Matematika attestatsiya №5 Yanvar 24, 2022Yanvar 24, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №5 ga 1 fikr bildirilgan 0% 2 ovozlar, 1 o'rtacha 0 12345678910111213141516171819202122232425262728293031323334353637383940 Matematika fanidan attestatsiya savollari №5 1 / 40 ni qanoatlantiruvchi yechimlar nechta? A) 1 B) 0 C) 3 D) 2 2 / 40 Agar va bo'lsa f(4) ning qiymatini toping. A) 12 B) 4 C) 11 D) 35 3 / 40 ni 9 ga bo’lgandagi qoldiqning kvadratini toping. A) 4 B) 16 C) 25 D) 9 4 / 40 Umumiy hadi xn=3+5n-n2 formula bo'yicha berilgan sonli ketma-ketlikning eng katta hadi 15 dan qanchaga kam? A) 5,75 B) 6 C) 13 D) 9,25 5 / 40 cosx=0,2x tenglama nechta yechimga ega? A) 1 B) 2 C) 3 D) 4 6 / 40 P(x), Q(x) va R(x) ko'phatdalar berilgan. Bunda P(x) ko'phadning odoz hadi Q(x) ko'phadning ozod hadidan ikki marta katta va P(0)≠0. P(x)=Q(x)·R(x+1) bo'lsa, R(x) ko'phadning koeffitsiyentlarining yig'indisini toping. A) 1 B) 2 C) 4 D) 3 7 / 40 Quyida berilgan ko`rinishda mashinadan yuknitushurish uchun necha metr taxta kerak ? A) 12 B) 14 C) 13 D) 11 8 / 40 Chizmaga ko`ra x ning eng kichik butun qiymatinitoping ? A) 8 B) 7 C) 6 D) 9 9 / 40 x ni toping ? A) 3 B) 6 C) 4 D) 5 10 / 40 Integralni hisoblang: A) 1 B) 3 C) 4 D) 2 11 / 40 ABCD trapetsiyaning AC diagonali CD yon tomonga perpendikulyar. Agar ∠D=69° va AB = BC bo‘lsa, B burchakni toping. A) 132° B) 135° C) 142° D) 138° 12 / 40 Quyidagi sonini 9 ga bo‘lganda qoladigan qoldiqni toping. A) 0 B) 5 C) 1 D) 8 13 / 40 Asoslari 5 va 5√7 ga teng bo‘lgan trapetsiyaning yuzini teng ikkiga bo‘luvchi kesma asoslarga parallel. Shu kesma uzunligini toping. A) 10 B) 6√7 C) 4√7 D) 8 14 / 40 Chizmadan foydalanib α ni toping. A) 30° B) 50° C) 20° D) 40° 15 / 40 Sonlarining o‘rta geometrik qiymatini toping. A) 3√2 B) 2√3 C) 4√3 D) 2√2 16 / 40 ABC uchburchakning A burchgi 30° ga, B burchagi 75° ga teng. B uchidan AC tomonga BD kesma o‘tkazilgan. ABD burchak 45° ga teng bo‘lsa, quyidagilardan qaysi biri noto‘g‘ri? A) AB = BC B) BC > AD C) DC < AD D) BD = BC 17 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 15 B) 13 C) 14 D) 12 18 / 40 Ifodaning qiymatini quyidagi sonlardan qaysi biriga teng. 319·25 316·28 313·28 329·28 A) 2 B) 4 C) 3 D) 1 19 / 40 x²-√11x+1=0 0 bo‘lsa, A) 12 B) 9 C) 11 D) 10 20 / 40 vekorning Oxy tekislikdagi proyeksiyasi bo‘lgan vektorni toping. A) 4 B) 1 C) 3 D) 2 21 / 40 tenglamaning ildizlari yig‘indisini (agar ildizi bitta bo‘lsa, o‘zini) toping. A) 8 B) 3 C) 5 D) -2 22 / 40 To‘g‘ri to‘rtburchakning 16 ga teng diagonali yon tomoni bilan 15° li burchak tashkil etadi. To‘rtburchak yuzini toping. A) 48 B) 42 C) 64 D) 32 23 / 40 kasrning o‘nli kasr ko‘rinishidagi raqamlarining yig‘indisini toping. A) 5 B) 11 C) 10 D) 7 24 / 40 b ning qanday qiymatlarida M(2;1) nuqtadan 4x - 3y + b = 0 to‘g‘ri chiziqqacha masofa 2 ga teng bo‘ladi? A) 6 B) 3 yoki –8 C) 4 yoki –12 D) 5 yoki –15 25 / 40 Kvadratga ikkita yarim aylana ichki chizilgan. Bo‘yalgan soha yuzini toping. A) 32 B) 8(π+2) C) 16(π-2) D) 64 26 / 40 Rasmdagi shakl perimetrini toping. A) 28 B) 30 C) 32 D) 24 27 / 40 Hisoblang: A) -√3/2 B) -1/2 C) 1/32 D) 0 28 / 40 Agar geometrik progressiyaning umumiy hadi bn= 3·2n bo‘lsa, ni toping. A) 4 B) 3 C) 1 D) 2 29 / 40 P(x+1)=x³+3x²-2x+a+3 ko‘phadi berilgan. P(x+2) ko‘phadining koeffitsiyentlari yig‘indisini 8 ga teng bo‘lsa, a nechaga teng? A) 5 B) -3 C) -6 D) -4 30 / 40 A(4;6), B(2;1), C(6;1) nuqtalarni tutashtirishdan hosil bo‘ladigan uchburchak yuzini toping. A) 20 B) 15 C) 8 D) 10 31 / 40 Agar α=60°, β=70°, γ=50° bo‘lsa, tgα+ tgβ+ tgγ yig‘indi quyidagilardan qaysi biriga teng? A) 2√3tg50° tg70° B) 4 √3tg50° tg70° C) √3tg50° tg70° D) √3ctg40° tg70° 32 / 40 bo‘lsa, A) 1 B) 3/2 C) 2/3 D) 2 33 / 40 Tenglikdan foydalanib a ni toping. (a+b+c+d)·(a-b-c+d)=(a-b+c-d)·(a+b-c-d) A) bd/c B) 1 C) cd/b D) bc/d 34 / 40 Tenglamalar sistemani yeching: A) (9; 0), (28; -1) B) (9; 0), (2; 7) C) (2; 3) D) (7; 2), (28; -1) 35 / 40 ABC to‘g‘ri burchakli uchburchakning og‘irlik markazi G nuqta. Bunda AB ⊥ BC, AG ⊥ GB va AG = 8 bo‘lsa, BG ni toping. A) 4√3 B) 4√2 C) 3√2 D) 6 36 / 40 Ifodaning qiymatini toping. A) 0,(04) B) 0,0(2) C) 0,0(4) D) 0,04 37 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 7 B) 5 C) 6 D) 8 38 / 40 Tengsizlik nechta butun juft yechimga ega? A) 116 B) 112 C) 110 D) 115 39 / 40 Hisoblang: A) 20/21 B) 10/11 C) 9/10 D) 19/20 40 / 40 Tenglamani yeching: A) -6 B) -6; 5 C) 6; -5 D) 5 O'rtacha ball 0% 0% Testni qayta ishga tushiring Fikr-mulohaza yuboring tomonidan Wordpress Quiz plugin Matematika attestatsiya
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