Matematika attestatsiya №7 Fevral 2, 2022Fevral 2, 2022 da chop etilgan InfoMaster tomonidan Matematika attestatsiya №7 ga 7 fikr bildirilgan 0% 10 12345678910111213141516171819202122232425262728293031323334353637383940 OMAD YOR BO'LSIN! Matematika fanidan attestatsiya savollari №7 DIQQAT! Endi siz o'z bilmingizni sinab ko'rish bilan birga sertifikatga ham ega bo'lishingiz mumkin. Sertifikat olish uchun barcha ma'lumotlarni to'g'ri kriting! e-mail manzilini to'g'ri kriting, barcha ma'lumotlar sizga yuboriladi. Testda 76% va undan yuqori natija oling va sertifikatni yuklab oling. 1 / 40 Kamayish tartibida joylashtiring. a)5√6 b)12 c)4√10 A) a>b>c B) b>a>c C) a>c>b D) c>a>b 2 / 40 1:(2:3) son 1:2:3 sonidan qanchaga katta? A) 9 B) 4/3 C) 6 D) 3 3 / 40 Tengsizlikni yeching. A) [-3;-2] B) [-2;1]∪{-3} C) [-3;2]∪{1} D) (-∞;-2] 4 / 40 Ushbu sistemaga ko'ra (ac+bd)² ni toping. A) 4 B) 2 C) 3 D) 1 5 / 40 Quyidakilardan qaysi biri juft: 200956+200855 31210+0! 55!+877 222+333+4444 A) 4 B) 2 C) 3 D) 1 6 / 40 Shaharlar orasidagi masofa xaritada 5 sm ga teng bo`lsava xaritaning masshtabi 1:4000000 bo`lsa , shaharlar orasidagi haqiqiy masofa qanchaga teng ? A) 200 km B) 0,2km C) 20 km D) 2 km 7 / 40 Funksiyaning aniqlanish sohasini toping. A) (-∞;0)∪(0;∞) B) x∈R C) (-∞;3]∪[2;∞) D) [-3;2] 8 / 40 Dastlabki n ta hadining yig‘indisi formula bilan aniqlanadigan arifmetik progressiyaning 6-hadini toping. A) 8 B) 10 C) 6 D) 9 9 / 40 an - arifmetik progressiyaning umumiy hadi bo‘lsa, quyidagi nisbatni toping: A) 5 B) 7 C) 6 D) 8 10 / 40 6-(5:3)·(-3)²-(-3)³+15:(-3) hisoblang. A) 13 B) 12 C) 14 D) 15 11 / 40 ABC uchburchakning og‘irilik markazi G nuqta. Agar BG = 1 dm, CG = 6 cm va AG ⊥ CG bo‘lsa, AG ni (cm) toping. A) 10 B) 6 C) 8 D) 9 12 / 40 Tenglamani yeching: tg (2x + 3) = tg (3x - 2) A) 7+πk, k∈Z B) 1+πk, k∈Z C) πk, k∈Z D) 5+πk, k∈Z 13 / 40 ifodani soddalashtiring. A) a B) -1 C) 1 D) -a 14 / 40 d₁ || d₂ bo‘lsa, α ni toping. A) 25 B) 15 C) 10 D) 20 15 / 40 bo‘lsa, 4a+3b+2c ni toping. A) 4 B) 16 C) 8 D) 12 16 / 40 Tenglama nechta yechimga ega? A) 3 B) 2 C) 1 D) 0 17 / 40 Agar bo‘lsa, tgα ni toping. A) 4 B) 1 C) 2 D) 3 18 / 40 Kasrni hisoblang: A) -5 B) 14/3 C) -14/3 D) 0 19 / 40 ni hisoblang. A) 3 B) 30 C) 0,3 D) 15 20 / 40 A = {1, 2,3,5,7} va B = {1, 2,3, 4,8} A va B to‘plamlar kesishmasini toping. A) {4,8} B) {1, 2,3, 4,5,8} C) {2,3, 4,5,8,9} D) {1,2,3} 21 / 40 T= 1·1!+2·2!+ 3· 3!+ ...+ 19·19! T bo‘lsa, T +1 yig‘indi nechta 0 bilan tugaydi? A) 2 B) 3 C) 4 D) 1 22 / 40 Diagonallarining soni tomonlari sonidan 1,5 marta ko‘p bo‘lgan muntazam ko‘pburchakning tomoni 4 ga teng bo‘lsa, unga ichki chizilgan doira yuzini toping. A) 16π B) 8π C) 12π D) 10π 23 / 40 (a∈N) a sonining qanday eng kichik qiymatida (65–a) ifoda mukammal sonlardan biriga teng bo‘ladi? A) 59 B) 28 C) 17 D) 37 24 / 40 Qavariq ko‘pburchakning diagonallari soni 5 ga teng