Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 55 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tengsizlik yechimi bo’la oladigan tub sonlar nechta? A) 5 B) 2 C) 4 D) 3 2 / 40 Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping. A) aniqlab bo‘lmaydi B) 18 C) 20 D) 16 3 / 40 Kichchik diagonali tomoniga teng bo’lgan rombga , tomoni diametr qilib yarim doira va uning ichiga romb tomoniga hamda yarim doiraga urunuvchi aylana chizilgan . Agar romb tomoni 8 bo’lsa aylana markazidan diagonallar kesishish nuqtasigacha bo’lgan masofani toping. A) 3 B) 1 C) 2 D) 4 4 / 40 Usta ishning 0,75 qismini 17/4 soatda bajaradi. Shu ishning 4/5 qismini qancha vaqtda bajaradi? A) 68/15 B) 67/15 C) 11/5 D) 31/85 5 / 40 x4+8x3+ax2+bx+1 ko'phadning kvadrati bo'lsa, a va b koeffitiyentlarning barcha qiymatlari yig'indisini toping. A) 26 B) 32 C) 27 D) 48 6 / 40 funksiyaning [2; 3] kesmadagi eng katta qiymatini A) 3 B) 7,5 C) 4 D) 4,5 7 / 40 Eldor velosipetida 13m/s bilan 3 soniyada 15m tepalikka ko`tarilgan bo`lsa AC kesma uzunligi necha metr? A) 32 B) 34 C) 36 D) 40 8 / 40 Quyida berilgan shakillar ichidagi sonlar yig`indisi nolgateng bo`lishi uchun . Nechanchi shakilni olib tashlash kerak? A) 4 B) 1 C) 3 D) 2 9 / 40 DC||AB , ∠DCE=45°,∠CEA=x va ∠EAB=115° ga tengbo`lsa x ni toping ? A) 110° B) 130° C) 100° D) 120° 10 / 40 275+330 sonini 41 ga bo‘lganda qoladigan qoldiqni aniqlang. A) 5 B) 0 C) 1 D) 9 11 / 40 A, B,C,D, E natural sonlar. Agar EKUB(A,B,C)=10, EKUB(B,C,D,E)=15 bo‘lsa, A+ B+C+D+ E ning eng kichik qiymatini toping. A) 100 B) 120 C) 80 D) 90 12 / 40 To‘g‘ri burchakli uchburchakning bir burchagi 52° ga teng bo‘lsa, to‘g‘ri burchak uchidan tushirilgan balandlik va mediana orasidagi burchakni toping. A) 7° B) 17° C) 14° D) 24° 13 / 40 Hisoblang: A) -1/2 B) 0 C) 1/32 D) -√3/2 14 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 1 C) 3 D) 4 15 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 5 yoki –15 D) 3 yoki –8 16 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 64 C) 16(π-2) D) 32 17 / 40 Tenglamalar sistemani yeching: A) (9; 0), (2; 7) B) (7; 2), (28; -1) C) (9; 0), (28; -1) D) (2; 3) 18 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 11 C) 10 D) 9 19 / 40 Tenglamani yeching: A) 6; -5 B) 5 C) -6 D) -6; 5 20 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) DC < AD C) BC > AD D) BD = BC 21 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 45 B) 43 C) 42 D) 44 22 / 40 sonlarini taqqolsang. A) a B) c C) c D) b 23 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 6 C) 3√2 D) 4√2 24 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 105 B) 25 C) 100 D) 96 25 / 40 Hisoblang: A) cos10° B) cos50° C) sin10° D) 1 26 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) -2 C) 5 D) 3 27 / 40 √3 A) 7/3 B) 3/2 C) 5/5 D) 21/10 28 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 1 D) 2 29 / 40 Ifodaning qiymatini toping. A) 0,0(4) B) 0,(04) C) 0,04 D) 0,0(2) 30 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 10 B) 12 C) 14 D) 20 31 / 40 bo‘lsa, A) 2/3 B) 1 C) 2 D) 3/2 32 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 35 C) 23 D) 14 33 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 15 B) 8 C) 20 D) 10 34 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 11 B) 7 C) 5 D) 10 35 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 3 B) 2 C) 4 D) 1 36 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 8 B) 6 C) 10 D) 12 37 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 115 C) 112 D) 116 38 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -3 B) 5 C) -4 D) -6 39 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 48 C) 42 D) 32 40 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bc/d B) bd/c C) cd/b D) 1 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
