Matematika attestatsiya №5 Yanvar 24, 2022Yanvar 24, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №5 ga 1 fikr bildirilgan 0% 2 ovozlar, 1 o'rtacha 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 tengsizlikning barcha butun yechimlari yig‘indisining natural bo’luvchilari yig‘indisi topilsin. A) 32 B) 28 C) 24 D) 21 2 / 40 Agar a-b+c=10 va bo‘lsa, ac-ab-bc ifodaning qiymatini toping. A) 16 B) 18 C) 20 D) aniqlab bo‘lmaydi 3 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 4 B) 16 C) 9 D) 25 4 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,7 m yoki 70 cm B) 0,6 m yoki 60 cm C) 0,9 m yoki 90 cm D) 0,5 m yoki 50 cm 5 / 40 f(x)=3x-2 funksiyaning qiymatlar sohasini toping. A) (0; ∞) B) (-2; ∞) C) (-1; ∞) D) [-1; ∞) 6 / 40 Agar a>0 bo'lsa, funksiyaning vertikal asimptotasini toping. A) y=1-a B) y=-a C) x=-a D) x=a 7 / 40 Hisoblang 200−199+198−197+⋯+4−3 A) 99 B) 101 C) 98 D) 100 8 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 4 B) 3 C) 2 D) 1 9 / 40 Soddalashtiring: A) 2 B) 3 C) Aniqlab bo`lmaydi D) 1 10 / 40 108 sonining natural bo‘luvchilari ko‘paytmasi quyidagilardan qaysi biriga teng? 212·318 22·33 28·310 26·39 A) 3 B) 4 C) 2 D) 1 11 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 6 B) 10 C) 9 D) 8 12 / 40 Yig‘indini toping. A) 1/12 B) 1/9 C) 1/4 D) 1/6 13 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 4√7 C) 8 D) 6√7 14 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 4 √3tg50° tg70° B) 2√3tg50° tg70° C) √3ctg40° tg70° D) √3tg50° tg70° 15 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 23 B) 14 C) 35 D) 24 16 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) bc/d C) 1 D) cd/b 17 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 2 B) 4 C) 1 D) 3 18 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) 121 B) 11 C) 22 D) berilganlar yetarli emas 19 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 32 C) 42 D) 64 20 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 20 B) 10 C) 14 D) 12 21 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 5 D) 6 22 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 2√2 B) 2√3 C) 4√3 D) 3√2 23 / 40 a+b+c=10, bo‘lsa, ni toping. A) 6 B) 11 C) 5 D) 4 24 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 7 B) 10 C) 5 D) 11 25 / 40 3x3 o‘lchamli kvadratning tugunlarida 16 ta nuqta belgilanib, ularning o‘ng tomondan eng yuqorisidagi A bilan belgilangan. Bir uchi A nuqtada, qolgan uchlari qolgan 15 ta nuqtada orasidan tanlanadigan uchburchaklarning sonini toping. A) 100 B) 105 C) 25 D) 96 26 / 40 P(x)=x¹ºº ko‘phadni x³-3x+2 ga bo‘lganda qoladigan qoldiqni toping. 2¹ºº-1 (2¹ºº-1)x+2(299-1) (2¹ºº-1)x-2(299-1) 2¹ººx-3·2100 A) 1 B) 2 C) 4 D) 3 27 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) -6 B) -4 C) 5 D) -3 28 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 6 C) 8 D) 12 29 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 10 D) 8 30 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 4 yoki –12 C) 5 yoki –15 D) 3 yoki –8 31 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 12 B) 14 C) 13 D) 15 32 / 40 Hisoblang: A) 9/10 B) 10/11 C) 19/20 D) 20/21 33 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 2 B) 4 C) 1 D) 3 34 / 40 Chizmadan foydalanib α ni toping. A) 50° B) 40° C) 20° D) 30° 35 / 40 bo‘lsa, A) 2/3 B) 2 C) 3/2 D) 1 36 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 4 B) 2 C) 1 D) 3 37 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) DC < AD B) BD = BC C) BC > AD D) AB = BC 38 / 40 Hisoblang: A) 0 B) -1/2 C) -√3/2 D) 1/32 39 / 40 x²-√11x+1=0 0 bo‘lsa, A) 10 B) 11 C) 9 D) 12 40 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 115 C) 110 D) 112 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika attestatsiya