bo‘lsa, burchaklari sonini toping. A) 7 B) 5 C) 6 D) 4 25 / 40 8x²+4x³-3x-7=0 tenglama ildizlari ko‘paytmasini toping. A) 1,75 B) -4 C) -2 D) -3 26 / 40 4·(-5)-6·(-3)+(-5)·(-2) sonli ifoda qiymatini toping. A) -12 B) 48 C) 8 D) 12 27 / 40 sonining oxirgi raqamini toping. A) 3 B) 9 C) 0 D) 1 28 / 40 3 ni 14 ga bo‘lganda verguldan keyingi yettinchi raqamni toping. A) 7 B) 8 C) 5 D) 6 29 / 40 Agar n ta juft son va m ta toq sonlarni qo‘shganda juft son chiqsa, m ning qiymati qanday? A) 0 B) juft C) 1 D) toq 30 / 40 va ab = 2 bo‘lsa, (a +b)³ ni toping. A) 125 B) -64 C) -27 D) 64 31 / 40 ABCD trapetsiyada AD va BC asoslari mos ravishda 10 va 2 ga teng hamda ∠BAD= 45° . CD yon tomonning o‘rtasi E nuqta va BE ⊥ AB bo‘lsa, SABCD ni toping. A) 18 B) 24 C) 48 D) 36 32 / 40 Ishchining maoshi 900000 so‘m edi. Uning maoshi ketma-ket ikki marta bir xil foizga oshgandan so‘ng, 1190250 so‘m bo‘ldi. Maosh har safar necha foizga oshgan? A) 18 B) 15 C) 12 D) 14 33 / 40 Tengsizlikning manfiy yechimlari o‘rta arifmetigini toping. A) -1 B) -2 C) -3 D) -1,5 34 / 40 x, 24 va 30 sonlarining EKUBi 6, EKUKi 360 ga teng. Bunga ko‘ra x ning eng kichik qiymatini toping. A) 18 B) 10 C) 12 D) 15 35 / 40 Chizmadan foydalanib noma’lum burchakni toping. A) 50° B) 80° C) 60° D) 70° 36 / 40 |x²-5ax|=15a tenglama bitta manfiy va 3 ta musbat ildizga ega bo‘ladigan a larni toping. A) (2,4;∞) B) (0;2,4] C) [2,5;∞) D) (0; 2,5] 37 / 40 Tengsizlikning qanoatlantiruvchi barcha butun sonlar ko‘paytmasini toping. A) -4 B) 2 C) -2 D) 3 38 / 40 ushbu kasrning maxrajini irratsionalikdan qutqaring. A) √10-√15+√21+√14 B) √10+√15+√14-√21 C) √10-√15+√14-√21 D) √10-√15+√21-√41 39 / 40 ABCD qavariq to‘rtburchakka aylana ichki chizilgan. AB = 8 va BC = 12 bo‘lsa, CD – AD ayirmani toping? A) 4 B) 3 C) aniqlab bo’lmaydi D) 2 40 / 40 Boshlang‘ich funksiyasini toping: A) F(x)=4cos(x/4+5)+C B) F(x)=5cos(x/4+5)+C C) F(x)=-4cos(x/4+5)+C D) F(x)=(1/4)cos(x/4+5)+C 0% Testni qayta ishga tushiring Baholash mezoni - 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) saqlansin”; - 75 foizdan past ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi)ga tushirilsin”; - 75 foiz va undan yuqori ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, oliy malaka toifasi (bosh o’qituvchi lavozimi) berilsin”; - 74 foizdan 65 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, birinchi malaka toifasi (yetakchi o’qituvchi lavozimi) saqlansin”; - 65 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi)ga tushirilsin” - 64 foizdan 60 foizgacha ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tdi, ikkinchi malaka toifasi (katta o’qituvchi lavozimi) saqlansin”; - 60 foizdan kam ko’rsatgichga ega bo’lsa - “Attestatsiyadan o’tmadi, mutaxassis (oliy yoki o’rta maxsus, kasb-hunar ma'lumotli o’qituvchi) lavozimiga tushirilsin” Fikr-mulohaza yuboring Author: InfoMaster Matematika attestatsiya