Uy » Attestatsiya testlar » Matematika attestatsiya » Matematika attestatsiya №5 Matematika attestatsiya Matematika attestatsiya №5 InfoMaster Yanvar 24, 2022 73 Ko'rishlar 1 izoh SaqlashSaqlanganOlib tashlandi 0 0% 2 ovozlar, 1 avg 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 bo‘lsa, x + y ni toping. A) 17 B) 16 C) 18 D) 20 2 / 40 Quyidagi javoblardan qaysi biri tengsizlikni yechimi bo'la oladi? A) 4 B) 1 C) 2 D) 3 3 / 40 Agar ni hisoblang. A) 8 B) Cheksiz C) 9 D) 0 4 / 40 f(x)=26sin6x·sin7x funksiya uchun boshlang'ich funksiyasini toping. A) 13sinx+sin13x + C B) -13cosx- cos13 x +C C) 13sinx-sin13x + C D) 13cosx-cos13x + C 5 / 40 Qadam uzunligi deb biricnhi iz tovon oxiridan ikkinchi iz tovon oxirigacha bo'lgan masofaga aytiladi. Erkak kishi yurayotganda uning qadami va qadamlar soni orasidagi bog'lanish quyidagi formula bilan ifodalanadi: (n/P) = 140. Bu yerda n – bir minutdagi qadamlar soni. P – qadam uzunligi (m). Hikmat 1 minutda 70 qadam bossa, formula yordamida uning qadami uzunligini toping. A) 0,7 m yoki 70 cm B) 0,6 m yoki 60 cm C) 0,5 m yoki 50 cm D) 0,9 m yoki 90 cm 6 / 40 funksiyaning qiymatlar to'plamini toping. A) [-√2;0)∪(0;√2] B) [-√2;√2] C) (-2√2;√2) D) [-√2;-1)∪(-1;1)∪(1;√2] 7 / 40 Soddalashtiring: A) 3 B) 1 C) Aniqlab bo`lmaydi D) 2 8 / 40 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 14 B) 13 C) 12 D) 11 9 / 40 Standart shaklda yozing 0,000000000000013 1,3·10-12 1,3·10-13 1,3·10-14 1,3·10-15 A) 3 B) 2 C) 1 D) 4 10 / 40 Yig‘indini toping. A) 1/9 B) 1/6 C) 1/4 D) 1/12 11 / 40 Uchburchakning 3 va 4 ga teng bo‘lgan tomonlariga o‘tkazilgan medianalar o‘zaro perpendikulyar bo‘lsa, bu uchburchakning uchinchi tomonini toping. A) 2,4 B) √5 C) √6 D) 2,5 12 / 40 x²-n≤0 tengsizlik o‘rinli bo‘ladigan x ning 7 ta butun ildizi bor bo‘lsa. n nechta turli butun qiymat qabul qiladi? A) 7 B) 15 C) 12 D) 9 13 / 40 Tenglamani yeching: A) -6; 5 B) 5 C) -6 D) 6; -5 14 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 10 C) 11 D) 7 15 / 40 Hisoblang: A) sin10° B) 1 C) cos10° D) cos50° 16 / 40 sonlari geometrik progressiyaning ketma-ket hadlari bo‘ladigan barcha n larning yig‘indisini (agar bitta qiymati bo‘lsa, o‘zini) toping. A) 14 B) 23 C) 24 D) 35 17 / 40 1+sin 2x = 7(sin x + cos x) tenglamani yeching. A) Ø B) -π/4+πk, k∈Z C) π/4+πk, k∈Z D) 0 18 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 0 D) 1/32 19 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 3 B) 1 C) 4 D) 2 20 / 40 Hisoblang: A) 20/21 B) 10/11 C) 9/10 D) 19/20 21 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 3 B) 1 C) 4 D) 2 22 / 40 √3 A) 21/10 B) 7/3 C) 3/2 D) 5/5 23 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) BC > AD B) AB = BC C) BD = BC D) DC < AD 24 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 10 D) 8 25 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 12 C) 14 D) 13 26 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (7; 2), (28; -1) C) (9; 0), (2; 7) D) (2; 3) 27 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 1 D) 2 28 / 40 Barcha ikki xonali sonlar ko‘paytmasi 4 ning qanday eng katta darajasiga bo‘linadi? A) 43 B) 45 C) 44 D) 42 29 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) 1 B) bd/c C) bc/d D) cd/b 30 / 40 ABC o‘tkir burchakli uchburchakning BC asosiga AD balandlik, AC yon tomoniga BE balandlik o‘tkazilgan. Bunda CE =2AE = 8, DC = 6 bo‘lsa, BD ni toping. A) 10 B) 8 C) 6 D) 12 31 / 40 Kvadratlarning yuzlari yig‘indisini toping. A) berilganlar yetarli emas B) 22 C) 11 D) 121 32 / 40 Tenglamalar sistemasining ildizlari yig‘indisini toping. A) 12 B) 14 C) 10 D) 20 33 / 40 Rasmdagi shakl perimetrini toping. A) 30 B) 28 C) 24 D) 32 34 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 8 C) 6 D) 5 35 / 40 x²-√11x+1=0 0 bo‘lsa, A) 11 B) 9 C) 12 D) 10 36 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 3 B) -2 C) 5 D) 8 37 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -6 D) -4 38 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 40° C) 20° D) 50° 39 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 5 yoki –15 B) 3 yoki –8 C) 6 D) 4 yoki –12 40 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 16(π-2) B) 8(π+2) C) 64 D) 32 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring Author: InfoMaster Foydali bo'lsa mamnunmiz
Istaklar ro'yxatiga qo'shildiIstaklar ro'yxatidan olib tashlandi 14 Matematika fanidan attestatsiya savollari №16
