Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 Agar ni hisoblang. A) 9 B) Cheksiz C) 8 D) 0 2 / 40 bo‘lsa, x + y ni toping. A) 16 B) 17 C) 18 D) 20 3 / 40 Berilgan sonlarning yig’indisini toping. A) 1/4 B) -452/18 C) 2/4 D) 3/18 4 / 40 20132015 ni 10 ga bo'lgandagi qoldiqni toping. A) 9 B) 7 C) 3 D) 1 5 / 40 Hisoblang: A) 7 B) 4 C) 9 D) 27 6 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 4 B) 1 C) 2 D) 3 7 / 40 Soddalashtiring. A) (b+2)/(1-b) B) (a-1)/(a-3) C) (a+1)/(-a-3) D) (a-1)/(1-b) 8 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 1 B) 2 C) 3 D) 4 9 / 40 Bir idishda 32/5 kg, ikkinchisida esa unga qaraganda 16/5 kg ortiq yog` bor. Ikkala idishda qancha yog` bor? A) 10 B) 48/5 C) 16 D) 64/5 10 / 40 cos75° ·cos 45° ·cos15° ni hisoblang. A) √3/4 B) 1/8 C) √3/8 D) √2/8 11 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 10 B) 6 C) 8 D) 9 12 / 40 Agar x2-6x+7=0 bo‘lsa, ni toping. A) 40 B) 28 C) 48 D) 52 13 / 40 Tengsizlik nechta butun juft yechimga ega? A) 110 B) 115 C) 112 D) 116 14 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 11 C) 7 D) 10 15 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -4 B) 5 C) -3 D) -6 16 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 14 C) 15 D) 13 17 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 96 B) 100 C) 25 D) 105 18 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 10 D) 8 19 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 6 C) 4√2 D) 4√3 20 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 21 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) AB = BC D) BC > AD 22 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 7 C) 5 D) 6 23 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) 0 B) -π/4+πk, k∈Z C) Ø D) π/4+πk, k∈Z 24 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (7; 2), (28; -1) C) (9; 0), (2; 7) D) (9; 0), (28; -1) 25 / 40 √3 A) 5/5 B) 21/10 C) 3/2 D) 7/3 26 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 40° C) 30° D) 50° 27 / 40 x²-√11x+1=0 0 bo‘lsa, A) 9 B) 11 C) 10 D) 12 28 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,0(4) D) 0,(04) 29 / 40 Hisoblang: A) sin10° B) cos10° C) 1 D) cos50° 30 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 3 D) 1 31 / 40 Tenglamani yeching: A) -6 B) 5 C) 6; -5 D) -6; 5 32 / 40 bo‘lsa, A) 3/2 B) 2/3 C) 2 D) 1 33 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) √3ctg40° tg70° C) √3tg50° tg70° D) 4 √3tg50° tg70° 34 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) -2 C) 5 D) 3 35 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 4 yoki –12 B) 3 yoki –8 C) 5 yoki –15 D) 6 36 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 44 B) 45 C) 42 D) 43 37 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 24 B) 23 C) 14 D) 35 38 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 8(π+2) B) 32 C) 64 D) 16(π-2) 39 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 32 D) 48 40 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) cd/b B) bc/d C) 1 D) bd/c O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
