Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 32 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, ning qiymatini toping. A) 0,5 B) 0,7 C) 1 D) 2 2 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8, BC = 12 bo‘lsa, CD – AD ayirmani toping. A) 4 B) 2 C) 3 D) aniqlab bo‘lmaydi 3 / 40 Muntazam oltiburchakning tomoni 2√6 ga teng. Shu ko‘pburchakka tengdosh bo‘lgan teng tomonli uchburchakning tomonini toping. A) 30 B) 24 C) 18 D) 12 4 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 5,75 B) 9,25 C) 6 D) 13 5 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) y=1-a B) y=-a C) x=-a D) x=a 6 / 40 Tengsizlikni yeching. A) (-∞;-2] B) [-3;-2] C) [-2;1]∪{-3} D) [-3;2]∪{1} 7 / 40 Soddalshtiring. A) -1 B) 1 C) 2 D) 6 8 / 40 Soddalashtiring. A) (b+2)/(1-b) B) (a-1)/(1-b) C) (a-1)/(a-3) D) (a+1)/(-a-3) 9 / 40 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 14 B) 11 C) 12 D) 13 10 / 40 Aylana tashqarisidagi nuqtadan aylanaga kesuvchi o‘tkazilgan. Berilgan nuqtadan aylanani kesgan nuqtalarigacha bo‘lgan masofalar mos ravishda 9 va 45 ga teng bo‘lsa, shu nuqtadan aylanaga o‘tkazilgan urinmaning urinish nuqtasigacha bo‘lgan masofa uzunligini toping. A) 8√3 B) 12√3 C) 9√5 D) 6√5 11 / 40 Yig‘indini toping. A) 1/6 B) 1/4 C) 1/12 D) 1/9 12 / 40 Bo‘yi 130 cm, eni 90 cm, balandligi 60 cm bo‘lgan idishdagi suvning 234 litri olindi. Idishda qolgan suvning (sathi) balandligini toping. A) 25 B) 35 C) 40 D) 20 13 / 40 Hisoblang: A) -1/2 B) 0 C) -√3/2 D) 1/32 14 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) 0 C) π/4+πk, k∈Z D) -π/4+πk, k∈Z 15 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 8 C) 10 D) 15 16 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 10 C) 9 D) 12 17 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BC > AD C) DC < AD D) BD = BC 18 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 42 B) 43 C) 44 D) 45 19 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 35 D) 24 20 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 2 B) 4 C) 1 D) 3 21 / 40 Ifodaning qiymatini toping. A) 0,04 B) 0,0(2) C) 0,(04) D) 0,0(4) 22 / 40 Tenglamalar sistemani yeching: A) (2; 3) B) (9; 0), (28; -1) C) (9; 0), (2; 7) D) (7; 2), (28; -1) 23 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 115 D) 110 24 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 8 B) 5 C) 6 D) 7 25 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 22 B) 11 C) berilganlar yetarli emas D) 121 26 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 105 C) 25 D) 96 27 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 10 B) 11 C) 7 D) 5 28 / 40 Hisoblang: A) 10/11 B) 20/21 C) 9/10 D) 19/20 29 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 1 C) 3 D) 4 30 / 40 Rasmdagi shakl perimetrini toping. A) 32 B) 30 C) 24 D) 28 31 / 40 √3 A) 21/10 B) 7/3 C) 3/2 D) 5/5 32 / 40 Tenglamani yeching: A) 6; -5 B) -6 C) -6; 5 D) 5 33 / 40 Chizmadan foydalanib α ni toping. A) 20° B) 30° C) 40° D) 50° 34 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -6 C) -3 D) -4 35 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 1 C) 2 D) 3 36 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 2 C) 4 D) 1 37 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 64 B) 42 C) 32 D) 48 38 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 14 B) 12 C) 15 D) 13 39 / 40 bo‘lsa, A) 1 B) 2 C) 3/2 D) 2/3 40 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 3√2 B) 4√2 C) 4√3 D) 6 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 13 Matematika fanidan attestatsiya savollari №16
