeching: A) (7; 2), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (9; 0), (28; -1) 21 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 15 C) 13 D) 14 22 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√2 B) 6 C) 4√3 D) 3√2 23 / 40 Tengsizlik nechta butun juft yechimga ega? A) 115 B) 112 C) 116 D) 110 24 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bd/c C) 1 D) bc/d 25 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 12 B) 8 C) 10 D) 6 26 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 64 B) 32 C) 8(π+2) D) 16(π-2) 27 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 1 D) 2 28 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 32 B) 64 C) 42 D) 48 29 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -4 D) -6 30 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 11 C) berilganlar yetarli emas D) 22 31 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 44 C) 43 D) 42 32 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) BD = BC C) AB = BC D) DC < AD 33 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) √3tg50° tg70° B) 4 √3tg50° tg70° C) 2√3tg50° tg70° D) √3ctg40° tg70° 34 / 40 Hisoblang: A) 10/11 B) 9/10 C) 19/20 D) 20/21 35 / 40 a+b+c=10, bo‘lsa, ni toping. A) 4 B) 11 C) 6 D) 5 36 / 40 Hisoblang: A) -1/2 B) 0 C) -√3/2 D) 1/32 37 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 11 C) 10 D) 7 38 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 12 D) 10 39 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 6 C) 3 yoki –8 D) 4 yoki –12 40 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√3 C) 4√3 D) 2√2 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
